Vanadium is a transition metal that can be found in the four consecutive oxidation states +2 to +5.
In aqueous solution, it forms different colored water complexes as shown in the figure above. [V(H 2 O) 6 ] 2+ is lilac, [V(H2O) 6 ] 3+ is green, [VO(H 2 O) 5 ] 2+ is blue, and [VO(H 2 O) 5 ] 3+ is yellow. Which compound do you expect to act as a reducing agent and which as an oxidant?
Solution
As vanadium has electronic configuration 3d 3 4s 2 .In [VO(H2O)5]3+ vanadium is in +5 oxidation state which is maximum oxidation state possessed by vanadium so it will try to accept the electron or it will reduce itself and oxidize other. So [VO(H2O)5]3+ will act as oxidizing agent.
While in [V(H2O)6]2+ vanadium is present in +2 oxidation state so it will try to oxidize itself into +3 or +5 state. So it will act as reducing agent.
and  [V(H2O)6]3+ in this vanadium(V)is present in +3 state so it can either reduce itself to +2 or oxidize itself to +5 state so it can act both as an oxidizing (oxidant) or reducing agent (reductant).
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Vanadium is a transition metal that can be found in the four consecuti.docx
1. Vanadium is a transition metal that can be found in the four consecutive oxidation states +2 to
+5.
In aqueous solution, it forms different colored water complexes as shown in the figure above.
[V(H 2 O) 6 ] 2+
is lilac, [V(H2O) 6 ] 3+
is green, [VO(H 2 O) 5 ] 2+
is blue, and [VO(H 2 O) 5 ] 3+
is
yellow. Which compound do you expect to act as a reducing agent and which as an oxidant?
Solution
As vanadium has electronic configuration 3d 3
4s 2
.In [VO(H2O)5]3+ vanadium is in +5
oxidation state which is maximum oxidation state possessed by vanadium so it will try to accept
the electron or it will reduce itself and oxidize other. So [VO(H2O)5]3+ will act as oxidizing
agent.
While in [V(H2O)6]2+ vanadium is present in +2 oxidation state so it will try to oxidize itself
into +3 or +5 state. So it will act as reducing agent.
and  [V(H2O)6]3+ in this vanadium(V)is present in +3 state so it can either reduce itself to
+2 or oxidize itself to +5 state so it can act both as an oxidizing (oxidant) or reducing agent
(reductant).
![Vanadium is a transition metal that can be found in the four consecutive oxidation states +2 to
+5.
In aqueous solution, it forms different colored water complexes as shown in the figure above.
[V(H 2 O) 6 ] 2+
is lilac, [V(H2O) 6 ] 3+
is green, [VO(H 2 O) 5 ] 2+
is blue, and [VO(H 2 O) 5 ] 3+
is
yellow. Which compound do you expect to act as a reducing agent and which as an oxidant?
Solution
As vanadium has electronic configuration 3d 3
4s 2
.In [VO(H2O)5]3+ vanadium is in +5
oxidation state which is maximum oxidation state possessed by vanadium so it will try to accept
the electron or it will reduce itself and oxidize other. So [VO(H2O)5]3+ will act as oxidizing
agent.
While in [V(H2O)6]2+ vanadium is present in +2 oxidation state so it will try to oxidize itself
into +3 or +5 state. So it will act as reducing agent.
and  [V(H2O)6]3+ in this vanadium(V)is present in +3 state so it can either reduce itself to
+2 or oxidize itself to +5 state so it can act both as an oxidizing (oxidant) or reducing agent
(reductant).](https://image.slidesharecdn.com/vanadiumisatransitionmetalthatcanbefoundinthefourconsecuti-230204021723-23e121af/85/vanadium-is-a-transition-metal-that-can-be-found-in-the-four-consecutidocx-1-320.jpg)
