In the alternation of generations life cycle exhibited by land plant.pdf

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In the alternation of generations life cycle exhibited by land plants, the ___ generation produces spores by the process of___? Solution Sporophytic generation, by process of meiosis. In land plants sporophyte is diploid and multicellular phase. By the process of meiosis which is also known as reduction division, it produces spores which in turn develop into gametophyte..

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Amino acids are joined together to make proteins in what kind of reactions? Hydrolysis hydration synthesis catabolic dehydration synthesis Solution Answer: 44. (d) Dehydration synthesis A peptide bond is a chemical bond formed between two molecules when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water (H2O). This is a dehydration synthesis reaction (also known as a condensation reaction), and usually occurs between amino acids resulting in the formation of a polypeptide chain..

Amino acids are joined together to make proteins in what kind of .pdf

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7. Mendel\'s Principle of Segregation states that the alleles of a gene will separate from one another during the formation of gametes. Consider the genotype Aa. If crossing-over does not occur, when specifically will these alleles separate? a. Mitosis or Meiosis I b. Mitosis and Meiosis II c. Meiosis I or Meiosis II d. Meiosis I e. Meiosis II 8. A student is studying 5 unlinked genes (referred to simply as gene 1, gene 2, gene 3, gene 4 and gene 5. The alleles of gene 1 are represented as A and a; the alleles for gene 2 are represented with the letters B and b; the alleles of gene 3 are Cand c, and so on. An individual has the genotype Aa Bb Cc Dd Ee. How many allele combinations can be made with the genotype? 2 a. b. 5 c. 10 d. 20 e. 32 Solution 7. (e) The alleles separate in the second part of meiosis, and form hapliod gametes. 8. (e) 32, Here n=5 so 2^5=32 1. (b) There are two non homologous chromosomes present. Each set of chromosome has one chromosome from each parent..

