Here are the step-by-step workings:1) 10,324 years / 5730 years per half-life = 1.8 half-lives elapsed2) After 1 half-life, 50% of original amount remains 3) After 1.8 half-lives, the remaining amount is (50%)^1.8 = 25% of original4) Original amount was 20g5) 25% of 20g is 0.25 * 20g = 5gTherefore, the approximate amount of 14C remaining after 10,324 years is 5g
Large hadron collider by 1329040094(shivam chaudhary)
Similar to Here are the step-by-step workings:1) 10,324 years / 5730 years per half-life = 1.8 half-lives elapsed2) After 1 half-life, 50% of original amount remains 3) After 1.8 half-lives, the remaining amount is (50%)^1.8 = 25% of original4) Original amount was 20g5) 25% of 20g is 0.25 * 20g = 5gTherefore, the approximate amount of 14C remaining after 10,324 years is 5g
Similar to Here are the step-by-step workings:1) 10,324 years / 5730 years per half-life = 1.8 half-lives elapsed2) After 1 half-life, 50% of original amount remains 3) After 1.8 half-lives, the remaining amount is (50%)^1.8 = 25% of original4) Original amount was 20g5) 25% of 20g is 0.25 * 20g = 5gTherefore, the approximate amount of 14C remaining after 10,324 years is 5g (20)
Here are the step-by-step workings:1) 10,324 years / 5730 years per half-life = 1.8 half-lives elapsed2) After 1 half-life, 50% of original amount remains 3) After 1.8 half-lives, the remaining amount is (50%)^1.8 = 25% of original4) Original amount was 20g5) 25% of 20g is 0.25 * 20g = 5gTherefore, the approximate amount of 14C remaining after 10,324 years is 5g
2. The concept of forces
Newton’s laws tell us how motion is ‘created’ from forces
3. Newton’s laws: Force and acceleration
• Acceleration is when an object is changing its velocity (like a car
accelerating from rest)
• Acceleration = change in velocity/time
8. The force of gravity
• Newton discovered gravity in
1686
• What is gravity?
9. The force of gravity
• Newton discovered gravity in
1686
• What is gravity?
• On the Earth, an object falls
down with a constant
acceleration, g
• What is this acceleration?
10. Law of gravitation-person on Earth
𝐹𝑔𝑟𝑎𝑣𝑖𝑡𝑦 = 𝐺
𝑀𝑚
𝑟2
𝐹𝑔𝑟𝑎𝑣𝑖𝑡𝑦 = 𝑚𝑔
g =
𝐺𝑀
𝑟2
r
m
M
Mass of Earth, M=5.972*1024 kg
Radius of Earth, r=6378.1 km
𝐺 =
11. Which object drops faster?
If I drop a feather, and I drop a ball,
which one falls to the Earth faster?
A) According to the law of gravity
B) In practice?
https://www.youtube.com/watch?v=E43-CfukEgs
16. Static electricity and charges
• Rubbing on the plastic slide
caused electrons to be
moved from the child to the
slide.
• This leaves the child
positively charged.
• We see the evidence of static
electricity by observing his
hair standing on end.
credit: Ken Bosma/Wikimedia Commons
17. Coulombs law
• Similar charged particles repel (positive force)
• Oppositely charged particles attract (negative force)
• Can you explain why the boy’s hair stands up from this?
19. Charged particles in an atom
We just learnt from Coulombs law that like
charges repel…
So why do the positive charges stick together
Within the nucleus??
20. Strong nuclear force
• The strong nuclear force is what holds the
nucleus together
• It is an extremely short range force, that binds
protons and neutrons, acting over 10-15m, the
size of the nucleus.
• The strong nuclear force is what gives an
atomic bomb its power.
21. Weak nuclear force
• Anyone heard of spontaneous fission?
• Also known as radioactive decay…
• Exponential decay in initial mass is characteristic of radioactive
substances
22. Radiocarbon dating
• Half life: characteristic time for sample amount
of substance to decay by half its initial amount
• A certain form of Carbon (14C) has a half life of
5730 years
• The ratio of 2 forms of Carbon (12C and 14C) can
be used to tell the age of paintings!
23. Suppose an organism has 20 g of 14C at its time of death. Approximately how much 14C remains
after 10,324 years?
Given: Half life of 14C is 5730 years
Radiocarbon dating: Example Problem
24. Suppose an organism has 20 g of 14C at its time of death. Approximately how much 14C remains
after 10,324 years?
Given: Half life of 14C is 5730 years
Radiocarbon dating: Example Problem