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INTRODUCTION TO
   STATISTICS

Md. Mortuza Ahmmed
Applications of Statistics

             Agriculture
       Business and economics
         Marketing Research
             Education
              Medicine
Variable

               Qualitative
                Variable

Independen                    Dependent
  t variable                   variable



 Discrete                     Continuous
 variable                      variable

               Quantitative
                Variable
Scales of Measurement



    Nominal   Ordinal
     scale     Scale


     Ratio    Interval
     scale     scale
FREQUENCY TABLE
Rating of                                  Relative
             Tally marks      Frequency
 Drink                                    Frequency

   P              IIII           05       05 / 25 = 0.20


   G           IIII IIII II      12       12 / 25 = 0.48


   E            IIII III         08       08 / 25 = 0.32


  Total                          25                1.00
SIMPLE BAR DIAGRAM
160
        150
140

120
               100
100

 80

 60                     56

 40
                                     25
 20

  0
      Muslim    Hindu   Christians   Others
COMPONENT BAR DIAGRAM


300

250

200
                              Section D
150                           Section C
                              Section B
100                           Section A

 50

  0

      Male   Female
MULTIPLE BAR DIAGRAM

100
 90
 80
 70
 60
                              Section A
 50                           Section B
 40                           Section C
 30                           Section D

 20
 10
  0
      Male   Female
PIE CHART

    Religion of students
Muslim    Hindu     Christians   Others

               8%

         15%
                         46%


         31%
LINE GRAPH

                 Share price of BEXIMCO
7000
                                  6400
6000

                      5600
5000
          5000                                          4500
4000

3000
                                           3000
2000

1000

   0
       July      August      September   October   November
HISTOGRAM

20
18
16
14
12
10
8
6
4
2
0
BAR DIAGRAM VS. HISTOGRAM

    Histogram              Bar diagram


Area gives frequency   Height gives frequency

Bars are adjacent to   Bars are not adjacent
    each others           to each others

  Constructed for         Constructed for
 quantitative data        qualitative data
STEM AND LEAF PLOT

     Stem    Leaf
 1          1479
 2          13479
 3          1379
 4          1347
 5          1349
 6          1347
SCATTER DIAGRAM

         300

         250

         200
Supply




         150

         100

          50

           0
               0   5   10    15     20   25   30
                            Price
COMPARISON AMONG THE GRAPHS

  Graph              Advantages                Disadvantages
                   Shows percent of total      Use only discrete data
  Pie chart
                     for each category
                Can compare to normal curve Use only continuous data
 Histogram

                  Compare 2 or 3 data sets     Use only discrete data
Bar diagram
                           easily
                  Compare 2 or 3 data sets    Use only continuous data
 Line graph
                           easily
                 Shows a trend in the data    Use only continuous data
 Scatter plot
                        relationship

Stem and Leaf   Handle extremely large data    Not visually appealing

    Plot                   sets
MEASURES OF CENTRAL TENDENCY

A measure of central tendency is a single value
 that attempts to describe a set of data by
 identifying the central position within that set of
 data.


            Arithmeticmean (AM)
            Geometric mean (GM)

            Harmonic mean (HM)

                  Median

                   Mode
ARITHMETIC MEAN

It is equal to the sum of all the values in the data
   set divided by the number of values in the data
   set.
PROBLEMS
   Find       the      average        of   the   values
    5, 9, 12, 4, 5, 14, 19, 16, 3, 5, 7.

   The mean weight of three dogs is 38
    pounds.    One of the dogs weighs 46
    pounds.   The other two dogs, Eddie and
    Tommy, have the same weight. Find Tommy’s
    weight.

   On her first 5 math tests, Zany received scores
    72, 86, 92, 63, and 77. What test score she must
    earn on her sixth test so that her average for all 6
    tests will be 80?
AFFECT OF EXTREME VALUES ON AM




Staff   1   2 3 4   5   6   7   8   9 10



Salary 15 18 16 14 15 15 12 17 90 95
CALCULATION OF AM FOR GROUPED DATA


   x              f          f.x
   0             05          00
   1             10          10
   2             05          10
   3             10          30
   4             05          20
  10             02          20
 Total        N = 37         90
AM     =   90 / 37   =       2.43
MEDIAN

1   3   2
                       MEDIAN = 2

1   2   3


1   4   3      2
                     MEDIAN = (2 + 3) / 2
                                   = 2.5
1   2   3      4
MODE
WHEN TO USE THE MEAN, MEDIAN AND
             MODE

                          Best measure of central
   Type of Variable
                                tendency
       Nominal                    Mode

       Ordinal                    Median

  Interval/Ratio (not
                                   Mean
       skewed)

Interval/Ratio (skewed)           Median
WHEN WE ADD OR MULTIPLY EACH VALUE
                   BY SAME AMOUNT


