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• If two ratios are equal, their
    “cross-products” are also equal.

• This concept helps you solve for an
  unknown value.
EXAMPLE 1         Use the cross products property

Solve the proportion 8 = 6
                     x 15
  8 = 6                                 Write original proportion.
  x     15
8 15 = x 6                              Cross products property

  120 = 6x                              Simplify.

   20 = x                               Divide each side by 6.

  ANSWER
 The solution is 20. Check by substituting 20 for x in the original
 proportion.
EXAMPLE 1      Use the cross products property


 CHECK
    8 ? 6
      =                            Substitute 20 for x.
   20 15
      ?
 8 15 = 20 6                       Cross products property

  120 = 120                        Simplify. Solution checks.
• Solve:

           4k   8
           10   20
EXAMPLE 3     Write and solve a proportion

 Seals
 Each day, the seals at an aquarium are each fed 8
 pounds of food for every 100 pounds of their body
 weight. A seal at the aquarium weighs 280 pounds.
 How much food should the seal be fed per day ?
 SOLUTION

 STEP 1
 Write a proportion involving two ratios that compare
 the amount of food with the weight of the seal.

             8     x          amount of food
                =
            100   280         weight of seal
EXAMPLE 3        Write and solve a proportion

 STEP 2
 Solve the proportion.
   8     x
      =                          Write proportion.
  100   280
 8 280 = 100 x                   Cross products property

  2240 = 100x                    Simplify.

  22.4 = x                       Divide each side by 100.

 ANSWER

 A 280 pound seal should be fed 22.4 pounds of food per
 day.
EXAMPLE 2         Standardized Test Practice

 What is the value of x in the proportion 4 = 8 ?
                                          x  x– 3
  A –6                 B   –3          C      3            D   6
 SOLUTION
   4    8
     =                            Write original proportion.
   x   x –3
 4(x – 3) = x 8                   Cross products property

 4x – 12 = 8x                     Simplify.

     – 12 = 4x                    Subtract 4x from each side.

     –3=x                         Divide each side by 4.
EXAMPLE 2
GUIDED PRACTICE         for Examples 1,2, and 3



    3    2
      =
    x   x –6                   Write original proportion.

 3(x – 6) = 2 x                Cross products property


 3x – 18 = 2x                  Distrubutive property


     18 = x                    Subtract 3x from each side.

  ANSWER
 The value of x is 18. Check by substituting 18 for x in the
 original proportion.
EXAMPLE 2
GUIDED PRACTICE    for Examples 1,2, and 3




    m   m–6
      =                   Write original proportion.
    5    4
  m 4 = 5(m – 6)          Cross products property


   4m = 5m – 30           Simplify


    m = 30                Subtract 5m from each side.
• Assignment: P. 171   (#6-10, 19-22)

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3.5 & 3.6 writing and solving ratios and proportions day 2

  • 1. • If two ratios are equal, their “cross-products” are also equal. • This concept helps you solve for an unknown value.
  • 2. EXAMPLE 1 Use the cross products property Solve the proportion 8 = 6 x 15 8 = 6 Write original proportion. x 15 8 15 = x 6 Cross products property 120 = 6x Simplify. 20 = x Divide each side by 6. ANSWER The solution is 20. Check by substituting 20 for x in the original proportion.
  • 3. EXAMPLE 1 Use the cross products property CHECK 8 ? 6 = Substitute 20 for x. 20 15 ? 8 15 = 20 6 Cross products property 120 = 120 Simplify. Solution checks.
  • 4. • Solve: 4k 8 10 20
  • 5. EXAMPLE 3 Write and solve a proportion Seals Each day, the seals at an aquarium are each fed 8 pounds of food for every 100 pounds of their body weight. A seal at the aquarium weighs 280 pounds. How much food should the seal be fed per day ? SOLUTION STEP 1 Write a proportion involving two ratios that compare the amount of food with the weight of the seal. 8 x amount of food = 100 280 weight of seal
  • 6. EXAMPLE 3 Write and solve a proportion STEP 2 Solve the proportion. 8 x = Write proportion. 100 280 8 280 = 100 x Cross products property 2240 = 100x Simplify. 22.4 = x Divide each side by 100. ANSWER A 280 pound seal should be fed 22.4 pounds of food per day.
  • 7. EXAMPLE 2 Standardized Test Practice What is the value of x in the proportion 4 = 8 ? x x– 3 A –6 B –3 C 3 D 6 SOLUTION 4 8 = Write original proportion. x x –3 4(x – 3) = x 8 Cross products property 4x – 12 = 8x Simplify. – 12 = 4x Subtract 4x from each side. –3=x Divide each side by 4.
  • 8. EXAMPLE 2 GUIDED PRACTICE for Examples 1,2, and 3 3 2 = x x –6 Write original proportion. 3(x – 6) = 2 x Cross products property 3x – 18 = 2x Distrubutive property 18 = x Subtract 3x from each side. ANSWER The value of x is 18. Check by substituting 18 for x in the original proportion.
  • 9. EXAMPLE 2 GUIDED PRACTICE for Examples 1,2, and 3 m m–6 = Write original proportion. 5 4 m 4 = 5(m – 6) Cross products property 4m = 5m – 30 Simplify m = 30 Subtract 5m from each side.
  • 10. • Assignment: P. 171 (#6-10, 19-22)