The circuit contains a 100 ohm resistor and a capacitor with a reactance of 46.43 ohms. The current is calculated to be 120 mA. The total impedance is 110.25 ohms and the applied voltage is calculated to be 13.22 volts. The phase angle between the current and voltage is 24.8 degrees.

1. Find:
(a) the current in the circuit
(b) the total capacitive reactance
(c) the impedance of the circuit
(d) the applied voltage
(e) the phase angle between the current and
the applied voltage

3. I = 12 = (120 x 10¯³) = 120 mA
100
Answer I = 120 mA

6. C
Z = √l00² + 46.43² = √12l55.75
Answer Z = 110.25 Ω

7. VC = I XC
VC = (120 x 10¯³) x 46.43
VC = 5.57 V
So,

8. V = √(12² + 5.57²) = √(144 + 31.02) = √175.02

9. ∅ = cos¯¹
12 = 24.8⁰
13.22
Answer ∅ = 24.8°