1) What would the concentration of OH- be if the concentration of H3O+.docx
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1) What would the concentration of OH - be if the concentration of H 3 O + was 1 × 10 -5 M? [H 3 O + ] × [OH - ] = K w = 1 × 10 -14 2) Over the past 50 years, the global amount of carbon dioxide in the atmosphere increased by 158 billion tons, but over 215 billion were released by burning of fossil fuels. Where did the rest go? A. It was recycled. B.It was converted into carbohydrates. C.it escaped into space. D.It was converted into acid rain. E.It was absorbed by the oceans. Solution 1) Ionic product of water Kw expeession is Kw = [H3O+][OH-] therefore, [H3O+] [OH-] = 1.0×10 -14 substitute the given H3O+ concentration 1.0×10 -5 M × [OH-] = 1.0×10 -14 M 2 [OH-] = 1.0×10 -14 M 2 /1.0×10 -5 M [OH-] = 1.0 ×10 -9 M Therefore, concentration of OH- = 1.0×10 -9 M 2) E) It was absorbed by the oceans .
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![1) What would the concentration of OH -
be if the concentration of H 3 O +
was 1 × 10 -5
M?
[H 3 O +
] × [OH -
] = K w = 1 × 10 -14
2) Over the past 50 years, the global amount of carbon dioxide in the atmosphere increased by
158 billion tons, but over 215 billion were released by burning of fossil fuels. Where did the rest
go? A. It was recycled. B.It was converted into carbohydrates. C.it escaped into space. D.It was
converted into acid rain. E.It was absorbed by the oceans.
Solution
1)
Ionic product of water Kw expeession is
Kw = [H3O+][OH-]
therefore,
[H3O+] [OH-] = 1.0×10 -14
substitute the given H3O+ concentration
1.0×10 -5
M × [OH-] = 1.0×10 -14
M 2
[OH-] = 1.0×10 -14
M 2
/1.0×10 -5
M
[OH-] = 1.0 ×10 -9
M
Therefore,
concentration of OH- = 1.0×10 -9
M
2) E) It was absorbed by the oceans](https://image.slidesharecdn.com/1whatwouldtheconcentrationofoh-beiftheconcentrationofh3o-230131003414-874e13aa/85/1-What-would-the-concentration-of-OH-be-if-the-concentration-of-H3O-docx-1-320.jpg)
Recommended
For H2SO3 pK1 = 1.8 and pK2 = 7.2 and thus K1 = .pdf
For H2SO3 pK1 = 1.8 and pK2 = 7.2 and thus K1 = 1.58E-2 and K2 = 6.31E-8
For a given pH (get to this in a minute), it can be shown [H+]=10^-pH [OH-] = Kw / [H+]
where Kw is the ion product of water (1E-14) [H2SO3] = [H+]^2 / f [HSO3-] = K1 [H+] / f
[SO3--] = K1 K2 / f where f = [H+]^2 + K1[H+] = K1K2 Given that H2SO3 is a weak acid, lets
assume that the pH is described by K1 or [H+] = sqrt(K1 C) where C is the acid conc (mol/l).
This leads to a [H+] = 0.05 and a pH = 1.07 Using the [H+] and data above yields in mol/l [H+]
8.51E-02 [OH-] 1.17E-13 [H2SO3] 3.88E-01 [HSO3-] 7.22E-02 [SO3--] 5.35E-08 Note the
above data describes the acid as 15% dissociated and the assumptiom that the pH of the solution
is best described by K1 is not necessarily a good assumption. A better way is as follows :- The
charge balance is this system is given by [H+] = [OH-] + [HSO3-] + 2*[SO3--] Set up all the
above relationships in MS Excel and Goal Seek a pH that makes the above charge balance
correct. Doing this yields a pH = 1.11 and the following concs (mol/l) [H+] 7.78E-02 [OH-]
1.28E-13 [H2SO3] 3.82E-01 [HSO3-] 7.78E-02 [SO3--] 6.31E-08 Be mindful that in all this
calculation, ionic strength impacts (ie activities) have been ignored or activity coefficients have
been taken as 1
Solution
For H2SO3 pK1 = 1.8 and pK2 = 7.2 and thus K1 = 1.58E-2 and K2 = 6.31E-8
For a given pH (get to this in a minute), it can be shown [H+]=10^-pH [OH-] = Kw / [H+]
where Kw is the ion product of water (1E-14) [H2SO3] = [H+]^2 / f [HSO3-] = K1 [H+] / f
[SO3--] = K1 K2 / f where f = [H+]^2 + K1[H+] = K1K2 Given that H2SO3 is a weak acid, lets
assume that the pH is described by K1 or [H+] = sqrt(K1 C) where C is the acid conc (mol/l).
This leads to a [H+] = 0.05 and a pH = 1.07 Using the [H+] and data above yields in mol/l [H+]
8.51E-02 [OH-] 1.17E-13 [H2SO3] 3.88E-01 [HSO3-] 7.22E-02 [SO3--] 5.35E-08 Note the
above data describes the acid as 15% dissociated and the assumptiom that the pH of the solution
is best described by K1 is not necessarily a good assumption. A better way is as follows :- The
charge balance is this system is given by [H+] = [OH-] + [HSO3-] + 2*[SO3--] Set up all the
above relationships in MS Excel and Goal Seek a pH that makes the above charge balance
correct. Doing this yields a pH = 1.11 and the following concs (mol/l) [H+] 7.78E-02 [OH-]
1.28E-13 [H2SO3] 3.82E-01 [HSO3-] 7.78E-02 [SO3--] 6.31E-08 Be mindful that in all this
calculation, ionic strength impacts (ie activities) have been ignored or activity coefficients have
been taken as 1.
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9- A combination of sand- salt- and water is an example of a A) homoge.docx
9. A combination of sand, salt, and water is an example of a A) homogeneous mixture B) heterogeneous mixture C) compound D) pure substance E) solid 10. Forthe following reaction Chldh +Oz ? CO2 + 11,0 what is the coefficient of oxygen? a. 2 b. 4 c. 6 d. 8 e. None of the above
Solution
9) Salt, sand and water mixture contains two different phases. liquid phase and solid phase.
and moreover they dont mix and form separate phases.
So, this is example of heterogeneous mixture. (B)
10)
Balance the reaction :
C 3 H 4 O2 + O 2 -----------> CO 2 + H 2 O
balance the reaction for Carbon ,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + H 2 O
balance the reaction for hydrogen,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + 2 H 2 O
now balance the reaction for oxygen,
C 3 H 4 O2 + 3 O 2 -----------> 3 CO 2 + 2 H 2 O
So, the answer is 3 and option is none of the above.
