addition of dissimilar fraction

Least Learned Skill:
Add dissimilar fractions.
Sub-task:
Find the LCD
Change dissimilar fraction to similar
fraction

Just
remember!
GUIDECARD
 Similar Fractions are fraction whose
denominators are the same
𝟒
𝟓
,
𝟑
𝟓
 Dissimilar Fractions are fraction whose
denominator is different
𝟒
𝟓
,
𝟏
𝟒
 LCD – Least Common Denominator

Just
remember!
GUIDECARD
 Find the least common denominator
 Rename each dissimilar fraction to its
equivalent fraction using the LCD
 Add the numerator and write over the
denominator
 Simplify the resulting fraction if possible

To find the least common denominator (LCD) of two or
more denominators, we mean to find the LCM of the
denominators.
𝟒
𝟓
,
𝟏
𝟒
5 = 5, 10, 15, 20, 25, 30 5 = 1 x 5
4 = 4, 8, 12, 16, 20, 24 4 = 1 x 4
LCD = 20 LCD = 5 X 4 = 20
Just
remember!
GUIDECARD

GUIDECARD
Just
remember!
Rename each dissimilar fraction to
its equivalent fraction using the
LCD
𝟒
𝟓
=
𝟏𝟔
𝟐𝟎
𝟏
𝟒
=
𝟓
𝟐𝟎÷=5
x
÷=4
x
 Divide the LCD by the
denominator
 Multiply the quotient by
numerator

𝟒
𝟓
𝟏
𝟒
𝟒
𝟓
𝟏
𝟒
GUIDECARD
What’s
next?

ACTIVITYCARD
Find the LCM of the given number
1. 3 =
4 =
5 =
LCM =
2. 7 =
6 =
LCM =
3. 2 =
4 =
6 =
LCM =

ACTIVITYCARD
Find the LCM of the given number
1. 3 = 3,6,9,12,15,18,21,24
6 = 6,12,18,24
9 = 9,18,27
LCM = 18
2. 7 = 7,14,21,28, 35,42
5 = 5,10,15,20,25,30,35
LCM = 35
3. 2 = 2
4 = 2 x 2
6 = 2 x 3
LCM = 2 x 2 x 3 = 12

ACTIVITYCARD
Rename dissimilar fraction to similar fraction
𝟐
𝟓
=
𝟒
𝟕
=
𝟏
𝟑
=
𝟓
𝟔
=
𝟏
𝟐
=
𝟑
𝟔
=
𝟑
𝟒
=

ACTIVITYCARD
Rename dissimilar fraction to similar fraction
𝟐
𝟓
=
𝟏𝟒
𝟑𝟓
𝟒
𝟕
=
𝟐𝟎
𝟑𝟓
𝟏
𝟑
=
𝟑
𝟗
𝟓
𝟗
=
𝟓
𝟗
𝟏
𝟐
=
𝟔
𝟏𝟐
𝟑
𝟔
=
𝟔
𝟏𝟐
𝟑
𝟒
=
𝟗
𝟏𝟐

ACTIVITYCARD
Use unit region to change to similar fractions.
𝟓
𝟖
=
𝟓
𝟔
=
𝟏
𝟐
=
𝟓
𝟖
=
𝟓
𝟔
=
𝟏
𝟐
=

ASSESSMENTCARD
Add the
numerator and
write over the
denominator
Don’t forget
to remember.
To add
dissimilar
fraction….
Rename each
dissimilar
fraction to its
equivalent
fraction using
the LCD
Find the least
common
denominator

ASSESSMENTCARD
𝟐
𝟓
+
𝟒
𝟕
=
LCD = 35
𝟐
𝟓
=
𝟏𝟒
𝟑𝟓
𝟒
𝟕
=
𝟐𝟎
𝟑𝟓
𝟏𝟒
𝟑𝟓
+
𝟐𝟎
𝟑𝟓
=
𝟏𝟒+𝟐𝟎
𝟑𝟓
=
𝟑𝟒
𝟑𝟓

ASSESSMENTCARD
𝟏
𝟑
+
𝟒
𝟖
=
𝟑
𝟓
+
𝟏
𝟐
+
𝟑
𝟒
=

ASSESSMENTCARD
1
3
+
4
8
=
8
24
+
12
24
=
8+12
24
=
20
24
or
5
6
3
5
+
1
2
+
3
4
=
12
20
+
10
20
+
15
20
=
12+10+15
20
=
37
20
or 1
17
20

ASSESSMENTCARD
𝟐
𝟑
+
𝟒
𝟓
= +

ASSESSMENTCARD
𝟐
𝟑
+
𝟏
𝟓
= +
+

ENRICHMENTCARD
𝑻𝒐 solve
worded
problem use
the Polya’s
Technique
UNDERSTAND
PLAN
SOLVE FOR THE ANSWER
LOOK BACK
𝒀𝒐𝒖 𝒄𝒂𝒏 𝒂𝒍𝒔𝒐
𝒖𝒔𝒆 𝒕𝒉𝒆
𝑩𝒍𝒐𝒄𝒌 𝑴𝒐𝒅𝒆𝒍
𝑨𝒑𝒑𝒓𝒐𝒂𝒄𝒉

ENRICHMENTCARD
UNDERSTAND
PLAN
LOOK BACK
Solve the problem using Polya’s Technique.
Ivy solved
𝟏
𝟑
her math homework on Saturday and
𝟏
𝟐
of it on Sunday. What Fraction of her homework did she
solve during those two days?

ENRICHMENTCARD
UNDERSTAND
𝟏
𝟑
of her homework solved on Saturday,
𝟏
𝟐
of her homework solved on
Sunday,Fraction of her homework solved in two days is unknown
PLAN add
𝟏
𝟑
and
𝟏
𝟐
𝟏
𝟑
+
𝟏
𝟐
=
𝟐
𝟔
+
𝟑
𝟔
=
𝟐+ 𝟑
𝟔
=
𝟓
𝟔
(fraction of her homework she solve for
two days)
LOOK BACK
Fraction Ivy solved for Saturday + Fraction Ivy solved for Sunday
𝟏
𝟑
+
𝟏
𝟐
=
𝟓
𝟔
(fraction of her homework she solve for two days)
Solve the problem using Polya’s Technique.
Ivy solved
𝟏
𝟑
𝟏
𝟐

ENRICHMENTCARD
Solve the problem using Block Model Approach.
Ivy solved
𝟏
𝟑
𝟏
𝟐
𝟏
𝟑
+
𝟏
𝟐
= +
Ivy solved for Saturday
Ivy solved for Sunday

ENRICHMENTCARD
Solve the problem using Block Model Approach.
Ivy solved
𝟏
𝟑
𝟏
𝟐
𝟏
𝟑
+
𝟏
𝟐
= +
+
𝟓
𝟔
(fraction of her homework she
solve for two days)

REFERENCECARD
BEC PELC MATHEMATICS 6
SOARIMG 21ST CENTURY
MATHEMATICS 6

addition of dissimilar fraction

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