1. Alanine has molecular formula C3H7NO2Molecular weight = 3 x at.pdf
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1. Alanine has molecular formula: C3H7NO2 Molecular weight = 3 x atomic mass of C + 7 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 3 x 12.01 + 7 x 1.008 + 1 x 14.01 + 2 x 16.00 = 89.1 g/mol 2. Arginine has molecular formula: C6H14N4O2 Molecular weight = 6 x atomic mass of C + 14 x atomic mass of H + 4 x atomic mass of N + 2 x atomic mass of O = 6 x 12.01 + 14 x 1.008 + 4 x 14.01 + 2 x 16.00 = 174.2 g/mol 3. Phenylalanine has molecular formula: C9H11NO2 Molecular weight = 9 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 9 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 = 165.2 g/mol 4. Tryptophan has molecular formula: C11H12N2O2 Molecular weight = 11 x atomic mass of C + 12 x atomic mass of H + 2 x atomic mass of N + 2 x atomic mass of O = 11 x 12.01 + 12 x 1.008 + 2 x 14.01 + 2 x 16.00 = 204.2 g/mol 5. Methionine has molecular formula: C5H11NO2S Molecular weight = 5 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O + 1 x atomic mass of S = 5 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 + 1 x 32.07 = 149.2 g/mol Solution 1. Alanine has molecular formula: C3H7NO2 Molecular weight = 3 x atomic mass of C + 7 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 3 x 12.01 + 7 x 1.008 + 1 x 14.01 + 2 x 16.00 = 89.1 g/mol 2. Arginine has molecular formula: C6H14N4O2 Molecular weight = 6 x atomic mass of C + 14 x atomic mass of H + 4 x atomic mass of N + 2 x atomic mass of O = 6 x 12.01 + 14 x 1.008 + 4 x 14.01 + 2 x 16.00 = 174.2 g/mol 3. Phenylalanine has molecular formula: C9H11NO2 Molecular weight = 9 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 9 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 = 165.2 g/mol 4. Tryptophan has molecular formula: C11H12N2O2 Molecular weight = 11 x atomic mass of C + 12 x atomic mass of H + 2 x atomic mass of N + 2 x atomic mass of O = 11 x 12.01 + 12 x 1.008 + 2 x 14.01 + 2 x 16.00 = 204.2 g/mol 5. Methionine has molecular formula: C5H11NO2S Molecular weight = 5 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O + 1 x atomic mass of S = 5 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 + 1 x 32.07 = 149.2 g/mol.
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population in 2012 and coming to the broadband usage it was 2.5% in 2000 and as in 2012 it was
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Solution
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ever really catch on here in the US?
sol:
Broadband is a transmission technique with high capcaticy using wide range of frequency for
data transmission
and communication.it has an capability of sending multiple singnals through different medium
like optical fiber,coaxial fiber.
potential for broadband wireless systems:
1)wireless broadband network has potencial of data rates which is equal to wired networks
2)it supports both symmetric (it means same data rates in both the direction)and asymmetric
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Thousands of repeating units called nephrons will form a kidney and .pdf
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kidneys will be found in all vertebrate kidneys.
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The primitive form of vertebrate kidney (archinephros) was known to have a segmental series of
tubules which was restricted to the trunk region of their body and each tubule was found to be
opened medially into the mesomeral coelom and these will be joined the hypomeral coelom
using a short canal. Later on these tubules curved posteriorly so that they can be united into a
common duct called archinephric duct and it has opened in cloaca.
The bulging of spherical cluster of capillaries in the nephrocoel of each segment was seen, in
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During the course of evolution the nephrocoel lost its connect with that of hypomeral coelom and
slowly it became specialized as Bowman\'s capsule and like this bowman’s capsule was able to
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vertebrates the excretory organs are derived from mesoderm and vertebrates got unique
adaptation by having glomerulus which is water permeable capillaries and its suitability for free
water clearance gave them extra advantage for vertebrates for the evolution radiation in the
physiologically fresh water hostile environment.
Solution
Thousands of repeating units called nephrons will form a kidney and these organs are useful in
extracting the waste from blood and provides a balance in body fluids and same basic design of
kidneys will be found in all vertebrate kidneys.
It is believed that it is the fresh water teleost or bony fish which had the kidneys first as to tackle
the problem of living in water as their body fluid is of high osmotic concentration. These kidneys
helped them to prevent water from outside to inside and to prevent the solutes leaving the body.
The nephrons in these animals use to absorb the ions across the nephron tubules.
The primitive form of vertebrate kidney (archinephros) was known to have a segmental series of
tubules which was restricted to the trunk region of their body and each tubule was found to be
opened medially into the mesomeral coelom and these will be joined the hypomeral coelom
using a short canal. Later on these tubules curved posteriorly so tha.
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shifting during the developement of our current landmass positions. When they shift,the land can
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prey animals will thrive through a lack of predators, such as smaller fish.This enables the fishing
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more chemicals and sewage are added to a body of water , the fish have no choice but to take in
those hazardous wastes. At first, humans will grow sick of ill- prepared fish. Second,the fish will
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The P is the present value of the cash flow stream
P = 100 / (1+10%)^1 + 50 / (1+10%)^2 + 100 / (1+10%)^3
= 207.36
Solution
The P is the present value of the cash flow stream
P = 100 / (1+10%)^1 + 50 / (1+10%)^2 + 100 / (1+10%)^3
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Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and
RNA structures respectively. C3\' endo sugar pucker is exclusively seen. D Ribose structure
which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the
glycosidic linkage with the N 1 of the nitrogenous base.
14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the
diphosphopyridine molecules, which having significant function in the cell.
Functions of Mono nucleotides:
Other functions used in molecular research studies like :
Solution
Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and
RNA structures respectively. C3\' endo sugar pucker is exclusively seen. D Ribose structure
which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the
glycosidic linkage with the N 1 of the nitrogenous base.
14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the
diphosphopyridine molecules, which having significant function in the cell.
Functions of Mono nucleotides:
Other functions used in molecular research studies like :.
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Ques-1: Prenatal diagnosis has both positive and potentially negative consequences. While it is
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potentially to select embryos based on sex, appearance, Where do you think we should draw the
line in allowing parents to use prenatal diagnosis
Answer:
Genetic testing is performed for prenatal diagnosis to know any chromosomal or genetical -
inherited abnormalities of implanted human embryo. It has positive consequence, as some
couples would like to avoid getting a baby with genetic abnormalities. However, there are
negative consequences such as various \"ethical and moral issues of prenatal diagnosis as
explained below. Therefore, it is crucial to draw a line when conducting prenatal diagnosis
finally a couple musty get legal permissions to undergo prenatal diagnosis.
Screening tests for genetic issues can be performed in the first trimester, second trimester or both
trimesters. Carrier testing is also an option performed prior to or during pregnancy. Carrier
testing provides information as to whether one or both parents are carriers for certain inherited
disorders. The results of these tests are used to determine an appropriate plan of care for the
patient. Genetic testing of the fetus and the parents offers both opportunities and ethical
challenges. As a Registered Nurse, you need to be aware of your own feelings in order to provide
non-biased professional support.
