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The lengths of pregnancies are normally distributed with mean
µ = 268 days and standard deviation σ = 15 days.
25. (a) If one pregnant woman is chosen at random, find the
probability that her length of pregnancy is between 260 and 278
days.
(b) Find the number of days above which lie the longest 1.5% of
all pregnancies.
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1/3
Name: Ian Tapia2.5
#1 Points possible: 1. Total attempts: 3
Find for the function.
#2 Points possible: 1. Total attempts: 3
The number
(in thousands) of cat flea collars demanded each year when the
price of a collar is dollars is
expressed by the function
. The collars are currently selling for each and the annual
number of sales is
. Find the approximate decrease in sales of the collar if the pric
e of each collar is
raised by .
The approximate decrease in sales is about collars.
#3 Points possible: 1. Total attempts: 3
Find for the function.
#4 Points possible: 1. Total attempts: 3
The monthly revenue
(in dollars) of a telephone polling service is related to the num
ber of completed
responses by the function
If the number of completed responses is increasing at the rate of
forms per month, find the rate at which
the monthly revenue is changing when .
The monthly revenue is changing by .
y'
2y3 − x4 = − 8
y' =
x p
x
3 + 250p2 = 15, 500 $4
22, 572
$1
y'
3√(y − 1)2 = − 2 + 3x
y' =
R x
R(x) = − 13000 + 15√4x2 + 20x 0 ≤ x ≤ 1000
10
x = 500
$
9/16/2016 xyzHomework Assessment
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2/3
#5 Points possible: 1. Total attempts: 3
Find for at the point .
At ,
#6 Points possible: 1. Total attempts: 3
Find for at the point .
At ,
#7 Points possible: 1. Total attempts: 3
Find for at the point .
At ,
#8 Points possible: 1. Total attempts: 3
The cost (in dollars) of manufacturing
number of high-quality computer laser printers is
Currently, the level of production is
printers and that level is increasing at the rate of printers per
month. Find the rate at which the cost is increasing each month.
The cost is increasing at about per month.
y' 3x5 + 2y4 − 3 = 26 ( − 1, − 2)
( − 1, − 2) y' =
y' (xy)3 / 2 = 64 (8, 2)
(8, 2) y' =
y' x − 3 + y − 3 = −
7
8
(2, − 1)
(2, − 1) y' =
C x
C(x) = 18x4 / 3 + 12x2 / 3 + 400, 000
729 400
$
9/16/2016 xyzHomework Assessment
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3/3
#9 Points possible: 1. Total attempts: 3
For the circle ,
find when .
find the slope of the tangent line where .
The slope of the tangent line at is .
find the points at which .
at
If the radius starts increasing at a constant rate of
cm/sec, how fast is the area increasing when
cm?
The area is increasing at square cm per second.
#10 Points possible: 1. Total attempts: 3
Find for the function.
#11 Points possible: 1. Total attempts: 3
Find for at the point .
At ,
x
2 + y2 = 25
a. y x = 4
y =
b. x = 4
x = 4
c. = 0
dy
dx
= 0
dy
dx
d. 3 r = 9
y'
(y − 1)4 = 3x2 − 5x − 1
y' =
y' x2y2 + 2x − y = 1 ( − 2, − 1)
( − 2, − 1) y' =
9/16/2016 xyzHomework Assessment
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1/4
Name: Ian Tapia2.4
#1 Points possible: 1. Total attempts: 3
Find the derivative of the function
at .
#2 Points possible: 1. Total attempts: 3
Find
without using the quotient rule; rather, rewrite the function by
using a negative exponent and then
use the product rule and the general power rule to find the deriv
ative.
#3 Points possible: 1. Total attempts: 3
If and , find and .
