The document describes a C++ program that finds the temperature in Celsius and Fahrenheit that are equal. It initializes the Celsius temperature to 100 degrees and decrements it in a loop. The corresponding Fahrenheit temperature is calculated each iteration using the conversion formula. The loop continues until the Celsius and Fahrenheit values are the same, at which point the common temperature of -40 degrees is output.

1. C++
Write a program that finds the temperature, as an integer , that is the same in both Celsius and
Fahrenheit. The formula to convert from Celsius to Fahrenheit is: Fahrenheit = 32 + (nine fifths)
times Celsius.
Your program should create two integer variables for the temperature in Celsius and
Fahrenheit. Initialize the temperature to 100 degrees Celsius. In a loop, decrement the Celsius
value and compute the corresponding temperature in Fahrenheit until the two values are the
same.
Output should be:
The temperature is the same at -40
Solution
/* C++ Program with proper comments that finds the temperature, as an integer , that is the
same in both Celsius and Fahrenheit. */ #include using namespace std; /*When we don't use
the std namespace, the computer will try to call cout or cin as if it weren't defined in a
namespace (as most functions in our codes). Since it doesn't exist there, the computer tries to
call something that doesn't exist! Hence, an error occurs.*/ int toFahrenheit( int celsius ) {
return ( ( 9.0 / 5 ) * celsius + 32 ); //returning the value of temp converted from C to F } int
main() { int celsius; //temp variable in celsius int fahrenheit; //temp variable in Fahrenheit
celsius = 100; while ( ( fahrenheit = toFahrenheit( celsius ) ) != celsius ) { celsius--;
//keep decrementing celsius value until both values become equal } cout << "The
temperature is the same at " << celsius // print same temp value with << endl;
// required message return 0; }