Geometric
Geometric
Sequences
Sequences
What is a Geometric Sequence?
What is a Geometric Sequence?
 In a geometric sequence, the ratio
In a geometric sequence, the ratio
between consecutive terms is
between consecutive terms is
constant. This ratio is called the
constant. This ratio is called the
common ratio
common ratio.
.
 Unlike in an arithmetic sequence, the
Unlike in an arithmetic sequence, the
difference between consecutive
difference between consecutive
terms varies.
terms varies.
 We look for
We look for multiplication
multiplication to
to
identify geometric sequences.
identify geometric sequences.
A sequence is geometric if the ratios of
consecutive terms are the same.
Geometric Sequence
Geometric Sequence
3
2 4
1 2 3
.....
a
a a
r
a a a
   
The number r is the common
ratio
ratio.
Ex: Determine if the sequence is geometric.
Ex: Determine if the sequence is geometric.
If so, identify the common ratio
If so, identify the common ratio
 1, -6, 36, -216
1, -6, 36, -216
yes. Common ratio=-6
yes. Common ratio=-6
 2, 4, 6, 8
2, 4, 6, 8
no. No common ratio
no. No common ratio
 3, 15, 75, 375
3, 15, 75, 375
yes. Common ratio=
yes. Common ratio=
Important Formulas for
Important Formulas for
Geometric Sequence:
Geometric Sequence:
 Recursive Formula
Recursive Formula  Explicit Formula
Explicit Formula
an = (an – 1 ) r an = a1 * r n-1
Where:
an is the nth term in the
sequence
a1 is the first term
n is the number of the term
r is the common ratio
Ex: Write the recursive formula for
Ex: Write the recursive formula for
each sequence
each sequence
First term: a
First term: a1
1 = 7
= 7
Common ratio = 1/3
Common ratio = 1/3
Recursive: an = an-1 * r
Now find the first five
terms:
a1 = 7
a2 = 7(1/3) = 7/3
a3 = 7/3(1/3) = 7/9
a4 = 7/9(1/3) = 7/27
a5 = 7/27(1/3) = 7/81
an = an-1 * (1/3)
Ex: Write the explicit formula for
Ex: Write the explicit formula for
each sequence
each sequence
First term: a
First term: a1
1 = 7
= 7
Common ratio = 1/3
Common ratio = 1/3
Explicit: an = a1 * r n-1
Now find the first five
terms:
a1 = 7(1/3) (1-1)
= 7
a2 = 7(1/3) (2-1)
= 7/3
a3 = 7(1/3) (3-1)
= 7/9
a4 = 7(1/3) (4-1)
= 7/27
a5 = 7(1/3) (5-1)
= 7/81
Recursive Geometic Sequence Problem
Recursive Geometic Sequence Problem
Find the 5
Find the 5th
th
and 6
and 6th
th
term in the
term in the
sequence of 11,33,99,297 . . .
sequence of 11,33,99,297 . . .
a6 = 891(3) = 2673
Common ratio = 3
a5 = 297 (3) = 891
Start with the recursive sequence
formula
Find the common ratio
between the values.
Plug in known values
Simplify
an = an-1 * r
Explicit Geometic Sequence Problem
Explicit Geometic Sequence Problem
Find the 19
Find the 19th
th
term in the sequence of
term in the sequence of
11,33,99,297 . . .
11,33,99,297 . . .
a19 = 11(3)18
=4,261,626,379
Common ratio = 3
a19 = 11 (3) (19-1)
Start with the explicit sequence formula
Find the common ratio
between the values.
Plug in known values
Simplify
an = a1 * r n-1
Let’s try one
Let’s try one
Find the 10
Find the 10th
th
term in the sequence of
term in the sequence of
1, -6, 36, -216 . . .
1, -6, 36, -216 . . .
a10 = 1(-6)9
= -10,077,696
Common ratio = -6
a10 = 1 (-6) (10-1)
Start with the explicit sequence formula
Find the common ratio
between the values.