.
5. A water sample with a total alkalinity of 2.00 x 10 molesL has .pdf
5. A water sample with a total alkalinity of 2.00 x 10 moles/L has a pH of 7.00. Compute the
equilibrium concentrations of CO2, HCOs , co,, and OH Note that water and carbon dioxide can
replace carbonic acid in the Kai reaction without changing the value of Kal H2O + CO2 H+ +
HCO, Ka1 = 4.5 x 10-7
Solution
The equilibrim equations involved are:
H2O +CO2 <---->H+ +HCO3- ka1=4.5*10^-7
HCO3- <--->CO32- +H+ ka2=4.8*10^-11
Also given, pH=-log [H+]=7.0
[H+]=10^-7 M ...........(a)
[OH-]=kw/[H+]=10^-14/[H+]=10^-14.............(b)
pH=pka +log [base]/[acid] [henderson-hasselbach equation]
pka2=-log ka2=-log(4.8*10^-11)=10.3
7.0=10.3 +log[CO32-]/[HCO3-]
or, [CO32-]/[HCO3-]=5.012e-4.
or,[CO32-]=(5.012e-4.)[HCO3-]..................(1)
Also, H2O +CO2 <---->H+ +HCO3- ka1=4.5*10^-7=[H+][HCO3-]/[CO2]
for x=[H+]=[HCO3-] (at equilibrium)
[CO2]=[CO2]o-x , [CO2]o=initial concentration,but x is very less for very less dissociation ( ka1
is very small)
[CO2]eq=[CO2]o
4.5*10^-7=[H+][HCO3-]/[CO2]=x^2/[CO2]
or,[CO2]eq=x^2/(4.5*10^-7)=[HCO3-]eq/(4.5*10^-7)
[CO2]eq=[HCO3-]eq^2/(4.5*10^-7) ...................(2)
total alkalnity=[HCO3-] +2[CO32-] +[OH-] -[H+]=2.0*10^-3 mol/L
plugging in eqn (a),(b),(1) & (2) in the equation for total alkalinity,
total alkalnity=[HCO3-] +2(5.012e-4.)[HCO3-]. =2.0*10^-3 mol/L
or, [HCO3-]=1.997*10^-3 mol/L
[CO32-]eq=(5.012e-4.)[HCO3-].=(5.012e-4.)(2.0*10^-3 mol/L)=1.002*10^-6 mol/l
[H+]eq=[OH-]eq=10^-7 mol/L
[CO2]=[HCO3-]eq^2/(4.5*10^-7) =(1.997*10^-3 mol/L)^2/(4.5*10^-7)=8.862 mol/L
[CO2]eq=8.862*10^3 mol/L.
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For H2SO3 pK1 = 1.8 and pK2 = 7.2 and thus K1 = .pdf
For H2SO3 pK1 = 1.8 and pK2 = 7.2 and thus K1 = 1.58E-2 and K2 = 6.31E-8
For a given pH (get to this in a minute), it can be shown [H+]=10^-pH [OH-] = Kw / [H+]
where Kw is the ion product of water (1E-14) [H2SO3] = [H+]^2 / f [HSO3-] = K1 [H+] / f
[SO3--] = K1 K2 / f where f = [H+]^2 + K1[H+] = K1K2 Given that H2SO3 is a weak acid, lets
assume that the pH is described by K1 or [H+] = sqrt(K1 C) where C is the acid conc (mol/l).
This leads to a [H+] = 0.05 and a pH = 1.07 Using the [H+] and data above yields in mol/l [H+]
8.51E-02 [OH-] 1.17E-13 [H2SO3] 3.88E-01 [HSO3-] 7.22E-02 [SO3--] 5.35E-08 Note the
above data describes the acid as 15% dissociated and the assumptiom that the pH of the solution
is best described by K1 is not necessarily a good assumption. A better way is as follows :- The
charge balance is this system is given by [H+] = [OH-] + [HSO3-] + 2*[SO3--] Set up all the
above relationships in MS Excel and Goal Seek a pH that makes the above charge balance
correct. Doing this yields a pH = 1.11 and the following concs (mol/l) [H+] 7.78E-02 [OH-]
1.28E-13 [H2SO3] 3.82E-01 [HSO3-] 7.78E-02 [SO3--] 6.31E-08 Be mindful that in all this
calculation, ionic strength impacts (ie activities) have been ignored or activity coefficients have
been taken as 1
Solution
For H2SO3 pK1 = 1.8 and pK2 = 7.2 and thus K1 = 1.58E-2 and K2 = 6.31E-8
For a given pH (get to this in a minute), it can be shown [H+]=10^-pH [OH-] = Kw / [H+]
where Kw is the ion product of water (1E-14) [H2SO3] = [H+]^2 / f [HSO3-] = K1 [H+] / f
[SO3--] = K1 K2 / f where f = [H+]^2 + K1[H+] = K1K2 Given that H2SO3 is a weak acid, lets
assume that the pH is described by K1 or [H+] = sqrt(K1 C) where C is the acid conc (mol/l).
This leads to a [H+] = 0.05 and a pH = 1.07 Using the [H+] and data above yields in mol/l [H+]
8.51E-02 [OH-] 1.17E-13 [H2SO3] 3.88E-01 [HSO3-] 7.22E-02 [SO3--] 5.35E-08 Note the
above data describes the acid as 15% dissociated and the assumptiom that the pH of the solution
is best described by K1 is not necessarily a good assumption. A better way is as follows :- The
charge balance is this system is given by [H+] = [OH-] + [HSO3-] + 2*[SO3--] Set up all the
above relationships in MS Excel and Goal Seek a pH that makes the above charge balance
correct. Doing this yields a pH = 1.11 and the following concs (mol/l) [H+] 7.78E-02 [OH-]
1.28E-13 [H2SO3] 3.82E-01 [HSO3-] 7.78E-02 [SO3--] 6.31E-08 Be mindful that in all this
calculation, ionic strength impacts (ie activities) have been ignored or activity coefficients have
been taken as 1.
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The document discusses acids, bases, and pH. It explains that acids donate H+ ions while bases accept H+ ions. Common acids include HCl and carbonic acid, while NaOH is a strong base. Neutralization reactions between acids and bases produce water and salts. Buffers resist changes in pH. The pH scale ranges from 0-14 with acidic solutions having a pH below 7 and basic solutions above 7. The carbonate buffering system and carbon dioxide system in the ocean help regulate ocean pH. Increasing carbon dioxide absorption is lowering ocean pH and threatening marine organisms with calcium carbonate shells or skeletons.
