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Chapters for First Semester
1. Chapter 6 - Deformation of Solids
2. Chapter 7 - Waves
3. Chapter 8 - Superposition
4. Chapter 17 - Oscillations
5. Topic 9 Electricity
Deformation of Solids
Stress and Strain
● Tensile and compressive
forces.
● Understand terms of load,
extension, compression
and limit of proportionality.
● Recall and use Hooke’s Law
Elastic and Plastic
Behaviour
● Understand terms of,
elastic deformation,
plastic deformation and
elastic limit.
● Understand graph of work
done.
● Determine the elastic
potential energy of
material deformation.
01 02
Tensile and
Compression
❖ The change of shape or size is called
deformation.
❖ Tensile deformation happens when an
object is stretched (a).
❖ Compressive deformation happens when
an object is squeezed/compressed (b).
Tensile strength is the amount of load or stress a
material can handle until it stretches or break.
What is MPa?
Megapascal
1 MPa = 1.000.000 Pa
Relationship of tensile strength, force and strain.
❖ What F stands for?
➢ Force
❖ What e stands for?
➢ Strain
❖ What is tensile force?
➢ The amount of load or stress a material can
handle until it stretches or breaks
Relationship of tensile strength, force and strain.
❖ What is elastic deformation?
➢ Temporary deformation, due to stress. After
the stress is released, shape of the body is
restored.
❖ What is plastic deformation?
➢ Permanent deformation, due to stress. After
the stress is released, shape of the body
elongate, compress, buckle, bend or twist.
Relationship of tensile strength, force and strain.
❖ What is breaking point?
➢ The point where the body breaks.
❖ What is elastic behaviour?
➢ Ability of a deformed body to return to its
original shape and size when the force is
released.
1. The extension of the spring is determined
by how much it has increased in length.
2. The limit of proportionality is the point
beyond which Hooke’s law is no longer
true when stretching a material i.e. the
extension is no longer proportional to the
applied load.
3. The point is identified on the graph where
the line is no longer straight and starts
to curve (flattens out).
4. Hooke’s law also applies to compression
as well as extension. The only difference is
that an applied force is now proportional
to the decrease in length.
5. The gradient of this graph is equal to the
spring constant k. This is explored further
in the revision notes “The Spring Constant”
Questions
What is meant by the limit of proportionality?
➢ Limit of proportionality is the point up to which the force is proportional
to the extension
Calculate the spring constant for a spring which extends by a
distance of 3.5 cm when a load of 14 N is hung from its end.
k = F / Δx
F = 14 N
Δx = 3.5 cm = 0.035 m
k = 14 N/0.035 m = 400 N/m
A steel extends by 1.5 mm when it is under a tensile force of 45
N. Calculate:
a. Spring constant of wire.
b. Tensile force required to extend it by 1.8 mm and
proportionality is not exceeded.
(a)Why do we use Hooke’s Law?
Because proportionality is not exceeded.
k = F / Δx
F = 45 N
Δx = 1.5 mm = 0.0015 m
k = 45 N/0.0015 m = 30.000 N/m
A steel extends by 1.5 mm when it is under a tensile force of 45
N. Calculate:
a. Spring constant of wire.
b. Tensile force required to extend it by 1.8 mm and
proportionality is not exceeded.
(b)Why do we use Hooke’s Law?
Because proportionality is not exceeded.
F = k. Δx
k = 30.000 N/m
Δx = 1.8 mm = 0.0018 m
F = 30.000 x 0.0018 = 54 N
● Tensile stress is the applied force per unit cross sectional area of a material.
● The ultimate tensile stress is the maximum force per original cross-
sectional area a wire is able to support before it breaks.
Stress
● Strain is the extension per unit length.
● This is a deformation of solid due to stress in the form of elongation and
contraction.
● Strains is a dimensionless unit because its the ratio of lengths.
Strain
Young’s Modulus
❖ The Young Modulus is the measure of the ability of material to
withstand changes in length with an added load (how stiff
materials are).
❖ Modulus Young represents the elasticity of a material.
❖ The Young Modulus is defined as the ratio of stress and strain.
Young’s Modulus
❖ Its unit is the as stress: Pa.
❖ Just like the Force-Extension
graph, stress and strain are
directly proportional to one
another for a material exhibiting
elastic behavior.
❖ A stress-strain graph is a straight
line with its gradient equal to
Young Modulus.
● Worked Example 6B
● Questions 4 and 5 Page 103-104
The heels on a pair of women’s shoes have a radius of .5
cm at the bottom. If 30% of the weight of a woman 480N
is supported by each heel, find the stress on each heel.
Parallel Spring Circuit
Series Spring Circuit
A B C D
Spring constant (k1 = k2 = k3) = 200 N/m
extension = 1 cm
what is the magnitude of the weight?
Force that pulls the spring is weight.
Hence Weight = F
Spring constant (k1 = k2 = k3 = k4) = 500 N/m
weight (w) = 20 Newton
calculate the extension
Graph of Potential Energy
Area under the graph = W = Ep
Elastic Potential Energy
Elastic potential energy is energy
strain in an object due to change of
shape or size.
