AnswerThe trophic interaction between microbes and plants is impo.pdf
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Answer: The trophic interaction between microbes and plants is important. Plant growth-promoting rhizobacteria (PGPR) are group of micro-organism that increasingly appreciated for their contribution to primary productivity through promotion of growth and triggering induced system registance. By triggering plant defense, PGPR can make an important contribution to biocontrol of pests and pathogens. The interactions increasing order of complexity, starting with single micro-organism to other organisms that are present in the soil such as nematodes, fungi, earthworm or protozoa and other soil dwelling organisms in the rhizosphere. In the rhizospheres, bacteria can have direct beneficial or harmful effect on plant. However there are also important indirect feedback interaction between plant roots and soil bacteria and other micro-organisms. For example root-released exudates promote bacterial growth. In turn plant growth stimulated by bacterivores (those eat bacteria) who liberate nutrients. Plant roots, bacteria and other microbes interact in complex food web to form a multi-trophic complex interaction between plants and bacteria. In maintaining sustainable agriculture, the enhancement of environmental quality and natural resources occurs. Sustainable agriculture focus on prucing livelyhood communities. Successful sustainable production in healthy soil is an ecologically sound practice that have little or no adverse effect on natural ecosystem. To reverse the damage of natural communities, renewable natural resourses are protected and recycled. Solution Answer: The trophic interaction between microbes and plants is important. Plant growth-promoting rhizobacteria (PGPR) are group of micro-organism that increasingly appreciated for their contribution to primary productivity through promotion of growth and triggering induced system registance. By triggering plant defense, PGPR can make an important contribution to biocontrol of pests and pathogens. The interactions increasing order of complexity, starting with single micro-organism to other organisms that are present in the soil such as nematodes, fungi, earthworm or protozoa and other soil dwelling organisms in the rhizosphere. In the rhizospheres, bacteria can have direct beneficial or harmful effect on plant. However there are also important indirect feedback interaction between plant roots and soil bacteria and other micro-organisms. For example root-released exudates promote bacterial growth. In turn plant growth stimulated by bacterivores (those eat bacteria) who liberate nutrients. Plant roots, bacteria and other microbes interact in complex food web to form a multi-trophic complex interaction between plants and bacteria. In maintaining sustainable agriculture, the enhancement of environmental quality and natural resources occurs. Sustainable agriculture focus on prucing livelyhood communities. Successful sustainable production in healthy soil is an ecologically sound practice that have littl.
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First lets draw out the Lewis structure such that each atom has.pdf
First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2
electrons (H)
The only way to do this is:
H-C=N:
There is a C-N triple bond and a lone pair on the N.
Now, the steric number is defined as the number of bonds to another atom + the number of lone
pairs on the atom.
For H: 1 bond = steric number of 1.
For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4)
For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4)
Solution
First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2
electrons (H)
The only way to do this is:
H-C=N:
There is a C-N triple bond and a lone pair on the N.
Now, the steric number is defined as the number of bonds to another atom + the number of lone
pairs on the atom.
For H: 1 bond = steric number of 1.
For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4)
For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4).
Interest.javaimport java.util.Scanner; public class Interest.pdf
// Interest.java
import java.util.Scanner;
public class Interest
{
//calculation method
public static double outputAmount(double amount)
{
double interest = amount * 0.5;
amount = amount + interest;
return amount;
}
// method to take input
public static double inputAmount()
{
Scanner sc = new Scanner(System.in);
System.out.print(\"Enter the invested amount: \");
double amount = sc.nextDouble();
return amount;
}
//main method
public static void main(String[] args)
{
double amount = inputAmount();
System.out.println(\"5% interest earned on $\" + amount + \" after one year is $\" +
outputAmount(amount));
}
}
/*
output:
Enter the invested amount: 2000
5% interest earned on $2000.0 after one year is $3000.0
*/
Solution
// Interest.java
import java.util.Scanner;
public class Interest
{
//calculation method
public static double outputAmount(double amount)
{
double interest = amount * 0.5;
amount = amount + interest;
return amount;
}
// method to take input
public static double inputAmount()
{
Scanner sc = new Scanner(System.in);
System.out.print(\"Enter the invested amount: \");
double amount = sc.nextDouble();
return amount;
}
//main method
public static void main(String[] args)
{
double amount = inputAmount();
System.out.println(\"5% interest earned on $\" + amount + \" after one year is $\" +
outputAmount(amount));
}
}
/*
output:
Enter the invested amount: 2000
5% interest earned on $2000.0 after one year is $3000.0
*/.