Lect w9 buffers_exercises
This document discusses several concepts related to buffers, including:
1) Calculating the pH of an acetate buffer with given concentrations. The pH is calculated to be 4.67.
2) Choosing an appropriate buffer to achieve a target pH of 4.30 from given options based on their pKa values. Acetate is chosen.
3) Calculating the acid concentration needed for a 0.100 M base concentration to achieve the target pH. The acid concentration is calculated to be 0.28 M.
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This document provides an overview of the global carbon cycle and the role of inland waters. It discusses carbon pools and fluxes at different time scales, from the modern perturbed cycle to pre-anthropocene, glacial-interglacial, and Earth's history. The key role of the ocean in regulating atmospheric CO2 levels over the past 10,000 years is explained through calculations showing that net heterotrophy in the ocean could account for the required imbalance. Links between the carbon and oxygen cycles through geological time are also briefly outlined.
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The document discusses the carbonate system and chemical weathering. It describes the carbonate equilibrium reactions and species like carbonic acid, bicarbonate, and carbonate that are involved. Chemical weathering plays an important role in regulating atmospheric carbon dioxide and climate by slowly breaking down continental rocks and sequestering carbon over millions of years. Factors like temperature, precipitation, and vegetation influence chemical weathering rates and provide negative feedback that moderates global temperatures.
9- A combination of sand- salt- and water is an example of a A) homoge.docx
9. A combination of sand, salt, and water is an example of a A) homogeneous mixture B) heterogeneous mixture C) compound D) pure substance E) solid 10. Forthe following reaction Chldh +Oz ? CO2 + 11,0 what is the coefficient of oxygen? a. 2 b. 4 c. 6 d. 8 e. None of the above
Solution
9) Salt, sand and water mixture contains two different phases. liquid phase and solid phase.
and moreover they dont mix and form separate phases.
So, this is example of heterogeneous mixture. (B)
10)
Balance the reaction :
C 3 H 4 O2 + O 2 -----------> CO 2 + H 2 O
balance the reaction for Carbon ,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + H 2 O
balance the reaction for hydrogen,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + 2 H 2 O
now balance the reaction for oxygen,
C 3 H 4 O2 + 3 O 2 -----------> 3 CO 2 + 2 H 2 O
So, the answer is 3 and option is none of the above.
.
5. A water sample with a total alkalinity of 2.00 x 10 molesL has .pdf
5. A water sample with a total alkalinity of 2.00 x 10 moles/L has a pH of 7.00. Compute the
equilibrium concentrations of CO2, HCOs , co,, and OH Note that water and carbon dioxide can
replace carbonic acid in the Kai reaction without changing the value of Kal H2O + CO2 H+ +
HCO, Ka1 = 4.5 x 10-7
Solution
The equilibrim equations involved are:
H2O +CO2 <---->H+ +HCO3- ka1=4.5*10^-7
HCO3- <--->CO32- +H+ ka2=4.8*10^-11
Also given, pH=-log [H+]=7.0
[H+]=10^-7 M ...........(a)
[OH-]=kw/[H+]=10^-14/[H+]=10^-14.............(b)
pH=pka +log [base]/[acid] [henderson-hasselbach equation]
pka2=-log ka2=-log(4.8*10^-11)=10.3
7.0=10.3 +log[CO32-]/[HCO3-]
or, [CO32-]/[HCO3-]=5.012e-4.
or,[CO32-]=(5.012e-4.)[HCO3-]..................(1)
Also, H2O +CO2 <---->H+ +HCO3- ka1=4.5*10^-7=[H+][HCO3-]/[CO2]
for x=[H+]=[HCO3-] (at equilibrium)
[CO2]=[CO2]o-x , [CO2]o=initial concentration,but x is very less for very less dissociation ( ka1
is very small)
[CO2]eq=[CO2]o
4.5*10^-7=[H+][HCO3-]/[CO2]=x^2/[CO2]
or,[CO2]eq=x^2/(4.5*10^-7)=[HCO3-]eq/(4.5*10^-7)
[CO2]eq=[HCO3-]eq^2/(4.5*10^-7) ...................(2)
total alkalnity=[HCO3-] +2[CO32-] +[OH-] -[H+]=2.0*10^-3 mol/L
plugging in eqn (a),(b),(1) & (2) in the equation for total alkalinity,
total alkalnity=[HCO3-] +2(5.012e-4.)[HCO3-]. =2.0*10^-3 mol/L
or, [HCO3-]=1.997*10^-3 mol/L
[CO32-]eq=(5.012e-4.)[HCO3-].=(5.012e-4.)(2.0*10^-3 mol/L)=1.002*10^-6 mol/l
[H+]eq=[OH-]eq=10^-7 mol/L
[CO2]=[HCO3-]eq^2/(4.5*10^-7) =(1.997*10^-3 mol/L)^2/(4.5*10^-7)=8.862 mol/L
[CO2]eq=8.862*10^3 mol/L.
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can you write the answer clearly to understand it thanksSolution Carb.docx
can you write the answer clearly to understand it
thanks
Solution
Carbon monoxide vs. Carbon dioxide
Main differences based upon their structure :-
1). Carbon dioxide ( CO 2 ) is composed of 1 carbon atom and 2 oxygen atoms on the other hand carbon monoxide CO) is composed by 1 carbon and 1 oxygen atom .
2). In CO 2 , surrounded oxygen atoms are covalently bonded with central carbon atom by double bond while in CO carbon and oxygen atoms are covalently bonded by triple bond in which carbon atom carry one unit negative charge and oxygen atom carry one unit positive charge and hence overall structure of CO is neutral .
Differences based upon their Chemical properties:-
1). Carbon dioxide is produced by complete combustion of carbon in the presence of oxygen on the other hand carbon monoxide is produced by incomplete combustion of carbon .
for e.g:- C (s) + O 2 (g) --------------------> CO 2 (g)Â Â Â Â ( Complete combustion )
C (s) + 1/2 O 2 (g) -------------------> CO (g) ( Incomplete combustion ) .