Worked Example 6C
Deformation of Solids Cambridge A Level Physics
Deformation of Solids Cambridge A Level Physics
Deformation of Solids Cambridge A Level Physics
Deformation of Solids Cambridge A Level Physics
Deformation of Solids Cambridge A Level Physics

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Deformation of Solids Cambridge A Level Physics

  • 1. Chapters for First Semester 1. Chapter 6 - Deformation of Solids 2. Chapter 7 - Waves 3. Chapter 8 - Superposition 4. Chapter 17 - Oscillations 5. Topic 9 Electricity
  • 2. Deformation of Solids Stress and Strain ● Tensile and compressive forces. ● Understand terms of load, extension, compression and limit of proportionality. ● Recall and use Hooke’s Law Elastic and Plastic Behaviour ● Understand terms of, elastic deformation, plastic deformation and elastic limit. ● Understand graph of work done. ● Determine the elastic potential energy of material deformation. 01 02
  • 3. Tensile and Compression ❖ The change of shape or size is called deformation. ❖ Tensile deformation happens when an object is stretched (a). ❖ Compressive deformation happens when an object is squeezed/compressed (b).
  • 4. Tensile strength is the amount of load or stress a material can handle until it stretches or break. What is MPa? Megapascal 1 MPa = 1.000.000 Pa
  • 5. Relationship of tensile strength, force and strain. ❖ What F stands for? ➢ Force ❖ What e stands for? ➢ Strain ❖ What is tensile force? ➢ The amount of load or stress a material can handle until it stretches or breaks
  • 6. Relationship of tensile strength, force and strain. ❖ What is elastic deformation? ➢ Temporary deformation, due to stress. After the stress is released, shape of the body is restored. ❖ What is plastic deformation? ➢ Permanent deformation, due to stress. After the stress is released, shape of the body elongate, compress, buckle, bend or twist.
  • 7. Relationship of tensile strength, force and strain. ❖ What is breaking point? ➢ The point where the body breaks. ❖ What is elastic behaviour? ➢ Ability of a deformed body to return to its original shape and size when the force is released.
  • 8.
  • 9. 1. The extension of the spring is determined by how much it has increased in length. 2. The limit of proportionality is the point beyond which Hooke’s law is no longer true when stretching a material i.e. the extension is no longer proportional to the applied load. 3. The point is identified on the graph where the line is no longer straight and starts to curve (flattens out). 4. Hooke’s law also applies to compression as well as extension. The only difference is that an applied force is now proportional to the decrease in length. 5. The gradient of this graph is equal to the spring constant k. This is explored further in the revision notes “The Spring Constant”
  • 10.
  • 11. Questions What is meant by the limit of proportionality? ➢ Limit of proportionality is the point up to which the force is proportional to the extension Calculate the spring constant for a spring which extends by a distance of 3.5 cm when a load of 14 N is hung from its end. k = F / Δx F = 14 N Δx = 3.5 cm = 0.035 m k = 14 N/0.035 m = 400 N/m
  • 12. A steel extends by 1.5 mm when it is under a tensile force of 45 N. Calculate: a. Spring constant of wire. b. Tensile force required to extend it by 1.8 mm and proportionality is not exceeded. (a)Why do we use Hooke’s Law? Because proportionality is not exceeded. k = F / Δx F = 45 N Δx = 1.5 mm = 0.0015 m k = 45 N/0.0015 m = 30.000 N/m
  • 13. A steel extends by 1.5 mm when it is under a tensile force of 45 N. Calculate: a. Spring constant of wire. b. Tensile force required to extend it by 1.8 mm and proportionality is not exceeded. (b)Why do we use Hooke’s Law? Because proportionality is not exceeded. F = k. Δx k = 30.000 N/m Δx = 1.8 mm = 0.0018 m F = 30.000 x 0.0018 = 54 N
  • 14.
  • 15. ● Tensile stress is the applied force per unit cross sectional area of a material. ● The ultimate tensile stress is the maximum force per original cross- sectional area a wire is able to support before it breaks. Stress
  • 16. ● Strain is the extension per unit length. ● This is a deformation of solid due to stress in the form of elongation and contraction. ● Strains is a dimensionless unit because its the ratio of lengths. Strain
  • 17. Young’s Modulus ❖ The Young Modulus is the measure of the ability of material to withstand changes in length with an added load (how stiff materials are). ❖ Modulus Young represents the elasticity of a material. ❖ The Young Modulus is defined as the ratio of stress and strain.
  • 18. Young’s Modulus ❖ Its unit is the as stress: Pa. ❖ Just like the Force-Extension graph, stress and strain are directly proportional to one another for a material exhibiting elastic behavior. ❖ A stress-strain graph is a straight line with its gradient equal to Young Modulus.
  • 19. ● Worked Example 6B ● Questions 4 and 5 Page 103-104
  • 20. The heels on a pair of women’s shoes have a radius of .5 cm at the bottom. If 30% of the weight of a woman 480N is supported by each heel, find the stress on each heel.
  • 23. A B C D
  • 24.
  • 25. Spring constant (k1 = k2 = k3) = 200 N/m extension = 1 cm what is the magnitude of the weight? Force that pulls the spring is weight. Hence Weight = F
  • 26. Spring constant (k1 = k2 = k3 = k4) = 500 N/m weight (w) = 20 Newton calculate the extension
  • 27.
  • 28. Graph of Potential Energy Area under the graph = W = Ep
  • 29. Elastic Potential Energy Elastic potential energy is energy strain in an object due to change of shape or size.