5. In this section we consider the case where
taking out the common factor does not make
the first term
2×3=6
6 + 1 =7
2
x
)3)(12(4
]1)3()3(2[4
]362[4
)372(4
12288
2
2
2
xx
xxx
xxx
xx
xx
4 is the largest
number that divide
exactly into 8,28
and 12
6. In this section we consider the case where
taking out the common factor does not make
the first term
12×-10=-120
15 - 8 =7
2
x
)54)(23(
)54(2)54(3
1081512
10712
2
2
xx
xxx
xxx
xx