Plug in known values
Simplify
an = a1 * r n-1
Example
Example
 Find the 7
Find the 7th
th
term of a geometric
term of a geometric
progression with a 1
progression with a 1st
st
term of 3 and
term of 3 and
a common ratio of 1/2?
a common ratio of 1/2?
an = a1 * r n-1
a7 = 3 * 1/2 7-1
a7 = 3 * 1/2 6
a7 = 3 * 1/64
a7 = 3/64
Ex.
Ex.
Write the first five terms of the
geometric sequence whose first
term is a1 = 9 and r = (1/3).
9 3 1
1
3
1
9
, , , ,
Ex.
Ex.
Find the 15
Find the 15th
th
term of the geometric
term of the geometric
sequence whose first term is 20 and
sequence whose first term is 20 and
whose common ratio is 1.05
whose common ratio is 1.05
an = a1rn – 1
a15 = (20)(1.05)15 – 1
a15 = 39.599
Ex. 4
Ex. 4
Find a formula for the nth term.
What is the 9th term?
5, 15, 45, …
an = 5(3)n – 1
an = 5(3)n – 1
a9 = 5(3)8
a9 = 32805
an = a1rn – 1
Example
Example
 Find the 6
Find the 6th
th
term of a geometric
term of a geometric
progression with a 1
progression with a 1st
st
term of 2 and
term of 2 and
a common ratio of 1/3?
a common ratio of 1/3?
an = a1 * r n-1
a6 = 2 * 1/3 6-1
a6 = 2 * 1/3 5
a6 = 2 * 1/243
a6 = 2/243
Ex. 5
Ex. 5
The fourth term of a geometric sequence is
The fourth term of a geometric sequence is
125, and the 10
125, and the 10th
th
term is 125/64. Find the
term is 125/64. Find the
14
14th
th
term. (Assume all terms are positive)
term. (Assume all terms are positive)
a4 = 125
a10 =
125
64
125
64
125 6
 r
a10 = a4r6
1
64
6
r
1
2
r
a14 = a10r4
125
1024
a14 =
4
14
2
1
64
125







a

A geometric progression, also known as a geometric sequence, is a mathematical sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed number called the common ratio

  • 1.
  • 2.
    What is aGeometric Sequence? What is a Geometric Sequence?  In a geometric sequence, the ratio In a geometric sequence, the ratio between consecutive terms is between consecutive terms is constant. This ratio is called the constant. This ratio is called the common ratio common ratio. .  Unlike in an arithmetic sequence, the Unlike in an arithmetic sequence, the difference between consecutive difference between consecutive terms varies. terms varies.  We look for We look for multiplication multiplication to to identify geometric sequences. identify geometric sequences.
  • 3.
    A sequence isgeometric if the ratios of consecutive terms are the same. Geometric Sequence Geometric Sequence 3 2 4 1 2 3 ..... a a a r a a a     The number r is the common ratio ratio.
  • 4.
    Ex: Determine ifthe sequence is geometric. Ex: Determine if the sequence is geometric. If so, identify the common ratio If so, identify the common ratio  1, -6, 36, -216 1, -6, 36, -216 yes. Common ratio=-6 yes. Common ratio=-6  2, 4, 6, 8 2, 4, 6, 8 no. No common ratio no. No common ratio  3, 15, 75, 375 3, 15, 75, 375 yes. Common ratio= yes. Common ratio=
  • 5.
    Important Formulas for ImportantFormulas for Geometric Sequence: Geometric Sequence:  Recursive Formula Recursive Formula  Explicit Formula Explicit Formula an = (an – 1 ) r an = a1 * r n-1 Where: an is the nth term in the sequence a1 is the first term n is the number of the term r is the common ratio
  • 6.
    Ex: Write therecursive formula for Ex: Write the recursive formula for each sequence each sequence First term: a First term: a1 1 = 7 = 7 Common ratio = 1/3 Common ratio = 1/3 Recursive: an = an-1 * r Now find the first five terms: a1 = 7 a2 = 7(1/3) = 7/3 a3 = 7/3(1/3) = 7/9 a4 = 7/9(1/3) = 7/27 a5 = 7/27(1/3) = 7/81 an = an-1 * (1/3)
  • 7.
