1. EXPERIMENT PRESENTED BY
MEMBERSOF THE SOCIETY OF PETROLEUMENGINEERs (
S.P.E) STUDENT CHAPTER OF THE UNIVERSITY OF BUEA
LEVEL 400 STUDENTS
Underthesupervisionof
Dr.fozaokennedy

2. TITLE OF EXPERIMENT
EXPERIMENT TO DETERMINE WATERFLOODING

3. AIM OF THE EXPERIMENT
To obtain the fractional flow curve using
the imbibition process in a horizontal
porous medium.
REQUIREMENTS
Pipe, pressure pipe, A tap, stopper,
gravel, bucket, graduated bucket,
water, A stop watch, oil(diesel).

4. SETUP OF THE EXPERIMENT

5. Volume of oil(diesel) in the pipe = 1.75l = 1.75x10−3 𝑚3

6. PROCEDURE
• A Pipe of length 0.5m was completely filled with
gravel and well saturated with oil(diesel).
• One end of the pipe was connected to A bucket
containing water.
• The other end of the pipe was connected to a tap
• A graduated bucket was placed at the end of the
tap so as to collect the displaced oil.
• A stopper was used to control the flow rate of
water and oil from the tap.

7. • The stopper was open at different time intervals,
and the volumes oil and water displaced were
recorded as shown on the table below.
SERIES TIME /s VOLUME OF
OIL/L
VOLUME OF
WATER/L
1 5.4 0.3 0.2
2 20.6 0.4 0.6
3 31.5 0.5 1.0
4 45.9 0.7 1.6

8. Flow rate

9. Result obtained (calculation)
The flow rate of water
Q=
V 𝑤
𝑇
𝑄 𝑤1=
0.2
5.4𝑥1000
= 3.7x10−5 𝑚3/s
𝑄 𝑤2=
0.6
20.6𝑥1000
= 2.9x10−5 𝑚3/s
𝑄 𝑤3=
1.0
31.5𝑥1000
= 3.2x10−5 𝑚3/s
𝑄 𝑤4=
1.6
45.9𝑥1000
= 3.5x10−5 𝑚3/s

10. The flow rate of oil
Q=
Vo
𝑇
𝑄 𝑜1=
0.3
5.4𝑥1000
= 5.5x10−5
𝑚3
/s
𝑄 𝑜2=
0.4
20.6𝑥1000
= 1.9x10−5
𝑚3
/s
𝑄 𝑜3=
0.5
31.5𝑥1000
= 1.6x10−5
𝑚3
/s
𝑄 𝑜4=
0.7
45.9𝑥1000
= 1.5x10−5
𝑚3
/s

11.  The fractional flow of water (𝑓𝑤)
𝑓𝑤=
𝑄 𝑤
𝑄 𝑤+𝑄 𝑜
𝑓𝑤1=
3.5𝑥10−5
3.5𝑥10−5+5.5𝑥10−5 =0.40
𝑓𝑤2=
2.9𝑥10−5
2.9𝑥10−5+1.9𝑥10−5 =0.60
𝑓𝑤3=
3.2𝑥10−5
3.2𝑥10−5+1.6𝑥10−5 =0.70
𝑓𝑤4=
3.5𝑥10−5
3.5𝑥10−5+1.5𝑥10−5 =0.70

12. The saturation of water
𝑠 𝑤 + 𝑠0= 1 ⟹ 𝑠 𝑤= 1 - 𝑠0
But 𝑠0=
𝑉 𝑂
𝑉 𝑃
and 𝑉𝑂= 𝑉𝑝- 𝑉𝑂
𝑠01=
(1.75−0.3)𝑥10−3
1.75𝑥10−3 = 0.8 ⟹ 𝑠 𝑤1= 1 - 0.8 = 0.2
𝑠02=
(1.75−0.4)𝑥10−3
1.75𝑥10−3 = 0.77 ⟹ 𝑠 𝑤2= 1 - 0.77 = 0.23
𝑠03=
(1.75−0.5)𝑥10−3
1.75𝑥10−3 = 0.71 ⟹ 𝑠 𝑤3= 1 – 0.71 = 0.29
𝑠04=
(1.75−0.7)𝑥10−3
1.75𝑥10−3 = 0.60 ⟹ 𝑠 𝑤4= 1 – 0.60 = 0.4

13. 𝑠 𝑤 0 0.20 0.23 0.29 0.40
𝑓𝑤 0 0.40 0.60 0.70 0.70
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0 0.2 0.23 0.29 0.4
Fractional flow curve
Fractional flow curve
𝑓𝑤
𝑠 𝑤

14. HAND PLOTTING OF THE FRACTIONAL FLOW CURVE

15. Thanks

16. TECHNICAL TEAM
• NKUMBE ELVIS NJUME
• BONAVENTURE DUM- BUNG
• MA - EFFETI NGALE A.
• BATE BORIS BATE
• MBOUNA KENFACK LEONEL
• NORISTAR MBI MUA
• NJOMO STEPHANIE
• MPARA CARINE BONGKA