2) . CO 2 serve as ligand in metal carbon dioxide complexes
for e.g :- Li - R + CO 2 --------------> R CO 2 Li
while CO form complexes with metals having lower oxidation number , in which CO act as ligand .
for e.g :- Fe   +   5 CO ------------> Fe(CO) 5
3) . CO 2 used in Photosynthesis process i.e CO 2 reacts with water in atmosphere as :
n CO 2 + nH 2 O --------------> ( CH 2 O) n + nO 2
on the other hand CO produce CO 2 and H 2 gases with water .
for e.g :-Â Â CO(g) +Â Â H 2 O -----------------> CO 2 +Â Â Â Â H 2
CO is very toxic and reactive gas . it is present rare in the air while CO 2 is non-poisoness gas . it is common gas in the air. CO 2 is required for plant life and it is most important greenhouse gas .
.
Hello- please use EULERS METHOD to solve and graph this- Please show -.docx
Hello, please use EULERS METHOD to solve and graph this. Please show *FULL* work. Thank you
I = Infected poplulation
S = Suscepitble population
Betta and alpha are constants.
transmission rate of the virus is Beta constant.
Recovery rate of virus is alpha constant.
alpha = 1.25
Gamma = 0.4
S(0) = 0.88
I(0) = 0.12
Step size = 0.25
Solution
import java.text.DecimalFormat; public class euler { public static void main(String[] Leonhard) { DecimalFormat df = new DecimalFormat(\"#.0000\"); double h = (1.0/3.0); // h is the step-size double t_0 = 0; // initial condition double x_0 = .3; // initial condition double x_f = 10; // I want to find x(10) using this method and compare it to an exact value of x(10) double[] t_k; t_k = new double[ (int)( ( x_f - x_0 ) / h ) + 1 ] ; // this two arrays hold the values of x_k and t_k double[] x_k; x_k = new double[ (int)( ( x_f - x_0 ) / h ) + 1 ] ; int i; // the counter System.out.println( \"k\\t t_k\\t x_k\" ); // table header for ( i = 0; k < (int)( ( x_f - x_0 ) / h ) + 1; i++ ) { if ( i == 0 ) // this if statement handles the initial conditions { t_k[i] = t_0; x_k[i] = x_0; } else if ( i > 0 ) { t_k[i] += i*h; x_k[i] = x_k[i-1] + h*( Math.exp(t_k[i-1]))*(Math.sin(x_k[i-1]) ); } System.out.println( k + \" \" + df.format(t_k[i]) + \" \" + df.format( x_k[i]) ); } } }
.
he above pictures best represents a solid lonic A) picture (a) B) pict.docx
he above pictures best represents a solid lonic A) picture (a) B) picture (b) C)picture Ic l picture (d) 3) Which contains both covalent bonds and lonic bonds? A) HBr B) Li 4) A reactive element with a relatively high electronegativfty would be expected to have a reletively A) small negative electron affinity and a relatiwely low ionization energy- B) small negative electron affinity and a reletively righ lonitation energy. C) large negative electron affinity and a relatively low lonization energy. D) large negative electron affinity and a relatively high ionization energy Est IGF ONLY
Solution
Solved the first problem as per Chegg guidelines, post multiple question to get the remaining answers
Q2) Correct answer is Option C (picture (c))
Reason: The ionic bond is formed when two elements with high electronegativity difference form a bond which result in the formation of + charge on cation and - charge on anion
Picture A and B contains only one type of atoms/element, hence it cannot form ionic bond with itself
Picture D has two types of atom/element, but far spread like gases, generally ionic compounds are solid in nature
.
Heidi Design acquired 20- of the outstanding common stock of Quigly Co (1).docx
Heidi Design acquired 20% of the outstanding common stock of Quigly Company on January 1, 2014, by paying $800,000 for the 30,000 shares. Quigly declared and paid $0.30 per share cash dividends on March 15, June 15, September 15, and December 15, 2014. Quigly reported net income of $320,000 for the year. At December 31, 2014, the market price of Quigly common stock was $34 per share.
Instructions
(b) Prepare the journal entries for Heidi Design for 2014, assuming Heidi Design can exercise significant influence over Quigly. Use equity method.
HINT: Revenue from stock investments $64,000.
Solution
the revenue from dividend is =30,000X0.3= $9000
and 4 times paid, so total dividend= 9000*4= $36,000
and the net income at the date 31,Dec 2014 is $320,000. if you divide it per share, it will be:
total shares are= 150,000 (i.e. when 20% shares are 30,000 in number, total shares are 150,000)
320,000/150,000= $2.133
and total apreciation can be $64,000 (2.133*30,000)
.
Heidi Design acquired 20- of the outstanding common stock of Quigly Co.docx
Heidi Design acquired 20% of the outstanding common stock of Quigly Company on January 1, 2014, by paying $800,000 for the 30,000 shares. Quigly declared and paid $0.30 per share cash dividends on March 15, June 15, September 15, and December 15, 2014. Quigly reported net income of $320,000 for the year. At December 31, 2014, the market price of Quigly common stock was $34 per share.
Instructions
(a) Prepare the journal entries for Heidi Design for 2014 assuming Heidi Design cannot exercise significant influence over Quigly. (Use the cost method and assume that Quigly common stock should be classified as a trading security).
HINT: Total divident revenue $36,000
Solution
Declaration of Dividend on 31st march2014
Declaration of Dividend on 30th  June 2014
Declaration of Dividend on 30th Sep 2014
Declaration of Dividend on 31st dec 2014
Dividend Amount = 30000x 0.03 = 9000
9000x3/12 = $2250
.
Halogens tend to have high- I- electronegativities II- solublity in a.docx
Halogens tend to have high:
I. electronegativities
II. solublity in aqueous solution
III. ionization energies
IV. degrees of reactvity
choose all that apply
Solution
--> Halogens are highly electronegativity because after taking one electron they can fulfill their orbital and become stable
--> they are less soluble in aquous solution because they are non-polar. They are highly soluble in organic solvent.
--> they have high ionization energy.
--> due to high electronegativity they have high reactivity.
So overall Halogens are highly electronegative, ionization energy and degree of reactivity.
If you satisfied with the solution please like it.. thanks..
.
Heat transfer summary questionsSolutionThermal energy is related to th.docx
Heat transfer summary questions
Solution
Thermal energy is related to the temperature of matter. For a given material and mass, the higher the temperature, the greater its thermal energy. Heat transfer is a study of the exchange of thermal energy through a body or between bodies which occurs when there is a temperature difference. When two bodies are at different temperatures, thermal energy transfers from the one with higher temperature to the one with lower temperature. Heat always transfers from hot to cold.
