pH = pka + log ( [salt[[acid]) = 4.76 + log ( 0..pdf

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pH = pka + log ( [salt[/[acid]) = 4.76 + log ( 0.452 /0.4) = 4.813 Solution pH = pka + log ( [salt[/[acid]) = 4.76 + log ( 0.452 /0.4) = 4.813.

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NH3 is lewis base according to lewis electron pair donar is base, nitrogen contains a lone pair of electrons. AlBr3 is lewis acid according to lewis electron pair acceptor is acid, Al has an empty orbital so it gains electron pair from nitrogen of ammonia leads to the formation of co ordinate covalent bond. Br3Al<............:NH3 Solution NH3 is lewis base according to lewis electron pair donar is base, nitrogen contains a lone pair of electrons. AlBr3 is lewis acid according to lewis electron pair acceptor is acid, Al has an empty orbital so it gains electron pair from nitrogen of ammonia leads to the formation of co ordinate covalent bond. Br3Al<............:NH3.

NH3 is lewis base according to lewis electron pai.pdf

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Li has high reduction potential than Cobalt ther.pdf

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Has two binding sites for oxygen .pdf

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Types of physical situations or occurrences: It is important to understand the spectrum of threats to information systems so that responsible administrators can make sure that anticipation measures are widespread.The three types of physical situations or occurrences that can constitute a threat to information systems within an enterprise are: 1. Environmental threats: Natural disasters are the source of a wide range of environmental threats to the information processing facilities. It is possible to evaluate the risk of different types of natural disasters and take suitable precautions so that catastrophic loss from natural disaster is prevented. 2. Technical threats: These threats include electrical power, electromagnetic interference. Electrical power is important for the operation of information system. All the electrical and electronic devices require power without interuptions. Power utility problems like low voltage, high voltage and noise may occur. Example: Most of the computers are designed to withstand long-drawn-out voltage reductions of about 20% without shutting down and without operational error. Therefore no damage occurs but service is interrupted. 3. Human caused threats: The human-caused threats are unauthorized physical access, theft, destruction of equipment or data, mis-use of the resources. These threats are difficult to handle compared to environmental and technical threats. The human caused threats are less predictable than other types of physical threats. Solution Types of physical situations or occurrences: It is important to understand the spectrum of threats to information systems so that responsible administrators can make sure that anticipation measures are widespread.The three types of physical situations or occurrences that can constitute a threat to information systems within an enterprise are: 1. Environmental threats: Natural disasters are the source of a wide range of environmental threats to the information processing facilities. It is possible to evaluate the risk of different types of natural disasters and take suitable precautions so that catastrophic loss from natural disaster is prevented. 2. Technical threats: These threats include electrical power, electromagnetic interference. Electrical power is important for the operation of information system. All the electrical and electronic devices require power without interuptions. Power utility problems like low voltage, high voltage and noise may occur. Example: Most of the computers are designed to withstand long-drawn-out voltage reductions of about 20% without shutting down and without operational error. Therefore no damage occurs but service is interrupted. 3. Human caused threats: The human-caused threats are unauthorized physical access, theft, destruction of equipment or data, mis-use of the resources. These threats are difficult to handle compared to environmental and technical threats. The human caused threats are less predictable than other type.