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GES Issue Brief - Synthetic Microorganisms for Agricultural Use
AUTHORED BY: JOHANNA ELSENSOHN AND KELLY SEARS
By 2050, the world’s population is estimated to exceed 9 billion people. A challenge to this rising food demand is that crops will have to be grown on the same or less land as today. Additionally, global climate change is causing considerable uncertainty in the ability of the current food production system to adapt to an unknown future.
To address these issues sustainably, scientists from many disciplines have been investigating ways to increase crop yields and prepare for a changing climate. Considerable effort has focused on enhancing the traits of the crop plants themselves, to enhance their growth, make them resistant to disease, or tolerant to environmental stressors like drought or high salinity conditions. Conversely, a growing area of research is looking at how microorganisms, such as bacteria and fungi, influence these plant characteristics.
The relationship between plants and microorganisms is well known. However, researchers are still working to understand the full complexity and extent of interactions between the two groups. We have seen that microbes are important for plant nutrient acquisition, plant growth and protection against disease. Certain types of bacteria are commercially available and used to increase yields and decrease fertilizer use (Farrar et al. 2014).
root microbial interaction for crop improvement seminar ppt
This document discusses root-microbial interactions and how they impact crop improvement. It covers how plant root exudates can influence both positive and negative interactions with other plants and microbes. On the plant-plant side, exudates can facilitate resource competition, allelopathy, or parasitic relationships. Positively, they may induce defenses in neighboring plants. With microbes, exudates enable symbiotic relationships like nitrogen fixation and mycorrhizal associations, but can also have antimicrobial effects against pathogens. A better understanding of these below-ground processes could help develop strategies to enhance soil health and crop yields.
ROLE OF BIOLOGICAL METHODS IN INTEGRATED DISEASE MANAGEMENT
The document discusses the role of biological methods in integrated disease management. It describes how biological control plays an important role in IDM by reducing pathogen inoculum through the use of biocontrol agents (BCAs) like Trichoderma, Pseudomonas, and Bacillus. The mechanisms of BCAs include hyperparasitism, competition, antibiosis, and inducing systemic resistance in plants. Biological methods like suppressive soils containing antagonistic microbes and use of trap crops can also help control soilborne and airborne pathogens.
Biosafety issues in biotechnology
This ppt have a detailed source about the Biosafety issues in Biotechnology and their implements over by the government. It have a topics about the issues in antibiotic resistance gene , GMO crops etc.
8 Soil organisms and plant-microbes interaction rev.1.ppt
This document discusses various types of interactions between soil organisms and microorganisms, including mutualistic, commensal, competitive, and antagonistic relationships. It provides examples of each type of interaction. Mutualistic relationships include symbiotic relationships between mycorrhizal fungi and plant roots that enhance nutrient uptake. Commensal relationships involve one organism benefiting without affecting the other, such as fungi breaking down cellulose that bacteria then use. Competitive relationships occur when organisms require the same limited resources. Antagonistic relationships harm one or both organisms and include the production of antibiotics. Overall, the complex web of interactions between soil microbes and plants influences nutrient cycling and soil health.