                    Data              Mean Mode Median
 Original     6, 7, 8, 10, 12, 14,    12.2   14   13
 data Set       14, 15, 16, 20

 Add 3 to    9, 10, 11, 13, 15, 17,   15.2   17   16
each value      17, 18, 19, 23

Multiply 2    12, 14, 16, 20, 24,     24.4   28   26
 to each      28, 28, 30, 32, 40
  value
MEAN, MEDIAN AND MODE FOR SERIES
              DATA


     For a series 1, 2, 3 ….n,
     mean = median = mode
           = (n + 1) / 2

    So, for a series 1, 2, 3 ….100,
      mean = median = mode
         = (100 + 1) / 2 = 50.5
GEOMETRIC MEAN
HARMONIC MEAN
AM X HM = (GM) 2

For any 2 numbers a                AM X HM
       and b,
                              = (a + b) / 2 . 2ab /
AM = (a + b) / 2                            (a + b)

GM = (ab) ^ ½               = ab

                            = (GM) 2
 HM = 2 / (1 / a + 1 / b)
      = 2ab / (a + b)
EXAMPLE
  For any two numbers, AM = 10 and
    GM = 8. Find out the numbers.

(ab)^ ½ = 08                (a - b)2 = (a + b)2 – 4ab

  ab = 64                            = (20)2 – 4 .64
                                     = 144
(a + b) / 2 = 10
  a + b = 20 . . . . .(1)     => a - b = 12 . . . .(2)

        Solving (1) and (2) (a, b) = (16, 4)
EXAMPLE

For any two numbers, GM = 4√3 and HM = 6. Find
           out AM and the numbers.
    AM           √ab = 4√3     (a - b)2
= (GM)2/   HM         =>ab = 48       = (a + b)2 – 4ab
= (4√3) 2 / 6                         = (16)2 – 4 . 48
=8               (a + b) / 2 = 8
                                      = 64

                 => a + b = 16 …(1)     a - b = 8 ...(2)

           Solving (1) & (2) (a, b) = (12, 4)
CRITERIA FOR GOOD MEASURES OF CENTRAL TENDENCY

                  Clearly defined

             Readily comprehensible

           Based on all observations

                 Easily calculated

          Less affected by extreme values

            Capable of further algebraic
                    treatment
AM ≥ GM ≥ HM
For any two numbers a & b   (√a - √b) 2 ≥ 0

AM = (a + b) / 2              a + b – 2(ab)^1/2 ≥ 0

GM = (ab)^1/2                 a+b     ≥ 2(ab)^1/2
HM = 2 / (1 / a + 1 / b)      (a + b) / 2 ≥ (ab)^1/2

     = 2ab / (a + b)        => AM   ≥ GM

   Multiplying both sides by 2(ab)^1/2 / (a + b)
                (ab)^1/2 ≥ 2ab / (a + b)
                       GM ≥ HM

             So, AM ≥ GM ≥ HM

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Introduction to Statistics Measurements