Types of physical situations or occurrencesIt is important to und.pdf

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The term illegal acts, refers to violations of laws or governmental regulations. Illegal acts by clients are acts attributable to the entity whose financial statements are under audit or acts by management or employees acting on behalf of the entity. Illegal acts by clients do not include personal misconduct by the entity\'s personnel unrelated to their business activities. When the auditor concludes, based on information obtained and, if necessary, consultation with legal counsel, that an illegal act has or is likely to have occurred, the auditor should consider the effect on the financial statements as well as the implications for other aspects of the audit. The auditor should assure himself that the audit committee is adequately informed as soon as practicable and prior to the issuance of the auditor\'s report with respect to illegal acts that come to the auditor’s attention. The auditor need not communicate matters that are clearly inconsequential and may reach agreement in advance with the audit committee on the nature of such matters to be communicated. The communication should describe the act, the circumstances of its occurrence, and the effect on the financial statements. Senior management may wish to have its remedial actions communicated to the audit committee simultaneously. Possible remedial actions include disciplinary action against involved personnel, seeking restitution, adoption of preventive or corrective company policies, and modifications of specific control activities. If senior management is involved in an illegal act, the auditor should communicate directly with the audit committee. The communication may be oral or written. If the communication is oral, the auditor should document it. Solution The term illegal acts, refers to violations of laws or governmental regulations. Illegal acts by clients are acts attributable to the entity whose financial statements are under audit or acts by management or employees acting on behalf of the entity. Illegal acts by clients do not include personal misconduct by the entity\'s personnel unrelated to their business activities. When the auditor concludes, based on information obtained and, if necessary, consultation with legal counsel, that an illegal act has or is likely to have occurred, the auditor should consider the effect on the financial statements as well as the implications for other aspects of the audit. The auditor should assure himself that the audit committee is adequately informed as soon as practicable and prior to the issuance of the auditor\'s report with respect to illegal acts that come to the auditor’s attention. The auditor need not communicate matters that are clearly inconsequential and may reach agreement in advance with the audit committee on the nature of such matters to be communicated. The communication should describe the act, the circumstances of its occurrence, and the effect on the financial statements. Senior management may wish to have its remedial a.

The term illegal acts, refers to violations of laws or governmental .pdf

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Strategic planning has long been used as a tool for transforming and revitalizing corporations, government agencies and nonprofit organizations. Recently, however, skepticism about planning has been on the rise. Political and economic uncertainty is the norm and the pace of technological and social change has accelerated. No organization exists in a static environment. Social, political and economic trends continually impact the demand for its offerings and services. Even as advances in technology present new opportunities, they also generate new expectations. Needs and community demographics are all subject to change. So too are methods for delivering programs and services. It is thus essential that a strategic plan reflect the external environment. Programs, services and operations should be reexamined and reshaped in light of current realities and future projections. Reference: Ten Keys to Successful Strategic Planning for Nonprofit and Foundation Leaders by Richard A. Mittenthal Solution Strategic planning has long been used as a tool for transforming and revitalizing corporations, government agencies and nonprofit organizations. Recently, however, skepticism about planning has been on the rise. Political and economic uncertainty is the norm and the pace of technological and social change has accelerated. No organization exists in a static environment. Social, political and economic trends continually impact the demand for its offerings and services. Even as advances in technology present new opportunities, they also generate new expectations. Needs and community demographics are all subject to change. So too are methods for delivering programs and services. It is thus essential that a strategic plan reflect the external environment. Programs, services and operations should be reexamined and reshaped in light of current realities and future projections. Reference: Ten Keys to Successful Strategic Planning for Nonprofit and Foundation Leaders by Richard A. Mittenthal.

Strategic planning has long been used as a tool for transforming and.pdf

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Sorry I didnt get the question what you postSolutionSorry I .pdf

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delta H = 282.1 = 164.2 KJ .pdf

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Sella turcica is the depression in the sphenoid bone of the skull. Sella turcica is also known as hypophysial fossa. It is located behind the chiasmatic groove and tuberculum sellae of the sphenoid bone which hold the pituitary gland. Solution Sella turcica is the depression in the sphenoid bone of the skull. Sella turcica is also known as hypophysial fossa. It is located behind the chiasmatic groove and tuberculum sellae of the sphenoid bone which hold the pituitary gland..

Sella turcica is the depression in the sphenoid bone of the skull. S.pdf

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P(child does not have a cavity) = (420)0.41 + (620)0.32 + (1020.pdf

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Ans 1) Difference - DNA is double stranded where as RNA is single stranded - Four Nitrogenous bases are adenine, thymine, cytosine, and guanine in DNA where as adenine, uracil , guanine, and cytosine in RNA. - DNA is found in nucleus where as RNA is found in cytiplasm Similar Both have phosphate group and 5 carbon sugar. Both are formed from nucleotides Solution Ans 1) Difference - DNA is double stranded where as RNA is single stranded - Four Nitrogenous bases are adenine, thymine, cytosine, and guanine in DNA where as adenine, uracil , guanine, and cytosine in RNA. - DNA is found in nucleus where as RNA is found in cytiplasm Similar Both have phosphate group and 5 carbon sugar. Both are formed from nucleotides.