How soil microbes help plants resist disease - Indogulf
soil microbes lend the entire plant a special kind of disease protection. When soil microbes are present, plants undergo what is called “induced systemic resistance,” an immunity boost that protects the plant from a broad range of pathogens. For more details visit https://www.indogulfbioag.com/soil-fertilizers
Trangenic vegetables for 21st century horticulture
This document summarizes research on transgenic vegetables for horticulture. It discusses how transgenic crops can be used to enhance pest resistance, quality traits, and sustainability in vegetable production. Specifically, it reviews advances in transgenic tomato, potato, eggplant, squash and sweet corn. Transgenic tomatoes have been developed to delay fruit ripening. Transgenic potatoes with resistance to the Colorado potato beetle and viruses were commercialized in the 1990s but later removed from the market due to trade and consumer issues. The document argues that transgenic crops have potential to address challenges in vegetable production, but their development and commercialization faces high costs and regulatory hurdles.
ideal characters of antagonist.pptx
The document discusses biological control of plant diseases. It describes ideal characteristics of biocontrol agents including being non-pathogenic and having a broad spectrum of activity. Common biocontrol agents used are fungi, bacteria, and actinomycetes from the genera Trichoderma, Gliocladium, Pseudomonas, and Bacillus. Mechanisms of biocontrol include direct mechanisms like hyperparasitism and antibiosis, as well as indirect mechanisms like competition and inducing systemic resistance in plants.
Plant Growth Promoting microbes.pptx
This document discusses plant growth-promoting microbes (PGPM) which are soil microorganisms that can positively influence plant growth. PGPM are divided into two main groups - plant growth-promoting rhizobacteria (PGPR) and plant growth-promoting fungi (PGPF). PGPR and PGPF help plants grow through mechanisms like nitrogen fixation, phosphate solubilization, siderophore production, phytohormone synthesis, and protecting plants from pathogens. They play important roles in agricultural sustainability by improving soil fertility, supplying nutrients, suppressing diseases, and assisting in environmental remediation.
Similar to AnswerThe trophic interaction between microbes and plants is impo.pdf (20)
14 bacterial inoculant.pdf for development of biofertilizer
14 bacterial inoculant.pdf for development of biofertilizer
Balancing Ecosystems And Crops Exploring The Role Of Microbial Inoculants In ...
Balancing Ecosystems And Crops Exploring The Role Of Microbial Inoculants In ...
Sustainable Management of Soil-borne Plant Diseases
Sustainable Management of Soil-borne Plant Diseases
PGPR in plant disease management and plant health .pptx
PGPR in plant disease management and plant health .pptx
GES Issue Brief - Synthetic Microorganisms for Agricultural Use
GES Issue Brief - Synthetic Microorganisms for Agricultural Use
root microbial interaction for crop improvement seminar ppt
root microbial interaction for crop improvement seminar ppt
ROLE OF BIOLOGICAL METHODS IN INTEGRATED DISEASE MANAGEMENT
ROLE OF BIOLOGICAL METHODS IN INTEGRATED DISEASE MANAGEMENT
8 Soil organisms and plant-microbes interaction rev.1.ppt
8 Soil organisms and plant-microbes interaction rev.1.ppt
How soil microbes help plants resist disease - Indogulf
How soil microbes help plants resist disease - Indogulf
Trangenic vegetables for 21st century horticulture
Trangenic vegetables for 21st century horticulture
More from aradhana9856
First lets draw out the Lewis structure such that each atom has.pdf
First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2
electrons (H)
The only way to do this is:
H-C=N:
There is a C-N triple bond and a lone pair on the N.
Now, the steric number is defined as the number of bonds to another atom + the number of lone
pairs on the atom.
For H: 1 bond = steric number of 1.
For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4)
For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4)
Solution
First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2
electrons (H)
The only way to do this is:
H-C=N:
There is a C-N triple bond and a lone pair on the N.
Now, the steric number is defined as the number of bonds to another atom + the number of lone
pairs on the atom.
For H: 1 bond = steric number of 1.
For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4)
For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4).
