PR 2
CORRELATI
ONAL
ANALYSIS
Page 02
What is Correlational
Analysis?
• this is the relationship or linkage of two
variables
• Looking at the variables if they co-occur, co-relate,
or go together therefore you will only use
statistical techniques pertaining to this if you want
to find the relationship magnitude, direction, and
significance of two variables.
What is Correlational
Analysis?
Page 03
• This correlation coefficient (r) can take a value of -1 to +1
where a value of zero shows that there is no association
between the two variables. When there is a positive
coefficient or r > than 0, this means that as one variable
increases, so does the value of the other variable. A value
of negative coefficient or r < 0 means that if a variable
increase, the value of the paired variable decreases.
However, correlation does not mean causation (Sowell,
2001; Tabachnick & Fidell, 2013) and the only way to
establish causation is through experiment and logic.
To analyze correlation the ff
statistical techniques can be use
Page 04
1. Pearson Product Moment
Correlation
• We can use Pearson Product Moment Correlation
to measure or prove an existence of relationship
between two variables.
(Pearson Product-Moment Correlation - When You
Should Run This Test, the Range of Values the
Coefficient Can Take and How to Measure Strength
of Association., n.d.)
Assumptions (requirements for
usage of technique)
Page 05
1.
Normality
• Variables should show an approximately bell
curve when plotted on a histogram, practical
implications if this assumption is violated may
lead to degraded solutions and biased results.
Assumptions (requirements for
usage of technique)
Page 06
2. Absence of Outliers
• If the data is observed, there are no very high
and very low values.
3. Level of Measurement
• Both variables should be either interval or ratio
or what we sometimes call as continuous data.
Assumptions (requirements for
usage of technique)
Page 11
3. Spearman’s Rank
Correlation
• When your data involves ranked data (1st,
2nd , 3 rd) or follows a hierarchal order (grade
1, grade 2, grade 3) or (child, teen, youth) or
simply when you know that there is an order
for the responses.
Assumptions (requirements for
usage of technique)
Page 08
1. Level of
Measurement
• Variables are ordinal (5 point scale from very low
to very high), and interval or ratio.
2. Paired Observations
• Observations should be paired, where if you get
the height of a respondent your other data
should also come from the same respondent
such as his birth order in the family
THE FORMULA
FOR PEARSON
PRODUCT
MOMENT
CORRELATION
PR 2
Formula for Pearson Product
Moment Correlation
Page 10
Page 08
• r= correlation coefficient: this tells us the strength
of relationship as well as the direction of
relationship depending on the value or polarity
(positive or negative)
Formula for Pearson Product
Moment Correlation
• x = variable x (we call them as such in replacement
of the name of the variable)
• y= variable y (we call them as such in replacement
of the name of the variable)
Page 12
• x
̅ = mean of variable x (we get it by adding all the
values in x and then divide them depending on
how many there are in the columns x)
Formula for Pearson Product
Moment Correlation
• y
̅̅ = mean of y (we get it by adding all the values in y
and then divide them depending on how many
there are in the columns y)
Page 13
Step 1: Create a table like the one shown below and
put the values on x and y columns – the context of this
example is a study between Knowledge and Attitude
towards COVID 19 where x is Knowledge and y as the
Attitude
Steps on How to Use the
Formula
Page 14
Steps on How to Use the
Formula
Page 15
Steps on How to Use the
Formula
Step 2: compute the mean for x
x
̅ = 3 + 4 + 4 + 4 +2 +3 + 3 +2 +1 +
1
10
x
̅ = 2.7
Step 3: compute the mean of y
y
̅ = 3 + 5 + 5 +5 + 3 + 4 + 4 + 3 + 2 + 2
10
y
̅ = 3.6
Page 16
Steps on How to Use the
Formula
Step 4: Fill out the
table by
subtracting the
value of x with x
̅
3 – 2.7 = 0.3
4 – 2.7 = 1.3
4 – 2.7 = 1.3 and so
on
Page 17
Steps on How to Use the
Formula
Step 5: Fill out the
table by
subtracting the
value of y by y
̅ .