Ans 1)Difference- DNA is double stranded where as RNA is single .pdf

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Mandibles refer to the feeding appendages (or jaws) using which food is ingested. Depending on the type of organism and the prey that has to be captured, the structure of the mandible has evolved over the ages. There are evolutionary and phylogenetic relationships to be considered with regard to common features in the development of mandibles in insects and vertebrates too. This is because several insect and crustacean adult mandibles are built in such a way that food is mainly handled with the lower portion of the jaw. Insect mandibles have evolved in accordance with the type of food or prey different species need to catch. Common food sources for insects include algae,other insects, fish, other plants etc. Insects may pierce the surface of their food and suck out fluids,or graze their food to separate it from mud and ingest it. They can even bite off some portions of their food before ingestion or engulf their food as a whole.Some insects chew leaves and other parts of plants. Their mandibles have evolved accordingly. Vertebrates have a variety of food sources and do not depend on any single trophic level for their survival. The muscles that enable mastication of food move the lower jaw of vertebrate mandibles. In humans, the voice box also moves the mandible. Most vertebrates either engulf their food or shred it. Many have teeth for feeding, and can be either herbivores or carnivores. Octopuses are invertebrates having a clever feeding mechanism. They use their long tentacles to explore crevices for their prey. On capturing their prey, they immediately inject their poisonous saliva to immobilize it, after which they use their beaks to crush and ingest their prey. They mostly eat crabs, mollusks, lobsters etc. If the shell of their prey is too tough to break, they use salivary papilla to drill a pinhole and eat the meat of their prey. Thus, the octopus has evolved a feeding mechanism suitable to it. Solution Mandibles refer to the feeding appendages (or jaws) using which food is ingested. Depending on the type of organism and the prey that has to be captured, the structure of the mandible has evolved over the ages. There are evolutionary and phylogenetic relationships to be considered with regard to common features in the development of mandibles in insects and vertebrates too. This is because several insect and crustacean adult mandibles are built in such a way that food is mainly handled with the lower portion of the jaw. Insect mandibles have evolved in accordance with the type of food or prey different species need to catch. Common food sources for insects include algae,other insects, fish, other plants etc. Insects may pierce the surface of their food and suck out fluids,or graze their food to separate it from mud and ingest it. They can even bite off some portions of their food before ingestion or engulf their food as a whole.Some insects chew leaves and other parts of plants. Their mandibles have evolved accordingly. Vertebrates have.

Mandibles refer to the feeding appendages (or jaws) using which food.pdf

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A and B. Half-duplex network communications describes two devices networked together where only one device may communicate at any one time. The other device must wait until the first device is finished before initiating communications. Full-duplex describes a situation where two networked devices may transmit information to each other simultaneously, much in the same way two people can speak at the same time during a phone conversation. Solution A and B. Half-duplex network communications describes two devices networked together where only one device may communicate at any one time. The other device must wait until the first device is finished before initiating communications. Full-duplex describes a situation where two networked devices may transmit information to each other simultaneously, much in the same way two people can speak at the same time during a phone conversation..

A and B. Half-duplex network communications describes two devices ne.pdf

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ionic equation 2Li+(aq)+ SO42-(aq) + Sr2+(aq) + 2Cl-(aq) - 2Li+(aq.pdf

