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Vertically polarized light that has an intensity of 200 W/m2 is incident on two polarizing filters.
The first filter is oriented 22.0 from the vertical while the second filter is oriented 50.0 from the
vertical in the same direction. 1) Predict the intensity of the light that emerges from the second
filter. (Express your answer to two significant figures. W/m2 Submit Your submissions: 171.9 X
Computed value: 171.9 Submitted: Monday, May 21 at 7:11 PM Feedback: 2) Predict the
polarization of the light that emerges from the second filter. Give an angle from the vertical.
(Express your answer as an integer.) 134 Submit Your submissions: 134 x Computed value: 134
Feedback: Submitted: Monday, May 21 at 7:11 PM
Solution
Solution:
1) Intensity after the light passes thru the first one at 22 degrees = I1 = Io cos^2 theta1
I1 =171.9 W/m^2; Now the angle between the light and 2nd polariser becomes 50-22 = 28
degrees.
I2 = I1 cos^2 28 = (171.9) cos^2 28 = 134 W/m^2
Intensity of light that emerges from the 2nd filter = 134 W/m^2
2) The angle from the vertical is 50 degrees .
This is same as the angle of orientation of the 2nd filter.
Vertically polarized light that has an intensity of 200 W-m2 is incide.docx

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Vertically polarized light that has an intensity of 200 W-m2 is incide.docx

  • 1. Vertically polarized light that has an intensity of 200 W/m2 is incident on two polarizing filters. The first filter is oriented 22.0 from the vertical while the second filter is oriented 50.0 from the vertical in the same direction. 1) Predict the intensity of the light that emerges from the second filter. (Express your answer to two significant figures. W/m2 Submit Your submissions: 171.9 X Computed value: 171.9 Submitted: Monday, May 21 at 7:11 PM Feedback: 2) Predict the polarization of the light that emerges from the second filter. Give an angle from the vertical. (Express your answer as an integer.) 134 Submit Your submissions: 134 x Computed value: 134 Feedback: Submitted: Monday, May 21 at 7:11 PM Solution Solution: 1) Intensity after the light passes thru the first one at 22 degrees = I1 = Io cos^2 theta1 I1 =171.9 W/m^2; Now the angle between the light and 2nd polariser becomes 50-22 = 28 degrees. I2 = I1 cos^2 28 = (171.9) cos^2 28 = 134 W/m^2 Intensity of light that emerges from the 2nd filter = 134 W/m^2 2) The angle from the vertical is 50 degrees . This is same as the angle of orientation of the 2nd filter.