E.moles of solute per liter of of solution .pdf
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1. Seminal vesicle2. Prostate gland3. bulbourethral gland4. Ep.pdf
1. Seminal vesicle
2. Prostate gland
3. bulbourethral gland
4. Epididymis
5. Testis
6. Scrotal sac
7. Urethra
8. Corpora Cavernosa
9. Ductus deferens (vas deferens)
10. Urinary bladder
Solution
1. Seminal vesicle
2. Prostate gland
3. bulbourethral gland
4. Epididymis
5. Testis
6. Scrotal sac
7. Urethra
8. Corpora Cavernosa
9. Ductus deferens (vas deferens)
10. Urinary bladder.
#include stdafx.h#include iostreamusing namespace std;cl.pdf
#include \"stdafx.h\"
#include
using namespace std;
class Inventory
{
private:
int itemNumber;
int quantity;
double cost;
double totalCost;
public:
Inventory()
{
itemNumber = 0;
quantity = 0;
cost = 0;
totalCost = 0;
}
Inventory(int newItemNumber, int newQuantity, double newCost)
{
itemNumber = newItemNumber;
quantity = newQuantity;
cost = newCost;
setTotalCost(quantity, cost); // this can be called as quantity and cost have now been
initialized.
}
void setItemNumber(int)
{
itemNumber = itemNumber;
}
void setQuantity(int)
{
quantity = quantity;
}
void setCost(double)
{
cost = cost;
}
void setTotalCost(int, double)
{
totalCost = quantity * cost;
}
int getItemNumber()
{
return itemNumber;
}
int getQuantity()
{
return quantity;
}
double getCost()
{
return cost;
}
double getTotalCost()
{
return totalCost;
}
};
int main()
{
int itemNumber;
int quantity;
double cost;
double totalCost;
cout << \"Enter the Item Number: \";
cin >> itemNumber;
while (itemNumber < 0)
{
cout << \"Please enter a positive value for the Item Number: \";
cin >> itemNumber;
}
cout << \"Enter the Quantity of the item: \";
cin >> quantity;
while (quantity < 0)
{
cout << \"Please enter a positive value for the Quantity of the item: \";
cin >> quantity;
}
cout << \"Enter the Cost of the item: \";
cin >> cost;
while (cost < 0)
{
cout << \"Please enter a positive value for the Cost of the item: \";
cin >> cost;
}
Inventory information(itemNumber, quantity, cost);
totalCost = information.getTotalCost();
itemNumber = information.getItemNumber();
cost = information.getCost();
quantity = information.getQuantity();
cout << \"The Item Number is: \" << itemNumber << endl;
cout << \"The Quantity is: \" << quantity << endl;
cout << \"The Cost is: \" << cost << endl;
cout << \"The Total Cost is: \" << totalCost << endl;
return 0;
}
int _tmain(int argc, _TCHAR* argv[])
{
return 0;
}
Solution
#include \"stdafx.h\"
#include
using namespace std;
class Inventory
{
private:
int itemNumber;
int quantity;
double cost;
double totalCost;
public:
Inventory()
{
itemNumber = 0;
quantity = 0;
cost = 0;
totalCost = 0;
}
Inventory(int newItemNumber, int newQuantity, double newCost)
{
itemNumber = newItemNumber;
quantity = newQuantity;
cost = newCost;
setTotalCost(quantity, cost); // this can be called as quantity and cost have now been
initialized.
}
void setItemNumber(int)
{
itemNumber = itemNumber;
}
void setQuantity(int)
{
quantity = quantity;
}
void setCost(double)
{
cost = cost;
}
void setTotalCost(int, double)
{
totalCost = quantity * cost;
}
int getItemNumber()
{
return itemNumber;
}
int getQuantity()
{
return quantity;
}
double getCost()
{
return cost;
}
double getTotalCost()
{
return totalCost;
}
};
int main()
{
int itemNumber;
int quantity;
double cost;
double totalCost;
cout << \"Enter the Item Number: \";
cin >> itemNumber;
while (itemNumber < 0)
{
cout << \"Please enter a positive value for the Item Number: \";
cin >> itemNumber;
}
cout << \"Enter the Quantity of the item: \";
cin >> quantity;
.
moles of Na2CO3 = massmolecular mass = 0.50106 .pdf
moles of Na2CO3 = mass/molecular mass = 0.50/106 = 4.72 x 10^-3 moles or 4.72
millimoles
Solution
moles of Na2CO3 = mass/molecular mass = 0.50/106 = 4.72 x 10^-3 moles or 4.72
millimoles.
Hydronium ion = hydrogen ion [H3O+] = [H+] = 2.15.pdf
Hydronium ion = hydrogen ion [H3O+] = [H+] = 2.15*10^-3 pH = - log [H+] pH =
- log ( 2.15*10^-3) = 2.667
Solution
Hydronium ion = hydrogen ion [H3O+] = [H+] = 2.15*10^-3 pH = - log [H+] pH =
- log ( 2.15*10^-3) = 2.667.
This is mainly based on Hard - Soft acid base theory.Hard Acid .pdf
This is mainly based on Hard - Soft acid base theory.
Hard Acid and bases :
i) Small in size
ii) Compact
iii) Nonpolarizable
Ex: Na+ , Al3+ , F-, Cl-
Soft acids and base :
i) Larger in size
ii) Low electronegativity
iii) Highly polarizable
ii) Low electronegativity
iii) Highly polarizable
Ex: Cu+, Hg+ , H-,I-
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
sulfide is a soft base whereas silicates, carbonates, and Oxides are hard bases. Hence Hg is
avilable as HgS.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable.
Solution
This is mainly based on Hard - Soft acid base theory.
Hard Acid and bases :
i) Small in size
ii) Compact
iii) Nonpolarizable
Ex: Na+ , Al3+ , F-, Cl-
Soft acids and base :
i) Larger in size
ii) Low electronegativity
iii) Highly polarizable
ii) Low electronegativity
iii) Highly polarizable
Ex: Cu+, Hg+ , H-,I-
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
sulfide is a soft base whereas silicates, carbonates, and Oxides are hard bases. Hence Hg is
avilable as HgS.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable..
We are generally omitt the concentration of the solids &the concentr.pdf
We are generally omitt the concentration of the solids &the concentration of the solvents from
the equilibrium constantexpression.
So the omitted substances areI2(s) , BaCO3(s) , Mg(s) , FeO(s) ,H2O(l) (solvent)
Solution
We are generally omitt the concentration of the solids &the concentration of the solvents from
the equilibrium constantexpression.
So the omitted substances areI2(s) , BaCO3(s) , Mg(s) , FeO(s) ,H2O(l) (solvent).