Table 1 shows the common SI and English units and conversion factors used for heat and heat transfer rates. Heat is typically given the symbol Q , and is expressed in joules (J) in SI units. The rate of heat transfer is measured in watts (W), equal to joules per second, and is denoted by q . The heat flux, or the rate of heat transfer per unit area, is measured in watts per area (W/m 2 ), and uses q\" for the symbol.
.
he following accounts were taken from ABC CompanySolutionCalculation o.docx
ABC Company's total assets are $320,000, calculated by adding account receivables, buildings, cash, equipment, inventory, prepaid insurance, and trademarks; and subtracting accumulated depreciation on equipment and buildings. The assets include $64,000 in accounts receivable, $81,000 building, $30,000 cash, $68,000 equipment, $62,000 inventory, $15,000 prepaid insurance, and $31,000 trademarks. Accumulated depreciation of $31,000 was subtracted.
he following accounts were taken from ABC CompanySolutionCalculation o (1).docx
ABC Company has total assets of $320,000 which is calculated by adding account receivables, building, cash, equipment, inventory, prepaid insurance, and trademark values and subtracting accumulated depreciation from the equipment amount. The assets include $64,000 in accounts receivable, $81,000 building, $30,000 cash, $68,000 equipment less $31,000 accumulated depreciation, $62,000 inventory, $15,000 prepaid insurance, and $31,000 trademark.
Harriet Pandel- an employer- is subject to FICA taxes but exempt from.docx
Harriet Pandel, an employer, is subject to FICA taxes but exempt from FUTA and SUTA taxes. During last quarter of the year, her employees earned monthly wages of $16,900, all of which is taxable. The amount of federal income taxes withheld each month is $1,698. Journalize the payment of wages and record the payroll tax on November 29.
Solution
Journal entry:
.
Harris Fell- CPA and member of the AICPA- was engaged to audit the fin.docx
Harris Fell, CPA and member of the AICPA, was engaged to audit the financial statements of Wilson Corporation. Fell had half-completed the audit when he had a dispute with the management of Wilson Corporation and was discharged. Hal Compton, CPA, was promptly engaged to replace Fell. Wilson Corporation did not compensate Fell for his work to date; therefore, Fell refused to allow Wilson Corporation’s management to examine his working papers. Some of the working papers consisted of adjusting journal entries and supporting analysis. Wilson Corporation’s management had no other source for this information. Did Fell violate the AICPA Code of Professional Conduct ? Explain fully. Remember to complete all parts of the problems. Do not forget to show the necessary steps and explain how you attained that outcome
Solution
It is apparent from the cae that Fell was dismissed and replaced rather quickly due to disagreement with managemnt .Wilson co. replaced him with Hal Compton, but Fell had not been paid for the work he had performed on the audit to date.Due to Fell\'s dismissal and Wilson co\'s did not compensate ,they were not given access to Fell\'s paperwok. I believe that Fell is not conforming to the AICPA\'s code of professional conduct.If Wilson Co. had still not paid Fell after a certain amount of time then he could have taken the appropirate actions to be paid for services rendered. Most companies do not pay for services as soon as task is completed . A company has a certain amount of time to pay thier bill before it goes int default .Fell shpuld have made his findings avialable to his repalacement and the Wilson Co. immediately as a show of professional and ethical courtsey
.
Gwen and Paul are deciding how to split their time between writing mus.docx
Gwen and Paul are deciding how to split their time between writing music and lyrics for their new album. Their PPFs for 72 hours of work are shown below. . Gwen and Paul have to write music for 8 songs and lyrics for 12 songs (4 songs already have music). When they are done, they can go to a private island and relax from all their hard work. It is possible that they will use more than 72 hours.
Once they start writing lyrics and music, assuming their hired help packs for them and their plane is waiting outside their door, in how many hours can they board the plane to their relaxing island getaway?
Gwen will write music for ?
Paul will write music for?
Gwen will write lyrics for?
Paul will write lyrics for?
Solution
Gwen will write Music For: 0 Songs (Because he has comparative advantage in Lyrics)
Paul will write Music For: 8 Songs (Because he has comparative advantage in Music)
Gwen will write Lyrics For: 12 Songs
Paul will write Lyrics For: 0 Songs
In 72 Hours Paul will write Music for 6 Songs, So average time required Per Song = 12 Hours
In 72 Hours Gwen will write Lyrics for 9 Songs, So average time required Per Song = 8 Hours
Extra Time Required will be: Paul: 12 x 2 = 24 Hours
Gwen: 8 x 3 = 24 Hours
So, an extra time of 24 Hours are required. Total time required will be 72 + 24 = 96 Hours
So, after 96 Hours they can board the plane to their relaxing island getaway.
Gwen will write Music For: 0 Songs
Paul will write Music For: 8 Songs
Gwen will write Lyrics For: 12 Songs
Paul will write Lyrics For: 0 Songs
.
Gordon Corporation reported the following equity section on its curren.docx
Gordon Corporation reported the following equity section on its current balance sheet. The common stock is currently selling for $11.50 per share.
a.  What would be the total paid-in capital after a 10% common stock dividend?
Solution
Stock dividend = 40,000 * 10% =4000shares
Additional paid in capital on stock dividend = (11.50 -5 ) *4000
= 6.50*4000
=$ 26,000
so total paid in capital = 120,000 +26,000
= $ 146,000
.
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can you write the answer clearly to understand it thanksSolution Carb.docx
can you write the answer clearly to understand it
thanks
Solution
Carbon monoxide vs. Carbon dioxide
Main differences based upon their structure :-
1). Carbon dioxide ( CO 2 ) is composed of 1 carbon atom and 2 oxygen atoms on the other hand carbon monoxide CO) is composed by 1 carbon and 1 oxygen atom .
2). In CO 2 , surrounded oxygen atoms are covalently bonded with central carbon atom by double bond while in CO carbon and oxygen atoms are covalently bonded by triple bond in which carbon atom carry one unit negative charge and oxygen atom carry one unit positive charge and hence overall structure of CO is neutral .
Differences based upon their Chemical properties:-
1). Carbon dioxide is produced by complete combustion of carbon in the presence of oxygen on the other hand carbon monoxide is produced by incomplete combustion of carbon .
for e.g:- C (s) + O 2 (g) --------------------> CO 2 (g)Â Â Â Â ( Complete combustion )
C (s) + 1/2 O 2 (g) -------------------> CO (g) ( Incomplete combustion ) .