Implications of genetic testing:
Genetic testing is the pre-implantation technology is now currently using in detecting and
screening embryo in order to assess whether the resultant embryos from fertilization are normal
or abnormal genotypically. A registered nurse must advice & support to a couple seeking
guidance about the genetic testing because genetic screening has various ethical and moral
aspects. The major rising ethical challenge is the connection between the pre-selection of
embryos based on meticulous genetic analysis followed by rising discrimination of disabled
people. This ethical problem is associated with selection of future children based on their low
levels of disabilities and abnormalities.
Ethical challenges with preimplantation of genetic testing or diagnosis (PGD):
1. PGD allows embryo selection after pregnancy or even before initiation of pregnancy.
However, this procedure is very controversial and faces a variety of moral ethics that are
completely relies upon moral status of embryo and prenatal diagnosis in selecting progeny
without the use of abortion (medical issue).
2. The major rising ethical challenge is the connection between the pre-selection of embryos
based on meticulous genetic analysis followed by rising discrimination of disabled people, a
psychological moral issue. This ethical problem is associated with selection of future children
based on their low levels of disabilities and abnormalities. A clinic should have license primarily
to perform preimplantatio.
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Question:
What are the elements of safe drinking water act? What are the aspect & provision for safe
drinking water act?
Solution
:
This act was passed in 2002. The main elements imposes in the act are providing the permissible
limit of contaminants in drinking water i.e. drinking water standard, establishes the rule for
operators of facilities, for drinking water systems, for laboratories that dealt with the drinking
water parameter testing, training & certification to operators & there are many other elements
that require for safe drinking purpose.
Its main aspect is to ensure the safety of consumers by drinking the potable water (the water
contain the contaminants up to prescribed limit given in the act. By consuming the potable water,
the diseases associated due to drinking of polluted water are minimized.
There are three parameters are described in the act. These are physical parameters, chemical
parameters, & biological parameters. Physical parameter includes suspended solid, turbidity,
dissolved solid, pH, hardness, acidity, alkanity etc. The chemical parameters include BOD,
COD, ThOD, DO, etc. The biological parameter includes E.coli, B.Coli bacteria, pathogenic
bacteria, disease causing bacteria. Amongst, three bacteria, it’s the biological parameters which
are very objectionable. The upper limit of this parameters are prescribed in the act upto which
the water are drinkable.
Note: All pollutant water are contaminants but its not necessary that all contaminant are
pollutant..
Programimport java.util.; import java.io.; class FoodTruck.pdf
Program:
import java.util.*;
import java.io.*;
class FoodTruck
{
String truckName;
double fuelintruck;
int numberofemplyees;
String menuItems[]=new String[5];
public void getData()
{
Scanner s=new Scanner(System.in);
System.out.print(\"Enter TruckName\");
truckName=s.next();
System.out.print(\"Enter Fuel in Tank \");
fuelintruck=s.nextDouble();
System.out.print(\"Enter number of employess in truck\");
numberofemplyees=s.nextInt();
System.out.print(\"Enter Menu Items\");
for(int i=0;i<5;i++)
menuItems[i]=s.next();
}
public void ckeckfuel()
{
if(fuelintruck<2.5)
System.out.println(\"Please refill your truck\");
else
System.out.println(\"Fuel is enough\");
}
public void displayMenu()
{
try
{
FileOutputStream fout=new FileOutputStream(\"Menu.txt\");
for(int i=0;i<5;i++)
{
byte b[]=menuItems[i].getBytes();
fout.write(b);
System.out.println(menuItems[i]);
}
}
catch(IOException e)
{
System.out.println(e.getMessage());
}
}
}
public class MyTruck1
{
public static void main(String ar[])
{
FoodTruck ft=new FoodTruck();
ft.getData();
ft.ckeckfuel();
ft.displayMenu();
}
}
Output:
Enter TruckNameFoodpanda
Enter Fuel in Tank 25.4
Enter number of employess in truck5
Enter Menu Itemssabji dal papad noodels paneer
Fuel is enough
sabji
dal
papad
noodels
paneer
Solution
Program:
import java.util.*;
import java.io.*;
class FoodTruck
{
String truckName;
double fuelintruck;
int numberofemplyees;
String menuItems[]=new String[5];
public void getData()
{
Scanner s=new Scanner(System.in);
System.out.print(\"Enter TruckName\");
truckName=s.next();
System.out.print(\"Enter Fuel in Tank \");
fuelintruck=s.nextDouble();
System.out.print(\"Enter number of employess in truck\");
numberofemplyees=s.nextInt();
System.out.print(\"Enter Menu Items\");
for(int i=0;i<5;i++)
menuItems[i]=s.next();
}
public void ckeckfuel()
{
if(fuelintruck<2.5)
System.out.println(\"Please refill your truck\");
else
System.out.println(\"Fuel is enough\");
}
public void displayMenu()
{
try
{
FileOutputStream fout=new FileOutputStream(\"Menu.txt\");
for(int i=0;i<5;i++)
{
byte b[]=menuItems[i].getBytes();
fout.write(b);
System.out.println(menuItems[i]);
}
}
catch(IOException e)
{
System.out.println(e.getMessage());
}
}
}
public class MyTruck1
{
public static void main(String ar[])
{
FoodTruck ft=new FoodTruck();
ft.getData();
ft.ckeckfuel();
ft.displayMenu();
}
}
Output:
Enter TruckNameFoodpanda
Enter Fuel in Tank 25.4
Enter number of employess in truck5
Enter Menu Itemssabji dal papad noodels paneer
Fuel is enough
sabji
dal
papad
noodels
paneer.
Please follow the data and description Active Directory In gen.pdf
Please follow the data and description :
Active Directory :
In general the Active Directory is abbrevated as AD and is a directory service that Microsoft
developed for Windows domain networks. It is included in most of the available Windows
Server operating systems as a set of processes and services.
Considerations for designing a Active Directory :
Before moving on directly to the planning ang implementation of the Active Directory we just
need to get some major factors and their considerations into account so as to handle them
perfectly. When we are designing the Active Directory network, it is important to use the four
divisions (forests, domains, organizational units, and sites) to their maximum potential. Some of
the important factors/considerations are described below :
a) Active Directory elements :
When designing an Active Directory, we need to be completely clear of what each element or
part actually means and how it fits into the overall design.
b) Active Directory forest :
In general, the forest, in terms of Active Directory, basically means every domain, organizational
unit, and any other object stored within its database. The forest is the absolute top level of the
Active Directory infrastructure. We can have more than one forest in a company, which actually
represent the high level security boundaries, and can therefore improve security between
different business units or companies belonging to a single organization. The point behind the
forest is that we have all our domains and domain tree within the organization itself contained
within it. It is designed so that we can have a transitive links between all of the trees within one
forest.
c) Active Directory tree :
A tree with reference to the Active Directory basically refers to a domain and all of its objects
that merge into a single DNS name.
d) Organizational Units and the Leaf Objects :
In an Active Directory, Organizational Units abbrevated as OUs, which are also called as the
Containers, and the Leaf Objects, which are of non-containing objects such as computer accounts
and user accounts, are directly related. We can access the OUs and other objects through the
Microsoft Management Console (MMC) or through the Users and Computers tool in the
Administrative Tools.