#4 Points possible: 1. Total attempts: 3
Find , if
and .
f(x) = (x2 − 3)
3
(3x − 5)4 x = 2
f' (2) =
dy
dx
y =
1
x + 5
=
dy
dx
f(x) = x2 g(x) = 3x3 − 3x + 5 (f ∘ g)(x) (g ∘ f)(x)
a. (f ∘ g)(x) =
b. (g ∘ f)(x) =
dy
dx
y = u3 − 2u u = 3x2 + 3
=
dy
dx
9/16/2016 xyzHomework Assessment
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2/4
#5 Points possible: 1. Total attempts: 3
Find
without using the quotient rule; rather, rewrite the function by
using a negative exponent and then
use the product rule and the general power rule to find the deriv
ative.
#6 Points possible: 1. Total attempts: 3
If and , find .
#7 Points possible: 1. Total attempts: 3
Find , if
.
#8 Points possible: 1. Total attempts: 3
Find , if
and .
#9 Points possible: 1. Total attempts: 3
Find the derivative of the function
at .
dy
dx
y = ( )
42x + 3
4x + 5
=
dy
dx
u(x) = 4x2 − 5 v(x) = x3 − 6 u(x) ⋅ v(x)
u(x) ⋅ v(x) =
dy
dx
y = (4x2 + 5x + 3)
3
=
dy
dx
dy
dx
y = 3u2 + 3u − 2 u = 6x + 2
=
dy
dx
f(x) = (4x2 + 3x − 5)
3
x = 1
f' (1) =
9/16/2016 xyzHomework Assessment
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3/4
#10 Points possible: 1. Total attempts: 3
Find
without using the quotient rule; rather, rewrite the function by
using a negative exponent and then
use the product rule and the general power rule to find the deriv
ative.
#11 Points possible: 1. Total attempts: 3
Find , if
.
#12 Points possible: 1. Total attempts: 3
Find the derivative of the function
at .
#13 Points possible: 1. Total attempts: 3
Find , if
and .
dy
dx
y =
(x2 − 3)
3
x + 3
=
dy
dx
dy
dx
y = 5√(x2 + 7)3
=
dy
dx
f(x) = 3√(x2 − 2)2 x = 1
f' (1) =
dy
dx
y = 7u − 3 u = 5x + 9
=
dy
dx
9/16/2016 xyzHomework Assessment
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4/4
#14 Points possible: 1. Total attempts: 3
Find , if
and .
#15 Points possible: 1. Total attempts: 3
Find , if
.
dy
dx
y = 3u + 4 u = − 2x2 − 2
=
dy
dx
dy
dx
y = (x2 + 1)
3
(3x + 3)4
=
dy
dx
9/16/2016 xyzHomework Assessment
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1/4
Name: Ian Tapia2.3
#1 Points possible: 1. Total attempts: 3
Suppose
represents the amount of money (in thousands of dollars) a cou
ntry spends on the local drug
war months from January ,
. Interpret the information provided by and .
Because the derivative of is Select an answer
, the cost of the drug war is Select an answer . Because
the second derivative is Select an answer
(so that the derivatives have Select an answer ), the function
is Select an answer and the function is Select an answer
at a(n) Select an answer rate.
#2 Points possible: 1. Total attempts: 3
Find and
3/16
‑3/32
#3 Points possible: 1. Total attempts: 3
Find , , and for the function.
6x^5‑10x^4+4
30x^4‑40x^3
120x^3‑120x^2
360x^2‑240x
C(t)
t 1 2000 C' (14) = 2.3 C' ' (14) > 0
C
C' (t) C(t)
f' (x) f' ' (x)
f(x) =
4x − 3
x
f' (x) =
f' ' (x) =
f' f' ' f' ' ' f ( 4 )
f(x) = x6 − 2x5 + 4x − 4
f' (x) =
f' ' (x) =
f' ' ' (x) =
f
( 4 ) (x) =
9/16/2016 xyzHomework Assessment
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2/4
#4 Points possible: 1. Total attempts: 3
Find , , and for the function.
#5 Points possible: 1. Total attempts: 3
Find and interpret and .
3/2
3/2
So at , is decreasing at a(n) decreasing rate.
#6 Points possible: 1. Total attempts: 3
Find and interpret and .
