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ASSIGNMENT
• Dale walks 500m heading North and then 200m back. Compute for his total
distance and displacement covered.
• distance = 700m
• displacement = 300 m North
• Joy runs 100m in 10 seconds while Trish runs 150m in 10 seconds. Who runs
faster?
• Joy: s = d/t = 100m / 10s = 10 m/s;
• Trish: s = d/t = 150m / 10s = 15 m/s
*Trish runs faster than Joy since she covered greater distance given the same
length of time.
DISTANCE
•One day, you went to the park with your dog. There are lots
of things that you can see in the park. There’s a seesaw,
swing, bench and flowering plant. At the right is a sketch of
the park:
•You first went to the bench, then walked 2 meters North to
reach the seesaw. After that, you again walked 5 meters to
the East to play in the swing. Then you saw a beautiful
flowering plant, so you walked 2 meters South to the
flowering plant. You got tired and walked 5 meters to the
West so that you can sit in the bench.
•Q1. What is the distance (how far was the path
traveled) covered during your entire walk?
distance = 2m + 5m + 2m + 5m = 14m
•Q2. What is the displacement (change in
position) during your entire walk?
displacement = 0m returns to the point of
origin
•While having some rest, you saw your dog ran from the
bench, to the seesaw, then to the swing, to the flowering
plant and back to the bench. You noticed that your dog
spent 5 minutes to do it
•Q3. How fast is your dog?
speed = distance/time = 14m/5min = 2.8m/min
•Q4. Can you tell its velocity?
•velocity = displacement/time = 0
•Velocity is defined as the change in position divided
by the time of travel. So, Velocity is displacement
over time. Since displacement is already zero,
velocity is also 0.
•A man drove his car from
point A to C. He took route
ABC and completed his
journey in 10 hrs. Use the
given diagram to describe the
motion of the car in terms of
the following: a. distance b.
displacement c. speed d.
velocity
• a. distance = 400km + 300km = 700km
• b. displacement = 500km
• c. speed = d/t = 700km / 10 hrs = 70km/hr
• d. velocity = 500km /10hrs = 50 km/hr
Northeast
ACCELERATION
• Describe the motion of an object in terms of acceleration; and
• Calculate the acceleration of a moving object.
ACCELERATION
• Acceleration is a vector quantity that is defined
as the rate at which an object changes its
velocity.
ACCELERATION
An object is accelerating if it is changing its velocity. Since
velocity is a speed and a direction, there are only two ways
for an object to accelerate: change the speed or change
direction – or change b
If an object is speeding up, then it is accelerating and has a
positive acceleration. If it is slowing down, it is also
accelerating (or decelerating) and has a negative
acceleration. A negative acceleration is referred as
deceleration.
ACCELERATION
An object moving at a constant speed but rounding a curve
or corner is accelerating, too. Although its speed remains
the same, its direction changes when it rounds a curve or
corner. Hence, the velocity of the object changes.
ACCELERATION
ACCELERATION
ACCELERATION
ACCELERATION
ACTIVITY 1
1. A car starts from rest and attains a speed of 40 km/h in
20 seconds. What is its acceleration in km/h/s?
2. A cyclist going up the Kawakawa Hill at a speed of 5 m/s
slows down to 1 m/s in 8 seconds. Find his acceleration.
ACCELERATION
ACTIVITY 1
1. A car starts from rest and attains a speed of 40 km/h in
20 seconds. What is its acceleration in km/h/s?
1.Vi = 0 a = Vf – Vi
Vf = 40 km/h t
t = 20 s = 40 km/h – 0
a = ? 20s
a = 2 km/h/s
ACCELERATION
ACTIVITY 1
2. A cyclist going up the Kawakawa Hill at a speed of 5 m/s
slows down to 1 m/s in 8 seconds. Find his acceleration.
2.Vi = 5 m/s a = Vf – Vi
Vf = 1 m/s t
t = 8 s = 1 m/s – 5 m/s
a = ? 8 s
a = - 0.5 m/s2
ASSIGNMENT
1. Which will have a higher speed after a minute of travel
starting from rest – a car accelerating at 2 m/s2 or a bus
accelerating at 5 m/s2?