e) Active Directory Sites :
The Sites and Services of the MMC is a utility that a lot of Windows administrators, particularly
in smaller organizations, completely overlook. This part of Active Directory, however, is one of
the most crucial parts to understand and implement correctly. These Sites give us a very unique
and well-designed approach to separate specific locations within the Active Directory. As the
principle of an Active Directory domain is global-meaning that it is meant to be the same
anywhere-it could present a problem for users who move from office to office, or for offices with
network connections that are slow. Active Directory sites allow one to specify the IP address
spaces or subnets used with.
package DataStructures; public class HelloWorld AnyType extends.pdf
package DataStructures;
public class HelloWorld >
{
public HelloWorld( )
{
root = null;
}
public void insert( AnyType x )
{
root = insert( x, root );
}
public void remove( AnyType x )
{
root = remove( x, root );
}
public AnyType findMin( )
{
if( isEmpty( ) )
System.out.println(\"tree is empty\");
return findMin( root ).element;
}
public AnyType findMax( )
{
if( isEmpty( ) )
System.out.println(\"tree is empty\");
return findMax( root ).element;
}
public boolean contains( AnyType x )
{
return contains( x, root );
}
public void makeEmpty( )
{
root = null;
}
public boolean isEmpty( )
{
return root == null;
}
public void printTree( )
{
if( isEmpty( ) )
System.out.println( \"Empty tree\" );
else
printTree( root );
}
private BinaryNode insert( AnyType x, BinaryNode t )
{
if( t == null )
return new BinaryNode( x, null, null );
int compareResult = x.compareTo( t.element );
if( compareResult < 0 )
t.left = insert( x, t.left );
else if( compareResult > 0 )
t.right = insert( x, t.right );
else
; // Duplicate; do nothing
return t;
}
private BinaryNode remove( AnyType x, BinaryNode t )
{
if( t == null )
return t; // Item not found; do nothing
int compareResult = x.compareTo( t.element );
if( compareResult < 0 )
t.left = remove( x, t.left );
else if( compareResult > 0 )
t.right = remove( x, t.right );
else if( t.left != null && t.right != null ) // Two children
{
t.element = findMin( t.right ).element;
t.right = remove( t.element, t.right );
}
else
t = ( t.left != null ) ? t.left : t.right;
return t;
}
private BinaryNode findMin( BinaryNode t )
{
if( t == null )
return null;
else if( t.left == null )
return t;
return findMin( t.left );
}
private BinaryNode findMax( BinaryNode t )
{
if( t != null )
while( t.right != null )
t = t.right;
return t;
}
private boolean contains( AnyType x, BinaryNode t )
{
if( t == null )
return false;
int compareResult = x.compareTo( t.element );
if( compareResult < 0 )
return contains( x, t.left );
else if( compareResult > 0 )
return contains( x, t.right );
else
return true; // Match
}
private void printTree( BinaryNode t )
{
if( t != null )
{
printTree( t.left );
System.out.println( t.element );
printTree( t.right );
}
}
private int height( BinaryNode t )
{
if( t == null )
return -1;
else
return 1 + Math.max( height( t.left ), height( t.right ) );
}
// Basic node stored in unbalanced binary search trees
private static class BinaryNode
{
// Constructors
BinaryNode( AnyType theElement )
{
this( theElement, null, null );
}
BinaryNode( AnyType theElement, BinaryNode lt, BinaryNode rt )
{
element = theElement;
left = lt;
right = rt;
}
AnyType element; // The data in the node
BinaryNode left; // Left child
BinaryNode right; // Right child
}
/** The tree root. */
private BinaryNode root;
public static void main( String [ ] args )
{
HelloWorld t = new HelloWorld( );
final int NUMS = 4000;
final int GAP = 37;
System.out.println( \"Checking... (no more output means success)\" );
for( int i = GAP; i != 0; i = ( i + GAP ) % NUMS )
t.insert.
it always attacks oxygen.the image doesnot workSolutionit alwa.pdf
it always attacks oxygen.the image doesnot work
Solution
it always attacks oxygen.the image doesnot work.
import java.util.Scanner;public class Fraction { instan.pdf
The document defines a Fraction class with methods to represent fractions, multiply fractions, and reduce fractions to their lowest terms. It includes constructors to initialize fractions to default or custom values, getter and setter methods, and a main method that demonstrates creating and manipulating Fraction objects.
Hi,Please find the Ansswer below.PLAYLIST.h#include iostrea.pdf
Hi,
Please find the Ansswer below.
//PLAYLIST.h
#include
#include
#include
#include
using namespace std;
class Playlist
{
private:
string uniqueID;
string songName;
string artistName;
int songLength;
public:
Playlist() { uniqueID = \"\", songName = \"\", artistName = \"\", songLength = 0; };
Playlist(string auniqueId, string asongName, string aArtistName, int aSongLength);
void InsertAfter();
void SetNext();
string GetID();
string GetSongName();
string GetArtistName();
int GetSongLength();
string GetNext();
void PrintPlaylistNode();
};
//PLAYLIST.CPP
#include \"Playlist.h\"
Playlist::Playlist(string auniqueId, string asongName, string aArtistName, int aSongLength)
{
uniqueID = auniqueId;
songName = asongName;
artistName = aArtistName;
songLength = aSongLength;
}
string Playlist::GetArtistName()
{
return artistName;
}
string Playlist::GetID()
{
return uniqueID;
}
string Playlist::GetSongName()
{
return songName;
}
int Playlist::GetSongLength()
{
return songLength;
}
void Playlist::SetNext()
{
}
string Playlist::GetNext()
{
return \"\";
}
void Playlist::InsertAfter() {
}
void Playlist::PrintPlaylistNode()
{
cout << \"Unique ID:\" << uniqueID << endl ;
cout << \"Song Name:\" << songName << endl;
cout << \"Artist Name:\" << artistName << endl;
cout << \"Song Length (in seconds):\" << songLength << endl;
}
//PLAYSLITSNODE.h
#pragma once
#include \"Playlist.h\"
#include
class PlaylistNode
{
private:
std::list library;
Playlist get(list _list, int _i);
void PrintPlaylist(Playlist aPlayList);
public:
void Addsong(Playlist aPlayslist);
void Removesong(string aUnwiid);
void Changeposition(int oldPostion, int anewPostion);
void PrintSongByartist(string aAstist);
void PrintSongtotalLen();
void PrintFullPlayList();
};
//PLAYLIST.CPP
#include \"PlaylistNode.h\"
void PlaylistNode::Addsong(Playlist aPlaylist)
{
library.push_back(aPlaylist);
}
void PlaylistNode::Removesong(string aUnwiid)
{
if (library.size > 0)
{
for (it = library.begin(); it != library.end(); ++it)
{
if (it->GetID() == aUnwiid)
{
cout << it->GetSongName() << endl;
library.remove(*it);
break;
}
}
}
}
Playlist PlaylistNode::get(list _list, int _i) {
list::iterator it = _list.begin();
for (int i = 0; i<_i; i++) {
++it;
}
return *it;
}
std::list::iterator it;
void PlaylistNode::PrintFullPlayList()
{
for (it = library.begin(); it != library.end(); ++it)
{
PrintPlaylist(*it);
}
}
void PlaylistNode::PrintSongByartist(string aartiename)
{
for (it = library.begin(); it != library.end(); ++it)
{
if(it->GetArtistName() == aartiename)
PrintPlaylist(*it);
}
}
void PlaylistNode::PrintSongtotalLen()
{
int TotalSonglengst = 0;
for (it = library.begin(); it != library.end(); ++it)
{
TotalSonglengst += it->GetSongLength();
}
cout << \"Total songs Length (in seconds):\" << TotalSonglengst << endl;
}
void PlaylistNode::PrintPlaylist(Playlist aPlayList)
{
cout << \"Unique ID:\" << aPlayList.GetID() << endl;
cout << \"Song Name:\" << aPlayList.GetSongName() << endl;
cout << \"Artist Name:\" << aPlayList.GetArtis.
