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Further factors
To solve the given quadratic equations
by taking out the common factor
20244
9123
2
2


xx
xx
Factorise
2
1021 xx
Factorise

In this section we consider the case where
taking out the common factor does not make
the first term
2×3=6
6 + 1 =7
2
x
)3)(12(4
]1)3()3(2[4
]362[4
)372(4
12288
2
2
2





xx
xxx
xxx
xx
xx
4 is the largest
number that divide
exactly into 8,28
and 12
In this section we consider the case where
taking out the common factor does not make
the first term
12×-10=-120
15 - 8 =7
2
x
)54)(23(
)54(2)54(3
1081512
10712
2
2
xx
xxx
xxx
xx




6148)5
302118)4
396)3
464)2
102515)1
2
2
2
2
2





xx
xx
xx
xx
xx
2
2
2
2
21624)4
42521)3
12712)2
654)1
xx
xx
xx
xx





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Further factor 5 - copy