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Student’s Task1.1.66
Name: ............................ Date: ............................
Application of Congruence
1. Look at Figure 1.
B
A D C
Figure 1
Given ∠ABD = ∠CBD, show that AB = CB.
Fill in the following blank spaces:
Statement
a. ∠ BAD = ∠ BCD
b. ∠ ABD = ∠ CBD
c. ∠ BAD + ∠ ABD = ∠ BCD + ∠ ....
d. ∠ BAD+ ∠ ABD+ ∠ ADB =
∠ BCD+ ∠ CBD+ ∠ . .. = 1800
e. ∠ ADB = ∠ . . .
f. BD = BD
a. Given (in Figure 1)
b. .............
c. ..............
d. The sum of the
three angles in a
triangle is 180°.
e. clear
f. ...
14 / Student’s Worksheet – Similarity and Congruency
According to the requirement (. . . , . . . , . . . ), ΔABD ≅ Δ . . .
AB and ... are corresponding sides, so that AB = . . .
2. Look at Figure 2.
ΔABC is an isosceles triangle. B is the vertex of ΔABC.
∠ ABD = ∠ CBD. BD is the angle bisector of ∠B.
Show that:
a. AD = DC
b. BD is perpendicular to AC.
To solve the two problems above, fill in the following blank spaces.
B
A C
D
Figure 2
a) Look at ΔABD and ΔCBD.
1). AB = CB
2). ∠ ABD = ∠ . . .
3). BD = BD
4). According to the requirement ( . . . , . . . , . . . ), ΔABD ≅ Δ . . .
5). AD and ... are corresponding sides, so that AD = . . .
b) Based on the result in (a), it can be concluded that AD = ...
It means that BD is the segment bisector of ΔABC.
Since BD is the segment bisector of ΔABC, then BD . . . . . AC .
Mathematics for Junior High School Grade 9 / 15

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Congruence and Similarity in Geometry

  • 1. Student’s Task1.1.66 Name: ............................ Date: ............................ Application of Congruence 1. Look at Figure 1. B A D C Figure 1 Given ∠ABD = ∠CBD, show that AB = CB. Fill in the following blank spaces: Statement a. ∠ BAD = ∠ BCD b. ∠ ABD = ∠ CBD c. ∠ BAD + ∠ ABD = ∠ BCD + ∠ .... d. ∠ BAD+ ∠ ABD+ ∠ ADB = ∠ BCD+ ∠ CBD+ ∠ . .. = 1800 e. ∠ ADB = ∠ . . . f. BD = BD a. Given (in Figure 1) b. ............. c. .............. d. The sum of the three angles in a triangle is 180°. e. clear f. ... 14 / Student’s Worksheet – Similarity and Congruency
  • 2. According to the requirement (. . . , . . . , . . . ), ΔABD ≅ Δ . . . AB and ... are corresponding sides, so that AB = . . . 2. Look at Figure 2. ΔABC is an isosceles triangle. B is the vertex of ΔABC. ∠ ABD = ∠ CBD. BD is the angle bisector of ∠B. Show that: a. AD = DC b. BD is perpendicular to AC. To solve the two problems above, fill in the following blank spaces. B A C D Figure 2 a) Look at ΔABD and ΔCBD. 1). AB = CB 2). ∠ ABD = ∠ . . . 3). BD = BD 4). According to the requirement ( . . . , . . . , . . . ), ΔABD ≅ Δ . . . 5). AD and ... are corresponding sides, so that AD = . . . b) Based on the result in (a), it can be concluded that AD = ... It means that BD is the segment bisector of ΔABC. Since BD is the segment bisector of ΔABC, then BD . . . . . AC . Mathematics for Junior High School Grade 9 / 15