Family as a Social Institution A family can be defined as group of .pdf
Family as a Social Institution: A family can be defined as group of two or more people living in
a household and connected to each other by blood or adoption or marriage. Family as social
constitution serves to create and maintain the family life in correct ways which are considered
good by a society. It is not an objective institution as it serves to give shape to feeling and
emotions of family memberns in fundamental ways.
Predominance of nuclear families: Smaller sized nuclear families indulge individualism in its
members. These small families are supported by increasingly reducing sized homes and are
easier to relocate. Further, small sized nuclear families can support the expensive education,
medication and other services to their children in a much better way as compared to the large
sized joint families.
Existence and characteristics of family structures: Some of the common family structures with
their characteristic features are as follows:
1: Nuclear family: The family with two generations i.e. parents and their children
2: Extended family: The family with three generations i.e. grandparents, parents and their
children constitutes an extended family.
3: Single parent family: The family in which one parent and children are residing in same
household is called as single parent family.
4: Reconstituted family: The family in which either or both of the parents have children from
their previous marriage living together are called as reconstituted family.
Characters of a family: A family is established by mating relation between man and woman
through marriage institution. Marriage is foundation of family irrespetive of mating relationship
without marriage. A family always resides in a common household wherein each family member
has his own name. Hence, marriage, common household, nomenclature of family members,
mode of interaction and communication and an economic provision are some of the
characteristics of a family.
Solution
Family as a Social Institution: A family can be defined as group of two or more people living in
a household and connected to each other by blood or adoption or marriage. Family as social
constitution serves to create and maintain the family life in correct ways which are considered
good by a society. It is not an objective institution as it serves to give shape to feeling and
emotions of family memberns in fundamental ways.
Predominance of nuclear families: Smaller sized nuclear families indulge individualism in its
members. These small families are supported by increasingly reducing sized homes and are
easier to relocate. Further, small sized nuclear families can support the expensive education,
medication and other services to their children in a much better way as compared to the large
sized joint families.
Existence and characteristics of family structures: Some of the common family structures with
their characteristic features are as follows:
1: Nuclear family: The family with two generations i.e. parents and t.
D. The actual development of new standards and protocols for the Int.pdf
D. The actual development of new standards and protocols for the Internet is carried out by
working groups chartered by the IETF. Answers A, B, and C are incorrect.
Solution
D. The actual development of new standards and protocols for the Internet is carried out by
working groups chartered by the IETF. Answers A, B, and C are incorrect..
Dependent Variable. A variable that depends on one or more other var.pdf
Dependent Variable. A variable that depends on one or more other variables The dependent
variable responds to the independent variable. It is called dependent because it \"depends\" on
the independent variable. So Answer Is D
Solution
Dependent Variable. A variable that depends on one or more other variables The dependent
variable responds to the independent variable. It is called dependent because it \"depends\" on
the independent variable. So Answer Is D.
C is correct. While all Layer 2 devices split collision domains, swi.pdf
C is correct. While all Layer 2 devices split collision domains, switches create a separate
collision domain for each port.
A, B, and D are incorrect. A is incorrect because hubs are Layer 1 devices and extend collision
domains. B is incorrect because a bridge is a Layer 2 device, but can split the network only into
two collision domains. D is incorrect.
Solution
C is correct. While all Layer 2 devices split collision domains, switches create a separate
collision domain for each port.
A, B, and D are incorrect. A is incorrect because hubs are Layer 1 devices and extend collision
domains. B is incorrect because a bridge is a Layer 2 device, but can split the network only into
two collision domains. D is incorrect..
Answer.The following organisms are present in pod.1. Prokaryotes.pdf
Answer.
The following organisms are present in pod.
1. Prokaryotes, eg. Bacteria
2. Eukaryotes
a. Algae (plants)
b. Protozoans
3. Protists (unicellular eukaryotes)
Solution
Answer.
The following organisms are present in pod.
1. Prokaryotes, eg. Bacteria
2. Eukaryotes
a. Algae (plants)
b. Protozoans
3. Protists (unicellular eukaryotes).
AnswerThe mobile elements are the elerments move form one place t.pdf
Answer:
The mobile elements are the elerments move form one place to other place, where the particular
element is deficient.
The deficiency of mobile elements first appear in older leave whereas the deficency of the
immobile elements first appear in the younger leaves
The immobile elements are iron, calcium, manganese, zinc, copper and boron
Solution
Answer:
The mobile elements are the elerments move form one place to other place, where the particular
element is deficient.
The deficiency of mobile elements first appear in older leave whereas the deficency of the
immobile elements first appear in the younger leaves
The immobile elements are iron, calcium, manganese, zinc, copper and boron.
Answer- high PCO2Explanation- CO2 combines with water to produce c.pdf
Answer- high PCO2
Explanation- CO2 combines with water to produce carbonic acid. The release of hydrogen ions
by carbonic acid auses a drop in pH.
Solution
Answer- high PCO2
Explanation- CO2 combines with water to produce carbonic acid. The release of hydrogen ions
by carbonic acid auses a drop in pH..
Ans CThese are like private addresses in IPv4b in that they are n.pdf
Ans: C
These are like private addresses in IPv4b in that they are not meant to be routed
Solution
Ans: C
These are like private addresses in IPv4b in that they are not meant to be routed.
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS Template 2023-2024 by: Irene S. Rueco
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Thousands of repeating units called nephrons will form a kidney and .pdf
Thousands of repeating units called nephrons will form a kidney and these organs are useful in
extracting the waste from blood and provides a balance in body fluids and same basic design of
kidneys will be found in all vertebrate kidneys.
It is believed that it is the fresh water teleost or bony fish which had the kidneys first as to tackle
the problem of living in water as their body fluid is of high osmotic concentration. These kidneys
helped them to prevent water from outside to inside and to prevent the solutes leaving the body.
The nephrons in these animals use to absorb the ions across the nephron tubules.
The primitive form of vertebrate kidney (archinephros) was known to have a segmental series of
tubules which was restricted to the trunk region of their body and each tubule was found to be
opened medially into the mesomeral coelom and these will be joined the hypomeral coelom
using a short canal. Later on these tubules curved posteriorly so that they can be united into a
common duct called archinephric duct and it has opened in cloaca.
The bulging of spherical cluster of capillaries in the nephrocoel of each segment was seen, in
later stages the glomerulus, nephrocoel and tubule will joined together to from a functional unit
known as archinephron-this is known as primitive vertebrate kidney.
During the course of evolution the nephrocoel lost its connect with that of hypomeral coelom and
slowly it became specialized as Bowman\'s capsule and like this bowman’s capsule was able to
form a union between glomerulus and renal tubule-it formed a functional unit called nephron.
