How many moles of NaOH are present in 294.2 mL of 1.747 M NaOH? Solution 1.747 M NaOH is 1.747 mol NaOH / 1 L of solution now volume of the solution = 294.2 ml = 294.2 ml x 1 L / 1000 ml volume of the solution = 0.2942 L now moles of NaOH = volume of solution x molarity moles of NaOH = 0.2942 L x 1.747 mol / L moles of NaOH = 0.513967 mol so there are 0.514 moles of NaOH.