Interest.javaimport java.util.Scanner; public class Interest.pdf
// Interest.java
import java.util.Scanner;
public class Interest
{
//calculation method
public static double outputAmount(double amount)
{
double interest = amount * 0.5;
amount = amount + interest;
return amount;
}
// method to take input
public static double inputAmount()
{
Scanner sc = new Scanner(System.in);
System.out.print(\"Enter the invested amount: \");
double amount = sc.nextDouble();
return amount;
}
//main method
public static void main(String[] args)
{
double amount = inputAmount();
System.out.println(\"5% interest earned on $\" + amount + \" after one year is $\" +
outputAmount(amount));
}
}
/*
output:
Enter the invested amount: 2000
5% interest earned on $2000.0 after one year is $3000.0
*/
Solution
// Interest.java
import java.util.Scanner;
public class Interest
{
//calculation method
public static double outputAmount(double amount)
{
double interest = amount * 0.5;
amount = amount + interest;
return amount;
}
// method to take input
public static double inputAmount()
{
Scanner sc = new Scanner(System.in);
System.out.print(\"Enter the invested amount: \");
double amount = sc.nextDouble();
return amount;
}
//main method
public static void main(String[] args)
{
double amount = inputAmount();
System.out.println(\"5% interest earned on $\" + amount + \" after one year is $\" +
outputAmount(amount));
}
}
/*
output:
Enter the invested amount: 2000
5% interest earned on $2000.0 after one year is $3000.0
*/.
13. The answer is C. 34Let D be the dominant allele and d be the.pdf
13. The answer is: C. 3/4
Let D be the dominant allele and d be the recessive allele.
Since father and mother are both heterozygous: Dd x DdDdDDD (affected)Dd (affected)dDd
(affected)dd (unaffected)
Solution
13. The answer is: C. 3/4
Let D be the dominant allele and d be the recessive allele.
Since father and mother are both heterozygous: Dd x DdDdDDD (affected)Dd (affected)dDd
(affected)dd (unaffected).
1) The Arrhenius Theory of acids and bases Acids are substances wh.pdf
1) The Arrhenius Theory of acids and bases: Acids are substances which produce hydrogen
ions in solution. Bases are substances which produce hydroxide ions in solution. Neutralisation
happens because hydrogen ions and hydroxide ions react to produce water. HCl(acid) + NaOH
(base) = H2O + NaCl 2) The Bronsted-Lowry Theory of acids and bases An acid is a proton
(hydrogen ion) donor. A base is a proton (hydrogen ion) acceptor. H2O (base) + HCl(acid) =
H3O^+ + Cl^- 3) The Lewis Theory of acids and bases: An acid is an electron pair acceptor. A
base is an electron pair donor. BH3(acid) + NH3(base) = H3B:NH3 (where NH3 donotes one
pair of electrons to the empty orbital of BH3 to form H3BNH3 complex.)
Solution
1) The Arrhenius Theory of acids and bases: Acids are substances which produce hydrogen
ions in solution. Bases are substances which produce hydroxide ions in solution. Neutralisation
happens because hydrogen ions and hydroxide ions react to produce water. HCl(acid) + NaOH
(base) = H2O + NaCl 2) The Bronsted-Lowry Theory of acids and bases An acid is a proton
(hydrogen ion) donor. A base is a proton (hydrogen ion) acceptor. H2O (base) + HCl(acid) =
H3O^+ + Cl^- 3) The Lewis Theory of acids and bases: An acid is an electron pair acceptor. A
base is an electron pair donor. BH3(acid) + NH3(base) = H3B:NH3 (where NH3 donotes one
pair of electrons to the empty orbital of BH3 to form H3BNH3 complex.).
1. Coenzyme A - C. A water soluble acyl group carrier.2. Thiamine .pdf
1. Coenzyme A - C. A water soluble acyl group carrier.
2. Thiamine pyrophosphate -B. A coenzyme frequently used in decarboxylation reactions.
3. Lipoate - A. The disulfide bond at its end enables it to participate in redox reactions as well as
carry acyl groups.
4. Folic acid - D. A one-carbon group donor. Essential to rapidly growing tissues. Recommended
for women during pregnancy.
Solution
1. Coenzyme A - C. A water soluble acyl group carrier.
2. Thiamine pyrophosphate -B. A coenzyme frequently used in decarboxylation reactions.
3. Lipoate - A. The disulfide bond at its end enables it to participate in redox reactions as well as
carry acyl groups.
4. Folic acid - D. A one-carbon group donor. Essential to rapidly growing tissues. Recommended
for women during pregnancy..
Using Clausius-Clapeyron relation Ln(P2P1) = (D.pdf
Using Clausius-Clapeyron relation: Ln(P2/P1) = (DH/R)*(1/T1-1/T2) where DH
reads Delta H, and is the Hvap you are looking for when P1641,P2=1atm, T1=81.2C, and
T2=99C.
