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ÑOÀ HOÏA 2D ÑÖÔØNG CONG Giaûng vieân: Nguyeãn Vaên Tröôøng Hoïc vieän kyõ thuaät Quaân Söï
Ñöôøng cong ñöôïc bieåu dieãn baèng haøm soá ,[object Object],[object Object],[object Object],[object Object],[object Object],x max x min y=f(x)
Thuaät toaùn x 0 x 1 x 2 x N-1 x N x min x max
Thuaät toaùn x 0 x 1 x 2 x N-1 x N y 0 y 1 y 2 y N-1 y N x min x max
Thuaät toaùn x 0 x 1 x 2 x N-1 x N y 0 y 1 y 2 y N-1 y N x min x max
Ví duï – ñoà thò ña thöùc baäc ba ,[object Object],[object Object],[object Object]
Ví duï – ñoà thò ña thöùc baäc ba ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Ví duï – ñoà thò ña thöùc baäc ba ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Vaán ñeà phaân ñoaïn ,[object Object],ñoä phaân giaûi coät
Vaán ñeà tính ña thöùc y i  +  a  x = y 0 a x N+1  +  b = y N ... ... y i  +  a  x = y i+1 a x i+1  +  b = y i+1 y i-1  +  a  x = y i a x i  +  b = y i ... ... y 1  +  a  x = y 2 a x 2  +  b = y 2 y 0  +  a  x = y 1 a x 1  +  b = y 1 a x 0  +  b = y 0 a x 0  +  b = y 0 Tính Tính a x 0  +  b y i  +  a  x = = y 0 y i+1 a x i  +  b = y i Caùch tính caûi tieán Caùch tính thoâng thöôøng Ña thöùc baäc nhaát y =  a x +  b
Vaán ñeà tính ña thöùc a x 0 2  +  b x 0  +  c 2 a  x x 0  +  a  x 2   +  b  x y i  +   y i  y i  + 2 a  x 2 = = = = y 0  y 0 y i+1  y i+1 a x i 2  +  b x i  +  c = y i Caùch tính caûi tieán Caùch tính thoâng thöôøng Ña thöùc baäc hai y =  a x 2  +  b x +  c
Vaán ñeà tính ña thöùc Ña thöùc baäc ba y =  a x 3  +  b x 2  +  c x +  d a x 0 3  +  b x 0 2  +  c x 0  +  d 3 a  x x 0 2  + (3 a  x 2  + 2b  x ) x 0  +  a  x 3  +  b  x 2  +  c  x 6 a  x 2 x 0  + 6 a  x 3  + 2b  x 2 y i  +   y i  y i  +   y i  y i  + 6a  x 3 = = = = = = y 0  y 0  y 0 y i+1  y i+1  y i+1 Caùch tính caûi tieán
Ñöôøng cong ñöôïc bieåu dieãn baèng ptts ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Thuaät toaùn t o t 1 t 2 t N Mieàn tham soá
Thuaät toaùn t o t 1 t 2 t i t N
Thuaät toaùn (x 0 , y 0 ) (x 1 , y 1 ) (x 2 , y 2 ) (x N , y N )
Ví duï – ñöôøng cong xoaén oác
ÑÖÔØNG CONG BEZIER
Ñònh nghóa ,[object Object],[object Object],[object Object],p 0 p 1 p n
Coâng thöùc
Caùc loaïi ñöôøng cong Bezier p 0 p 1
Caùc loaïi ñöôøng cong Bezier p 0 p 2 p 1
Caùc loaïi ñöôøng cong Bezier
Ví duï veà ñöôøng cong Bezier baäc ba
Tính chaát ,[object Object],[object Object],[object Object]
Ñaïo haøm baäc 1 vaø baäc 2
Caùch veõ
Ñaùnh giaù
ÑÖÔØNG CONG HERMITE
Ñònh nghóa ,[object Object],[object Object],[object Object],[object Object],p 0 p 1
Ví duï
Tính chaát
Caùch veõ
Ñaùnh giaù
ÑÖÔØNG CONG B-SPLINE
ÑÖÔØNG CONG B-SPLINE
Ñònh nghóa ,[object Object],[object Object]
Ví duï
Tính chaát
Ñaùnh giaù

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