7. Mendels Principle of Segregation states that the alleles of a ge.pdf

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4. Based on our sample data, can we conclude that males and females are distributed across grades in a similar pattern within the population? What are the hypothesis statements: Ho: Ha: Do manual calculations per cell here (if desired) A B C D E F A B C D E F OBS COUNT - m M OBS COUNT - f F Sum = EXPECTED What is the value of the chi square statistic: What is the p-value associated with this value: Is the p-value <0.05? Do you reject or not reject the null hypothesis: If you rejected the null, what is the Phi correlation: What does this correlation mean? What does this decision mean for our equal pay question: ID Salary Compa Midpoint Age Performance Rating Service Gender Raise Degree Gender1 Gr 1 66.1 1.159 57 34 85 8 0 5.7 0 M E 2 25.9 0.834 31 52 80 7 0 3.9 0 M B 3 35.2 1.135 31 30 75 5 1 3.6 1 F B 4 55.3 0.971 57 42 100 16 0 5.5 1 M E 5 49.6 1.033 48 36 90 16 0 5.7 1 M D 6 78.3 1.168 67 36 70 12 0 4.5 1 M F 7 42.3 1.058 40 32 100 8 1 5.7 1 F C 8 22.8 0.990 23 32 90 9 1 5.8 1 F A 9 78 1.164 67 49 100 10 0 4 1 M F 10 23.3 1.014 23 30 80 7 1 4.7 1 F A 11 23.6 1.025 23 41 100 19 1 4.8 1 F A 12 60.8 1.067 57 52 95 22 0 4.5 0 M E 13 40.6 1.014 40 30 100 2 1 4.7 0 F C 14 21.7 0.943 23 32 90 12 1 6 1 F A 15 21.8 0.949 23 32 80 8 1 4.9 1 F A 16 37.4 0.934 40 44 90 4 0 5.7 0 M C 17 57 1.000 57 27 55 3 1 3 1 F E 18 33.5 1.081 31 31 80 11 1 5.6 0 F B 19 23 1.000 23 32 85 1 0 4.6 1 M A 20 36 1.162 31 44 70 16 1 4.8 0 F B 21 76 1.135 67 43 95 13 0 6.3 1 M F 22 43.7 0.911 48 48 65 6 1 3.8 1 F D 23 25.3 1.098 23 36 65 6 1 3.3 0 F A 24 48.9 1.019 48 30 75 9 1 3.8 0 F D 25 25.8 1.122 23 41 70 4 0 4 0 M A 26 23.3 1.013 23 22 95 2 1 6.2 0 F A 27 42.3 1.057 40 35 80 7 0 3.9 1 M C 28 75.2 1.122 67 44 95 9 1 4.4 0 F F 29 80.9 1.208 67 52 95 5 0 5.4 0 M F 30 49 1.020 48 45 90 18 0 4.3 0 M D 31 24.2 1.054 23 29 60 4 1 3.9 1 F A 32 27.5 0.886 31 25 95 4 0 5.6 0 M B 33 63.6 1.115 57 35 90 9 0 5.5 1 M E 34 28.6 0.922 31 26 80 2 0 4.9 1 M B 35 22.4 0.976 23 23 90 4 1 5.3 0 F A 36 23.6 1.026 23 27 75 3 1 4.3 0 F A 37 24.3 1.057 23 22 95 2 1 6.2 0 F A 38 63 1.105 57 45 95 11 0 4.5 0 M E 39 34.8 1.123 31 27 90 6 1 5.5 0 F B 40 24.3 1.057 23 24 90 2 0 6.3 0 M A 41 42.8 1.071 40 25 80 5 0 4.3 0 M C 42 23 0.998 23 32 100 8 1 5.7 1 F A 43 75.4 1.125 67 42 95 20 1 5.5 0 F F 44 60.7 1.065 57 45 90 16 0 5.2 1 M E 45 57.9 1.206 48 36 95 8 1 5.2 1 F D 46 62.2 1.091 57 39 75 20 0 3.9 1 M E 47 62.2 1.091 57 37 95 5 0 5.5 1 M E 48 70.1 1.230 57 34 90 11 1 5.3 1 F E 49 61.7 1.083 57 41 95 21 0 6.6 0 M E 50 61.4 1.077 57 38 80 12 0 4.6 0 M E A B C D E F A B C D E F OBS COUNT - m M OBS COUNT - f F Sum = EXPECTED Solution Based on our sample data, can we conclude that males and females are distributed across grades in a similar pattern within the population? What are the hypothesis statements: Ho: Males and females are distributed across grades in a similar pattern within the population Ha: Males and females are distributed across grades in a different pattern within the population Obs.

4. Based on our sample data, can we conclude that males and females .pdf

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An unassuming single-celled organism called Toxoplasma gondii is one of the most successful parasites on Earth, infecting an estimated 11 percent of Americans and perhaps half of all people worldwide. It’s just as prevalent in many other species of mammals and birds. In a recent study in Ohio, scientists found the parasite in three-quarters of the white-tailed deer they studied. One reason for Toxoplasma’s success is its ability to manipulate its hosts. The parasite can influence their behavior, so much so that hosts can put themselves at risk of death. Scientists first discovered this strange mind control in the 1990s, but it’s been hard to figure out how they manage it. Now a new study suggests that Toxoplasma can turn its host’s genes on and off — and it’s possible other parasites use this strategy, too. Toxoplasma manipulates its hosts to complete its life cycle. Although it can infect any mammal or bird, it can reproduce only inside of a cat. The parasites produce cysts that get passed out of the cat with its feces; once in the soil, the cysts infect new hosts. Toxoplasma returns to cats via their prey. But a host like a rat has evolved to avoid cats as much as possible, taking evasive action from the very moment it smells feline odor. Experiments on rats and mice have shown that Toxoplasma alters their response to cat smells. Many infected rodents lose their natural fear of the scent. Some even seem to be attracted to it. Manipulating the behavior of a host is a fairly common strategy among parasites, but it’s hard to fathom how they manage it. A rat’s response to cat odor, for example, emerges from complex networks of neurons that detect an odor, figure out its source and decide on the right response in a given moment. Within each of the neurons in those networks, thousands of genes are producing proteins and other molecules essential for relaying all of the necessary information throughout the body. Simple Toxoplasma seems ill-equipped to take over such a complicated system. But a new study published in the journal Molecular Ecology hints that the parasite can do so by relying on an eerily elegant strategy. Think of the genes in a host as keys on a piano. Toxoplasma, it seems, simply plays some of the keys differently to produce a new melody. A rat is made up of lots of different kinds of cells, from the neurons in its brain to the bone-producing cells in its skeleton to the insulin-making cells in its pancreas. Yet all of them carry the same 20,000 genes. Depending on the function of a particular cell, some of its genes are switched on and others are shut down. Genes may be switched off, or silenced, by the attachment of molecular caps called methyl groups, a process called methylation. In order to switch a gene on again, the caps are removed. Methylation does more than just allow cells to develop into a variety of organs. It lets them change the way they work in response to signals from the outside. In the brain, for example, neuron.