Recommended
1. Seminal vesicle2. Prostate gland3. bulbourethral gland4. Ep.pdf
1. Seminal vesicle
2. Prostate gland
3. bulbourethral gland
4. Epididymis
5. Testis
6. Scrotal sac
7. Urethra
8. Corpora Cavernosa
9. Ductus deferens (vas deferens)
10. Urinary bladder
Solution
1. Seminal vesicle
2. Prostate gland
3. bulbourethral gland
4. Epididymis
5. Testis
6. Scrotal sac
7. Urethra
8. Corpora Cavernosa
9. Ductus deferens (vas deferens)
10. Urinary bladder.
#include stdafx.h#include iostreamusing namespace std;cl.pdf
#include \"stdafx.h\"
#include
using namespace std;
class Inventory
{
private:
int itemNumber;
int quantity;
double cost;
double totalCost;
public:
Inventory()
{
itemNumber = 0;
quantity = 0;
cost = 0;
totalCost = 0;
}
Inventory(int newItemNumber, int newQuantity, double newCost)
{
itemNumber = newItemNumber;
quantity = newQuantity;
cost = newCost;
setTotalCost(quantity, cost); // this can be called as quantity and cost have now been
initialized.
}
void setItemNumber(int)
{
itemNumber = itemNumber;
}
void setQuantity(int)
{
quantity = quantity;
}
void setCost(double)
{
cost = cost;
}
void setTotalCost(int, double)
{
totalCost = quantity * cost;
}
int getItemNumber()
{
return itemNumber;
}
int getQuantity()
{
return quantity;
}
double getCost()
{
return cost;
}
double getTotalCost()
{
return totalCost;
}
};
int main()
{
int itemNumber;
int quantity;
double cost;
double totalCost;
cout << \"Enter the Item Number: \";
cin >> itemNumber;
while (itemNumber < 0)
{
cout << \"Please enter a positive value for the Item Number: \";
cin >> itemNumber;
}
cout << \"Enter the Quantity of the item: \";
cin >> quantity;
while (quantity < 0)
{
cout << \"Please enter a positive value for the Quantity of the item: \";
cin >> quantity;
}
cout << \"Enter the Cost of the item: \";
cin >> cost;
while (cost < 0)
{
cout << \"Please enter a positive value for the Cost of the item: \";
cin >> cost;
}
Inventory information(itemNumber, quantity, cost);
totalCost = information.getTotalCost();
itemNumber = information.getItemNumber();
cost = information.getCost();
quantity = information.getQuantity();
cout << \"The Item Number is: \" << itemNumber << endl;
cout << \"The Quantity is: \" << quantity << endl;
cout << \"The Cost is: \" << cost << endl;
cout << \"The Total Cost is: \" << totalCost << endl;
return 0;
}
int _tmain(int argc, _TCHAR* argv[])
{
return 0;
}
Solution
#include \"stdafx.h\"
#include
using namespace std;
class Inventory
{
private:
int itemNumber;
int quantity;
double cost;
double totalCost;
public:
Inventory()
{
itemNumber = 0;
quantity = 0;
cost = 0;
totalCost = 0;
}
Inventory(int newItemNumber, int newQuantity, double newCost)
{
itemNumber = newItemNumber;
quantity = newQuantity;
cost = newCost;
setTotalCost(quantity, cost); // this can be called as quantity and cost have now been
initialized.
}
void setItemNumber(int)
{
itemNumber = itemNumber;
}
void setQuantity(int)
{
quantity = quantity;
}
void setCost(double)
{
cost = cost;
}
void setTotalCost(int, double)
{
totalCost = quantity * cost;
}
int getItemNumber()
{
return itemNumber;
}
int getQuantity()
{
return quantity;
}
double getCost()
{
return cost;
}
double getTotalCost()
{
return totalCost;
}
};
int main()
{
int itemNumber;
int quantity;
double cost;
double totalCost;
cout << \"Enter the Item Number: \";
cin >> itemNumber;
while (itemNumber < 0)
{
cout << \"Please enter a positive value for the Item Number: \";
cin >> itemNumber;
}
cout << \"Enter the Quantity of the item: \";
cin >> quantity;
.
moles of Na2CO3 = massmolecular mass = 0.50106 .pdf
moles of Na2CO3 = mass/molecular mass = 0.50/106 = 4.72 x 10^-3 moles or 4.72
millimoles
Solution
moles of Na2CO3 = mass/molecular mass = 0.50/106 = 4.72 x 10^-3 moles or 4.72
millimoles.
Hydronium ion = hydrogen ion [H3O+] = [H+] = 2.15.pdf
Hydronium ion = hydrogen ion [H3O+] = [H+] = 2.15*10^-3 pH = - log [H+] pH =
- log ( 2.15*10^-3) = 2.667
Solution
Hydronium ion = hydrogen ion [H3O+] = [H+] = 2.15*10^-3 pH = - log [H+] pH =
- log ( 2.15*10^-3) = 2.667.
This is mainly based on Hard - Soft acid base theory.Hard Acid .pdf
This is mainly based on Hard - Soft acid base theory.
Hard Acid and bases :
i) Small in size
ii) Compact
iii) Nonpolarizable
Ex: Na+ , Al3+ , F-, Cl-
Soft acids and base :
i) Larger in size
ii) Low electronegativity
iii) Highly polarizable
ii) Low electronegativity
iii) Highly polarizable
Ex: Cu+, Hg+ , H-,I-
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
sulfide is a soft base whereas silicates, carbonates, and Oxides are hard bases. Hence Hg is
avilable as HgS.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable.
Solution
This is mainly based on Hard - Soft acid base theory.
Hard Acid and bases :
i) Small in size
ii) Compact
iii) Nonpolarizable
Ex: Na+ , Al3+ , F-, Cl-
Soft acids and base :
i) Larger in size
ii) Low electronegativity
iii) Highly polarizable
ii) Low electronegativity
iii) Highly polarizable
Ex: Cu+, Hg+ , H-,I-
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
It should be remembered that hard acid reacts with a hard base and soft acid reacts with a soft
base.
Here Hg+ is a soft, so it reacts with a soft base to form a stable compound.
sulfide is a soft base whereas silicates, carbonates, and Oxides are hard bases. Hence Hg is
avilable as HgS.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable.
Zn is a border line acid. It will have the intermediate properties between the hard and soft.
It is mainly avilable as ZnS. Even ZnO is also avilable..
We are generally omitt the concentration of the solids &the concentr.pdf
We are generally omitt the concentration of the solids &the concentration of the solvents from
the equilibrium constantexpression.
So the omitted substances areI2(s) , BaCO3(s) , Mg(s) , FeO(s) ,H2O(l) (solvent)
Solution
We are generally omitt the concentration of the solids &the concentration of the solvents from
the equilibrium constantexpression.
So the omitted substances areI2(s) , BaCO3(s) , Mg(s) , FeO(s) ,H2O(l) (solvent).
COVALENT ionic hydrogen bonding .pdf
COVALENT ionic hydrogen bonding
Solution
COVALENT ionic hydrogen bonding.
The reaction is maintained at a low temperature with slow addition o.pdf
The reaction is maintained at a low temperature with slow addition of the HNO3/H2SO4 mixture
to ensure that only one NO2 group is substituted into the benzene ring (i.e. mononitration).
If the temperature and nitronium ion (NO2+) concentration are too high (from quick addition of
HNO3/H2SO4), then the chances of more than one NO2 group substituting into the benzene ring
increases. This would give rise to unwanted dinitration products.