2. Give concrete examples of accelerating objects that can
be seen in the following places:
a. on the road b. at an amusement park
ASSIGNMENT

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ACCELERATAION.pptx

  • 2. • Dale walks 500m heading North and then 200m back. Compute for his total distance and displacement covered. • distance = 700m • displacement = 300 m North • Joy runs 100m in 10 seconds while Trish runs 150m in 10 seconds. Who runs faster? • Joy: s = d/t = 100m / 10s = 10 m/s; • Trish: s = d/t = 150m / 10s = 15 m/s *Trish runs faster than Joy since she covered greater distance given the same length of time.
  • 4. •One day, you went to the park with your dog. There are lots of things that you can see in the park. There’s a seesaw, swing, bench and flowering plant. At the right is a sketch of the park: •You first went to the bench, then walked 2 meters North to reach the seesaw. After that, you again walked 5 meters to the East to play in the swing. Then you saw a beautiful flowering plant, so you walked 2 meters South to the flowering plant. You got tired and walked 5 meters to the West so that you can sit in the bench.
  • 5. •Q1. What is the distance (how far was the path traveled) covered during your entire walk? distance = 2m + 5m + 2m + 5m = 14m
  • 6. •Q2. What is the displacement (change in position) during your entire walk? displacement = 0m returns to the point of origin
  • 7. •While having some rest, you saw your dog ran from the bench, to the seesaw, then to the swing, to the flowering plant and back to the bench. You noticed that your dog spent 5 minutes to do it •Q3. How fast is your dog? speed = distance/time = 14m/5min = 2.8m/min
  • 8. •Q4. Can you tell its velocity? •velocity = displacement/time = 0 •Velocity is defined as the change in position divided by the time of travel. So, Velocity is displacement over time. Since displacement is already zero, velocity is also 0.
  • 9. •A man drove his car from point A to C. He took route ABC and completed his journey in 10 hrs. Use the given diagram to describe the motion of the car in terms of the following: a. distance b. displacement c. speed d. velocity
  • 10. • a. distance = 400km + 300km = 700km • b. displacement = 500km • c. speed = d/t = 700km / 10 hrs = 70km/hr • d. velocity = 500km /10hrs = 50 km/hr Northeast
  • 11. ACCELERATION • Describe the motion of an object in terms of acceleration; and • Calculate the acceleration of a moving object.
  • 12. ACCELERATION • Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity.
  • 13.
  • 14.
  • 15.
  • 16. ACCELERATION An object is accelerating if it is changing its velocity. Since velocity is a speed and a direction, there are only two ways for an object to accelerate: change the speed or change direction – or change b If an object is speeding up, then it is accelerating and has a positive acceleration. If it is slowing down, it is also accelerating (or decelerating) and has a negative acceleration. A negative acceleration is referred as deceleration.
  • 17. ACCELERATION An object moving at a constant speed but rounding a curve or corner is accelerating, too. Although its speed remains the same, its direction changes when it rounds a curve or corner. Hence, the velocity of the object changes.
  • 21. ACCELERATION ACTIVITY 1 1. A car starts from rest and attains a speed of 40 km/h in 20 seconds. What is its acceleration in km/h/s? 2. A cyclist going up the Kawakawa Hill at a speed of 5 m/s slows down to 1 m/s in 8 seconds. Find his acceleration.
  • 22. ACCELERATION ACTIVITY 1 1. A car starts from rest and attains a speed of 40 km/h in 20 seconds. What is its acceleration in km/h/s? 1.Vi = 0 a = Vf – Vi Vf = 40 km/h t t = 20 s = 40 km/h – 0 a = ? 20s a = 2 km/h/s
  • 23. ACCELERATION ACTIVITY 1 2. A cyclist going up the Kawakawa Hill at a speed of 5 m/s slows down to 1 m/s in 8 seconds. Find his acceleration. 2.Vi = 5 m/s a = Vf – Vi Vf = 1 m/s t t = 8 s = 1 m/s – 5 m/s a = ? 8 s a = - 0.5 m/s2
  • 24. ASSIGNMENT 1. Which will have a higher speed after a minute of travel starting from rest – a car accelerating at 2 m/s2 or a bus accelerating at 5 m/s2? 2. Give concrete examples of accelerating objects that can be seen in the following places: a. on the road b. at an amusement park