An unassuming single-celled organism called Toxoplasma gondii is one.pdf

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A boy with Klinefelter Syndrome (XXY) has colorblindness, which is an X-linked recessive trait. His mother and father both have normal vision. Did nondisjunction occur during the formation of the egg or the sperm in this situation? How do you know? Solution Color blindness is an X-recessive trait, there is no way that the father can have color-blindness gene (let’s say Xc). Hence, the color blindness gene should come from mother (but only a single copy of gene is present as it is not expressed). Genotype Mother: XXc Father: XY Child: XcXcY (for trait to be expressed, color blindness gene should be present on both the copies of X) Xc can be inherited only from mother (as father doesn’t have it) and both the copies of Xc should come from her. The egg must have arisen from a nondisjunction in meiosis II. In meiosis I, the homologous X chromosomes separate, so one cell has X and the other has Xc. Failure of chromatids to separate in meiosis II would then result in an egg with two copies of Xc.

A boy with Klinefelter Syndrome (XXY) has colorblindness, which is a.pdf

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What is unrefined and refined foods? Solution Answer: Refined foods undergo undergone manufacturing or repackaging processes. They are the foods altered from their original state. Foods are sometimes refined to enhance the texture, and/or to increase their shelf life. Sometimes they are added with additives also. Example: Refined wheat flour, which is polished to remove the bran. During this process a number of essential nutrients are lost. Unrefined foods are unprocessed, they are not entirely altered in their nutritional value. Whole wheat flour will have everything that a wheat grain has. Fibers, carbohydrates and proteins. Also Vitamins on the outer wheat bran also retained. In comparison, unrefined foods absorbed slowly while refined foods quickly. Refined foods are unhealthy since they are linked with diseases related to absorption and metabolism..

What is unrefined and refined foodsSolutionAnswerRefined f.pdf

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What is the function of CFTR? (details are important) (5 points) Solution Ans:- Cystic fibrosis transmembrane conductance regulator (CFTR) is a membrane protein and chloride channel in vertebrates that is encoded by the CFTR gene.CFTR functions as a ATP gated anion channel increasing the conductance for certain anions to flow down their electrochemical gradient.ATP driven conformational changes in CFTR open and close a gate to allow transmembrane flow of anions down their electrochemical gradient. Essentially CFTR is an ion channel that evolved as a broken ABC transporter that leaks when in open conformation.The CFTR is found in the epithelial cells of many organs including the lungs,liver ,pancreas,digestive tract ,reproductive tract and skin.Normally the protein moves chloride and thiocyanate ions out of an epithelial cell covering mucus.Positively chargedsodium ions follow passively increasing the total electrolyte concentration in the mucus resulting in the movement of water out of the cell via osmosis.In sweat glands defective CSTR results in reduced transport of sodium chloride and sodium thiocyanate in the reabsorptive duct and therefore saltier sweat..

What is the function of CFTR (details are important) (5 points).pdf

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What are transgenic animalsSolutionTransgenic animals are tho.pdf

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Urea concentration in the phospholipid bilayer is 0.02mM, 3.65mM in cytoplasm, what is the urea partition coefficient in these two liquids? Solution Partition coefficient of urea (relative solubility of urea in lipid to aqueous layer) = The concentration in the phospholipid bilayer / The concentration in the cytoplasm Partition coefficient of urea is = 0.02mM/ 3.65mM = 1:182.5 mM (phospholipid: cytoplasm)..