2) . CO 2 serve as ligand in metal carbon dioxide complexes
for e.g :- Li - R + CO 2 --------------> R CO 2 Li
while CO form complexes with metals having lower oxidation number , in which CO act as ligand .
for e.g :- Fe   +   5 CO ------------> Fe(CO) 5
3) . CO 2 used in Photosynthesis process i.e CO 2 reacts with water in atmosphere as :
n CO 2 + nH 2 O --------------> ( CH 2 O) n + nO 2
on the other hand CO produce CO 2 and H 2 gases with water .
for e.g :-Â Â CO(g) +Â Â H 2 O -----------------> CO 2 +Â Â Â Â H 2
CO is very toxic and reactive gas . it is present rare in the air while CO 2 is non-poisoness gas . it is common gas in the air. CO 2 is required for plant life and it is most important greenhouse gas .
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More from deant5
Hello- please use EULERS METHOD to solve and graph this- Please show -.docx
Hello, please use EULERS METHOD to solve and graph this. Please show *FULL* work. Thank you
I = Infected poplulation
S = Suscepitble population
Betta and alpha are constants.
transmission rate of the virus is Beta constant.
Recovery rate of virus is alpha constant.
alpha = 1.25
Gamma = 0.4
S(0) = 0.88
I(0) = 0.12
Step size = 0.25
Solution
import java.text.DecimalFormat; public class euler { public static void main(String[] Leonhard) { DecimalFormat df = new DecimalFormat(\"#.0000\"); double h = (1.0/3.0); // h is the step-size double t_0 = 0; // initial condition double x_0 = .3; // initial condition double x_f = 10; // I want to find x(10) using this method and compare it to an exact value of x(10) double[] t_k; t_k = new double[ (int)( ( x_f - x_0 ) / h ) + 1 ] ; // this two arrays hold the values of x_k and t_k double[] x_k; x_k = new double[ (int)( ( x_f - x_0 ) / h ) + 1 ] ; int i; // the counter System.out.println( \"k\\t t_k\\t x_k\" ); // table header for ( i = 0; k < (int)( ( x_f - x_0 ) / h ) + 1; i++ ) { if ( i == 0 ) // this if statement handles the initial conditions { t_k[i] = t_0; x_k[i] = x_0; } else if ( i > 0 ) { t_k[i] += i*h; x_k[i] = x_k[i-1] + h*( Math.exp(t_k[i-1]))*(Math.sin(x_k[i-1]) ); } System.out.println( k + \" \" + df.format(t_k[i]) + \" \" + df.format( x_k[i]) ); } } }
.
he above pictures best represents a solid lonic A) picture (a) B) pict.docx
he above pictures best represents a solid lonic A) picture (a) B) picture (b) C)picture Ic l picture (d) 3) Which contains both covalent bonds and lonic bonds? A) HBr B) Li 4) A reactive element with a relatively high electronegativfty would be expected to have a reletively A) small negative electron affinity and a relatiwely low ionization energy- B) small negative electron affinity and a reletively righ lonitation energy. C) large negative electron affinity and a relatively low lonization energy. D) large negative electron affinity and a relatively high ionization energy Est IGF ONLY
Solution
Solved the first problem as per Chegg guidelines, post multiple question to get the remaining answers
Q2) Correct answer is Option C (picture (c))
Reason: The ionic bond is formed when two elements with high electronegativity difference form a bond which result in the formation of + charge on cation and - charge on anion
Picture A and B contains only one type of atoms/element, hence it cannot form ionic bond with itself
Picture D has two types of atom/element, but far spread like gases, generally ionic compounds are solid in nature
.
Heidi Design acquired 20- of the outstanding common stock of Quigly Co (1).docx
Heidi Design acquired 20% of the outstanding common stock of Quigly Company on January 1, 2014, by paying $800,000 for the 30,000 shares. Quigly declared and paid $0.30 per share cash dividends on March 15, June 15, September 15, and December 15, 2014. Quigly reported net income of $320,000 for the year. At December 31, 2014, the market price of Quigly common stock was $34 per share.
Instructions
(b) Prepare the journal entries for Heidi Design for 2014, assuming Heidi Design can exercise significant influence over Quigly. Use equity method.
HINT: Revenue from stock investments $64,000.
Solution
the revenue from dividend is =30,000X0.3= $9000
and 4 times paid, so total dividend= 9000*4= $36,000
and the net income at the date 31,Dec 2014 is $320,000. if you divide it per share, it will be:
total shares are= 150,000 (i.e. when 20% shares are 30,000 in number, total shares are 150,000)
320,000/150,000= $2.133
and total apreciation can be $64,000 (2.133*30,000)
.
Heidi Design acquired 20- of the outstanding common stock of Quigly Co.docx
Heidi Design acquired 20% of the outstanding common stock of Quigly Company on January 1, 2014, by paying $800,000 for the 30,000 shares. Quigly declared and paid $0.30 per share cash dividends on March 15, June 15, September 15, and December 15, 2014. Quigly reported net income of $320,000 for the year. At December 31, 2014, the market price of Quigly common stock was $34 per share.
Instructions
(a) Prepare the journal entries for Heidi Design for 2014 assuming Heidi Design cannot exercise significant influence over Quigly. (Use the cost method and assume that Quigly common stock should be classified as a trading security).
HINT: Total divident revenue $36,000
Solution
Declaration of Dividend on 31st march2014
Declaration of Dividend on 30th  June 2014
Declaration of Dividend on 30th Sep 2014
Declaration of Dividend on 31st dec 2014
Dividend Amount = 30000x 0.03 = 9000
9000x3/12 = $2250
.
Halogens tend to have high- I- electronegativities II- solublity in a.docx
Halogens tend to have high:
I. electronegativities
II. solublity in aqueous solution
III. ionization energies
IV. degrees of reactvity
choose all that apply
Solution
--> Halogens are highly electronegativity because after taking one electron they can fulfill their orbital and become stable
--> they are less soluble in aquous solution because they are non-polar. They are highly soluble in organic solvent.
--> they have high ionization energy.
--> due to high electronegativity they have high reactivity.
So overall Halogens are highly electronegative, ionization energy and degree of reactivity.
If you satisfied with the solution please like it.. thanks..
.
Heat transfer summary questionsSolutionThermal energy is related to th.docx
Heat transfer summary questions
Solution
Thermal energy is related to the temperature of matter. For a given material and mass, the higher the temperature, the greater its thermal energy. Heat transfer is a study of the exchange of thermal energy through a body or between bodies which occurs when there is a temperature difference. When two bodies are at different temperatures, thermal energy transfers from the one with higher temperature to the one with lower temperature. Heat always transfers from hot to cold.
