This document contains 14 multiple choice questions with answers regarding binary, octal, hexadecimal, binary coded decimal, 1's complement, 2's complement, and excess-3 code conversions and operations. The questions cover topics such as binary addition and multiplication, 1's and 2's complement, conversion between number systems, and counting 1s in binary representations. For each question, the correct multiple choice answer is provided.

2. Q1: 1’S COMPLEMENT OF 101101
A. 010010
B. 010011
 The correct answer is: A(010010)

3. Q2: 2’S COMPLEMENT OF 0101101
A. 1010010
B. 1010011
 The correct answer is: B(1010011)

4. Q3: PRODUCT OF TWO BINARY
NUMBERS 0101 AND 0110 IS:
A. 11110
B. 11101
 The correct answer is: A(11110)
{0101=5 and 0110=6,5x6=30 and 30 in binary=11110}

5. Q4:OCTAL EQUIVALENT OF 101101 IS:
A. (55)8
B. (15)8
 The correct answer is: (55)8

6. Q5: 1’S AND 2’S COMPLEMENT OF
110010111
A. (001101111) and (001101000)
B. (001101000) and (001101001)

The correct answer is: (001101000) and (001101001)

7. Q6: Binary equivalent of (86)10 is:
A. (1010110)2
B. (1001100)2
 The correct ans is: (1010110)2

8. Q6: BCD ADDITION OF 56 AND 21 IS:
A. (01110111)2
B. (1001101)2
 The correct ans is: A (01110111)2
 56 IN BCD=0101 0110 AND 21 IN
BCD=0010 0001(56+21=77)=>77 IN BCD
=01110111

9. Q7: Octal and Hexadecimal equivalent
of (10101101010)2
A. (1552)8 and (19A)16
B. (2552)8 and (56A)16
 The correct answer is: (2552)8 and (56A)16

10. Q8: BCD equivalent code of (589)10
A. (010110001001)
B. (011001111001)
 The correct answer is: A (010110001001)

{In BCD code, we write 4 bit binary equivalent of each
digit, so 5=0101,8=1000,9=1001}

11. Q9: SUM OF 15 AND 24 IN BINARY
A. (0001101)
B. (100111)
 The correct answer is: B (100111)
 {15+24=39, 39 in binary=100111}

12. Q:Find excess-3 code for the decimal
number 564
A. 100010010111
B. 100101100100
 The correct answer is A(100010010111)
 {5+3=8=1000,6+3=9=1001,4+3=7=0111=>564
=100010010111}

13. Q10: (101)2 X (1010)2 is:
A. (110010)
B. (100101)
 The correct answer is: A (110010)
 {101=5 and 1010=10, 5*10=50, 50 in
binary=110010}

14. Q11 Number of 1’s present in the
binary equivalent of 5x5 is:
A. 2
B. 3
 The correct answer is: B(3)

{5x5=25, 25 in binary=11001 so total no of 1’s =3}

15. Q: Find the decimal equivalent of
excess-3 code 110010010101.1100
A. (962.9)
B. (965.5)
 The correct answer is: A(962.9)
{1100=12-3=9,
1001=9-3=6 ,
0101=5-3=2
1100=12-3=9}

16. Q12: Hexadecimal equivalent of (86)10
A. (56)16
B. (9A)16
 The correct answer is: (56)16

17. Q13: what is the binary equivalent of
Gray code 11100?
A. (01011)
B. (10111)
 The correct answer is: B (10111)


{gray code retain first bit but takes X-OR of
consecutive bits of given binary value
1 SAME,0 + 1=1,1 + 0=1,1 + 1=0,1 + 1=0}

18. Q13:Total number of 1’s in the 2’s
complement of 11000100
A. 4
B. 5
 The correct answer is: A (4)

{2’S COMPLEMENT OF 11000100=00111100}

19. Q14: Binary representation of
hexadecimal number (125)16 IS:
A. (0000000111011010)2
B. (0000000100100101)2

The correct answer is: B (0000000100100101)2