Urea concentration in the phospholipid bilayer is 0.02mM, 3.65mM in .pdf

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A diploid organism has a somatic chromosome number of 16. The centromeres of the 8 homologouspairs are designated as Aa, Bb, Cc, Dd, Ee, Ff, Gg and Hh, with uppercase letters referring to the centromeres of maternal chromosomes and lowercase letters to the centromeres of paternal chromosomes. Each centromere represents one chromosome. Where n = the haploid chromosome number. How many different combinations of centromeres could be produced during meiosis? a.) 8 b.) 64 c.) 256 d.) 512 e.) 6561 Solution At the meiosis, total number of chromosome is 16. During the meiosis 1st spliting of homologous chromosome take place, so each cell has 8 chromosome and centromere..

A diploid organism has a somatic chromosome number of 16. The centro.pdf

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the heights of a sample of 10 father/son pairs of subjects were measured. Minitab results are shown below. Is there sufficient evidence to support the claim that there is a linear correlation between the heights of fathers and the heights of their sons? explain (use significance level of 0.05) Pearson correlation of FATHER and SON= 0.149 P-value=0.681 How do I begin to answer this problem? How do I use the values they give me to get the answer? Solution.

the heights of a sample of 10 fatherson pairs of subjects were meas.pdf

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Should the FCC regulate the media, and if yes, how far should you go? Should it require toning down sex and violence, airing the shows only later at night, or should it take down shows like Sex and the City off air? Solution The FCC also acts as a police agency of the airwaves, and it can fine broadcasters for violating public decency standards on the air. Critics contend that media consolidation limits consumers’ choices because a small number of companies own all the media outlets. They argue that consolidation is not competitive and that corporate owners might restrict or manipulate news coverage. Some critics also lament the homogenization of American culture due to media consolidation. Because radio and television formats have become increasingly uniform, people throughout the country receive the same broadcasts..

Should the FCC regulate the media, and if yes, how far should you go.pdf

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Read carefully and follow exactly Java: You are to write a Breakout game, using Java applets for animation. The requirements for this program are designed so that you will also use an ArrayList, Generics, an abstract class, polymorphism, and file I/O. Please read the following instructions very carefully, as they attempt to explain how the various parts of the animation work; then you can update the applet, using your knowledge of ArrayLists, Generics, abstract classes, and polymorphism. Existing classes: There are a number of existing classes that are already written and ready for use. They are contained in the file Breakout.java (they are not defined as public so they don’t have to be in a file that matches their name). Please look them over carefully to see what functionality is available. The classes (implemented inside Breakout.java) are: Ball: this is defined as a subclass of Rectangle (even though that is geometrically invalid!). The reason for this is so Ball can inherit data for its x coordinate, y coordinate, width, and height. It also adds some data of its own (see the code) and methods (among others) to: bounceLeftRight() (which changes the angle at which it moves after bouncing off a left or right side), bounceTopBottom() (which changes the angle at which it moves after bouncing off a top or bottom) move() (change its coordinates), freeze()/unfreeze() itself, It also inherits important methods from the Rectangle class translate – changes its x and y coordinates respectively by the 2 numbers that are passed in intersects(Rectangle other) – returns true if it intersects another Rectangle intersection(Rectangle other) – returns the Rectangle that is the intersection Paddle: this is also defined as a subclass of Rectangle so it inherits the same data/methods that are described above for the Ball class. The fact that Ball and Rectangle are both Rectangles means that code can ask a Ball if it intersects a Paddle, so it can easily tell when to make things happen. Wall: this is not in its own file, but rather in the Breakout.java file. Wall is also a subclass of Rectangle to it is easy to determine if the ball has collided a wall. The Breakout class (which is an Applet): if you look at the code for the Breakout class, you will notice it has a number of things: It is a subclass of Applet, so it inherits data and methods as well as the ability to function as an Applet. For example, if you want to know the height of the applet you can ask it through the this.getHeight(); method. It implements the KeyListener interface, which gives it the ability to “listen” for keystrokes from the keyboard. If you were to look up the KeyListener interface in the documentation, you would find that anything that implements it must have the KeyPressed, KeyReleased, and KeyTyped methods. These are all there; KeyPressed and KeyReleased set/unset Boolean flags which remember that the left or right arrow keys are or are not being pressed. It has a method called in.