Solution
The reaction is maintained at a low temperature with slow addition of the HNO3/H2SO4 mixture
to ensure that only one NO2 group is substituted into the benzene ring (i.e. mononitration).
If the temperature and nitronium ion (NO2+) concentration are too high (from quick addition of
HNO3/H2SO4), then the chances of more than one NO2 group substituting into the benzene ring
increases. This would give rise to unwanted dinitration products..
There are two reasons.1. Presence of natural immunity2. Immunity.pdf
There are two reasons.
1. Presence of natural immunity
2. Immunity to superinfection
Bacteria have defense mechanisms to combat phage infection. This comprises of restriction
endonuclease system, the enzyme system which modifies the host DNA and specifically
recognize and cleave the exogenous DNA. When a phage infects, only its genome is injected into
the host cell. The injected DNA is recognized by the host restriction endonuclease system and is
cleaved into fragments.
The other reason is that immunity to superinfection. If a lysogenic phage infects a host cell, it
integrates into genome into the host chromosome. At the same time, it also prevents the host
from being infected by another lysogenic phage. The accumulation of cI protein in the host due
to the existing prophage prevents infection by other phages.
Some other reasons for resistance are lack of a receptor that facilitates the entry of the phage,
lack of supporting machinery for the phage replication.
Solution
There are two reasons.
1. Presence of natural immunity
2. Immunity to superinfection
Bacteria have defense mechanisms to combat phage infection. This comprises of restriction
endonuclease system, the enzyme system which modifies the host DNA and specifically
recognize and cleave the exogenous DNA. When a phage infects, only its genome is injected into
the host cell. The injected DNA is recognized by the host restriction endonuclease system and is
cleaved into fragments.
The other reason is that immunity to superinfection. If a lysogenic phage infects a host cell, it
integrates into genome into the host chromosome. At the same time, it also prevents the host
from being infected by another lysogenic phage. The accumulation of cI protein in the host due
to the existing prophage prevents infection by other phages.
Some other reasons for resistance are lack of a receptor that facilitates the entry of the phage,
lack of supporting machinery for the phage replication..
The difference between maximization of value of the corporation and .pdf
The difference between maximization of value of the corporation and profit maximization and
return to the shareholder and maximise their wealth is the difference of objectives of living one
and non-living legal entity.
The firms objective is not only the maximisation of the wealth or return to the Shareholders but
creating values in the product is produced, development of the society in which it operates and
growth of the persons attached to it like employees, suppliers and customers. On the other hand,
it is the Shareholders whose objective to invest in the corporation is mainly to earn return on
their investment. The shareholders wants the corporation to earns more and more profits for them
every quater. The value of the corporation can be raised by only when the general society would
recognises the company and its products and services. The corporation concentrates on the
growth and development whereas the Shareholders pay attention to the return or profits.
Solution
The difference between maximization of value of the corporation and profit maximization and
return to the shareholder and maximise their wealth is the difference of objectives of living one
and non-living legal entity.
The firms objective is not only the maximisation of the wealth or return to the Shareholders but
creating values in the product is produced, development of the society in which it operates and
growth of the persons attached to it like employees, suppliers and customers. On the other hand,
it is the Shareholders whose objective to invest in the corporation is mainly to earn return on
their investment. The shareholders wants the corporation to earns more and more profits for them
every quater. The value of the corporation can be raised by only when the general society would
recognises the company and its products and services. The corporation concentrates on the
growth and development whereas the Shareholders pay attention to the return or profits..
The changes between the steady state.SolutionThe changes betwe.pdf
The changes between the steady state.
Solution
The changes between the steady state..
Spore forming bacteria (prokaryotes) such as Bacillus anthracis can .pdf
Spore forming bacteria (prokaryotes) such as Bacillus anthracis can be dormant & survive even
for 1000 years under the exposure of ultra-violet rays (the longest UV exposure). This is because
of the following properties
Bacillus subtilis produce dormant spores by sporulation ate suitable conditions and these spores
are called as endospores. These endopores have the capability to survive at extreme temperatures
followed by insufficient nutrient availability and their spore DNA is completely resistant to
mutagens such as UV light, chemicals. They are also resistant to desiccation and resistant to
extreme freezing and chemical disinfectants.
Factor-1: These endospores possess very complex diversified structure that can withstand all the
possible mutation inducing changes. These possess structural adaptations such as exosporium,
hard spore coat and these are acts as very hard complex resistant materials, which can eliminate
digesting enzymes such as lysozymes. These endospores possess cortex composed of
peptidoglycan and it has a core wall that is present under the cortex and surrounds protoplast.
These layers potentially protect spore DNA material.
Factor-2: Core material of the spore also possesses calcium dipicolinate that enable stability of
chromosomal DNA by protecting it from oxidizing agents. Inside the core material, spore
possess DNA and it is covered by specifically small acid-soluble spore proteins an these are
similar to chromatin-like proteins and enable in protecting DNA from heat as well as UV
radiation inducing mutation.
Factor-3: In order to keep the spore dormancy all the spore structural components formed and
maintain signal transduction pathways, which further result in elevated activity of the cAMP-
dependent protein kinase, triggers rapid encapsulation.
Solution
Spore forming bacteria (prokaryotes) such as Bacillus anthracis can be dormant & survive even
for 1000 years under the exposure of ultra-violet rays (the longest UV exposure). This is because
of the following properties
Bacillus subtilis produce dormant spores by sporulation ate suitable conditions and these spores
are called as endospores. These endopores have the capability to survive at extreme temperatures
followed by insufficient nutrient availability and their spore DNA is completely resistant to
mutagens such as UV light, chemicals. They are also resistant to desiccation and resistant to
extreme freezing and chemical disinfectants.
Factor-1: These endospores possess very complex diversified structure that can withstand all the
possible mutation inducing changes. These possess structural adaptations such as exosporium,
hard spore coat and these are acts as very hard complex resistant materials, which can eliminate
digesting enzymes such as lysozymes. These endospores possess cortex composed of
peptidoglycan and it has a core wall that is present under the cortex and surrounds protoplast.
These layers potentially protect spore DNA material.
Factor-2: Core mater.
b) the solutes volatilize at different rates in t.pdf
b) the solutes volatilize at different rates in the injector
Solution
b) the solutes volatilize at different rates in the injector.
Partnership Firms are taxed at multiple levels the Corporate Level.pdf
Partnership Firms are taxed at multiple levels : the Corporate Level, which is the taxation for the
firm, and individual level, which is the taxation of the individual partners on a one-to-one basis.
Solution
Partnership Firms are taxed at multiple levels : the Corporate Level, which is the taxation for the
firm, and individual level, which is the taxation of the individual partners on a one-to-one basis..
Please give the problem detailsWhat are the solutions being mixed.pdf
Please give the problem details:
What are the solutions being mixed?, the volumes, concentrations?
Solution
Please give the problem details:
What are the solutions being mixed?, the volumes, concentrations?.
One case of paternity testing has been given in the figure. Four aut.pdf
One case of paternity testing has been given in the figure. Four autoradiographs (autorads) that
show DNA \"fingerprints\" for three individuals: a mother, her child, and the child\'s alleged
father(said father/without proof). Each autorad compares the traits inherited by these three
individuals - four traits are looked at, one for each autorad.