  • 1. INTRODUCTION TO STATISTICS Md. Mortuza Ahmmed
  • 2. Applications of Statistics Agriculture Business and economics Marketing Research Education Medicine
  • 3. Variable Qualitative Variable Independen Dependent t variable variable Discrete Continuous variable variable Quantitative Variable
  • 4. Scales of Measurement Nominal Ordinal scale Scale Ratio Interval scale scale
  • 5. FREQUENCY TABLE Rating of Relative Tally marks Frequency Drink Frequency P IIII 05 05 / 25 = 0.20 G IIII IIII II 12 12 / 25 = 0.48 E IIII III 08 08 / 25 = 0.32 Total 25 1.00
  • 6. SIMPLE BAR DIAGRAM 160 150 140 120 100 100 80 60 56 40 25 20 0 Muslim Hindu Christians Others
  • 7. COMPONENT BAR DIAGRAM 300 250 200 Section D 150 Section C Section B 100 Section A 50 0 Male Female
  • 8. MULTIPLE BAR DIAGRAM 100 90 80 70 60 Section A 50 Section B 40 Section C 30 Section D 20 10 0 Male Female
  • 9. PIE CHART Religion of students Muslim Hindu Christians Others 8% 15% 46% 31%
  • 10. LINE GRAPH Share price of BEXIMCO 7000 6400 6000 5600 5000 5000 4500 4000 3000 3000 2000 1000 0 July August September October November
  • 12. BAR DIAGRAM VS. HISTOGRAM Histogram Bar diagram Area gives frequency Height gives frequency Bars are adjacent to Bars are not adjacent each others to each others Constructed for Constructed for quantitative data qualitative data
  • 13. STEM AND LEAF PLOT Stem Leaf 1 1479 2 13479 3 1379 4 1347 5 1349 6 1347
  • 14. SCATTER DIAGRAM 300 250 200 Supply 150 100 50 0 0 5 10 15 20 25 30 Price
  • 15. COMPARISON AMONG THE GRAPHS Graph Advantages Disadvantages Shows percent of total Use only discrete data Pie chart for each category Can compare to normal curve Use only continuous data Histogram Compare 2 or 3 data sets Use only discrete data Bar diagram easily Compare 2 or 3 data sets Use only continuous data Line graph easily Shows a trend in the data Use only continuous data Scatter plot relationship Stem and Leaf Handle extremely large data Not visually appealing Plot sets
  • 16. MEASURES OF CENTRAL TENDENCY A measure of central tendency is a single value that attempts to describe a set of data by identifying the central position within that set of data.  Arithmeticmean (AM)  Geometric mean (GM)  Harmonic mean (HM)  Median  Mode
  • 17. ARITHMETIC MEAN It is equal to the sum of all the values in the data set divided by the number of values in the data set.
  • 18. PROBLEMS  Find the average of the values 5, 9, 12, 4, 5, 14, 19, 16, 3, 5, 7.  The mean weight of three dogs is 38 pounds. One of the dogs weighs 46 pounds. The other two dogs, Eddie and Tommy, have the same weight. Find Tommy’s weight.  On her first 5 math tests, Zany received scores 72, 86, 92, 63, and 77. What test score she must earn on her sixth test so that her average for all 6 tests will be 80?
  • 19. AFFECT OF EXTREME VALUES ON AM Staff 1 2 3 4 5 6 7 8 9 10 Salary 15 18 16 14 15 15 12 17 90 95
  • 20. CALCULATION OF AM FOR GROUPED DATA x f f.x 0 05 00 1 10 10 2 05 10 3 10 30 4 05 20 10 02 20 Total N = 37 90 AM = 90 / 37 = 2.43
  • 21. MEDIAN 1 3 2 MEDIAN = 2 1 2 3 1 4 3 2 MEDIAN = (2 + 3) / 2 = 2.5 1 2 3 4
  • 22. MODE
  • 23. WHEN TO USE THE MEAN, MEDIAN AND MODE Best measure of central Type of Variable tendency Nominal Mode Ordinal Median Interval/Ratio (not Mean skewed) Interval/Ratio (skewed) Median
  • 24. WHEN WE ADD OR MULTIPLY EACH VALUE BY SAME AMOUNT Data Mean Mode Median Original 6, 7, 8, 10, 12, 14, 12.2 14 13 data Set 14, 15, 16, 20 Add 3 to 9, 10, 11, 13, 15, 17, 15.2 17 16 each value 17, 18, 19, 23 Multiply 2 12, 14, 16, 20, 24, 24.4 28 26 to each 28, 28, 30, 32, 40 value
  • 25. MEAN, MEDIAN AND MODE FOR SERIES DATA For a series 1, 2, 3 ….n, mean = median = mode = (n + 1) / 2 So, for a series 1, 2, 3 ….100, mean = median = mode = (100 + 1) / 2 = 50.5
  • 28. AM X HM = (GM) 2 For any 2 numbers a AM X HM and b, = (a + b) / 2 . 2ab / AM = (a + b) / 2 (a + b) GM = (ab) ^ ½ = ab = (GM) 2 HM = 2 / (1 / a + 1 / b) = 2ab / (a + b)
  • 29. EXAMPLE For any two numbers, AM = 10 and GM = 8. Find out the numbers. (ab)^ ½ = 08 (a - b)2 = (a + b)2 – 4ab ab = 64 = (20)2 – 4 .64 = 144 (a + b) / 2 = 10 a + b = 20 . . . . .(1) => a - b = 12 . . . .(2) Solving (1) and (2) (a, b) = (16, 4)
  • 30. EXAMPLE For any two numbers, GM = 4√3 and HM = 6. Find out AM and the numbers. AM √ab = 4√3 (a - b)2 = (GM)2/ HM =>ab = 48 = (a + b)2 – 4ab = (4√3) 2 / 6 = (16)2 – 4 . 48 =8 (a + b) / 2 = 8 = 64 => a + b = 16 …(1) a - b = 8 ...(2) Solving (1) & (2) (a, b) = (12, 4)
  • 31. CRITERIA FOR GOOD MEASURES OF CENTRAL TENDENCY Clearly defined Readily comprehensible Based on all observations Easily calculated Less affected by extreme values Capable of further algebraic treatment
  • 32. AM ≥ GM ≥ HM For any two numbers a & b (√a - √b) 2 ≥ 0 AM = (a + b) / 2 a + b – 2(ab)^1/2 ≥ 0 GM = (ab)^1/2 a+b ≥ 2(ab)^1/2 HM = 2 / (1 / a + 1 / b) (a + b) / 2 ≥ (ab)^1/2 = 2ab / (a + b) => AM ≥ GM Multiplying both sides by 2(ab)^1/2 / (a + b) (ab)^1/2 ≥ 2ab / (a + b) GM ≥ HM So, AM ≥ GM ≥ HM