    Ex: Write theexplicit formula for Ex: Write the explicit formula for each sequence each sequence First term: a First term: a1 1 = 7 = 7 Common ratio = 1/3 Common ratio = 1/3 Explicit: an = a1 * r n-1 Now find the first five terms: a1 = 7(1/3) (1-1) = 7 a2 = 7(1/3) (2-1) = 7/3 a3 = 7(1/3) (3-1) = 7/9 a4 = 7(1/3) (4-1) = 7/27 a5 = 7(1/3) (5-1) = 7/81
  • 8.
    Recursive Geometic SequenceProblem Recursive Geometic Sequence Problem Find the 5 Find the 5th th and 6 and 6th th term in the term in the sequence of 11,33,99,297 . . . sequence of 11,33,99,297 . . . a6 = 891(3) = 2673 Common ratio = 3 a5 = 297 (3) = 891 Start with the recursive sequence formula Find the common ratio between the values. Plug in known values Simplify an = an-1 * r
  • 9.
    Explicit Geometic SequenceProblem Explicit Geometic Sequence Problem Find the 19 Find the 19th th term in the sequence of term in the sequence of 11,33,99,297 . . . 11,33,99,297 . . . a19 = 11(3)18 =4,261,626,379 Common ratio = 3 a19 = 11 (3) (19-1) Start with the explicit sequence formula Find the common ratio between the values. Plug in known values Simplify an = a1 * r n-1
  • 10.
    Let’s try one Let’stry one Find the 10 Find the 10th th term in the sequence of term in the sequence of 1, -6, 36, -216 . . . 1, -6, 36, -216 . . . a10 = 1(-6)9 = -10,077,696 Common ratio = -6 a10 = 1 (-6) (10-1) Start with the explicit sequence formula Find the common ratio between the values. Plug in known values Simplify an = a1 * r n-1
  • 11.
    Example Example  Find the7 Find the 7th th term of a geometric term of a geometric progression with a 1 progression with a 1st st term of 3 and term of 3 and a common ratio of 1/2? a common ratio of 1/2? an = a1 * r n-1 a7 = 3 * 1/2 7-1 a7 = 3 * 1/2 6 a7 = 3 * 1/64 a7 = 3/64
  • 12.
    Ex. Ex. Write the firstfive terms of the geometric sequence whose first term is a1 = 9 and r = (1/3). 9 3 1 1 3 1 9 , , , ,
  • 13.
    Ex. Ex. Find the 15 Findthe 15th th term of the geometric term of the geometric sequence whose first term is 20 and sequence whose first term is 20 and whose common ratio is 1.05 whose common ratio is 1.05 an = a1rn – 1 a15 = (20)(1.05)15 – 1 a15 = 39.599
  • 14.
    Ex. 4 Ex. 4 Finda formula for the nth term. What is the 9th term? 5, 15, 45, … an = 5(3)n – 1 an = 5(3)n – 1 a9 = 5(3)8 a9 = 32805 an = a1rn – 1
  • 15.
    Example Example  Find the6 Find the 6th th term of a geometric term of a geometric progression with a 1 progression with a 1st st term of 2 and term of 2 and a common ratio of 1/3? a common ratio of 1/3? an = a1 * r n-1 a6 = 2 * 1/3 6-1 a6 = 2 * 1/3 5 a6 = 2 * 1/243 a6 = 2/243
  • 16.
    Ex. 5 Ex. 5 Thefourth term of a geometric sequence is The fourth term of a geometric sequence is 125, and the 10 125, and the 10th th term is 125/64. Find the term is 125/64. Find the 14 14th th term. (Assume all terms are positive) term. (Assume all terms are positive) a4 = 125 a10 = 125 64 125 64 125 6  r a10 = a4r6 1 64 6 r 1 2 r a14 = a10r4 125 1024 a14 = 4 14 2 1 64 125        a