3 – 3.6 = -0.6
5 - 3.6 = 1.4
5 - 3.6 = 1.4
Page 18
Steps on How to Use the
Formula
Step 6: compute
for (x-x
̅ ) x (y-y
̅ )
0.3 x -0.6 = -0.18
1.3 x 1.4 = 1.82
Step 7: compute
for sum of (x-x
̅ ) x
(y-y
̅ ) by adding all
the values in its
column
-0.18 + 1.82 + 1.82 + 1.82 + 0.42 + 0.12 +
0.12 + 0.42 + 2.72 + 2.72 = 11.8
Page 19
Steps on How to Use the
Formula
Step 7: compute
for (x -x
̅ ) 2 by
squaring all the
values in (x-x
̅ )
0.3 x 0.3 or (0.3) 2 =
0.09
1.3 x 1.3 or (1.3) 2 =
1.69
Page 20
Steps on How to Use the
Formula
Step 8: compute
for the sum of (x -
x
̅ ) 2 by adding all
the values in its
column
0.09 + 1.69 + 1.69 +
1.69 + 0.49 + 0.09 +
0.09 + 0.49 + 2.89 +
2.89 = 12.1
Page 21
Steps on How to Use the
Formula
Step 10: compute
for the sum of (y-y
̅ )
2 by adding all the
values in its
column
0.36 + 1.96 + 1.96
+1.96 + 0.36 + 0.16
+ 0.16 + 0.36 + 2.56
Page 22
Steps on How to Use the
Formula
Step 11: Substitute
all the values to
our formula
Page 23
Steps on How to Use the
Formula
Step 11: Substitute
all the values to
our formula
Page 24
Substitute all the values
in the formula
Multiply 12.1 by 12.4
Substituted:
Page 25
Substituted:
Get the square root of
150.04
r = .963 Divide 11.8 by 12.25
Page 26
Interpretation for Positive
Value Result
Page 27
Interpretation for
Negative Value Result
Page 28
Since we got .963 as the r value, we can interpret the
relationship as “very high positive correlation” and we can
also say that knowledge and attitude towards COVID 19 has
a very high positive correlation
Now we have the magnitude and direction, the next
phase is to check if the relationship is significant.
Page 29
Get the significance by solving t
- subsitute the values from the table
.963 is our r
.927 is the result
of .963 being squared
10 is the number of
our samples
Page 30
073 is the difference of
1 and .927
8 is the difference of 10
and 2
.0091 is the result of
dividing .073 by 8
09
Page 31
.0955 is the result of
getting the root
of .0091
10.08 is the result of
dividing .963 by .0955
.0954
Page 32
t Table
Page 33
Steps:
Step 1 – compute for Degree of freedom wherein we just
subtract one (1) from the total sample of 10 which is
equals to 9.
Step 2 – look for the column of your alpha value which
is .05
Step 3 – make a cross on the table and you should find
that it meets at 2.262
Page 34
We can see that the computed t of 10.09 is greater
than our critical value of 2.262. This means that our
computed t is on the rejection region wherein we
can see that there is sufficient evidence to reject the
null hypothesis.
10.09
Page 35
Format for
interpretation:
Page 36
A ___________ (Statistical technique) was run to find out the
significance, magnitude, and direction of relationship
between ________ (variable A) and ________(variable B).
Results show that _________ (Variable A) and _________
(Variable B) were found to have a ___________ (descriptive
interpretation) ________(Direction) ___________(significance), r
_______ (degree of freedom) ______(r statistic), _____
(computed T) ______ (greater or lesser than sign) ), _____
Data applied in the
format
Page 36
A Pearson product moment correlation was run to
find out the significance, magnitude, and direction
of relationship between Knowledge and Attitude
towards COVID-19. Results show that Knowledge
and Attitude were found to have a Significant Very
High Positive Correlation, r(8) = .963, t=10.09 >
2.262.
Data applied in the
format
Instruction: Analyze the data given by filling out the
table, using the formula, drawing the table, and writing
the interpretation.
Title: Alcohol Sales and Covid-19 Cases in Davao City
Page 38
Page 39
Page 40
Page 41
-36.29
-51.29
-62.29
6.71
37.71
26.71
78.71
=200
=2451.29
-50
-15
-11
-10
10
20
56
1,814.5
769.35
685.19
-67.1
371.1
534.2
4,407.76
=8,521
-1,316.96
-2,630.66
-3,880.04
45.02
1,422.04
713.42
6,195.26
=548.08
-2,500
-225
-121
-100
100
400
3,136
=690
Page 42
r=
8,521
r =
13.86
8,521
(548.08)(690)
(378,175.2)
8,521
8,521
614.96
THANK
YOU!!
