(SHREYA) Chakan Call Girls Just Call 7001035870 [ Cash on Delivery ] Pune Esc...
Β
Ideal gas-processes
1.
2. ο§ Isometric process is the manner of changing the state of thermal condition of fluid
at constant volume. It could be internally reversible or internally irreversible.
ο§ Nonflow Closed System (Internally Reversible)
5. ο§ A scuba tank contains 1.5 kg of air. The air in the tank is initially at
15β. The tank is left near an engine exhaust line and the tankβs
pressure doubles. Determine a) the final temperature; b) the change
in internal energy; and c) the heat added.
6. ο§ A scuba tank contains 1.5 kg of air. The air in the tank is initially at
15β. The tank is left near an engine exhaust line and the tankβs
pressure doubles. Determine a) the final temperature; b) the change
in internal energy; and c) the heat added.
7. ο§ The pressure in an automobile tire was checked at a service station and
found to be 30 ππ π π when the temperature was 65β. Later, the same tire was
checked again, and the pressure gauge reads 35ππ π. Assuming that the
atmospheric pressure of 14.7 psi did not change, what was the new
temperature of the air in the tire?
8. ο§ The pressure in an automobile tire was checked at a service station and
found to be 30 ππ π π when the temperature was 65β. Later, the same tire was
checked again, and the pressure gauge reads 35ππ π. Assuming that the
atmospheric pressure of 14.7 psi did not change, what was the new
temperature of the air in the tire?
9. ο§ An isobaric process is an internally reversible process of a substance during which
the pressure remains constant.
Nonflow Closed System
10. ο§ Relation between V and T
π· = πͺ
π½ π
π½ π
=
π» π
π» π
ο§ Nonflow work
πΎ π =
π
π
π·π π½ = π·(π½ π β π½ π)
ο§ Change of internal energy
βπΌ = ππ π π» π β π» π
ο§ Heat transferred
πΈ = ππ π π» π β π» π
12. ο§ Consider that 1 kg of air has a 21.7 kJ decrease of internal energy
while its temperature is reduced to one third of the initial
temperature during a reversible non-flow constant pressure process.
Determine a) the initial and final temperatures, b) Q, c) W, and d)
βπ.
13. ο§ Consider that 1 kg of air has a 21.7 kJ decrease of internal energy
while its temperature is reduced to one third of the initial
temperature during a reversible non-flow constant pressure process.
Determine a) the initial and final temperatures, b) Q, c) W, and d)
βπ.
14. ο§ Assume 0.9 kg of hydrogen simultaneously rejects heat and receives paddle work
input in a nonflow change of state at constant pressure from an initial
temperature of 21β to a final temperature of 32.2β. If the heat rejected is thrice
the paddle work, determine a) βπΌ, βπ―, βπΊ for the system; b) π; and c) ππππ‘.
15. ο§ Assume 0.9 kg of hydrogen simultaneously rejects heat and receives paddle work
input in a nonflow change of state at constant pressure from an initial
temperature of 21β to a final temperature of 32.2β. If the heat rejected is thrice
the paddle work, determine a) βπΌ, βπ―, βπΊ for the system; b) π; and c) ππππ‘.
16.
17.
18. ο§ An isothermal process is an internally reversible constant temperature process of
a substance.
21. ο§ During a reversible process, there are abstracted 317 kJ/s from 1.134
kg/s of certain gas while the temperature remains constant at 27β. For
this gas, π π = 2.232
ππ½
ππ
πΎ and π π£ = 1.713
ππ½
ππ
πΎ. The initial pressure is 586
kPaa. For both nonflow and steady-flow βπ = 0, βπΎ = 0 processes,
determine a) π1, π2, and π2 ; b) W and Q, and c) βπ and βπ».
22. ο§ During a reversible process, there are abstracted 317 kJ/s from 1.134
kg/s of certain gas while the temperature remains constant at 27β. For
this gas, π π = 2.232
ππ½
ππ
πΎ and π π£ = 1.713
ππ½
ππ
πΎ. The initial pressure is 586
kPaa. For both nonflow and steady-flow βπ = 0, βπΎ = 0 processes,
determine a) π1, π2, and π2 ; b) W and Q, and c) βπ and βπ».
23. ο§ During a reversible process, there are abstracted 317 kJ/s from 1.134
kg/s of certain gas while the temperature remains constant at 27β. For
this gas, π π = 2.232
ππ½
ππ
πΎ and π π£ = 1.713
ππ½
ππ
πΎ. The initial pressure is 586
kPaa. For both nonflow and steady-flow βπ = 0, βπΎ = 0 processes,
determine a) π1, π2, and π2 ; b) W and Q, and c) βπ and βπ».
24. ο§ An isentropic process is a reversible adiabatic process. Adiabatic
simply means no heat. A reversible adiabatic is one of constant
entropy.
25. ο§ Relation between P and V
π· π π½ π
π
= π· π π½ π
π
= π
ο§ Relation between T and V
π» π
π» π
=
π½ π
π½ π
πβπ
ο§ Relation between T and P
From π1 π1
π
= π1 π2
π
and
π1 π1
π1
=
π2 π2
π2
π» π
π» π
=
π· π
π· π
πβπ
π
28. ο§ During an isentropic process of 1.36 kg/s of air, the temperature
increases from 5β to 116β. For nonflow process and steady flow
process, find a) βπΌ; b) W; c) βπ―; d) βπΊ; and e) Q.
29. ο§ During an isentropic process of 1.36 kg/s of air, the temperature
increases from 5β to 116β. For nonflow process and steady flow
process, find a) βπΌ; b) W; c) βπ―; d) βπΊ; and e) Q.
30. ο§ A nozzle is designed to expand air from 689 kPaa and 32β to 138 kPaa. Assume
an isentropic expansion and negligible approach velocity. The airflow rate is 1.36
kg/s. calculate a) the exit velocity; b) the proper exit cross-sectionl area.