3/8
‑2/27
So at , is decreasing at a(n) increasing rate.
f' f' ' f' ' ' f ( 4 )
f(x) = x4 − x3 + 10x − 1
f' (x) =
f' ' (x) =
f' ' ' (x) =
f
( 4 ) (x) =
f' (4) f' ' (4)
f(x) = 6√x
f' (4) =
f' ' (4) =
x = 4 f(x)
f' (27) f' ' (27)
f(x) = 9 3√x
f' (27) =
f' ' (27) =
x = 27 f(x)
9/16/2016 xyzHomework Assessment
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3/4
#7 Points possible: 1. Total attempts: 3
Find and interpret and .
9
‑2
So at , is increasing at a(n) increasing rate.
#8 Points possible: 1. Total attempts: 3
Find and
5‑4/x^3
12/x^4
#9 Points possible: 1. Total attempts: 3
If , then
The values of for which are ,
The values of for which are
f' ( − 2) f' ' ( − 2)
f(x) = − x2 + 5x + 4
f' ( − 2) =
f' ' ( − 2) =
x = − 2 f(x)
f' (x) f' ' (x)
f(x) =
5x3 + 2
x2
f' (x) =
f' ' (x) =
f(x) = (4x + 1)(2x − 1)
a. f(1) =
b. f' (1) =
c. f' ' (1) =
d. x f(x) = 0
e. x f' (x) = 0
9/16/2016 xyzHomework Assessment
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4/4
#10 Points possible: 1. Total attempts: 3
Find , , and
for the function. You will answer the coefficient in the first bo
x and then select
the term for each.
Select an answer
Select an answer
Select an answer
Select an answer
#11 Points possible: 1. Total attempts: 3
Find and interpret and .
So at , is Select an answer at a(n) Select an answer rate.
#12 Points possible: 1. Total attempts: 3
Find and interpret and .
So at , is Select an answer at a(n) Select an answer rate.
f' f' ' f' ' ' f ( 4 )
x
f(x) = − 12√x
f' (x) =
f' ' (x) =
f' ' ' (x) =
f
( 4 ) (x) =
f' (1) f' ' (1)
f(x) =
2
x
f' (1) =
f' ' (1) =
x = 1 f(x)
f' (1) f' ' (1)
f(x) = 9x
4
3
f' (1) =
f' ' (1) =
x = 1 f(x)

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The lengths of pregnancies are normally distributed with mean µ = .docx

  • 1. The lengths of pregnancies are normally distributed with mean µ = 268 days and standard deviation σ = 15 days. 25. (a) If one pregnant woman is chosen at random, find the probability that her length of pregnancy is between 260 and 278 days. (b) Find the number of days above which lie the longest 1.5% of all pregnancies. 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 1/3 Name: Ian Tapia2.5 #1 Points possible: 1. Total attempts: 3 Find for the function. #2 Points possible: 1. Total attempts: 3 The number (in thousands) of cat flea collars demanded each year when the price of a collar is dollars is expressed by the function . The collars are currently selling for each and the annual number of sales is . Find the approximate decrease in sales of the collar if the pric
  • 2. e of each collar is raised by . The approximate decrease in sales is about collars. #3 Points possible: 1. Total attempts: 3 Find for the function. #4 Points possible: 1. Total attempts: 3 The monthly revenue (in dollars) of a telephone polling service is related to the num ber of completed responses by the function If the number of completed responses is increasing at the rate of forms per month, find the rate at which the monthly revenue is changing when . The monthly revenue is changing by . y' 2y3 − x4 = − 8 y' = x p x 3 + 250p2 = 15, 500 $4 22, 572
  • 3. $1 y' 3√(y − 1)2 = − 2 + 3x y' = R x R(x) = − 13000 + 15√4x2 + 20x 0 ≤ x ≤ 1000 10 x = 500 $ 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 2/3 #5 Points possible: 1. Total attempts: 3 Find for at the point . At , #6 Points possible: 1. Total attempts: 3 Find for at the point . At ,