Presence or absence of different alleles (called DNA fingerprints) has been compared in each
case. These alleles (DNA fragments) differ in length from person to person; for this reason they
are used as genetic markers.
In case I-these alleles are A, B, C and D
In case II-E, G and F
In case III-H, I, J and K
In case IV-L, M, N and O
Ans 1
Case
Genotype of Mother
Genotype of Child
Genotype of alleged father
I
A/D
A/C
B/C
II
G/G
E/G
E/F
III
I/J
I/K
H/K
IV
M/N
M/O
L/O
Ans 2
In each case, child has inherited one copy of allele from mother and one from father so by
looking at the genotype of child, contribution from the parents can be predicted (by comparing
the genotype of all three persons)
Case
Genotype of child
Allele inherited from mother
Allele inherited from father
I
A/C
A
C
II
E/G
G
E
III
I/K
I
K
IV
M/O
M
O
Ans-3
In each case, we can see that child has inherited one copy of allele from mother and one from
father. So by making the comparison, it can be predicted that that the alleged father could be the
biological father of this child.
Ans 4
The DNA fingerprint assay is also useful in chimerism analysis after liver transplantation. Four
percent of donor lymphocytes (transient lymphocytes) are present for up to 3 weeks after
transplantation. If the donor lymphocytes persist, they can cause graft-versus-host disease
(GVHD), which is an underdiagnosed and often fatal complication that occurs in approximately
1% of cases, usually 2 to 6 weeks after transplantation. The following cases illustrate the utility
of the this assay in chimerism analysis.
A liver transplant recipient presented with a skin rash 2 weeks after transplant, and a punch
biopsy of the skin was obtained. The pathologist noted the presence of a lymphocyte infiltrate in
the dermis. Possible causes included a drug reaction, a viral infection, or early GVHD. DNA was
extracted from the area of lymphocyte infiltration, and DNA fingerprinting analysis was
performed. The results showed that some of the lymphocytes were of donor origin, confirming
the diagnosis of early GVHD.
https://www.ncbi.nlm.nih.gov/pmc/articles/PMC1200713/
Case
Genotype of Mother
Genotype of Child
Genotype of alleged father
I
A/D
A/C
B/C
II
G/G
E/G
E/F
III
I/J
I/K
H/K
IV
M/N
M/O
L/O
Solution
One case of paternity testing has been given in the figure. Four autoradiographs (autorads) that
show DNA \"fingerprints\" for three individuals: a mother, her child, and the child\'s alleged
father(said father/without proof). Each autorad compares the traits inherited by these three
individuals - four traits are looked at, one for each autorad.
Presence or absence of different alleles.
Answer is D. I (1) will add at the carbonyl rath.pdf
Answer is D. I (1) will add at the carbonyl rather than the double bond
Solution
Answer is D. I (1) will add at the carbonyl rather than the double bond.
Nasal cavity( nasal mucosa)-In humans, olfaction occurs when odora.pdf
Nasal cavity( nasal mucosa)
-In humans, olfaction occurs when odorant molecules bind to specific sites on the olfactory
receptors. These receptors are used to detect the presence of smell.
Solution
Nasal cavity( nasal mucosa)
-In humans, olfaction occurs when odorant molecules bind to specific sites on the olfactory
receptors. These receptors are used to detect the presence of smell..
Media literacy is the process of evaluating, creating and analyzing .pdf
Media literacy is the process of evaluating, creating and analyzing the media messages. In
today’s world we get a lot of information through different modes of media. Interpretation of
messages of the different media is essential. Good skills is required to understand the messages
of media. The skills of understanding the messages of different media becomes very essential.
Media literacy is the skills and ability to analyze, interpret, and evaluate the messages of media.
Media Literacy is very important because of the following reasons.
If anyone is non media literate people than they are not able to understand the messages of the
media. Even they can’t evaluate and analyze the messages of media because they don’t have
media literacy skills.
Solution
Media literacy is the process of evaluating, creating and analyzing the media messages. In
today’s world we get a lot of information through different modes of media. Interpretation of
messages of the different media is essential. Good skills is required to understand the messages
of media. The skills of understanding the messages of different media becomes very essential.
Media literacy is the skills and ability to analyze, interpret, and evaluate the messages of media.
Media Literacy is very important because of the following reasons.
If anyone is non media literate people than they are not able to understand the messages of the
media. Even they can’t evaluate and analyze the messages of media because they don’t have
media literacy skills..
In Unix (and some other operating systems) a library is a collection.pdf
In Unix (and some other operating systems) a library is a collection of related object files group
together. Libraries can be linked with other libraries and other object files to create executables.
To use system calls and library functions in a C program we simply call the appropriate C
function.
Examples of standard library functions we have met include the higher level I/O functions --
fprintf(), malloc() ...
Aritmetic operators, random number generators random(), srandom(), lrand48(), drand48() etc.
and basic C types to string conversion are memebers of the stdlib.h standard library.
Interprocess communication (IPC) is a set of programming interfaces that allow a programmer to
coordinate activities among different program processes that can run concurrently in an operating
system.
This allows a program to handle many user requests at the same time. Since even a single user
request may result in multiple processes running in the operating system on the user\'s behalf, the
processes need to communicate with each other.
The IPC interfaces make this possible. Each IPC method has its own advantages and limitations
so it is not unusual for a single program to use all of the IPC methods.
In Unix libraries executable code is there where as using Os level IPC different operating system
we will execute the program.
In Unix same opereting system program will executed and as comparing with other this is easy
that why using Unix libraries.
X.Org Implementation on X window system is not posssible.
X was specifically designed to be used over network connections rather than on an integral or
attached display device.
X features network transparency, which means an X program running on a computer somewhere
on a network (such as the Internet) can display its user interface on an X server running on some
other computer on the network.
Solution
In Unix (and some other operating systems) a library is a collection of related object files group
together. Libraries can be linked with other libraries and other object files to create executables.
To use system calls and library functions in a C program we simply call the appropriate C
function.
Examples of standard library functions we have met include the higher level I/O functions --
fprintf(), malloc() ...
Aritmetic operators, random number generators random(), srandom(), lrand48(), drand48() etc.
and basic C types to string conversion are memebers of the stdlib.h standard library.
Interprocess communication (IPC) is a set of programming interfaces that allow a programmer to
coordinate activities among different program processes that can run concurrently in an operating
system.
This allows a program to handle many user requests at the same time. Since even a single user
request may result in multiple processes running in the operating system on the user\'s behalf, the
processes need to communicate with each other.
The IPC interfaces make this possible. Each IPC method has its own advantages and limitations
so .
It is a bamboo plantFamily PoaceaeGenus Bambusa arundinaceaA.pdf
It is a bamboo plant
Family: Poaceae
Genus: Bambusa arundinacea
Authority name: Bambusa arundinacea(Retz.) Willd.