Solution
Using Clausius-Clapeyron relation: Ln(P2/P1) = (DH/R)*(1/T1-1/T2) where DH
reads Delta H, and is the Hvap you are looking for when P1641,P2=1atm, T1=81.2C, and
T2=99C..
purines are double ringed nitrogenous bases of DN.pdf
purines are double ringed nitrogenous bases of DNA and RNA including adenine
and guanine. the three others are cytosine and thymine( uracil is present instead of thymine in
RNA) are pyrimidines. So your answer should be (B) Improve Answer
Solution
purines are double ringed nitrogenous bases of DNA and RNA including adenine
and guanine. the three others are cytosine and thymine( uracil is present instead of thymine in
RNA) are pyrimidines. So your answer should be (B) Improve Answer.
(i) Deques cannot be implemented using arrays. false Justif.pdf
(i) Deques cannot be implemented using arrays. : false
Justification:
We can implement dequeue using circular array. We need to maintain two pointers rear and
front.
Ex :
1. Create an array of any element type like int [] dequeue.
2. Create two indexes front and rear and initialize them to 0.
3. Create an element capacity.(it should be length of an array - 1).
(ii) If we require all add/remove operations to run in O(1) time, we cannot use a Deque
implemented with a singly linked list. False
Justification :
In linklist there will be two pointers head and tail.
Adding an element :
tail -> next = newelement;
newelement -> next = NULL;
tail = newelement;
These all are O(1) operation.
Removing an element :
head = head->next; O(1) operation
(iii) A Deque can be used as a stack as well as a queue. : true
Justification :
Using as stack : You can use dequeue as stack by removing and inserting the element at
one end.
Using as queue : You can use dequeue as queue by inserting the element at front and
removing at rear.
(iv) Assume the Deque contains n elements and n is odd. The middle element is the e lement
equidistant from either end. The middle element cannot be determined in O(1) time in any
implementation : false
Justification :
You can achieve this in O(1) operation with the help of doubly link list. You will have to
maintain a mid pointer to achieve this. You can move this pointer in either direction with previos
and next pointers.
Solution
(i) Deques cannot be implemented using arrays. : false
Justification:
We can implement dequeue using circular array. We need to maintain two pointers rear and
front.
Ex :
1. Create an array of any element type like int [] dequeue.
2. Create two indexes front and rear and initialize them to 0.
3. Create an element capacity.(it should be length of an array - 1).
(ii) If we require all add/remove operations to run in O(1) time, we cannot use a Deque
implemented with a singly linked list. False
Justification :
In linklist there will be two pointers head and tail.
Adding an element :
tail -> next = newelement;
newelement -> next = NULL;
tail = newelement;
These all are O(1) operation.
Removing an element :
head = head->next; O(1) operation
(iii) A Deque can be used as a stack as well as a queue. : true
Justification :
Using as stack : You can use dequeue as stack by removing and inserting the element at
one end.
Using as queue : You can use dequeue as queue by inserting the element at front and
removing at rear.
(iv) Assume the Deque contains n elements and n is odd. The middle element is the e lement
equidistant from either end. The middle element cannot be determined in O(1) time in any
implementation : false
Justification :
You can achieve this in O(1) operation with the help of doubly link list. You will have to
maintain a mid pointer to achieve this. You can move this pointer in either direction with previos
and next pointers..
no reaction note 1-butanol is a primary alcohol.pdf
no reaction note: 1-butanol is a primary alcohol that cannot react with Lucas
reagent. both tertiary, secondary alcohols can react with this reagent.
Solution
no reaction note: 1-butanol is a primary alcohol that cannot react with Lucas
reagent. both tertiary, secondary alcohols can react with this reagent..
What type of variable is number of people in the roomNominal.pdf
What type of variable is number of people in the room?
Nominal
Ratio
Interval
Ordinal
What type of variable is number of people in the room?