  • 4. #7 Points possible: 1. Total attempts: 3 Find for at the point . At , #8 Points possible: 1. Total attempts: 3 The cost (in dollars) of manufacturing number of high-quality computer laser printers is Currently, the level of production is printers and that level is increasing at the rate of printers per month. Find the rate at which the cost is increasing each month. The cost is increasing at about per month. y' 3x5 + 2y4 − 3 = 26 ( − 1, − 2) ( − 1, − 2) y' = y' (xy)3 / 2 = 64 (8, 2) (8, 2) y' = y' x − 3 + y − 3 = − 7 8 (2, − 1) (2, − 1) y' = C x C(x) = 18x4 / 3 + 12x2 / 3 + 400, 000
  • 5. 729 400 $ 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 3/3 #9 Points possible: 1. Total attempts: 3 For the circle , find when . find the slope of the tangent line where . The slope of the tangent line at is . find the points at which . at If the radius starts increasing at a constant rate of cm/sec, how fast is the area increasing when cm? The area is increasing at square cm per second. #10 Points possible: 1. Total attempts: 3 Find for the function. #11 Points possible: 1. Total attempts: 3
  • 6. Find for at the point . At , x 2 + y2 = 25 a. y x = 4 y = b. x = 4 x = 4 c. = 0 dy dx = 0 dy dx d. 3 r = 9 y' (y − 1)4 = 3x2 − 5x − 1 y' = y' x2y2 + 2x − y = 1 ( − 2, − 1) ( − 2, − 1) y' =
  • 7. 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 1/4 Name: Ian Tapia2.4 #1 Points possible: 1. Total attempts: 3 Find the derivative of the function at . #2 Points possible: 1. Total attempts: 3 Find without using the quotient rule; rather, rewrite the function by using a negative exponent and then use the product rule and the general power rule to find the deriv ative. #3 Points possible: 1. Total attempts: 3 If and , find and . #4 Points possible: 1. Total attempts: 3 Find , if
  • 8. and . f(x) = (x2 − 3) 3 (3x − 5)4 x = 2 f' (2) = dy dx y = 1 x + 5 = dy dx f(x) = x2 g(x) = 3x3 − 3x + 5 (f ∘ g)(x) (g ∘ f)(x) a. (f ∘ g)(x) = b. (g ∘ f)(x) = dy dx y = u3 − 2u u = 3x2 + 3 =
  • 9. dy dx 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 2/4 #5 Points possible: 1. Total attempts: 3 Find without using the quotient rule; rather, rewrite the function by using a negative exponent and then use the product rule and the general power rule to find the deriv ative. #6 Points possible: 1. Total attempts: 3 If and , find . #7 Points possible: 1. Total attempts: 3 Find , if . #8 Points possible: 1. Total attempts: 3 Find , if
  • 10. and . #9 Points possible: 1. Total attempts: 3 Find the derivative of the function at . dy dx y = ( ) 42x + 3 4x + 5 = dy dx u(x) = 4x2 − 5 v(x) = x3 − 6 u(x) ⋅ v(x) u(x) ⋅ v(x) = dy dx y = (4x2 + 5x + 3) 3
  • 11. = dy dx dy dx y = 3u2 + 3u − 2 u = 6x + 2 = dy dx f(x) = (4x2 + 3x − 5) 3 x = 1 f' (1) = 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 3/4 #10 Points possible: 1. Total attempts: 3 Find without using the quotient rule; rather, rewrite the function by using a negative exponent and then
  • 12. use the product rule and the general power rule to find the deriv ative. #11 Points possible: 1. Total attempts: 3 Find , if . #12 Points possible: 1. Total attempts: 3 Find the derivative of the function at . #13 Points possible: 1. Total attempts: 3 Find , if and . dy dx y = (x2 − 3) 3 x + 3
