Find the equation of the line that passes through (2,3) and (-3,3). Solution A line which passes through 2 given points, A(2,3) and B(-3,3), has the following equation: (xB-xA)/(x-xA) = (yB-yA)/(y-yA) (-3-2)/(x-2) = (3-3)/(y-3) -5/(x-2) = 0/(y-3) We\'ll cross multiply: -5(y-3) = 0(x-2) -5y+15 = 0 We\'ll isolate -5y to the left side. For this reason, we\'ll subtract 20 both sides: -5y = -15 We\'ll divide by -5: y = 3 The equation of the line is y=3..