Malpighian body was formed by the combination of glomerulus and Bowman\'s capsule and in
vertebrates the excretory organs are derived from mesoderm and vertebrates got unique
adaptation by having glomerulus which is water permeable capillaries and its suitability for free
water clearance gave them extra advantage for vertebrates for the evolution radiation in the
physiologically fresh water hostile environment.
Solution
Thousands of repeating units called nephrons will form a kidney and these organs are useful in
extracting the waste from blood and provides a balance in body fluids and same basic design of
kidneys will be found in all vertebrate kidneys.
It is believed that it is the fresh water teleost or bony fish which had the kidneys first as to tackle
the problem of living in water as their body fluid is of high osmotic concentration. These kidneys
helped them to prevent water from outside to inside and to prevent the solutes leaving the body.
The nephrons in these animals use to absorb the ions across the nephron tubules.
The primitive form of vertebrate kidney (archinephros) was known to have a segmental series of
tubules which was restricted to the trunk region of their body and each tubule was found to be
opened medially into the mesomeral coelom and these will be joined the hypomeral coelom
using a short canal. Later on these tubules curved posteriorly so tha.
To understand the complexicities of the issue at hand we must first .pdf
To understand the complexicities of the issue at hand we must first look at what cause inland
seas. According to the geographic descrptions,it was more than likely a result of tectonic plates
shifting during the developement of our current landmass positions. When they shift,the land can
either sinkor have its ocean basins fill with water from flooding.This is called
Transgression.Either case causes a developement of a salty body of water with aquatic animals
trapped inside.Being that is surrounded by a desert-like biome,itis more likely to be the result of
the tectonic plates spreading, causing the land to sink and fill in with salt water.As this occurs,
prey animals will thrive through a lack of predators, such as smaller fish.This enables the fishing
industry to boom as it did. The fishing trade in this area is at risk of falling.when humans alter
systems such as this one,their stabilty declines.For a while this was more than likely a self-
sustaining environment.The implementation of irrigation systemshave first,affected the wildlife
surrounding the inland sea, which was assisting its survival. Every animal plays a role in the
ecosystem.When the industries were built around the body of water, the land ecosystem
suffered.As a result, the fish in the corresponding water will eventually suffer.Being a self-
sustaining system, it will keep water cycling by itself. When the system was built for local
farmers, water supplies were being pulled from the natural made sea and into other locations. this
is normally fine for areas,but in one such as this,without any natural made filtering system, it will
begin losing water. the process will takea while due to the water cycle consistently adding some
back,but will occur. As the water levels decrease,so will the fish.This is the cause of research
number two. With an increasing salinity count,the pHof the water and soil will change as well.
Adding salt to the soil as it is doing through wind patterns, slowly crops, which once thrived in
the surrounding land,will begin todeplete.Not all plants require the same nutrient levels..If the
farmer \'s crops are thriving now, with lower salinity counts and lower pH\'s then the same crops
will not grow as well in higher salt concentrations and higher pH\'values .Another factor
affecting local farmers as well as the fishermen is the pesticides and chemicals.These will not
only affect the water\'s pH ,it will also affect the stability of the water for the fish to live in.As
more chemicals and sewage are added to a body of water , the fish have no choice but to take in
those hazardous wastes. At first, humans will grow sick of ill- prepared fish. Second,the fish will
slowly begin to die off causing the fishermen to lose a source of income. The future of this
environment is devasting. Local animals , which do use the sea as a source of food ,will
inadvertently be affected as well . While these animals may be capable of migrating , they cannot
move far into a desert w.
The P is the present value of the cash flow streamP = 100 (1+10.pdf
The P is the present value of the cash flow stream
P = 100 / (1+10%)^1 + 50 / (1+10%)^2 + 100 / (1+10%)^3
= 207.36
Solution
The P is the present value of the cash flow stream
P = 100 / (1+10%)^1 + 50 / (1+10%)^2 + 100 / (1+10%)^3
= 207.36.
Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleo.pdf
Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and
RNA structures respectively. C3\' endo sugar pucker is exclusively seen. D Ribose structure
which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the
glycosidic linkage with the N 1 of the nitrogenous base.
14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the
diphosphopyridine molecules, which having significant function in the cell.
Functions of Mono nucleotides:
Other functions used in molecular research studies like :
Solution
Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and
RNA structures respectively. C3\' endo sugar pucker is exclusively seen. D Ribose structure
which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the
glycosidic linkage with the N 1 of the nitrogenous base.
14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the
diphosphopyridine molecules, which having significant function in the cell.
Functions of Mono nucleotides:
Other functions used in molecular research studies like :.
Ques-1 Prenatal diagnosis has both positive and potentially negativ.pdf
Ques-1: Prenatal diagnosis has both positive and potentially negative consequences. While it is
most often used to detect serious problems with the fetus, the technology can also be used
potentially to select embryos based on sex, appearance, Where do you think we should draw the
line in allowing parents to use prenatal diagnosis
Answer:
Genetic testing is performed for prenatal diagnosis to know any chromosomal or genetical -
inherited abnormalities of implanted human embryo. It has positive consequence, as some
couples would like to avoid getting a baby with genetic abnormalities. However, there are
negative consequences such as various \"ethical and moral issues of prenatal diagnosis as
explained below. Therefore, it is crucial to draw a line when conducting prenatal diagnosis
finally a couple musty get legal permissions to undergo prenatal diagnosis.
Screening tests for genetic issues can be performed in the first trimester, second trimester or both
trimesters. Carrier testing is also an option performed prior to or during pregnancy. Carrier
testing provides information as to whether one or both parents are carriers for certain inherited
disorders. The results of these tests are used to determine an appropriate plan of care for the
patient. Genetic testing of the fetus and the parents offers both opportunities and ethical
challenges. As a Registered Nurse, you need to be aware of your own feelings in order to provide
non-biased professional support.
Implications of genetic testing:
Genetic testing is the pre-implantation technology is now currently using in detecting and
screening embryo in order to assess whether the resultant embryos from fertilization are normal
or abnormal genotypically. A registered nurse must advice & support to a couple seeking
guidance about the genetic testing because genetic screening has various ethical and moral
aspects. The major rising ethical challenge is the connection between the pre-selection of
embryos based on meticulous genetic analysis followed by rising discrimination of disabled
people. This ethical problem is associated with selection of future children based on their low
levels of disabilities and abnormalities.
Ethical challenges with preimplantation of genetic testing or diagnosis (PGD):
1. PGD allows embryo selection after pregnancy or even before initiation of pregnancy.
However, this procedure is very controversial and faces a variety of moral ethics that are
completely relies upon moral status of embryo and prenatal diagnosis in selecting progeny
without the use of abortion (medical issue).
2. The major rising ethical challenge is the connection between the pre-selection of embryos
based on meticulous genetic analysis followed by rising discrimination of disabled people, a
psychological moral issue. This ethical problem is associated with selection of future children
based on their low levels of disabilities and abnormalities. A clinic should have license primarily
to perform preimplantatio.
QuestionWhat are the elements of safe drinking water act What ar.pdf
Question:
What are the elements of safe drinking water act? What are the aspect & provision for safe
drinking water act?
Solution
:
This act was passed in 2002. The main elements imposes in the act are providing the permissible
limit of contaminants in drinking water i.e. drinking water standard, establishes the rule for
operators of facilities, for drinking water systems, for laboratories that dealt with the drinking
water parameter testing, training & certification to operators & there are many other elements
that require for safe drinking purpose.