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Instruction Format: Machine instruction has an opcode and zero or more operands. Architectures are differentiated from one another by the number of bits allowed per instruction (16, 32, and 64 are the most common), by the number of operands allowed per instruction, and by the types of instructions and data each can process. More specifically, instruction sets are differentiated by the following features: • Operand storage in the CPU (data can be stored in a stack structure or in registers) • Number of explicit operands per instruction (zero, one, two, and three being the most common) • Operand location (instructions can be classified as register-to-register, register-to-memory or memory-to-memory, which simply refer to the combinations of operands allowed per instruction) • Operations (including not only types of operations but also which instructions can access memory and which cannot) • Type and size of operands (operands can be addresses, numbers, or even characters) The following are some common instruction formats: • OPCODE only (zero addresses) • OPCODE + 1 Address (usually a memory address) • OPCODE + 2 Addresses (usually registers, or one register and one memory address) • OPCODE + 3 Addresses (usually registers, or combinations of registers and memory) Instruction Length: The traditional method for describing a computer architecture is to specify the maximum number of operands, or addresses, contained in each instruction. This has a direct impact on the length of the instruction itself. Instructions on current architectures can be formatted in two ways: • Fixed length-Wastes space but is fast and results in better performance when instruction-level pipelining is used, as we see in Section 5.5. • Variable length-More complex to decode but saves storage space. Memory organization affects instruction format. If memory has, for example, 16 or 32-bit words and is not byte-addressable, it is difficult to access a single character. For this reason, even machines that have 16-, 32-, or 64-bit words are often byteaddressable, meaning every byte has a unique address even though words are longer than 1 byte. COMMON BUS Structure: The basic computer has eight registers, a memory unit, and a control unit. Paths must be provided to transfer information from one register to another and between memory and registers. The number of wires will be excessive if connections are made between the outputs of each register and the inputs of the other registers. A more efficient scheme for transferring information in a system with many registers is to use a common bus. It is known that how to construct a bus PC AR 11 0 11 0 15 0 15 0 7 0 7 0 IR TR INPR AC DR 15 0 15 0 Memory 4096 words 16 bits per word 6 system using multiplexers or three-state buffer gates. The outputs of seven registers and memory are connected to the common bus. The specific output that is selected for the bus lines at any given time is determined from the binary value of the selection vari.

Instruction FormatMachine instruction has an opcode and zero or m.pdf

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Human infant.Human infant takes time to learn and gradually captur.pdf

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Grit and other organic material interfere with the Coliform count. The organisms may remain viable but without division within the grit. The abrasive grit particles may cause damage to the cells and lead to less coliform count than the actual count. In general, grit is removed by placing grids that specifically remove grit. Or else, differential sedimentation is applied to remove grit. At the upstream source, generally the organisms enter the stream at a point source and hence are more concentrated. When they travel down, the cells gradually get dilution since the volume of water wherein the cells are spread increases with time and space. Hence, lesser density of coliforms is observed at a downstream site. Solution Grit and other organic material interfere with the Coliform count. The organisms may remain viable but without division within the grit. The abrasive grit particles may cause damage to the cells and lead to less coliform count than the actual count. In general, grit is removed by placing grids that specifically remove grit. Or else, differential sedimentation is applied to remove grit. At the upstream source, generally the organisms enter the stream at a point source and hence are more concentrated. When they travel down, the cells gradually get dilution since the volume of water wherein the cells are spread increases with time and space. Hence, lesser density of coliforms is observed at a downstream site..

Grit and other organic material interfere with the Coliform count. T.pdf

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Hi, Please find my code. I have correted all of your classes. Please let me know in case if do not get concpt. ######## Node.java ########### public class Node { private E element; private Node next; public Node() { this.element = null; this.next = null; } public Node(E e) { this.element = e; this.next = null; } public E getElement() { return this.element; } public void setElement(E element) { this.element= element; } public Node getNext() { return next; } public void setNext(Node next) { this.next = next; } } ########## Stack.java ############# public class Stack { private int N; private Node top; public Stack() { N = 0; this.top =null; } /* * places element on the top of the stack */ public void push(E element){ Node temp = new Node(element); temp.setNext(top); top = temp; N++; } /* * remove the top node and return its contents */ public E pop(){ if(top == null) return null; E e = top.getElement(); top = top.getNext(); N--; return e; } /* * Look at the top element of the Stack and return it, without removing */ public E peek(){ if(top == null) return null; return top.getElement(); } //returns the size of the stack public int size(){ return N; //replace } public boolean isEmpty(){ return top==null; } } ############ Queue.java ############ public class Queue { private Node front; private Node back; private int N; public Queue() { this.front = null; this.back = null; N = 0; } /* * places element in the back of the Queue */ public void enqueue(E element){ Node temp = new Node(element); if(front == null) { front = temp; back = temp; } else{ back.setNext(temp); back = temp; } N++; } /* * remove the front node of the queue and return it */ public E dequeue(){ if(front == null) { return null; } E item = front.getElement(); front = front.getNext(); // if we had only one element if(front == null){ back = null; } N--; return item; } /* * Look at the front of the queue and return it, without removing */ public E peek(){ if(back == null) return null; return back.getElement(); } //returns the size of the queue public int size(){ return N; } public boolean isEmpty(){ return front==null; } } ########### Palindrome.java ############ import java.util.Scanner; public class Palindrome { public static void main(String[ ] args) { Scanner input = new Scanner(System.in); String inputString; System.out.print(\"Please enter your string: \"); inputString = input.next( ); if (isPalindrome( inputString )){ System.out.println(\"Yes it is a palindrome.\"); } else{ System.out.println(\"No this is not a palindrome.\"); } } public static boolean isPalindrome(String input) { Queue q = new Queue (); Stack s = new Stack (); char letter; int i; for (i = 0; i < input.length( ); i++) { letter = input.charAt(i); q.enqueue(letter); s.push(letter); } while (!q.isEmpty( )) { if (q.dequeue() != s.pop( )) return false; } return true; } } /* Sample Output: Please enter your string: MadaM Yes it is a palindrome. */ Solution Hi, Please find my code. I have correted all of your classes. Pl.

