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U.S. Department of Homeland Security
Citizenship and Immigration Services
[LOCATION] Service Center [see p. 10 of the I-589
instructions]
[ADDRESS LINE 1]
[ADDRESS LINE 2]
[DATE]
Re: Letter of Asylum
Respected Sir/ Madam,
My name is __________, I am _____________ years old and I
belong to Tunisia. I migrated to the United States in 2014 after
completing my school. From 2014 to till now I am still living
here as an immigrant. Due to some uncertainties, I left my
homeland. At my homeland, there was a holy site of Muslims
where they teach Quran to children. Later on, I noticed that
there were no more teachings of Quran was given to children,
but instead, it turned out in a reunion house where many Islamic
extremists meet. As there were a lot of people who regularly
visited than and it seems to be abnormal to me. With every
passing day, the number of students reduced and some Islamic
extremist increase. I decided to took a precautionary action by
calling the police and informed them about the current situation.
The police give me special instruction to keep an eye on them
and if I noticed any suspicious activity then urgently call them.
I started noticing their activities, and one day I see that they
were not using this holy site for good purpose. They were using
it for a bad purpose, and they were planning on creating a mess
in the country. From 2012 to 2015, there were many terrorist
attacks in Tunisia. One day I noticed some suspicious activities
in my neighborhood as they were planning for something big. I
immediately called the police and informed them what’s going
on there. At the meanwhile the police arrive, inspect that place
and arrest some of their partners who were accused of doing
such crimes. Some of their fellows admit that they embraced
Radical and they believed in Jihad.
It was my bad luck that some of them found out that it was me
behind the whole strong who informed the police about their
suspicious activities. I started receiving threatening letters from
their side. These letters state that I was never safe because I am
the one who ruined their plan. Sometimes, these lines were also
written on my house wall. Therefore, in 2014 when I completed
my school I left my homeland and moved to the United States.
After living here for one year. I went back to my home in late
2015 to get married. But unfortunately, these groups still
existed there.
I received a letter again from their side that they will not let me
go until they buried six feet under the ground. I didn’t take it
seriously. But after few days when I have my bachelors party, I
got into my house and ruined my whole party. I called the
police. It was my good luck that police arrived on time and save
me. They arrested some of them while other remain successful
in fleeing away from the scene.
I decided to go back to the United States and live my whole life
there. Therefore, I am applying for asylum the land of freedom
and safety. In my homeland, I informed the police about the
whole situation. I did not apply for asylum before I thought that
situation might be changed in my homeland and I will be able to
live there. But it was my bad luck that all things remain the
same after so many years. I was so much stress from this
situation that I have fee meetings with a psychologist that help
me in overcoming my fear.
With this letter, I am also attaching police reports, my medical
reports along with psychologist certificate. Please do not
hesitate to connect me at my number. If you have any question
regarding my matter, please call me. Thank you for your
consideration.
Sincerely,
Name: ___________________
Cell Number: ___________________
HYPOTHESIS TESTING 1
Course Project - Phase 3 6
Course Project - Phase 3
Jessica Seifert
Rasmussen College
January 21, 2018
1. Discuss the process of hypothesis testing.
In statistics and other subjects of learning, the hypothesis is an
opinion or a claim on an issue or item which is then tested to
find out if it is accurate. The statistical inference to be specific
is a conjuncture on a population parameter which then gets
checked to find out whether it is correct or not.
2. The eight steps of hypothesis testing
I. Null hypothesis stating
This process involves the creation of a statement that can get
defined on the opposite side of the calculated guess towards the
research. A good example is where a biologist thinks that using
fertilizer will lead to different height for the plants. The null
hypothesis, in this instance, will be that there will be no
different is plant heights.
II. Alternative Hypothesis
This statement is the opposite of null hypothesis. In our
example,
the alternative hypothesis will be that there will be a difference
in plant heights.
III. Setting the level of significance
This process is setting the probability of the commitment of a
Type 1 error which is arguably the most grievous error one can
commit when conducting the exercise. The error gets denoted by
α.
IV. Data collection
This part is where the data set gets collected. That implies that
the data collection can either be observational or experimental
exercises.
V. Test statistic
In this stage, one states what they want to test this could be the
sample proportion, sample mean or a difference of the two.
VI. Decision on type of test
The test can either be one or two-tailed. One tail testing is
where the error will be found on one side of the data while two-
tailed testing is where the error will be on the two side
extremes.
VII. Acceptance or rejection regions
This method is where the critical values of the test will be used
to determine the rejection or acceptance region of the
hypothesis. An appropriate level of significance is used to
manage the regions.
VIII. Standardization of the test statistic
This part is where the z-test will assist in the decision making
on the rejection and acceptance of the set hypothesis. The
standardization helps in concluding H0 so that where p-value
will be less than less than α, then Accept Ha and Reject H0.
3. Preferred method - P-Value method or Critical Value
method? Why?
The critical value is the preferred method as it involves the
determination of the unlikeliness or likeliness thereby
determining whether the observed test statistic is extreme than
the expectation of the null hypothesis was correct. It entails the
comparison between the test statistic and a cutoff value known
as the critical value. Where the test statistic is found to be
extreme than the critical value, the null hypothesis will get
rejected, and the alternative hypothesis accepted and vice versa.