Solution
It is a bamboo plant
Family: Poaceae
Genus: Bambusa arundinacea
Authority name: Bambusa arundinacea(Retz.) Willd..
i am ready to help youSolutioni am ready to help you.pdf
i am ready to help you
Solution
i am ready to help you.
a) Fe is oxidized, Cu2+ is reduced fe goes from 0.pdf
a) Fe is oxidized, Cu2+ is reduced fe goes from 0 to +2 and cu +2 to 0
Solution
a) Fe is oxidized, Cu2+ is reduced fe goes from 0 to +2 and cu +2 to 0.
Acid is a subtance which reacts with a base.Definitions of1. A .pdf
Acid is a subtance which reacts with a base.
Definitions of:
1. A Brønsted–Lowry acid is:
That which loses/\"donates\" a proton (i.e. a H+)
2. A Brønsted–Lowry base is:
That which gains/\"accept\" a proton
Now in the reaction HSO + CN HCN + SO
HSO3 is losing the H+ thus making it Brønsted–Lowry acid.
Meanwhile, CN is gaining a H+ thus making it a Brønsted–Lowry base.
Now the 3 types of definintion of acid-base can get confusing so becareful to memorize the
different definitions of based on the different acid-base theories. They are:
1. Arrhenius acid-base
2. Brønsted–Lowry acid-base
3. Lewis acid-base
Good Luck!
Solution
Acid is a subtance which reacts with a base.
Definitions of:
1. A Brønsted–Lowry acid is:
That which loses/\"donates\" a proton (i.e. a H+)
2. A Brønsted–Lowry base is:
That which gains/\"accept\" a proton
Now in the reaction HSO + CN HCN + SO
HSO3 is losing the H+ thus making it Brønsted–Lowry acid.
Meanwhile, CN is gaining a H+ thus making it a Brønsted–Lowry base.
Now the 3 types of definintion of acid-base can get confusing so becareful to memorize the
different definitions of based on the different acid-base theories. They are:
1. Arrhenius acid-base
2. Brønsted–Lowry acid-base
3. Lewis acid-base
Good Luck!.
a. The program addresses MDG 6 Combat HIVAIDS, Malaria and other d.pdf
a. The program addresses MDG 6: Combat HIV/AIDS, Malaria and other diseases.
b. Combatting HIV/AIDS, malaria and other diseases such as tuberculosis is vital for improving
the overall health in developing countries. Rates of HIV infection can be significantly reduced
through education and behaviour change and both malaria and tuberculosis are preventable. Such
diseases contribute significantly to disease burden yet can be prevented through cost effective
methods (including education, provision of condoms).
c. By introducing the use of bed nets into the community, individuals can drastically reduce their
risk of malaria to prevent ill health.
Early detection and referrals of serious malaria cases to major hospitals ensures that those who
are infected are able to access health careto get treatment and restore their health.
Bed nets can provide individuals with peace of mind and reduce the stress and anxiety
surrounding the possibility of infection from mosquito bites.
By reducing the malaria risk posed to individuals, children are more ableto attend school in good
health to develop to their full potential and enhance their capabilities.
he program is directly increasing access to health care in disadvantaged Bangladeshi
communities to improve the health and capacities for human development.
Solution
a. The program addresses MDG 6: Combat HIV/AIDS, Malaria and other diseases.
b. Combatting HIV/AIDS, malaria and other diseases such as tuberculosis is vital for improving
the overall health in developing countries. Rates of HIV infection can be significantly reduced
through education and behaviour change and both malaria and tuberculosis are preventable. Such
diseases contribute significantly to disease burden yet can be prevented through cost effective
methods (including education, provision of condoms).
c. By introducing the use of bed nets into the community, individuals can drastically reduce their
risk of malaria to prevent ill health.
Early detection and referrals of serious malaria cases to major hospitals ensures that those who
are infected are able to access health careto get treatment and restore their health.
Bed nets can provide individuals with peace of mind and reduce the stress and anxiety
surrounding the possibility of infection from mosquito bites.
By reducing the malaria risk posed to individuals, children are more ableto attend school in good
health to develop to their full potential and enhance their capabilities.
he program is directly increasing access to health care in disadvantaged Bangladeshi
communities to improve the health and capacities for human development..
Molecular Orbitals for the N2Molecule The 2s-sigma orbital as a bo.pdf
Molecular Orbitals for the N2Molecule The 2s-sigma orbital as a bonding orbital. Note that
thereis a build-up of electron density between the nuclei. This orbitalis \"occupied\" by two
electrons in the N2 molecule. The2s-sigma star orbital is an \"antibonding\" orbital. This orbital
isnot occupied in the ground-state N2 molecule. For thisorbital, not only is there no build-up of
electron density betweenthe nuclei, there is a node between them. The 2p-sigma orbital is a
bonding orbital which can be approximatedby two 2p orbitals with their electron density lobes
pointingtoward each other. This orbital is occupied by two electrons in theground-state N2
molecule. The 2p-sigma star orbital isan antibonding orbital. This orbital is not occupied in
theground-state N2 molecule. Note that there is a nodebetween the nuclei. The 2p-pi orbital is a
bonding orbital. It is approximately two 2porbitals aligned side-by-side. It has a nodal plane just
like patomic orbitals do. There is another 2p-pi orbital that has thesame shape as this one. You
can see what it looks like by rotatingthis one by 90 degrees toward you. Both of these orbitals
areoccupied in the ground-state N2 molecule. The 2p-pi starorbital is an antibonding orbital. It
has a node between the nucleiand a nodal plane containing the nuclei. There is another 2p-pistar
orbital with the same shape as this one in the N2molecule.
Solution
Molecular Orbitals for the N2Molecule The 2s-sigma orbital as a bonding orbital. Note that
thereis a build-up of electron density between the nuclei. This orbitalis \"occupied\" by two
electrons in the N2 molecule. The2s-sigma star orbital is an \"antibonding\" orbital. This orbital
isnot occupied in the ground-state N2 molecule. For thisorbital, not only is there no build-up of
electron density betweenthe nuclei, there is a node between them. The 2p-sigma orbital is a
bonding orbital which can be approximatedby two 2p orbitals with their electron density lobes
pointingtoward each other. This orbital is occupied by two electrons in theground-state N2
molecule. The 2p-sigma star orbital isan antibonding orbital. This orbital is not occupied in
theground-state N2 molecule. Note that there is a nodebetween the nuclei. The 2p-pi orbital is a
bonding orbital. It is approximately two 2porbitals aligned side-by-side. It has a nodal plane just
like patomic orbitals do. There is another 2p-pi orbital that has thesame shape as this one. You
can see what it looks like by rotatingthis one by 90 degrees toward you. Both of these orbitals
areoccupied in the ground-state N2 molecule. The 2p-pi starorbital is an antibonding orbital. It
has a node between the nucleiand a nodal plane containing the nuclei. There is another 2p-pistar
orbital with the same shape as this one in the N2molecule..
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
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COVALENT ionic hydrogen bonding .pdf
COVALENT ionic hydrogen bonding
Solution
COVALENT ionic hydrogen bonding.
The reaction is maintained at a low temperature with slow addition o.pdf
The reaction is maintained at a low temperature with slow addition of the HNO3/H2SO4 mixture
to ensure that only one NO2 group is substituted into the benzene ring (i.e. mononitration).
