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NaOH will completely react will acetic acid and t.pdf

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NaOH will completely react will acetic acid and turn it into salt. Conc . of NaOH left = 16.67*.12-2 /36.67*10^-3 =0.0109 pOH = -log(0.0109) =1.963 pH = 14 -1.963 =12.037 Solution NaOH will completely react will acetic acid and turn it into salt. Conc . of NaOH left = 16.67*.12-2 /36.67*10^-3 =0.0109 pOH = -log(0.0109) =1.963 pH = 14 -1.963 =12.037.

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NaOH will completely react will acetic acid and turn it into salt. Conc . of NaOH left = 16.67*.12-2 /36.67*10^-3 =0.0109 pOH = -log(0.0109) =1.963 pH = 14 -1.963 =12.037 Solution NaOH will completely react will acetic acid and turn it into salt. Conc . of NaOH left = 16.67*.12-2 /36.67*10^-3 =0.0109 pOH = -log(0.0109) =1.963 pH = 14 -1.963 =12.037

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NaOH will completely react will acetic acid and t.pdf

  • 1. NaOH will completely react will acetic acid and turn it into salt. Conc . of NaOH left = 16.67*.12-2 /36.67*10^-3 =0.0109 pOH = -log(0.0109) =1.963 pH = 14 -1.963 =12.037 Solution NaOH will completely react will acetic acid and turn it into salt. Conc . of NaOH left = 16.67*.12-2 /36.67*10^-3 =0.0109 pOH = -log(0.0109) =1.963 pH = 14 -1.963 =12.037