3. 3
Adiabatically Mix
Flow rate = 600kg/hr.
Pressure= 1 bar
Enthalpy = 2675.4kj/kg
Temperature = 450C
Pressure = 1 bar
Enthalpy = 3382.4 kj/kg
Temperature = 350C
Pressure = 1 bar
Enthalpy =3175.6kj/kg
4. Material balance
The flow rate of saturated steam is given and the
flow rate of product and second steam are
supposed to be ‘’X’’ and ‘’Y’’ respectively and the
equation become
600 + x = y
x = y – 600
4
5. As in material balance calculation the energy
balance calculation also sees that what types of
system is. The given system is adiabatically system
means that process occurs without transferring
heat or mass between the system and its
surroundings. So the equation reduced to
Flow rate in * enthalpy in = flow rate out *enthalpy
out
5
6. Energy balance or enthalpy balance
The enthalpy at input saturated steam for 1
kg is 2675.4 kj/kg and for the 600 kj/kg is
600kg/hr. *2675.4 kj/kg the value is
1,605,240 kj/hr. and the calculation simply
start from here..
6
7. The total energy balance formula is comes out as
INPUT = OUT PUT
Mass flow rate in * Enthalpy in = Mass flow rate out *
Enthalpy out
7
8. 600.*2675.4 + 3382.4 X = 3175.6Y
putting from Material Balance the
X= Y-600
600.*2675.4 + 3382.4 (600-y)= 3175.6Y
1,605,240 + 2,028,240 = 3175.6Y+3382.4Y
5,661,720 = 6,558 Y
Y= 5661720/6558
Y = 863.33kg/hr.
8
9. By putting the value of the Y in equation of material balance we get the flow rate of
the X
X = 863.33 – 600
X = 263.33
The values of X and Y are 263.33 kg/hr. and 863.33 kg/hr. respectively.
9