Nominal
Ratio
Interval
Ordinal
Nominal
Ratio
Interval
Ordinal
Nominal
Ratio
Interval
Ordinal
Solution
Ratio. Although the number of people in a room is integral, there is a well-defined 0 and the
difference between numbers of people in a room is meaningful..
What is the oxidation number for oxygen in H2O2; for OF2 Explain..pdf
What is the oxidation number for oxygen in H2O2; for OF2 ? Explain.
Solution
In H2O2
The oxidation number of Oxygen is -1. The oxidation number of Oxygen in compounds is
usually -2, but it is -1 in peroxides.
Another Way
The oxidation number of H is +1. For two H atoms, the sum is +2.
Since H2O2 is a neutral compound (no charge), (The sum of the oxidation numbers of all the
atoms in a neutral compound is 0.)
The total oxidation number of the two O atoms must be -2.
Hence the oxidation number of one oxygen atom must be -1.
For OF2
The electronegativity of F is 4.0 and of O 3.5, so Oxygen is surely (+) in this compound.
Oxidation number of F2 is -1
Let oxidation number of O be n
n+ 2*(-1) = 0
n= 2
oxidation number of Oxyfen is 2..
We all know humans are good at removing the competition and it is di.pdf
We all know humans are good at removing the competition and it is difficult for any other
species to dominate or even evolve to super intelligent like us. With large brains evolved and we
had taught ourselves how to control other animals as they tends to have not so evolved brains
like humans. There can be seen in zoo, circus dancing on the tunes of human’s orders.
Since humans are self-centred, each and everything is designed or developed is based on the
same feeling human is only species which is important, others are just to serve for its pleasure,
food, and etc. we believe we can do anything we want with animals and their habitats.
Due to industrialization and continue growth of big cities, there is war like condition between
animals and cities. And history has teaches us in number of times, the strong one who has more
number wins the war. Same is the case we can see in NYC, we humans has tendency to get
threaten by whole species even an individual attacks one single person, which itself is rare case.
In this regard there tends to forget these lands was initially dominated by animals, later humans
have conquered and started ruling it.
Solution
We all know humans are good at removing the competition and it is difficult for any other
species to dominate or even evolve to super intelligent like us. With large brains evolved and we
had taught ourselves how to control other animals as they tends to have not so evolved brains
like humans. There can be seen in zoo, circus dancing on the tunes of human’s orders.
Since humans are self-centred, each and everything is designed or developed is based on the
same feeling human is only species which is important, others are just to serve for its pleasure,
food, and etc. we believe we can do anything we want with animals and their habitats.
Due to industrialization and continue growth of big cities, there is war like condition between
animals and cities. And history has teaches us in number of times, the strong one who has more
number wins the war. Same is the case we can see in NYC, we humans has tendency to get
threaten by whole species even an individual attacks one single person, which itself is rare case.
In this regard there tends to forget these lands was initially dominated by animals, later humans
have conquered and started ruling it..
Theories devised by keynes and Minsky are similar in concept since M.pdf
Theories devised by keynes and Minsky are similar in concept since Minsky himself was a post-
Keynesian. He supported quite much of Keynes\' theories and rather contributed to the
economics of financial markets by providing theories on why such markets fail and how they
recover. So they are a more advanced extension of Keynes\' theory to explain the behaviour of
financial markets and how they influence the overall economy.
For understanding the similarities between the two theories, we need to look at some of their
main points in brief, without going into detail and then compare them on where they stood
unique shared the same concept. Since nearly very business cycle theory explains through some
common points, their mode can be different, for Keynes\' theory explained business cycle on a
macro economic scale while Minsky\'s was more market related. Some of the main key points
for Keynes\' and Minsky\'s theories are listed down below.
Keynes\' theory of business cycles
Minsky, as I already told, was a Keynesian himself and all his theories have been always been an
extension of Keynesian concepts to explain the economics of today. His most valuable thesis on
the workings of financial markets why they fail becasue of fluctuations is a Kynesian modifed
concept.
Minsky proposed his theory in pure financial terminology. His point was that during propserity
when cash flows are maximum to pay off the debts, the resulting euphoria that develops into
society results in a debt crises that the borrowers are unable to pay. This leads to banks
restructing money supply which in the end contracts the whole economy.