Table 1 shows the common SI and English units and conversion factors used for heat and heat transfer rates. Heat is typically given the symbol Q , and is expressed in joules (J) in SI units. The rate of heat transfer is measured in watts (W), equal to joules per second, and is denoted by q . The heat flux, or the rate of heat transfer per unit area, is measured in watts per area (W/m 2 ), and uses q\" for the symbol.
.
he following accounts were taken from ABC CompanySolutionCalculation o.docx
ABC Company's total assets are $320,000, calculated by adding account receivables, buildings, cash, equipment, inventory, prepaid insurance, and trademarks; and subtracting accumulated depreciation on equipment and buildings. The assets include $64,000 in accounts receivable, $81,000 building, $30,000 cash, $68,000 equipment, $62,000 inventory, $15,000 prepaid insurance, and $31,000 trademarks. Accumulated depreciation of $31,000 was subtracted.
he following accounts were taken from ABC CompanySolutionCalculation o (1).docx
ABC Company has total assets of $320,000 which is calculated by adding account receivables, building, cash, equipment, inventory, prepaid insurance, and trademark values and subtracting accumulated depreciation from the equipment amount. The assets include $64,000 in accounts receivable, $81,000 building, $30,000 cash, $68,000 equipment less $31,000 accumulated depreciation, $62,000 inventory, $15,000 prepaid insurance, and $31,000 trademark.
Harriet Pandel- an employer- is subject to FICA taxes but exempt from.docx
Harriet Pandel, an employer, is subject to FICA taxes but exempt from FUTA and SUTA taxes. During last quarter of the year, her employees earned monthly wages of $16,900, all of which is taxable. The amount of federal income taxes withheld each month is $1,698. Journalize the payment of wages and record the payroll tax on November 29.
Solution
Journal entry:
.
Harris Fell- CPA and member of the AICPA- was engaged to audit the fin.docx
Harris Fell, CPA and member of the AICPA, was engaged to audit the financial statements of Wilson Corporation. Fell had half-completed the audit when he had a dispute with the management of Wilson Corporation and was discharged. Hal Compton, CPA, was promptly engaged to replace Fell. Wilson Corporation did not compensate Fell for his work to date; therefore, Fell refused to allow Wilson Corporation’s management to examine his working papers. Some of the working papers consisted of adjusting journal entries and supporting analysis. Wilson Corporation’s management had no other source for this information. Did Fell violate the AICPA Code of Professional Conduct ? Explain fully. Remember to complete all parts of the problems. Do not forget to show the necessary steps and explain how you attained that outcome
Solution
It is apparent from the cae that Fell was dismissed and replaced rather quickly due to disagreement with managemnt .Wilson co. replaced him with Hal Compton, but Fell had not been paid for the work he had performed on the audit to date.Due to Fell\'s dismissal and Wilson co\'s did not compensate ,they were not given access to Fell\'s paperwok. I believe that Fell is not conforming to the AICPA\'s code of professional conduct.If Wilson Co. had still not paid Fell after a certain amount of time then he could have taken the appropirate actions to be paid for services rendered. Most companies do not pay for services as soon as task is completed . A company has a certain amount of time to pay thier bill before it goes int default .Fell shpuld have made his findings avialable to his repalacement and the Wilson Co. immediately as a show of professional and ethical courtsey
.
Gwen and Paul are deciding how to split their time between writing mus.docx
Gwen and Paul are deciding how to split their time between writing music and lyrics for their new album. Their PPFs for 72 hours of work are shown below. . Gwen and Paul have to write music for 8 songs and lyrics for 12 songs (4 songs already have music). When they are done, they can go to a private island and relax from all their hard work. It is possible that they will use more than 72 hours.
Once they start writing lyrics and music, assuming their hired help packs for them and their plane is waiting outside their door, in how many hours can they board the plane to their relaxing island getaway?
Gwen will write music for ?
Paul will write music for?
Gwen will write lyrics for?
Paul will write lyrics for?
Solution
Gwen will write Music For: 0 Songs (Because he has comparative advantage in Lyrics)
Paul will write Music For: 8 Songs (Because he has comparative advantage in Music)
Gwen will write Lyrics For: 12 Songs
Paul will write Lyrics For: 0 Songs
In 72 Hours Paul will write Music for 6 Songs, So average time required Per Song = 12 Hours
In 72 Hours Gwen will write Lyrics for 9 Songs, So average time required Per Song = 8 Hours
Extra Time Required will be: Paul: 12 x 2 = 24 Hours
Gwen: 8 x 3 = 24 Hours
So, an extra time of 24 Hours are required. Total time required will be 72 + 24 = 96 Hours
So, after 96 Hours they can board the plane to their relaxing island getaway.
Gwen will write Music For: 0 Songs
Paul will write Music For: 8 Songs
Gwen will write Lyrics For: 12 Songs
Paul will write Lyrics For: 0 Songs
.
Gordon Corporation reported the following equity section on its curren.docx
Gordon Corporation reported the following equity section on its current balance sheet. The common stock is currently selling for $11.50 per share.
a.  What would be the total paid-in capital after a 10% common stock dividend?
Solution
Stock dividend = 40,000 * 10% =4000shares
Additional paid in capital on stock dividend = (11.50 -5 ) *4000
= 6.50*4000
=$ 26,000
so total paid in capital = 120,000 +26,000
= $ 146,000
.
Goodwill would appear in which balance sheet section- a- Investments b.docx
Goodwill would appear in which balance sheet section?
a.
Investments
b.
Property, plant, and equipment
c.
Current assets
d.
Intangible assets
Solution
Intangible assets
.
1- A genetic map is a(an) set of identical copies of DNA segments from.docx
1. A genetic map is a(an)
set of identical copies of DNA segments from a single ancestor.
list of locations of markers that relate to inheritable traits.
2.A gene is a(an)
Solution
1) set of identical copies of DNA segments from a single ancestor.
list of locations of markers that relate to inheritable traits.
2) set of identical copies of DNA segments from a single ancestor.
.
1- A buyout involving the target firms current management is called a.docx
1. A buyout involving the target firm’s current management is called a management buyout. In what way do these type of deal represent agency conflicts between managers and shareholders? What board procedures can be put in place to mitigate such conflicts? How can activist investors help mitigate such conflicts?
Solution
A management buyout (MBO) is a form of acquisition where a company\'s existing managers acquire a large part or all of the company from either the parent company or from the private owners.