If the temperature and nitronium ion (NO2+) concentration are too high (from quick addition of
HNO3/H2SO4), then the chances of more than one NO2 group substituting into the benzene ring
increases. This would give rise to unwanted dinitration products.
Solution
The reaction is maintained at a low temperature with slow addition of the HNO3/H2SO4 mixture
to ensure that only one NO2 group is substituted into the benzene ring (i.e. mononitration).
If the temperature and nitronium ion (NO2+) concentration are too high (from quick addition of
HNO3/H2SO4), then the chances of more than one NO2 group substituting into the benzene ring
increases. This would give rise to unwanted dinitration products..
There are two reasons.1. Presence of natural immunity2. Immunity.pdf
There are two reasons.
1. Presence of natural immunity
2. Immunity to superinfection
Bacteria have defense mechanisms to combat phage infection. This comprises of restriction
endonuclease system, the enzyme system which modifies the host DNA and specifically
recognize and cleave the exogenous DNA. When a phage infects, only its genome is injected into
the host cell. The injected DNA is recognized by the host restriction endonuclease system and is
cleaved into fragments.
The other reason is that immunity to superinfection. If a lysogenic phage infects a host cell, it
integrates into genome into the host chromosome. At the same time, it also prevents the host
from being infected by another lysogenic phage. The accumulation of cI protein in the host due
to the existing prophage prevents infection by other phages.
Some other reasons for resistance are lack of a receptor that facilitates the entry of the phage,
lack of supporting machinery for the phage replication.
Solution
There are two reasons.
1. Presence of natural immunity
2. Immunity to superinfection
Bacteria have defense mechanisms to combat phage infection. This comprises of restriction
endonuclease system, the enzyme system which modifies the host DNA and specifically
recognize and cleave the exogenous DNA. When a phage infects, only its genome is injected into
the host cell. The injected DNA is recognized by the host restriction endonuclease system and is
cleaved into fragments.
The other reason is that immunity to superinfection. If a lysogenic phage infects a host cell, it
integrates into genome into the host chromosome. At the same time, it also prevents the host
from being infected by another lysogenic phage. The accumulation of cI protein in the host due
to the existing prophage prevents infection by other phages.
Some other reasons for resistance are lack of a receptor that facilitates the entry of the phage,
lack of supporting machinery for the phage replication..
The difference between maximization of value of the corporation and .pdf
The difference between maximization of value of the corporation and profit maximization and
return to the shareholder and maximise their wealth is the difference of objectives of living one
and non-living legal entity.
The firms objective is not only the maximisation of the wealth or return to the Shareholders but
creating values in the product is produced, development of the society in which it operates and
growth of the persons attached to it like employees, suppliers and customers. On the other hand,
it is the Shareholders whose objective to invest in the corporation is mainly to earn return on
their investment. The shareholders wants the corporation to earns more and more profits for them
every quater. The value of the corporation can be raised by only when the general society would
recognises the company and its products and services. The corporation concentrates on the
growth and development whereas the Shareholders pay attention to the return or profits.
Solution
The difference between maximization of value of the corporation and profit maximization and
return to the shareholder and maximise their wealth is the difference of objectives of living one
and non-living legal entity.
The firms objective is not only the maximisation of the wealth or return to the Shareholders but
creating values in the product is produced, development of the society in which it operates and
growth of the persons attached to it like employees, suppliers and customers. On the other hand,
it is the Shareholders whose objective to invest in the corporation is mainly to earn return on
their investment. The shareholders wants the corporation to earns more and more profits for them
every quater. The value of the corporation can be raised by only when the general society would
recognises the company and its products and services. The corporation concentrates on the
growth and development whereas the Shareholders pay attention to the return or profits..
The changes between the steady state.SolutionThe changes betwe.pdf
The changes between the steady state.
Solution
The changes between the steady state..
Spore forming bacteria (prokaryotes) such as Bacillus anthracis can .pdf
Spore forming bacteria (prokaryotes) such as Bacillus anthracis can be dormant & survive even
for 1000 years under the exposure of ultra-violet rays (the longest UV exposure). This is because
of the following properties
Bacillus subtilis produce dormant spores by sporulation ate suitable conditions and these spores
are called as endospores. These endopores have the capability to survive at extreme temperatures
followed by insufficient nutrient availability and their spore DNA is completely resistant to
mutagens such as UV light, chemicals. They are also resistant to desiccation and resistant to
extreme freezing and chemical disinfectants.
Factor-1: These endospores possess very complex diversified structure that can withstand all the
possible mutation inducing changes. These possess structural adaptations such as exosporium,
hard spore coat and these are acts as very hard complex resistant materials, which can eliminate
digesting enzymes such as lysozymes. These endospores possess cortex composed of
peptidoglycan and it has a core wall that is present under the cortex and surrounds protoplast.
These layers potentially protect spore DNA material.
Factor-2: Core material of the spore also possesses calcium dipicolinate that enable stability of
chromosomal DNA by protecting it from oxidizing agents. Inside the core material, spore
possess DNA and it is covered by specifically small acid-soluble spore proteins an these are
similar to chromatin-like proteins and enable in protecting DNA from heat as well as UV
radiation inducing mutation.
Factor-3: In order to keep the spore dormancy all the spore structural components formed and
maintain signal transduction pathways, which further result in elevated activity of the cAMP-
dependent protein kinase, triggers rapid encapsulation.
Solution
Spore forming bacteria (prokaryotes) such as Bacillus anthracis can be dormant & survive even
for 1000 years under the exposure of ultra-violet rays (the longest UV exposure). This is because
of the following properties
Bacillus subtilis produce dormant spores by sporulation ate suitable conditions and these spores
are called as endospores. These endopores have the capability to survive at extreme temperatures
followed by insufficient nutrient availability and their spore DNA is completely resistant to
mutagens such as UV light, chemicals. They are also resistant to desiccation and resistant to
extreme freezing and chemical disinfectants.
Factor-1: These endospores possess very complex diversified structure that can withstand all the
possible mutation inducing changes. These possess structural adaptations such as exosporium,
hard spore coat and these are acts as very hard complex resistant materials, which can eliminate
digesting enzymes such as lysozymes. These endospores possess cortex composed of
peptidoglycan and it has a core wall that is present under the cortex and surrounds protoplast.
These layers potentially protect spore DNA material.
Factor-2: Core mater.
b) the solutes volatilize at different rates in t.pdf
b) the solutes volatilize at different rates in the injector
Solution
b) the solutes volatilize at different rates in the injector.
Partnership Firms are taxed at multiple levels the Corporate Level.pdf
Partnership Firms are taxed at multiple levels : the Corporate Level, which is the taxation for the
firm, and individual level, which is the taxation of the individual partners on a one-to-one basis.
Solution
Partnership Firms are taxed at multiple levels : the Corporate Level, which is the taxation for the
firm, and individual level, which is the taxation of the individual partners on a one-to-one basis..
Please give the problem detailsWhat are the solutions being mixed.pdf
Please give the problem details:
What are the solutions being mixed?, the volumes, concentrations?