Solution
Theories devised by keynes and Minsky are similar in concept since Minsky himself was a post-
Keynesian. He supported quite much of Keynes\' theories and rather contributed to the
economics of financial markets by providing theories on why such markets fail and how they
recover. So they are a more advanced extension of Keynes\' theory to explain the behaviour of
financial markets and how they influence the overall economy.
For understanding the similarities between the two theories, we need to look at some of their
main points in brief, without going into detail and then compare them on where they stood
unique shared the same concept. Since nearly very business cycle theory explains through some
common points, their mode can be different, for Keynes\' theory explained business cycle on a
macro economic scale while Minsky\'s was more market related. Some of the main key points
for Keynes\' and Minsky\'s theories are listed down below.
Keynes\' theory of business cycles
Minsky, as I already told, was a Keynesian himself and all his theories have been always been an
extension of Keynesian concepts to explain the economics of today. His most valuable thesis on
the workings of financial markets why they fail becasue of fluctuations is a Kynesian modifed
concept.
Minsky proposed his theory in pure financial terminology. His point was that durin.
They might have consumed cyanide.The pit of Apricot contains cyani.pdf
They might have consumed cyanide.
The pit of Apricot contains cyanide.
Cyanide acts by inhibiting the enzyme cytochrome c oxidase of the electron transport chain
which prevents the cell from producing ATP which is important for aerobic respiration of cells.
Hydroxocobalamin, Sodium thiosulfate, Sodium nitrite are the common antedotes used in
cyanide poisoning
Solution
They might have consumed cyanide.
The pit of Apricot contains cyanide.
Cyanide acts by inhibiting the enzyme cytochrome c oxidase of the electron transport chain
which prevents the cell from producing ATP which is important for aerobic respiration of cells.
Hydroxocobalamin, Sodium thiosulfate, Sodium nitrite are the common antedotes used in
cyanide poisoning.
The attacking of the nucleophile formed in the reactionof acetone an.pdf
The attacking of the nucleophile formed in the reactionof acetone and benzaldehyde on most
preferntially on the carbonylcarbon of the benzaldehyde but not on the acetaldehyde. This
isbecause the electrophilic cheractor of the carbonyl carbon of thebenzaldehyde is increases due
to the presence of the electron withdrawing benzene. Hence it readily participate in the
reactioncompare with the acetaldehyde.
Ethanol is polar solvent. When washes a compound withthis solvent remove the impurities has
the polar nature.
Solution
The attacking of the nucleophile formed in the reactionof acetone and benzaldehyde on most
preferntially on the carbonylcarbon of the benzaldehyde but not on the acetaldehyde. This
isbecause the electrophilic cheractor of the carbonyl carbon of thebenzaldehyde is increases due
to the presence of the electron withdrawing benzene. Hence it readily participate in the
reactioncompare with the acetaldehyde.
Ethanol is polar solvent. When washes a compound withthis solvent remove the impurities has
the polar nature..
Terry And Hill can develop a method of profit sharing on below facto.pdf
Terry And Hill can develop a method of profit sharing on below factors
Unequal capital contribution
Compensate by paying interest on capital - Compensate for the uneven contributions towards
capital by paying interest on their capital contributions. Greater the Capital contributed, greater
the interest earned. This would set right the difference in contributions in the form of capital.
Profit equal to the total \"Interest on Capital\" on all the capital of the firm is set aside and is
distributed to the partners in the ratio of their capitals.Rest of the profits can be shared equally if
all other contributions are equal.
Unequal time and efforts -
Compensate by paying Salary to Partner. - Compensate for the uneven contributions of time and
efforts towards the firm by paying salary to partner. The salary paid to Hill would be
compensation for his greater contribution. Profit equal to the total \"Salary to Partners\" to all the
partners who have made a contribution in this respect is set aside and is distributed to them in
proportion to the value of their contributions as agreed upon between partners. Rest of the profits
can be shared equally if all other contributions are equal.
and if terry and hill are not interested in compensating by above methods then profit sharing by
effort in running the partnership is more preferable as its helping in generating income of
partnership.
