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1. Experiments show that the hydronium ion, H3O, is actually further hydrated so that the proton may have several water molecules associated with it. Why then do we use H3O\', and even more frequently H\', to represent the aqueous proton? Solution Actuall H + does not exist in aqueous solutions it is always exist as H 3 O + (aq) and this is correct way of representation. Further, hydronium ion is not a unique species and can pick up additional waters of hydration to form, for example H 5 O 2 + . So, while H 3 O + is more correct than writing H + , it is not prefectly correct. However, we will most often use H + , since more H 2 O is present, as compared with H + when we deal with weak acids for example HA is a weak acid and dissolved in water now we have HA (l) + H 2 O (l) <==> H 3 O + (aq) + A - (aq) dissociation constant K a = [H + ][A - ] / [HA] only H 3 O + (aq) <==> H + (aq) + H 2 O (l) Hope this helped you! Thank You So Much! Please Rate this answer as you wish.(\"Thumbs Up\") .
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![1. Experiments show that the hydronium ion, H3O, is actually further hydrated so that the proton
may have several water molecules associated with it. Why then do we use H3O', and even more
frequently H', to represent the aqueous proton?
Solution
Actuall H +
does not exist in aqueous solutions it is always exist as H 3 O +
(aq) and this is correct
way of representation. Further, hydronium ion is not a unique species and can pick up additional
waters of hydration to form, for example H 5 O 2
+
. So, while H 3 O +
is more correct than writing
H +
, it is not prefectly correct. However, we will most often use H +
, since more H 2 O is
present, as compared with H + when we deal with weak acids for example
HA is a weak acid and dissolved in water now we have
HA (l) + H 2 O (l) <==> H 3 O +
(aq) + A -
(aq)
dissociation constant K a = [H +
][A -
] / [HA] only
H 3 O +
(aq) <==> H +
(aq) + H 2 O (l)
Hope this helped you!
Thank You So Much! Please Rate this answer as you wish.("Thumbs Up")](https://image.slidesharecdn.com/1-experimentsshowthatthehydroniumion-h3o-isactuallyfurtherh-230131010801-c35ef578/85/1-Experiments-show-that-the-hydronium-ion-H3O-is-actually-further-h-docx-1-320.jpg)
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Self-centered : The person might be self-centered. She might have no interest of seeing other things apart from her duty.
Unaware of consequence : The person might have no knowledge of consequence of fraud. Fraud not only creates loss of wealth, but it is also the loss of net income on regular basis. She might be unaware of such loss.
Threat of life : The person might have belief that if the fraud is reported, her life would be in danger. In that case she will not report it.
Corruption all rounds : If everybody is corrupted, reporting would be useless. Therefore, she may be reluctant to do reporting.
Well-known coworker : If the coworker is well-known, the person might be manipulated not to disclose the fraud.
.
Herbie Corp-'s Balance Sheet showed the following at 12-31-13 Common S.docx
Herbie Corp\'s Balance Sheet showed the following at 12/31/13
Common Stock, $10 par $100,000
APIC $50,000
Retained Earnings $20,000
A cash dividend is declared on 12/31/13, and is payable on 1/20/14 to shareholders of record as of 1/10/14.
Show all appropriate journal entires assuming a cash dividend of $1 per share
Show all appropriate entries for a $5 per share dividend
Solution
1. Journal entry to record dividend of $1 per share. No. of shares is 10,000 ($100,000/$10)
31-12-2013 - Entry for dividend declaration will be recorded
Retained earnings (10,000X1) Debit 10,000
To Dividend payable Credit 10,000
20-1-2014, Entry to record dividend payment. There will be no entry on 10-1-2014 i.e. the record date. As record date merely determines the names of the stakeholders that will receive dividend.
Dividend payable Debit 10,000
To Cash Credit 10,000
2. Cash dividend of $5 per share. Retained earnings can be used for dividend payments. APIC cannot be used because the Company cannot declare dividends more than retained earnings. In this case, Retained earnings balance will be negative.
31-12-14
Retained earnings Debit 50,000
To Dividend payable Credit 50,000
20-1-14
Dividend payable Debit 50,000
To cash Credit 50,000
.
Here is a list of the main characters in Shakespeare-'s Romeo and Juli.docx
Here is a list of the main characters in Shakespeare\'s Romeo and Juliet. The first seven characters are male and the last four are female.
Escalus, prince of Verona
Paris, kinsman to the prince
Romeo, of Montague Household
Mercutio, friend of Romeo
Benvolio, friend of Romeo
Tybalt, nephew to Lady Capulet
Friar Lawrence, a Franciscan
Lady Montague, of Montague Household
Lady Capulet, of Capulet Household
Juliet, of Capulet Household
Juliet\'s Nurse
A total of 13 male and 7 female actors are available to play these roles. How many possible casts are there? (All roles are to be played by actors of the same gender as the character.)
I have worked this out multiple times and just can\'t get it right...please help. I would like the solution as well as how you came to it if possible.
Solution
We need to combine a choice of 7 out of 13 possible male actors with a choice of 4 out of 7 possible female actors.
13C7 * 7C4
= [13! / (7! 6!)] * [7! / (4! 4!)]
= [13*12*11*10*9*8 / (6*5*4*3*2*1)] * [7*6*5 / (4*3*2*1)]
= 1716 * 8.75
= 15015 possible casts.
.
1- How many ATOMS of sulfur are present in 2-25 moles of sulfur trioxi.docx
1. How many ATOMS of sulfur are present in 2.25 moles of sulfur trioxide ?
____ atoms of sulfur.
2. How many MOLES of oxygen are present in 1.01×1023 molecules of sulfur trioxide ?
___moles of oxygen.
Solution
Ans. #1. 1 mol SO 3 consists of 1 S-atoms.
So, moles of S in SO 3 = 2.25 mol
Now,
Number of S-atoms = Moles of S x N A
= 2.25 mol x (6.022 x 10 23 atoms/ mol)
= 1.355 x 10 24 atoms
#2. Moles of SO 3 = Number of SO 3 molecules / N A
= 1.01 x 10 23 molecule / (6.022 x 10 23 molecules / mol)
= 0.1677 mol
# 1 SO 3 molecule consists of 3 O-atoms.
So,
Moles of O = 3 x Moles of SO 3 = 3 x 0.1677 mol = 0.5032 mol
.
1- How does having a scope and WBS help project teams during project e.docx
1. How does having a scope and WBS help project teams during project execution? Why is it difficult to develop good plans? 2. Name the main planning tasks performed as part of project integration management? What are the main documents created, and what should they contain? 3. Identify the planning tasks performed as part of project time management. What is the critical path for a project? Why is it important to know which tasks are on the critical path? How would you gain support from the project sponsor on the tasks on the critical path? 4. During project cost management, what are the main planning tasks performed? Identify the difference between a cost estimate and a cost performance baseline. Why is it important to have clear ground rules and assumptions for a cost estimate?
Solution
1. How does having a scope and WBS help project teams during project execution? Why is it difficult to develop good plans?
The main purpose of project planning is to guide project execution. To guide execution, plans must be realistic and useful, so a fair amount of effort must go into the project planning process (Schwalbe, 2013).
Planning is often the most difficult and unappreciated process in project management because people often do not want to take the time to plan well, but theory and practice show that good planning is crucial to good execution (Schwalbe, 2013).
2. Name the main planning tasks performed as part of project integration management? What are the main documents created, and what should they contain?
Project integration management involves coordinating all the project management knowledge areas throughout a project
.
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