its a project work presenttation

1. Name Id
Abdullah al sakib 1610127025
Noyeem Alam Nasiv 1612837025
Md.Eftakher Hossain 1610728025

2. Water Volume calculation
The average water consumption range for
household works is taken 165 gallons/person-day
( Reff:how to make men smell better)
So, for 5000 persons, we need total:
=(5000*165)gallons/day
= 825000 gallons/day
=0.825 MGD (Million Gallons/Day)
= (0.825*3.785*103) m3/day
= 3122.625 m3/day
=3123 m3/day
Total number of basin we need for the
design: 03
Therefore, the water flow ,Q =(3123/3) m3/day
= 1041 m3/day

3. Surface Area (Circular Basin)
Compute surface Area: ( Provide three basin at 1041 m3/day
each )
We know, Q= q0*As
Over flow rates for flocculating particle range from (0.6 – 1.0) m/h
= (14.4-24) m/d [Ref: Env. Eng. By Howard(Page no. 126)]
Over flowrate rate q0= 18 m/day
Surface Area , As = Q /q0
= (1041 m3/day)/(18m/day)
=57.83 m2
Say ,=58 m2

4. Diameter calculation
Calculation of basin
diameter:
We know,
Area, A =
πd2/4= 58 m2
Diameter, d2= 232 m2 / π
d = 8.59 m
Say, = 9 m
Radius, r = d/2 =4.5 m

5. Basin volume and Detention Time
Basin Volume , = πr2h
=3.1416*(4.5m)2*4m
=254.47 m3
Detention time Calculation :
Detention time DT= (Volume/Flow)
=254.47 m3*day*24hours /1041 m3 *1 day
=5.86 hr
(Reff:howard s, peavy env ..page. 126)
Detention time range from (4 to 6)H for
Flocculating suspensions ..

6. Autocad ( circular clarifier)

7.  Thank You