Though it is considered that post MBO, the commitment of the managment towards the company increases. However it results in agency conflicts between managers & shareholders as it leads to moral hazard as management takes the risk while shareholders pay its consequences. Also there could be cases where the management subtlely forces the stock price downwards by releasing adverse information, delibrately going ahead with projects against public preception, etc.
VarÂiÂous strateÂgies may be used by investors to move manÂageÂment board memÂbers away from parÂticÂiÂpatÂing in the deal on both sides. The most freÂquent is to form a speÂcial purÂpose vehiÂcle (SPV) for an MBO. ManÂageÂment board memÂbers conÂtribute funds to the SPV proÂvided for a purÂchase of shares in the comÂpany they manÂage. The remainÂing funds come from other instiÂtuÂtions financÂing the MBO (mainly banks and priÂvate equity funds). In negoÂtiÂaÂtions with the tarÂget comÂpany, repÂreÂsenÂtaÂtives of such instiÂtuÂtions often act on behalf of the SPV instead of as managers.
HavÂing many parÂticÂiÂpants in the deal reduces the risk that manÂageÂment board memÂbers will act under a conÂflict of interÂest, facilÂiÂtate getÂting more funds to finance the underÂtakÂing, and increase the chance of success.
.
1- 2- 3- 5- Part B Constants- Periodic Table nteractive 3D display mod.docx
1.
2.
3.
5.
Part B Constants| Periodic Table nteractive 3D display mode H2 Which of the following compounds would react with Tollens\' reagent, Benedicts reagent, both, or neither? You may want to reference (Pages 525-527) Section 14.3 while completing this problem Benedict\'s reagent O neither Tollens\' reagent nor Benedict\'s reagent O Tollens\' reagent O both Tollens\' reagent and Benedict\'s reagent Submit Incorrect; Try Again; 5 attempts remaining Benedict\'s reagent is a solution containing Cu, and it selectively oxidizes aldehydes in which the carbon atom adjacent to the aldehyde group bears a hydroxyl group. Simple aldehydes and ketones are not oxidized by Benedict\'s reagent. Tollens\' reagent is a solution of Ag and ammonia, and it selectively oxidizes aldehydes. (Ketones are not oxidized by Tollens\' reagent.)
Solution
1.
Reacts with both Tollens reagent and Benedicts reagents. Actually this is test used to confirm presence of aldehyde functional group.
2.
Its Acetic acid.
3.
A. Acetal
B. Acetaldehyde and Methanol.
C. Hemiacetal.
D. Ethyl methyl ketone and Ethanol.
E.Acetal
F.Cyclohexanone and Ethanol.
4.
Not chiral. Two same presents on both side.
5.
Not chiral. symmetry present.
First two answer given by you are correct, don’t know why it showing wrong.
.
1- (TCO 5) Which form type displays records in a tabular format simila.docx
1. (TCO 5) Which form type displays records in a tabular format similar to a Datasheet view but has more editing options such as adding graphics? (Points : 5) Â Â Â Â Â Â Datasheet Form
Multiple Items Form
Split Form
Subform
form that looks like a menu or a series of menus that ties objects in a database.
report that looks like a menu or a series of menus that ties objects in a database.
screen that is used to hide objects from users.
Solution
1. Correct option is Subform
2. 2. new form in layout view
3.3. identifier
4.4. Sales: GP*qty
5.5. Form
6.6. Query
7.7. correct answer is first option
8.8. Correct anser is second option
9.9. Correct answer is fourth option
10.10...
11.11. Records are arranged in order of predecence is cascading.
.
1- (TCO F) Which of the following is correct with respect to Internal.docx
1. (TCO F) Which of the following is correct with respect to Internal Service Funds? (Points : 5)
A. Net assets (fund equity) are to be reported in two categories: assigned and unassigned.
B. Â Â Internal service funds use accrual accounting and the economic resource measurement focus.
C.   Internal service funds account for long-term debt but not long-term fixed assets.
D. All of the above are false statements.
Question 2. 2. (TCO F) Government units use which fund type to account for services provided to the general public on a user-fee basis? (Points : 5)
A. General Fund
B. Enterprise Fund
C. Internal Service Fund
D. Permanent Fund
Solution
1. A. Net assets (fund equity) are to be reported in two categories: assigned and unassigned.
2. Internal service fund
.
1- (Learning Objective 2- Describe components of internal control) Lis.docx
1. (Learning Objective 2: Describe components of internal control) List the components of internal control. Briefly describe each component.
2. (Learning Objective 2: Explain the objectives of internal control) Explain why separation of duties is often described as the cornerstone of internal control for safeguarding assets. Describe what can happen if the same person has custody of an asset and also accounts for the asset.
3.(Learning Objective 1: Define fraud) Define
Solution
WHAT ARE THE COMPONENTS OF INTERNAL CONTROL?
Internal control consists of the following five interrelated components:
1. CONTROL ENVIRONMENT
Control environment is the attitude toward internal control and control consciousness established and maintained by the management and the employees of an organization. It is a product of management\'s philosophy, style and supportive attitude, as well as the competence, ethical values, integrity, and morale of the organization\'s people. The organization structure and accountability relationships are key factors in the control environment.
Elements of the Control Environment
- Ethical Values and Integrity
- Management
.
1)What are the advantages and disadvantages for MNEs to provide post-a.docx
1)What are the advantages and disadvantages for MNEs to provide post-assignment guarantees of employment to their expatriates?
2)How can MNEs recoup their investment in human capital through the process of knowledge and competence transfer upon expatriates
Solution
1)What are the advantages and disadvantages for MNEs to provide post-assignment guarantees of employment to their expatriates?
Advantages:-
1.Multinational Enterprises (MNEs) are continuously looking for the ideal \" globally astute expatriate. \"
2.Women as well as men are being sought out for these positions.
3.Maintaining contact with the expatriate throughout the assignment.
4.Ensuring expatriates are kept up to date with developments in the home country.
5.Ensuring expatriates are retained in existing management development programs
6.Assisting expatriates with the repatriation process, including helping them with a repatriation position
Disadvantages:-
1.MNEs usually pay local workers a lower salary rate.
2.No post-assignment guarantee of employment.
3.Period overseas causes loss of visibility.
4.Changes in the home workplace that affect re-entry positions and the employment relationship.
5.Coping with new role demands is another factor in readjustment, along with loss of status and pay.
2)How can MNEs recoup their investment in human capital through the process of knowledge and competence transfer upon expatriates
.
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