PR 2.

Correlational Analysis on Quantitative Research.pptx

  • 1.
  • 2.
    Page 02 What isCorrelational Analysis? • this is the relationship or linkage of two variables • Looking at the variables if they co-occur, co-relate, or go together therefore you will only use statistical techniques pertaining to this if you want to find the relationship magnitude, direction, and significance of two variables.
  • 3.
    What is Correlational Analysis? Page03 • This correlation coefficient (r) can take a value of -1 to +1 where a value of zero shows that there is no association between the two variables. When there is a positive coefficient or r > than 0, this means that as one variable increases, so does the value of the other variable. A value of negative coefficient or r < 0 means that if a variable increase, the value of the paired variable decreases. However, correlation does not mean causation (Sowell, 2001; Tabachnick & Fidell, 2013) and the only way to establish causation is through experiment and logic.
  • 4.
    To analyze correlationthe ff statistical techniques can be use Page 04 1. Pearson Product Moment Correlation • We can use Pearson Product Moment Correlation to measure or prove an existence of relationship between two variables. (Pearson Product-Moment Correlation - When You Should Run This Test, the Range of Values the Coefficient Can Take and How to Measure Strength of Association., n.d.)
  • 5.
    Assumptions (requirements for usageof technique) Page 05 1. Normality • Variables should show an approximately bell curve when plotted on a histogram, practical implications if this assumption is violated may lead to degraded solutions and biased results.
  • 6.
    Assumptions (requirements for usageof technique) Page 06 2. Absence of Outliers • If the data is observed, there are no very high and very low values. 3. Level of Measurement • Both variables should be either interval or ratio or what we sometimes call as continuous data.
  • 7.
    Assumptions (requirements for usageof technique) Page 11 3. Spearman’s Rank Correlation • When your data involves ranked data (1st, 2nd , 3 rd) or follows a hierarchal order (grade 1, grade 2, grade 3) or (child, teen, youth) or simply when you know that there is an order for the responses.
  • 8.
    Assumptions (requirements for usageof technique) Page 08 1. Level of Measurement • Variables are ordinal (5 point scale from very low to very high), and interval or ratio. 2. Paired Observations • Observations should be paired, where if you get the height of a respondent your other data should also come from the same respondent such as his birth order in the family
  • 9.
  • 10.
    Formula for PearsonProduct Moment Correlation Page 10
  • 11.
    Page 08 • r=correlation coefficient: this tells us the strength of relationship as well as the direction of relationship depending on the value or polarity (positive or negative) Formula for Pearson Product Moment Correlation • x = variable x (we call them as such in replacement of the name of the variable) • y= variable y (we call them as such in replacement of the name of the variable)
  • 12.
    Page 12 • x ̅= mean of variable x (we get it by adding all the values in x and then divide them depending on how many there are in the columns x) Formula for Pearson Product Moment Correlation • y ̅̅ = mean of y (we get it by adding all the values in y and then divide them depending on how many there are in the columns y)
  • 13.
    Page 13 Step 1:Create a table like the one shown below and put the values on x and y columns – the context of this example is a study between Knowledge and Attitude towards COVID 19 where x is Knowledge and y as the Attitude Steps on How to Use the Formula
  • 14.
    Page 14 Steps onHow to Use the Formula
  • 15.
    Page 15 Steps onHow to Use the Formula Step 2: compute the mean for x x ̅ = 3 + 4 + 4 + 4 +2 +3 + 3 +2 +1 + 1 10 x ̅ = 2.7 Step 3: compute the mean of y y ̅ = 3 + 5 + 5 +5 + 3 + 4 + 4 + 3 + 2 + 2 10 y ̅ = 3.6
  • 16.
    Page 16 Steps onHow to Use the Formula Step 4: Fill out the table by subtracting the value of x with x ̅ 3 – 2.7 = 0.3 4 – 2.7 = 1.3 4 – 2.7 = 1.3 and so on
  • 17.