Its main aspect is to ensure the safety of consumers by drinking the potable water (the water
contain the contaminants up to prescribed limit given in the act. By consuming the potable water,
the diseases associated due to drinking of polluted water are minimized.
There are three parameters are described in the act. These are physical parameters, chemical
parameters, & biological parameters. Physical parameter includes suspended solid, turbidity,
dissolved solid, pH, hardness, acidity, alkanity etc. The chemical parameters include BOD,
COD, ThOD, DO, etc. The biological parameter includes E.coli, B.Coli bacteria, pathogenic
bacteria, disease causing bacteria. Amongst, three bacteria, it’s the biological parameters which
are very objectionable. The upper limit of this parameters are prescribed in the act upto which
the water are drinkable.
Note: All pollutant water are contaminants but its not necessary that all contaminant are
pollutant..
Programimport java.util.; import java.io.; class FoodTruck.pdf
Program:
import java.util.*;
import java.io.*;
class FoodTruck
{
String truckName;
double fuelintruck;
int numberofemplyees;
String menuItems[]=new String[5];
public void getData()
{
Scanner s=new Scanner(System.in);
System.out.print(\"Enter TruckName\");
truckName=s.next();
System.out.print(\"Enter Fuel in Tank \");
fuelintruck=s.nextDouble();
System.out.print(\"Enter number of employess in truck\");
numberofemplyees=s.nextInt();
System.out.print(\"Enter Menu Items\");
for(int i=0;i<5;i++)
menuItems[i]=s.next();
}
public void ckeckfuel()
{
if(fuelintruck<2.5)
System.out.println(\"Please refill your truck\");
else
System.out.println(\"Fuel is enough\");
}
public void displayMenu()
{
try
{
FileOutputStream fout=new FileOutputStream(\"Menu.txt\");
for(int i=0;i<5;i++)
{
byte b[]=menuItems[i].getBytes();
fout.write(b);
System.out.println(menuItems[i]);
}
}
catch(IOException e)
{
System.out.println(e.getMessage());
}
}
}
public class MyTruck1
{
public static void main(String ar[])
{
FoodTruck ft=new FoodTruck();
ft.getData();
ft.ckeckfuel();
ft.displayMenu();
}
}
Output:
Enter TruckNameFoodpanda
Enter Fuel in Tank 25.4
Enter number of employess in truck5
Enter Menu Itemssabji dal papad noodels paneer
Fuel is enough
sabji
dal
papad
noodels
paneer
Solution
Program:
import java.util.*;
import java.io.*;
class FoodTruck
{
String truckName;
double fuelintruck;
int numberofemplyees;
String menuItems[]=new String[5];
public void getData()
{
Scanner s=new Scanner(System.in);
System.out.print(\"Enter TruckName\");
truckName=s.next();
System.out.print(\"Enter Fuel in Tank \");
fuelintruck=s.nextDouble();
System.out.print(\"Enter number of employess in truck\");
numberofemplyees=s.nextInt();
System.out.print(\"Enter Menu Items\");
for(int i=0;i<5;i++)
menuItems[i]=s.next();
}
public void ckeckfuel()
{
if(fuelintruck<2.5)
System.out.println(\"Please refill your truck\");
else
System.out.println(\"Fuel is enough\");
}
public void displayMenu()
{
try
{
FileOutputStream fout=new FileOutputStream(\"Menu.txt\");
for(int i=0;i<5;i++)
{
byte b[]=menuItems[i].getBytes();
fout.write(b);
System.out.println(menuItems[i]);
}
}
catch(IOException e)
{
System.out.println(e.getMessage());
}
}
}
public class MyTruck1
{
public static void main(String ar[])
{
FoodTruck ft=new FoodTruck();
ft.getData();
ft.ckeckfuel();
ft.displayMenu();
}
}
Output:
Enter TruckNameFoodpanda
Enter Fuel in Tank 25.4
Enter number of employess in truck5
Enter Menu Itemssabji dal papad noodels paneer
Fuel is enough
sabji
dal
papad
noodels
paneer.
Please follow the data and description Active Directory In gen.pdf
Please follow the data and description :
Active Directory :
In general the Active Directory is abbrevated as AD and is a directory service that Microsoft
developed for Windows domain networks. It is included in most of the available Windows
Server operating systems as a set of processes and services.
Considerations for designing a Active Directory :
Before moving on directly to the planning ang implementation of the Active Directory we just
need to get some major factors and their considerations into account so as to handle them
perfectly. When we are designing the Active Directory network, it is important to use the four
divisions (forests, domains, organizational units, and sites) to their maximum potential. Some of
the important factors/considerations are described below :
a) Active Directory elements :
When designing an Active Directory, we need to be completely clear of what each element or
part actually means and how it fits into the overall design.
b) Active Directory forest :
In general, the forest, in terms of Active Directory, basically means every domain, organizational
unit, and any other object stored within its database. The forest is the absolute top level of the
Active Directory infrastructure. We can have more than one forest in a company, which actually
represent the high level security boundaries, and can therefore improve security between
different business units or companies belonging to a single organization. The point behind the
forest is that we have all our domains and domain tree within the organization itself contained
within it. It is designed so that we can have a transitive links between all of the trees within one
forest.
c) Active Directory tree :
A tree with reference to the Active Directory basically refers to a domain and all of its objects
that merge into a single DNS name.
d) Organizational Units and the Leaf Objects :
In an Active Directory, Organizational Units abbrevated as OUs, which are also called as the
Containers, and the Leaf Objects, which are of non-containing objects such as computer accounts
and user accounts, are directly related. We can access the OUs and other objects through the
Microsoft Management Console (MMC) or through the Users and Computers tool in the
Administrative Tools.
e) Active Directory Sites :
The Sites and Services of the MMC is a utility that a lot of Windows administrators, particularly
in smaller organizations, completely overlook. This part of Active Directory, however, is one of
the most crucial parts to understand and implement correctly. These Sites give us a very unique
and well-designed approach to separate specific locations within the Active Directory. As the
principle of an Active Directory domain is global-meaning that it is meant to be the same
anywhere-it could present a problem for users who move from office to office, or for offices with
network connections that are slow. Active Directory sites allow one to specify the IP address
spaces or subnets used with.