Hi, Please find my code.I have correted all of your classes.Plea.pdf

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Functional dependencies:An FD X->Y is satisfied in an instance r of R if for every pair of tuples, t and s if t and s agree on all attributes in X then they must agree on all attributes in Y A key constraint is a special kind of functional dependency:all attributes of relation occur on the right-hand side of the FD: SSN ->SSN,Name,Address FD: A->ABC 1st NF: A->B A->C BC->A D->E It has primary key is unique so it is sastify the 1st normal form.Using the First Normal Form, data redundancy increases, as there will be many columns with same data in multiple rows but each row as a whole will be unique. 2nd Normal Form:As per the Second Normal Form there must not be any partial dependency of any column on primary key. It is 2nd Normal Form . Third Normal form:Third Normal form applies that every non-prime attribute of table must be dependent on primary key, or we can say that, there should not be the case that a non-prime attribute is determined by another non-prime attribute.So this transitive functional dependency should be removed from the table and also the table must be in Second Normal form. Boyce and codd Normal Form: It is a higher version of the Third Normal form. This form deals with certain type of anamoly that is not handled by 3NF.A 3NF table which does not have multiple overlapping candidate keys is said to be in BCNF. R(ABC) A->B is super key. Solution Functional dependencies:An FD X->Y is satisfied in an instance r of R if for every pair of tuples, t and s if t and s agree on all attributes in X then they must agree on all attributes in Y A key constraint is a special kind of functional dependency:all attributes of relation occur on the right-hand side of the FD: SSN ->SSN,Name,Address FD: A->ABC 1st NF: A->B A->C BC->A D->E It has primary key is unique so it is sastify the 1st normal form.Using the First Normal Form, data redundancy increases, as there will be many columns with same data in multiple rows but each row as a whole will be unique. 2nd Normal Form:As per the Second Normal Form there must not be any partial dependency of any column on primary key. It is 2nd Normal Form . Third Normal form:Third Normal form applies that every non-prime attribute of table must be dependent on primary key, or we can say that, there should not be the case that a non-prime attribute is determined by another non-prime attribute.So this transitive functional dependency should be removed from the table and also the table must be in Second Normal form. Boyce and codd Normal Form: It is a higher version of the Third Normal form. This form deals with certain type of anamoly that is not handled by 3NF.A 3NF table which does not have multiple overlapping candidate keys is said to be in BCNF. R(ABC) A->B is super key..

Functional dependenciesAn FD X-Y is satisfied in an instance r of .pdf

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CNS fibers lack a neurilemma. The neurilemma plays an important role in fiber regeneration. Wallerian degeneration is the process of degeneration of the axon distal to a site of transection. It happens in both the CNS and the PNS. Neuroregeneration refers to the regrowth or repair of nervous tissues, cells or cell products. Such mechanisms may include generation of new neurons, glia, axons, myelin, or synapses. Solution CNS fibers lack a neurilemma. The neurilemma plays an important role in fiber regeneration. Wallerian degeneration is the process of degeneration of the axon distal to a site of transection. It happens in both the CNS and the PNS. Neuroregeneration refers to the regrowth or repair of nervous tissues, cells or cell products. Such mechanisms may include generation of new neurons, glia, axons, myelin, or synapses..

CNS fibers lack a neurilemma. The neurilemma plays an important role.pdf

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