  • 13. = dy dx dy dx y = 5√(x2 + 7)3 = dy dx f(x) = 3√(x2 − 2)2 x = 1 f' (1) = dy dx y = 7u − 3 u = 5x + 9 = dy dx 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php
  • 14. 4/4 #14 Points possible: 1. Total attempts: 3 Find , if and . #15 Points possible: 1. Total attempts: 3 Find , if . dy dx y = 3u + 4 u = − 2x2 − 2 = dy dx dy dx y = (x2 + 1) 3 (3x + 3)4 =
  • 15. dy dx 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 1/4 Name: Ian Tapia2.3 #1 Points possible: 1. Total attempts: 3 Suppose represents the amount of money (in thousands of dollars) a cou ntry spends on the local drug war months from January , . Interpret the information provided by and . Because the derivative of is Select an answer , the cost of the drug war is Select an answer . Because the second derivative is Select an answer (so that the derivatives have Select an answer ), the function is Select an answer and the function is Select an answer at a(n) Select an answer rate. #2 Points possible: 1. Total attempts: 3 Find and 3/16
  • 16. ‑3/32 #3 Points possible: 1. Total attempts: 3 Find , , and for the function. 6x^5‑10x^4+4 30x^4‑40x^3 120x^3‑120x^2 360x^2‑240x C(t) t 1 2000 C' (14) = 2.3 C' ' (14) > 0 C C' (t) C(t) f' (x) f' ' (x) f(x) = 4x − 3 x f' (x) = f' ' (x) = f' f' ' f' ' ' f ( 4 ) f(x) = x6 − 2x5 + 4x − 4
  • 17. f' (x) = f' ' (x) = f' ' ' (x) = f ( 4 ) (x) = 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 2/4 #4 Points possible: 1. Total attempts: 3 Find , , and for the function. #5 Points possible: 1. Total attempts: 3 Find and interpret and . 3/2 3/2 So at , is decreasing at a(n) decreasing rate. #6 Points possible: 1. Total attempts: 3
  • 18. Find and interpret and . 3/8 ‑2/27 So at , is decreasing at a(n) increasing rate. f' f' ' f' ' ' f ( 4 ) f(x) = x4 − x3 + 10x − 1 f' (x) = f' ' (x) = f' ' ' (x) = f ( 4 ) (x) = f' (4) f' ' (4) f(x) = 6√x f' (4) = f' ' (4) = x = 4 f(x) f' (27) f' ' (27) f(x) = 9 3√x f' (27) =
  • 19. f' ' (27) = x = 27 f(x) 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 3/4 #7 Points possible: 1. Total attempts: 3 Find and interpret and . 9 ‑2 So at , is increasing at a(n) increasing rate. #8 Points possible: 1. Total attempts: 3 Find and 5‑4/x^3 12/x^4 #9 Points possible: 1. Total attempts: 3 If , then
  • 20. The values of for which are , The values of for which are f' ( − 2) f' ' ( − 2) f(x) = − x2 + 5x + 4 f' ( − 2) = f' ' ( − 2) = x = − 2 f(x) f' (x) f' ' (x) f(x) = 5x3 + 2 x2 f' (x) = f' ' (x) = f(x) = (4x + 1)(2x − 1) a. f(1) = b. f' (1) = c. f' ' (1) = d. x f(x) = 0
  • 21. e. x f' (x) = 0 9/16/2016 xyzHomework Assessment http://www.xyzhomework.com/imathas/assessment/printtest.php 4/4 #10 Points possible: 1. Total attempts: 3 Find , , and for the function. You will answer the coefficient in the first bo x and then select the term for each. Select an answer Select an answer Select an answer Select an answer #11 Points possible: 1. Total attempts: 3 Find and interpret and . So at , is Select an answer at a(n) Select an answer rate. #12 Points possible: 1. Total attempts: 3 Find and interpret and .
  • 22. So at , is Select an answer at a(n) Select an answer rate. f' f' ' f' ' ' f ( 4 ) x f(x) = − 12√x f' (x) = f' ' (x) = f' ' ' (x) = f ( 4 ) (x) = f' (1) f' ' (1) f(x) = 2 x f' (1) = f' ' (1) = x = 1 f(x) f' (1) f' ' (1) f(x) = 9x 4 3
  • 23. f' (1) = f' ' (1) = x = 1 f(x)