Solution
Please give the problem details:
What are the solutions being mixed?, the volumes, concentrations?.
One case of paternity testing has been given in the figure. Four aut.pdf
One case of paternity testing has been given in the figure. Four autoradiographs (autorads) that
show DNA \"fingerprints\" for three individuals: a mother, her child, and the child\'s alleged
father(said father/without proof). Each autorad compares the traits inherited by these three
individuals - four traits are looked at, one for each autorad.
Presence or absence of different alleles (called DNA fingerprints) has been compared in each
case. These alleles (DNA fragments) differ in length from person to person; for this reason they
are used as genetic markers.
In case I-these alleles are A, B, C and D
In case II-E, G and F
In case III-H, I, J and K
In case IV-L, M, N and O
Ans 1
Case
Genotype of Mother
Genotype of Child
Genotype of alleged father
I
A/D
A/C
B/C
II
G/G
E/G
E/F
III
I/J
I/K
H/K
IV
M/N
M/O
L/O
Ans 2
In each case, child has inherited one copy of allele from mother and one from father so by
looking at the genotype of child, contribution from the parents can be predicted (by comparing
the genotype of all three persons)
Case
Genotype of child
Allele inherited from mother
Allele inherited from father
I
A/C
A
C
II
E/G
G
E
III
I/K
I
K
IV
M/O
M
O
Ans-3
In each case, we can see that child has inherited one copy of allele from mother and one from
father. So by making the comparison, it can be predicted that that the alleged father could be the
biological father of this child.
Ans 4
The DNA fingerprint assay is also useful in chimerism analysis after liver transplantation. Four
percent of donor lymphocytes (transient lymphocytes) are present for up to 3 weeks after
transplantation. If the donor lymphocytes persist, they can cause graft-versus-host disease
(GVHD), which is an underdiagnosed and often fatal complication that occurs in approximately
1% of cases, usually 2 to 6 weeks after transplantation. The following cases illustrate the utility
of the this assay in chimerism analysis.
A liver transplant recipient presented with a skin rash 2 weeks after transplant, and a punch
biopsy of the skin was obtained. The pathologist noted the presence of a lymphocyte infiltrate in
the dermis. Possible causes included a drug reaction, a viral infection, or early GVHD. DNA was
extracted from the area of lymphocyte infiltration, and DNA fingerprinting analysis was
performed. The results showed that some of the lymphocytes were of donor origin, confirming
the diagnosis of early GVHD.
https://www.ncbi.nlm.nih.gov/pmc/articles/PMC1200713/
Case
Genotype of Mother
Genotype of Child
Genotype of alleged father
I
A/D
A/C
B/C
II
G/G
E/G
E/F
III
I/J
I/K
H/K
IV
M/N
M/O
L/O
Solution
One case of paternity testing has been given in the figure. Four autoradiographs (autorads) that
show DNA \"fingerprints\" for three individuals: a mother, her child, and the child\'s alleged
father(said father/without proof). Each autorad compares the traits inherited by these three
individuals - four traits are looked at, one for each autorad.
Presence or absence of different alleles.
Answer is D. I (1) will add at the carbonyl rath.pdf
Answer is D. I (1) will add at the carbonyl rather than the double bond
Solution
Answer is D. I (1) will add at the carbonyl rather than the double bond.
Nasal cavity( nasal mucosa)-In humans, olfaction occurs when odora.pdf
Nasal cavity( nasal mucosa)
-In humans, olfaction occurs when odorant molecules bind to specific sites on the olfactory
receptors. These receptors are used to detect the presence of smell.
Solution
Nasal cavity( nasal mucosa)
-In humans, olfaction occurs when odorant molecules bind to specific sites on the olfactory
receptors. These receptors are used to detect the presence of smell..
Media literacy is the process of evaluating, creating and analyzing .pdf
Media literacy is the process of evaluating, creating and analyzing the media messages. In
today’s world we get a lot of information through different modes of media. Interpretation of
messages of the different media is essential. Good skills is required to understand the messages
of media. The skills of understanding the messages of different media becomes very essential.
Media literacy is the skills and ability to analyze, interpret, and evaluate the messages of media.
Media Literacy is very important because of the following reasons.
If anyone is non media literate people than they are not able to understand the messages of the
media. Even they can’t evaluate and analyze the messages of media because they don’t have
media literacy skills.
Solution
Media literacy is the process of evaluating, creating and analyzing the media messages. In
today’s world we get a lot of information through different modes of media. Interpretation of
messages of the different media is essential. Good skills is required to understand the messages
of media. The skills of understanding the messages of different media becomes very essential.
Media literacy is the skills and ability to analyze, interpret, and evaluate the messages of media.
Media Literacy is very important because of the following reasons.
If anyone is non media literate people than they are not able to understand the messages of the
media. Even they can’t evaluate and analyze the messages of media because they don’t have
media literacy skills..
In Unix (and some other operating systems) a library is a collection.pdf
In Unix (and some other operating systems) a library is a collection of related object files group
together. Libraries can be linked with other libraries and other object files to create executables.
To use system calls and library functions in a C program we simply call the appropriate C
function.
Examples of standard library functions we have met include the higher level I/O functions --
fprintf(), malloc() ...
Aritmetic operators, random number generators random(), srandom(), lrand48(), drand48() etc.
and basic C types to string conversion are memebers of the stdlib.h standard library.
Interprocess communication (IPC) is a set of programming interfaces that allow a programmer to
coordinate activities among different program processes that can run concurrently in an operating
system.
This allows a program to handle many user requests at the same time. Since even a single user
request may result in multiple processes running in the operating system on the user\'s behalf, the
processes need to communicate with each other.
The IPC interfaces make this possible. Each IPC method has its own advantages and limitations
so it is not unusual for a single program to use all of the IPC methods.
In Unix libraries executable code is there where as using Os level IPC different operating system
we will execute the program.
In Unix same opereting system program will executed and as comparing with other this is easy
that why using Unix libraries.
X.Org Implementation on X window system is not posssible.
X was specifically designed to be used over network connections rather than on an integral or
attached display device.
X features network transparency, which means an X program running on a computer somewhere
on a network (such as the Internet) can display its user interface on an X server running on some
other computer on the network.
Solution
In Unix (and some other operating systems) a library is a collection of related object files group
together. Libraries can be linked with other libraries and other object files to create executables.
To use system calls and library functions in a C program we simply call the appropriate C
function.
Examples of standard library functions we have met include the higher level I/O functions --
fprintf(), malloc() ...
Aritmetic operators, random number generators random(), srandom(), lrand48(), drand48() etc.
and basic C types to string conversion are memebers of the stdlib.h standard library.
Interprocess communication (IPC) is a set of programming interfaces that allow a programmer to
coordinate activities among different program processes that can run concurrently in an operating
system.
This allows a program to handle many user requests at the same time. Since even a single user
request may result in multiple processes running in the operating system on the user\'s behalf, the
processes need to communicate with each other.
The IPC interfaces make this possible. Each IPC method has its own advantages and limitations
so .