    Page 17 Steps onHow to Use the Formula Step 5: Fill out the table by subtracting the value of y by y ̅ . 3 – 3.6 = -0.6 5 - 3.6 = 1.4 5 - 3.6 = 1.4
  • 18.
    Page 18 Steps onHow to Use the Formula Step 6: compute for (x-x ̅ ) x (y-y ̅ ) 0.3 x -0.6 = -0.18 1.3 x 1.4 = 1.82 Step 7: compute for sum of (x-x ̅ ) x (y-y ̅ ) by adding all the values in its column -0.18 + 1.82 + 1.82 + 1.82 + 0.42 + 0.12 + 0.12 + 0.42 + 2.72 + 2.72 = 11.8
  • 19.
    Page 19 Steps onHow to Use the Formula Step 7: compute for (x -x ̅ ) 2 by squaring all the values in (x-x ̅ ) 0.3 x 0.3 or (0.3) 2 = 0.09 1.3 x 1.3 or (1.3) 2 = 1.69
  • 20.
    Page 20 Steps onHow to Use the Formula Step 8: compute for the sum of (x - x ̅ ) 2 by adding all the values in its column 0.09 + 1.69 + 1.69 + 1.69 + 0.49 + 0.09 + 0.09 + 0.49 + 2.89 + 2.89 = 12.1
  • 21.
    Page 21 Steps onHow to Use the Formula Step 10: compute for the sum of (y-y ̅ ) 2 by adding all the values in its column 0.36 + 1.96 + 1.96 +1.96 + 0.36 + 0.16 + 0.16 + 0.36 + 2.56
  • 22.
    Page 22 Steps onHow to Use the Formula Step 11: Substitute all the values to our formula
  • 23.
    Page 23 Steps onHow to Use the Formula Step 11: Substitute all the values to our formula
  • 24.
    Page 24 Substitute allthe values in the formula Multiply 12.1 by 12.4 Substituted:
  • 25.
    Page 25 Substituted: Get thesquare root of 150.04 r = .963 Divide 11.8 by 12.25
  • 26.
    Page 26 Interpretation forPositive Value Result
  • 27.
  • 28.
    Page 28 Since wegot .963 as the r value, we can interpret the relationship as “very high positive correlation” and we can also say that knowledge and attitude towards COVID 19 has a very high positive correlation Now we have the magnitude and direction, the next phase is to check if the relationship is significant.
  • 29.
    Page 29 Get thesignificance by solving t - subsitute the values from the table .963 is our r .927 is the result of .963 being squared 10 is the number of our samples
  • 30.
    Page 30 073 isthe difference of 1 and .927 8 is the difference of 10 and 2 .0091 is the result of dividing .073 by 8
  • 31.
    09 Page 31 .0955 isthe result of getting the root of .0091 10.08 is the result of dividing .963 by .0955 .0954
  • 32.
  • 33.
    Page 33 Steps: Step 1– compute for Degree of freedom wherein we just subtract one (1) from the total sample of 10 which is equals to 9. Step 2 – look for the column of your alpha value which is .05 Step 3 – make a cross on the table and you should find that it meets at 2.262
  • 34.
    Page 34 We cansee that the computed t of 10.09 is greater than our critical value of 2.262. This means that our computed t is on the rejection region wherein we can see that there is sufficient evidence to reject the null hypothesis.
  • 35.
  • 36.
    Page 36 A ___________(Statistical technique) was run to find out the significance, magnitude, and direction of relationship between ________ (variable A) and ________(variable B). Results show that _________ (Variable A) and _________ (Variable B) were found to have a ___________ (descriptive interpretation) ________(Direction) ___________(significance), r _______ (degree of freedom) ______(r statistic), _____ (computed T) ______ (greater or lesser than sign) ), _____ Data applied in the format
  • 37.
    Page 36 A Pearsonproduct moment correlation was run to find out the significance, magnitude, and direction of relationship between Knowledge and Attitude towards COVID-19. Results show that Knowledge and Attitude were found to have a Significant Very High Positive Correlation, r(8) = .963, t=10.09 > 2.262. Data applied in the format
  • 38.
    Instruction: Analyze thedata given by filling out the table, using the formula, drawing the table, and writing the interpretation. Title: Alcohol Sales and Covid-19 Cases in Davao City Page 38
  • 39.
  • 40.
  • 41.
  • 42.
  • 43.