package DataStructures; public class HelloWorld AnyType extends.pdf
package DataStructures;
public class HelloWorld >
{
public HelloWorld( )
{
root = null;
}
public void insert( AnyType x )
{
root = insert( x, root );
}
public void remove( AnyType x )
{
root = remove( x, root );
}
public AnyType findMin( )
{
if( isEmpty( ) )
System.out.println(\"tree is empty\");
return findMin( root ).element;
}
public AnyType findMax( )
{
if( isEmpty( ) )
System.out.println(\"tree is empty\");
return findMax( root ).element;
}
public boolean contains( AnyType x )
{
return contains( x, root );
}
public void makeEmpty( )
{
root = null;
}
public boolean isEmpty( )
{
return root == null;
}
public void printTree( )
{
if( isEmpty( ) )
System.out.println( \"Empty tree\" );
else
printTree( root );
}
private BinaryNode insert( AnyType x, BinaryNode t )
{
if( t == null )
return new BinaryNode( x, null, null );
int compareResult = x.compareTo( t.element );
if( compareResult < 0 )
t.left = insert( x, t.left );
else if( compareResult > 0 )
t.right = insert( x, t.right );
else
; // Duplicate; do nothing
return t;
}
private BinaryNode remove( AnyType x, BinaryNode t )
{
if( t == null )
return t; // Item not found; do nothing
int compareResult = x.compareTo( t.element );
if( compareResult < 0 )
t.left = remove( x, t.left );
else if( compareResult > 0 )
t.right = remove( x, t.right );
else if( t.left != null && t.right != null ) // Two children
{
t.element = findMin( t.right ).element;
t.right = remove( t.element, t.right );
}
else
t = ( t.left != null ) ? t.left : t.right;
return t;
}
private BinaryNode findMin( BinaryNode t )
{
if( t == null )
return null;
else if( t.left == null )
return t;
return findMin( t.left );
}
private BinaryNode findMax( BinaryNode t )
{
if( t != null )
while( t.right != null )
t = t.right;
return t;
}
private boolean contains( AnyType x, BinaryNode t )
{
if( t == null )
return false;
int compareResult = x.compareTo( t.element );
if( compareResult < 0 )
return contains( x, t.left );
else if( compareResult > 0 )
return contains( x, t.right );
else
return true; // Match
}
private void printTree( BinaryNode t )
{
if( t != null )
{
printTree( t.left );
System.out.println( t.element );
printTree( t.right );
}
}
private int height( BinaryNode t )
{
if( t == null )
return -1;
else
return 1 + Math.max( height( t.left ), height( t.right ) );
}
// Basic node stored in unbalanced binary search trees
private static class BinaryNode
{
// Constructors
BinaryNode( AnyType theElement )
{
this( theElement, null, null );
}
BinaryNode( AnyType theElement, BinaryNode lt, BinaryNode rt )
{
element = theElement;
left = lt;
right = rt;
}
AnyType element; // The data in the node
BinaryNode left; // Left child
BinaryNode right; // Right child
}
/** The tree root. */
private BinaryNode root;
public static void main( String [ ] args )
{
HelloWorld t = new HelloWorld( );
final int NUMS = 4000;
final int GAP = 37;
System.out.println( \"Checking... (no more output means success)\" );
for( int i = GAP; i != 0; i = ( i + GAP ) % NUMS )
t.insert.
it always attacks oxygen.the image doesnot workSolutionit alwa.pdf
it always attacks oxygen.the image doesnot work
Solution
it always attacks oxygen.the image doesnot work.
import java.util.Scanner;public class Fraction { instan.pdf
The document defines a Fraction class with methods to represent fractions, multiply fractions, and reduce fractions to their lowest terms. It includes constructors to initialize fractions to default or custom values, getter and setter methods, and a main method that demonstrates creating and manipulating Fraction objects.
Hi,Please find the Ansswer below.PLAYLIST.h#include iostrea.pdf
Hi,
Please find the Ansswer below.
//PLAYLIST.h
#include
#include
#include
#include
using namespace std;
class Playlist
{
private:
string uniqueID;
string songName;
string artistName;
int songLength;
public:
Playlist() { uniqueID = \"\", songName = \"\", artistName = \"\", songLength = 0; };
Playlist(string auniqueId, string asongName, string aArtistName, int aSongLength);
void InsertAfter();
void SetNext();
string GetID();
string GetSongName();
string GetArtistName();
int GetSongLength();
string GetNext();
void PrintPlaylistNode();
};
//PLAYLIST.CPP
#include \"Playlist.h\"
Playlist::Playlist(string auniqueId, string asongName, string aArtistName, int aSongLength)
{
uniqueID = auniqueId;
songName = asongName;
artistName = aArtistName;
songLength = aSongLength;
}
string Playlist::GetArtistName()
{
return artistName;
}
string Playlist::GetID()
{
return uniqueID;
}
string Playlist::GetSongName()
{
return songName;
}
int Playlist::GetSongLength()
{
return songLength;
}
void Playlist::SetNext()
{
}
string Playlist::GetNext()
{
return \"\";
}
void Playlist::InsertAfter() {
}
void Playlist::PrintPlaylistNode()
{
cout << \"Unique ID:\" << uniqueID << endl ;
cout << \"Song Name:\" << songName << endl;
cout << \"Artist Name:\" << artistName << endl;
cout << \"Song Length (in seconds):\" << songLength << endl;
}
//PLAYSLITSNODE.h
#pragma once
#include \"Playlist.h\"
#include
class PlaylistNode
{
private:
std::list library;
Playlist get(list _list, int _i);
void PrintPlaylist(Playlist aPlayList);
public:
void Addsong(Playlist aPlayslist);
void Removesong(string aUnwiid);
void Changeposition(int oldPostion, int anewPostion);
void PrintSongByartist(string aAstist);
void PrintSongtotalLen();
void PrintFullPlayList();
};
//PLAYLIST.CPP
#include \"PlaylistNode.h\"
void PlaylistNode::Addsong(Playlist aPlaylist)
{
library.push_back(aPlaylist);
}
void PlaylistNode::Removesong(string aUnwiid)
{
if (library.size > 0)
{
for (it = library.begin(); it != library.end(); ++it)
{
if (it->GetID() == aUnwiid)
{
cout << it->GetSongName() << endl;
library.remove(*it);
break;
}
}
}
}
Playlist PlaylistNode::get(list _list, int _i) {
list::iterator it = _list.begin();
for (int i = 0; i<_i; i++) {
++it;
}
return *it;
}
std::list::iterator it;
void PlaylistNode::PrintFullPlayList()
{
for (it = library.begin(); it != library.end(); ++it)
{
PrintPlaylist(*it);
}
}
void PlaylistNode::PrintSongByartist(string aartiename)
{
for (it = library.begin(); it != library.end(); ++it)
{
if(it->GetArtistName() == aartiename)
PrintPlaylist(*it);
}
}
void PlaylistNode::PrintSongtotalLen()
{
int TotalSonglengst = 0;
for (it = library.begin(); it != library.end(); ++it)
{
TotalSonglengst += it->GetSongLength();
}
cout << \"Total songs Length (in seconds):\" << TotalSonglengst << endl;
}
void PlaylistNode::PrintPlaylist(Playlist aPlayList)
{
cout << \"Unique ID:\" << aPlayList.GetID() << endl;
cout << \"Song Name:\" << aPlayList.GetSongName() << endl;
cout << \"Artist Name:\" << aPlayList.GetArtis.
Family as a Social Institution A family can be defined as group of .pdf
Family as a Social Institution: A family can be defined as group of two or more people living in
a household and connected to each other by blood or adoption or marriage. Family as social
constitution serves to create and maintain the family life in correct ways which are considered
good by a society. It is not an objective institution as it serves to give shape to feeling and
emotions of family memberns in fundamental ways.
Predominance of nuclear families: Smaller sized nuclear families indulge individualism in its
members. These small families are supported by increasingly reducing sized homes and are
easier to relocate. Further, small sized nuclear families can support the expensive education,
medication and other services to their children in a much better way as compared to the large
sized joint families.