Solution
Terry And Hill can develop a method of profit sharing on below factors
Unequal capital contribution
Compensate by paying interest on capital - Compensate for the uneven contributions towards
capital by paying interest on their capital contributions. Greater the Capital contributed, greater
the interest earned. This would set right the difference in contributions in the form of capital.
Profit equal to the total \"Interest on Capital\" on all the capital of the firm is set aside and is
distributed to the partners in the ratio of their capitals.Rest of the profits can be shared equally if
all other contributions are equal.
Unequal time and efforts -
Compensate by paying Salary to Partner. - Compensate for the uneven contributions of time and
efforts towards the firm by paying salary to partner. The salary paid to Hill would be
compensation for his greater contribution. Profit equal to the total \"Salary to Partners\" to all the
partners who have made a contribution in this respect is set aside and is distributed to them in
proportion to the value of their contributions as agreed upon between partners. Rest of the profits
can be shared equally if all other contributions are equal.
and if terry and hill are not interested in compensating by above methods then profit sharing by
effort in running the partnership is more preferable as its helping in generating income of
partnership..
The algorithm to reverse a linked list by rearranging the required p.pdf
The algorithm to reverse a linked list by rearranging the required pointers is given as follows:
The pseudo-code to show the working of the algorithm is given as follows:
//Define the function to reverse a list.
node* reverseList(node* head)
{
//Declare and initialize the required pointer variables.
node* prev_node;
node* cur_node;
node* next_node;
prev_node = NULL;
next_node = NULL;
cur_node = head;
//Traverse the whole list using while loop.
while(cur_node != NULL)
{
//Rearrange the pointers to reverse the list.
next_node = cur_node->next;
cur_node->next = prev_node;
prev_node = cur_node;
cur_node = next_node;
}
//Make the recent previous node as head of the list.
head = prev_node;
//Return the head of the list.
return head;
}
Solution
The algorithm to reverse a linked list by rearranging the required pointers is given as follows:
The pseudo-code to show the working of the algorithm is given as follows:
//Define the function to reverse a list.
node* reverseList(node* head)
{
//Declare and initialize the required pointer variables.
node* prev_node;
node* cur_node;
node* next_node;
prev_node = NULL;
next_node = NULL;
cur_node = head;
//Traverse the whole list using while loop.
while(cur_node != NULL)
{
//Rearrange the pointers to reverse the list.
next_node = cur_node->next;
cur_node->next = prev_node;
prev_node = cur_node;
cur_node = next_node;
}
//Make the recent previous node as head of the list.
head = prev_node;
//Return the head of the list.
return head;
}.
Splicing mechanismSmall nuclear ribonucleic acid (snRNA) It is al.pdf
Small nuclear RNAs (snRNAs), including U1snRNA and U4snRNA, play important roles in splicing. U1snRNA mediates splicing by binding to 5' splice sites and removing introns, while U4snRNA forms a complex with U1snRNA, U2snRNA, and U5snRNA called the spliceosome to remove introns from pre-mRNA. U4snRNA also has a specific role in the 3' end of hnRNA. Ribozymes such as peptidyl transferase rRNA also mediate RNA splicing through their enzymatic activity.
since both are strong acids we can add up their individual contribut.pdf
since both are strong acids we can add up their individual contributions towards H+
concentration
[H+]=(4.4+5.3)*10-2=(9.7)*10-2
pH=2-log(9.7)=1.013
Solution
since both are strong acids we can add up their individual contributions towards H+
concentration
[H+]=(4.4+5.3)*10-2=(9.7)*10-2
pH=2-log(9.7)=1.013.
public int getPosition(T anObject) { int result = null; result .pdf
public int getPosition(T anObject)
{ int result = null; // result to return
int lastIndex = length - 1;
for(int index=0; index < lastIndex;index++){
if(anObject.equals(list[index]))
{
result = index;
}
}
return result;
} // end getPosition
Solution
public int getPosition(T anObject)
{ int result = null; // result to return
int lastIndex = length - 1;
for(int index=0; index < lastIndex;index++){
if(anObject.equals(list[index]))
{
result = index;
}
}
return result;
} // end getPosition.
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