Read carefully and follow exactly Java You are to write a Breakou.pdf

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Pennings, S. C., and R. M. Callaway. 1992. Salt marsh plant zonation: the relative importance of competition and physical factors. Ecology 73:681–690. Questions 1. What three factors did the authors investigate in this study? 2. Summarize the design used for the two Salicornia experiments. Describe the predictor variables, including their treatment levels, response variables, and number of replicates used in each experiment. Explain how randomization was incorporated into the study. Provide a visual diagram of the experimental design. 3. The authors state that as marsh elevation increases, stress from flooding decreases, while stress from salinity increases. Did their results support this assertion? Which figures (number and letter) present the results for flooding (soil waterlogging) and salinity (soil water potential)? 4. The authors state that one potential problem with the transplant experiment is that transplanting itself may have an adverse effect. Did transplanting affect mortality? If yes, provide documentation from the paper. Did transplanting affect growth? If yes, provide documentation from the paper. 5. What evidence (cite relevant figures—number and letter) supports the author’s contention that competition with Salicornia limits Arthrocnemum in the high Salicornia zone? What evidence (cite relevant figures—number and letter) supports their contention that competition with Arthrocnemum limits Salicornia in the Arthrocnemum zone? 6. Do the authors support their contention that multiple factors, both physical stresses and interspecific competition, influence the zonation patterns observed in the salt marsh? Solution 1. Flooding, soil salinity and competition 2. Two experiments were performed to investigate the relative importance of biological factors in Salicornia and Arthrocnemum zoneation. Growth rate and biomass in several marsh zones were measured initially followed by the reciprocally transplanted both species. Mass of green portions, total mass and final percent were the prdictor variables. Growth of the plants were also monitored and this is comes under response variables. Totally 3 replicates were used. 3. The broader marsh zones are determined by Salicornia greater flooding tolerance and it allowing exist low in the marsh as well as Arthrocnemum greater tolerance to high salinity. Figure 6-8 indicated that growth and survival of Salicornia and they are affected by both soil water potential and flooding. Waterlogging affects redox potential and also affects the availability of nutrients in the soil. 4. Survival of transplants was lower than the Salicornia, because survival and growth are affected due to transplantation. 5 Figure 7 and Figure 8. Both species, not grown well in transition zone even through flooding is much reduced. It is mainly due to the high salinity of the transition zone soil 6. Field patterns are ususlly determined by two physical factors that operating in a combination with interspecific competition..

Pennings, S. C., and R. M. Callaway. 1992. Salt marsh plant zonation.pdf

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Lel X_1,...X_n be independent and identically distributed continuous random variables having cumulative distribution function F(x) and and density function f(x). The quantity M = [X_11 + X_11]/2. defined to be the average of the smallest and largest values in X_1...X_11 is called the \"midrange\" of the sequence. Show that M has the cumulative distribution function Also calculate this function when X, are (a) independent identical Exponential random variables with parameter lambda. and (b) independent identical Uniform (O.I) random variables. Solution a) as you can see FM(M) has a f(x) multiply by the distribution of F since we know that f(x) is a probability distribution (mass) we knwo that if we multiply that for Fm we willhave a cumulative distribution function.

Lel X_1,...X_n be independent and identically distributed continuous .pdf

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Match the cell type of the pancreatic islets with the hormones secreted by each cell. 1.alpha cells 2. beta cells 3. delta cells 4. F cells A. glucagon B. insulin C. pancreatic polypeptide D. somatostatin Solution Pancreas is an irregular organ held to mesentry between between the two limb of the duodenum. It is heterocrine gland containing two type of tissue exicrine and endocrine. Endocrine tissue of pancreas consists islet of Langerhans. Five type of cells present in it. Alpha cell producing glucagon beta cell producing insulin Delta cell producing somatostatin Pp cell producing pancreatic polypeptied Epsilon cell producing ghrelin.

Match the cell type of the pancreatic islets with the hormones secre.pdf

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