It is a bamboo plantFamily PoaceaeGenus Bambusa arundinaceaA.pdf
It is a bamboo plant
Family: Poaceae
Genus: Bambusa arundinacea
Authority name: Bambusa arundinacea(Retz.) Willd.
Solution
It is a bamboo plant
Family: Poaceae
Genus: Bambusa arundinacea
Authority name: Bambusa arundinacea(Retz.) Willd..
i am ready to help youSolutioni am ready to help you.pdf
i am ready to help you
Solution
i am ready to help you.
a) Fe is oxidized, Cu2+ is reduced fe goes from 0.pdf
a) Fe is oxidized, Cu2+ is reduced fe goes from 0 to +2 and cu +2 to 0
Solution
a) Fe is oxidized, Cu2+ is reduced fe goes from 0 to +2 and cu +2 to 0.
Acid is a subtance which reacts with a base.Definitions of1. A .pdf
Acid is a subtance which reacts with a base.
Definitions of:
1. A Brønsted–Lowry acid is:
That which loses/\"donates\" a proton (i.e. a H+)
2. A Brønsted–Lowry base is:
That which gains/\"accept\" a proton
Now in the reaction HSO + CN HCN + SO
HSO3 is losing the H+ thus making it Brønsted–Lowry acid.
Meanwhile, CN is gaining a H+ thus making it a Brønsted–Lowry base.
Now the 3 types of definintion of acid-base can get confusing so becareful to memorize the
different definitions of based on the different acid-base theories. They are:
1. Arrhenius acid-base
2. Brønsted–Lowry acid-base
3. Lewis acid-base
Good Luck!
Solution
Acid is a subtance which reacts with a base.
Definitions of:
1. A Brønsted–Lowry acid is:
That which loses/\"donates\" a proton (i.e. a H+)
2. A Brønsted–Lowry base is:
That which gains/\"accept\" a proton
Now in the reaction HSO + CN HCN + SO
HSO3 is losing the H+ thus making it Brønsted–Lowry acid.
Meanwhile, CN is gaining a H+ thus making it a Brønsted–Lowry base.
Now the 3 types of definintion of acid-base can get confusing so becareful to memorize the
different definitions of based on the different acid-base theories. They are:
1. Arrhenius acid-base
2. Brønsted–Lowry acid-base
3. Lewis acid-base
Good Luck!.
a. The program addresses MDG 6 Combat HIVAIDS, Malaria and other d.pdf
a. The program addresses MDG 6: Combat HIV/AIDS, Malaria and other diseases.
b. Combatting HIV/AIDS, malaria and other diseases such as tuberculosis is vital for improving
the overall health in developing countries. Rates of HIV infection can be significantly reduced
through education and behaviour change and both malaria and tuberculosis are preventable. Such
diseases contribute significantly to disease burden yet can be prevented through cost effective
methods (including education, provision of condoms).
c. By introducing the use of bed nets into the community, individuals can drastically reduce their
risk of malaria to prevent ill health.
Early detection and referrals of serious malaria cases to major hospitals ensures that those who
are infected are able to access health careto get treatment and restore their health.
Bed nets can provide individuals with peace of mind and reduce the stress and anxiety
surrounding the possibility of infection from mosquito bites.
By reducing the malaria risk posed to individuals, children are more ableto attend school in good
health to develop to their full potential and enhance their capabilities.
he program is directly increasing access to health care in disadvantaged Bangladeshi
communities to improve the health and capacities for human development.
Solution
a. The program addresses MDG 6: Combat HIV/AIDS, Malaria and other diseases.
b. Combatting HIV/AIDS, malaria and other diseases such as tuberculosis is vital for improving
the overall health in developing countries. Rates of HIV infection can be significantly reduced
through education and behaviour change and both malaria and tuberculosis are preventable. Such
diseases contribute significantly to disease burden yet can be prevented through cost effective
methods (including education, provision of condoms).
c. By introducing the use of bed nets into the community, individuals can drastically reduce their
risk of malaria to prevent ill health.
Early detection and referrals of serious malaria cases to major hospitals ensures that those who
are infected are able to access health careto get treatment and restore their health.
Bed nets can provide individuals with peace of mind and reduce the stress and anxiety
surrounding the possibility of infection from mosquito bites.
By reducing the malaria risk posed to individuals, children are more ableto attend school in good
health to develop to their full potential and enhance their capabilities.
he program is directly increasing access to health care in disadvantaged Bangladeshi
communities to improve the health and capacities for human development..
Molecular Orbitals for the N2Molecule The 2s-sigma orbital as a bo.pdf
Molecular Orbitals for the N2Molecule The 2s-sigma orbital as a bonding orbital. Note that
thereis a build-up of electron density between the nuclei. This orbitalis \"occupied\" by two
electrons in the N2 molecule. The2s-sigma star orbital is an \"antibonding\" orbital. This orbital
isnot occupied in the ground-state N2 molecule. For thisorbital, not only is there no build-up of
electron density betweenthe nuclei, there is a node between them. The 2p-sigma orbital is a
bonding orbital which can be approximatedby two 2p orbitals with their electron density lobes
pointingtoward each other. This orbital is occupied by two electrons in theground-state N2
molecule. The 2p-sigma star orbital isan antibonding orbital. This orbital is not occupied in
theground-state N2 molecule. Note that there is a nodebetween the nuclei. The 2p-pi orbital is a
bonding orbital. It is approximately two 2porbitals aligned side-by-side. It has a nodal plane just
like patomic orbitals do. There is another 2p-pi orbital that has thesame shape as this one. You
can see what it looks like by rotatingthis one by 90 degrees toward you. Both of these orbitals
areoccupied in the ground-state N2 molecule. The 2p-pi starorbital is an antibonding orbital. It
has a node between the nucleiand a nodal plane containing the nuclei. There is another 2p-pistar
orbital with the same shape as this one in the N2molecule.
Solution
Molecular Orbitals for the N2Molecule The 2s-sigma orbital as a bonding orbital. Note that
thereis a build-up of electron density between the nuclei. This orbitalis \"occupied\" by two
electrons in the N2 molecule. The2s-sigma star orbital is an \"antibonding\" orbital. This orbital
isnot occupied in the ground-state N2 molecule. For thisorbital, not only is there no build-up of
electron density betweenthe nuclei, there is a node between them. The 2p-sigma orbital is a
bonding orbital which can be approximatedby two 2p orbitals with their electron density lobes
pointingtoward each other. This orbital is occupied by two electrons in theground-state N2
molecule. The 2p-sigma star orbital isan antibonding orbital. This orbital is not occupied in
theground-state N2 molecule. Note that there is a nodebetween the nuclei. The 2p-pi orbital is a
bonding orbital. It is approximately two 2porbitals aligned side-by-side. It has a nodal plane just
like patomic orbitals do. There is another 2p-pi orbital that has thesame shape as this one. You
can see what it looks like by rotatingthis one by 90 degrees toward you. Both of these orbitals
areoccupied in the ground-state N2 molecule. The 2p-pi starorbital is an antibonding orbital. It
has a node between the nucleiand a nodal plane containing the nuclei. There is another 2p-pistar
orbital with the same shape as this one in the N2molecule..
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