Existence and characteristics of family structures: Some of the common family structures with
their characteristic features are as follows:
1: Nuclear family: The family with two generations i.e. parents and their children
2: Extended family: The family with three generations i.e. grandparents, parents and their
children constitutes an extended family.
3: Single parent family: The family in which one parent and children are residing in same
household is called as single parent family.
4: Reconstituted family: The family in which either or both of the parents have children from
their previous marriage living together are called as reconstituted family.
Characters of a family: A family is established by mating relation between man and woman
through marriage institution. Marriage is foundation of family irrespetive of mating relationship
without marriage. A family always resides in a common household wherein each family member
has his own name. Hence, marriage, common household, nomenclature of family members,
mode of interaction and communication and an economic provision are some of the
characteristics of a family.
Solution
Family as a Social Institution: A family can be defined as group of two or more people living in
a household and connected to each other by blood or adoption or marriage. Family as social
constitution serves to create and maintain the family life in correct ways which are considered
good by a society. It is not an objective institution as it serves to give shape to feeling and
emotions of family memberns in fundamental ways.
Predominance of nuclear families: Smaller sized nuclear families indulge individualism in its
members. These small families are supported by increasingly reducing sized homes and are
easier to relocate. Further, small sized nuclear families can support the expensive education,
medication and other services to their children in a much better way as compared to the large
sized joint families.
Existence and characteristics of family structures: Some of the common family structures with
their characteristic features are as follows:
1: Nuclear family: The family with two generations i.e. parents and t.
D. The actual development of new standards and protocols for the Int.pdf
D. The actual development of new standards and protocols for the Internet is carried out by
working groups chartered by the IETF. Answers A, B, and C are incorrect.
Solution
D. The actual development of new standards and protocols for the Internet is carried out by
working groups chartered by the IETF. Answers A, B, and C are incorrect..
Dependent Variable. A variable that depends on one or more other var.pdf
Dependent Variable. A variable that depends on one or more other variables The dependent
variable responds to the independent variable. It is called dependent because it \"depends\" on
the independent variable. So Answer Is D
Solution
Dependent Variable. A variable that depends on one or more other variables The dependent
variable responds to the independent variable. It is called dependent because it \"depends\" on
the independent variable. So Answer Is D.
C is correct. While all Layer 2 devices split collision domains, swi.pdf
C is correct. While all Layer 2 devices split collision domains, switches create a separate
collision domain for each port.
A, B, and D are incorrect. A is incorrect because hubs are Layer 1 devices and extend collision
domains. B is incorrect because a bridge is a Layer 2 device, but can split the network only into
two collision domains. D is incorrect.
Solution
C is correct. While all Layer 2 devices split collision domains, switches create a separate
collision domain for each port.
A, B, and D are incorrect. A is incorrect because hubs are Layer 1 devices and extend collision
domains. B is incorrect because a bridge is a Layer 2 device, but can split the network only into
two collision domains. D is incorrect..
Answer.The following organisms are present in pod.1. Prokaryotes.pdf
Answer.
The following organisms are present in pod.
1. Prokaryotes, eg. Bacteria
2. Eukaryotes
a. Algae (plants)
b. Protozoans
3. Protists (unicellular eukaryotes)
Solution
Answer.
The following organisms are present in pod.
1. Prokaryotes, eg. Bacteria
2. Eukaryotes
a. Algae (plants)
b. Protozoans
3. Protists (unicellular eukaryotes).
AnswerThe mobile elements are the elerments move form one place t.pdf
Answer:
The mobile elements are the elerments move form one place to other place, where the particular
element is deficient.
The deficiency of mobile elements first appear in older leave whereas the deficency of the
immobile elements first appear in the younger leaves
The immobile elements are iron, calcium, manganese, zinc, copper and boron
Solution
Answer:
The mobile elements are the elerments move form one place to other place, where the particular
element is deficient.
The deficiency of mobile elements first appear in older leave whereas the deficency of the
immobile elements first appear in the younger leaves
The immobile elements are iron, calcium, manganese, zinc, copper and boron.
Answer- high PCO2Explanation- CO2 combines with water to produce c.pdf
Answer- high PCO2
Explanation- CO2 combines with water to produce carbonic acid. The release of hydrogen ions
by carbonic acid auses a drop in pH.
Solution
Answer- high PCO2
Explanation- CO2 combines with water to produce carbonic acid. The release of hydrogen ions
by carbonic acid auses a drop in pH..
Ans CThese are like private addresses in IPv4b in that they are n.pdf
Ans: C
These are like private addresses in IPv4b in that they are not meant to be routed
Solution
Ans: C
These are like private addresses in IPv4b in that they are not meant to be routed.
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Hi,Please find the Ansswer below.PLAYLIST.h#include iostrea.pdf
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1. Alanine has molecular formula C3H7NO2Molecular weight = 3 x at.pdf
- 1. 1. Alanine has molecular formula: C3H7NO2 Molecular weight = 3 x atomic mass of C + 7 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 3 x 12.01 + 7 x 1.008 + 1 x 14.01 + 2 x 16.00 = 89.1 g/mol 2. Arginine has molecular formula: C6H14N4O2 Molecular weight = 6 x atomic mass of C + 14 x atomic mass of H + 4 x atomic mass of N + 2 x atomic mass of O = 6 x 12.01 + 14 x 1.008 + 4 x 14.01 + 2 x 16.00 = 174.2 g/mol 3. Phenylalanine has molecular formula: C9H11NO2 Molecular weight = 9 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 9 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 = 165.2 g/mol 4. Tryptophan has molecular formula: C11H12N2O2 Molecular weight = 11 x atomic mass of C + 12 x atomic mass of H + 2 x atomic mass of N + 2 x atomic mass of O = 11 x 12.01 + 12 x 1.008 + 2 x 14.01 + 2 x 16.00 = 204.2 g/mol 5. Methionine has molecular formula: C5H11NO2S Molecular weight = 5 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O + 1 x atomic mass of S = 5 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 + 1 x 32.07 = 149.2 g/mol Solution 1. Alanine has molecular formula: C3H7NO2 Molecular weight = 3 x atomic mass of C + 7 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 3 x 12.01 + 7 x 1.008 + 1 x 14.01 + 2 x 16.00 = 89.1 g/mol 2. Arginine has molecular formula: C6H14N4O2 Molecular weight = 6 x atomic mass of C + 14 x atomic mass of H + 4 x atomic mass of N + 2 x
- 2. atomic mass of O = 6 x 12.01 + 14 x 1.008 + 4 x 14.01 + 2 x 16.00 = 174.2 g/mol 3. Phenylalanine has molecular formula: C9H11NO2 Molecular weight = 9 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O = 9 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 = 165.2 g/mol 4. Tryptophan has molecular formula: C11H12N2O2 Molecular weight = 11 x atomic mass of C + 12 x atomic mass of H + 2 x atomic mass of N + 2 x atomic mass of O = 11 x 12.01 + 12 x 1.008 + 2 x 14.01 + 2 x 16.00 = 204.2 g/mol 5. Methionine has molecular formula: C5H11NO2S Molecular weight = 5 x atomic mass of C + 11 x atomic mass of H + 1 x atomic mass of N + 2 x atomic mass of O + 1 x atomic mass of S = 5 x 12.01 + 11 x 1.008 + 1 x 14.01 + 2 x 16.00 + 1 x 32.07 = 149.2 g/mol