This method gives a clear explanation on when to accept or
reject the null hypothesis.
4. Test the hypothesis for the Minnesota case.
Since σ is unknown, we thus use the t-test which is given by:
t = (Mean –u)/s/√n
Mean = 65,000
From the case scenario, the mean is u = 62,306
And the standard deviation is unknown. Hence we use the
sample in scenario 1=19149
Sample size n= 364.
Definition of the hypothesis will be
H0= The average wage for all jobs in Minnesota is equal to
$65,000.(μ=65000)
H1= the average salary for all jobs in Minnesota less than
$65,000( μ<65000)
Hence t = (65000-62306)/(19149/√364
t = 2694/100.68
t = 2.68
At α = 0.05 with n-1 degree of freedom (364-1)=363 under one
tail
t- Value v= 1.658
Since the t-computed (2.68) is greater than t-tabulated (from
table=1.658), the null hypothesis will be rejection, and a
conclusion made that the average salary for all job categories is
lower than $65,000.
5. Null and alternative hypothesis symbolically
H0= μ=65,000
H1= μ<65,000
6. Is the test two-tailed, left-tailed or even right-tailed?
Explain…
The test is left tailed since the chances for the average salary
being lower than the mean are greater. This part is on the left-
hand side of the normal distribution shape.
7. Which test statistic will you use for your hypothesis test;
z-test or t-test? Explain.
A t-test will get used because the data gets normally distributed
and that the σ is unknown therefore the need for finding the
standard error to be able to standardize the average salary.
8. What is the value of the test statistic? What is the P-value?
t=2.68, p-value<0.05.
9. What is the critical Value?
From the table t (.05,263) =1.658
10. What is your decision?
The decision is to reject null hypothesis since the t-computed
(2.68) is greater than the t-tabulate found from the table (1.658)
at p<.05
11. The conclusion in non-technical terms
The null hypothesis got rejected because there was enough
evidence to show that the average salary for all job categories is
lower than $65,000.
Running Head: STATISTICS – CONFIDENCE INTERVALS 1
CONFIDENCE INTERVALS 5
Course Project - Phase 2
Jessica Seifert
Rasmussen College
January 12, 2018
Question 1
Confidence intervals get used for giving a range of two
figures whereby we can expect the population parameter which
would include the mean to fall in within. Confidence intervals
include confidence levels which get given by a percentage of
how sure we are on where the population parameter will fall
into the specified range. The confidence interval is calculated
using the below formula: (x ̅-E<μ<x ̅+E).
A point estimate is represented as a single value and can also
be said to be one statistic.
An example is the best point estimate for a population mean
(μ) would be defined as a sample mean (x ̅). This is arguably the
best point estimate because we are aware of the value of the
entire population`s mean and therefore would take a sample of
the population and calculate the sample mean and then use it on
our confidence interval formula which would help in figuring
the entire range of the whole population.
Confidence intervals get used as we are not aware of what is
the real value of the population parameter. We, therefore, opt to
use a small sample data to help us get a better idea of the data.
Question 2
After reviewing the data in the excel sheet, I found that the
sample mean 62,306 although both sample mean and population
mean are not the same it’s a reasonable point estimate for the
population mean. I found the standard deviation of my
spreadsheet is 19,149.21.
Question 3
We already know that the sample mean is (x ̅=62,306) and
sample standard deviation (s=19,149.21), we would have to find
our margin of error to construct our confidence interval. The
formula to see our margin of error when σ is unknown is
=t_(α/2) ∙s/√n. To solve this equating we need to find our t
critical value corresponding to a 95% confidence level.
Step 1
Degrees of freedom (df) = n-1
364-1 = 363
Alpha (α) = 1-(confidence level/100)
= 1-(95/100)
=0.05
Critical probability (p) = 1-( α/2).
= 05/2 is .025
1-0.25 = p=.975.
Step 2
Use excel formula to find t critical value
=T.INV(.975,363) gives us t_(α/2)=1.967
To calculate margin of error
=1.967*19,149.21/sqrt(364)
E=1,974.261
(x ̅-E<μ<x ̅+E). 62,306 – 1,974.261=60,331.739,
and 62,306 + 1,974.261=64,280.261
The confidence interval in this scenario being (60,331.739 < μ <
64,280.261).
Question 4
This confidence interval means that the population mean of the
salaries in Minnesota that range in between $40,000 and
$120,000 have a 95% chance of being around $60,331.739 and
$64,280.261 a year. The values give a range in which to expect
the value of the mean of the population. The sample mean is the
midpoint between the two numbers that provide the confidence
interval. For this reason, the sample mean is referred to as the
best point estimate of the population mean.
Question 5
The confidence intervals are 95% and 99%. This affects the
standard deviation since the other factors are constant. As
standard deviation changes so do risk, it reduces as one
increases the confidence interval. Increase in confidence
interval means a subsequent increase in standard deviation.
A confidence interval is meant to give a range of values
where the estimated value will fall. The best value to use as the
point of the estimate is the mean of the sample data. This occurs
when the midpoint of two figures that are part of the range
where the actual number could fall. By reducing the confidence
interval, one increases the risk of the figure falling outside the
set intervals. This means that the likelihood of obtaining the
actual value would be reduced dramatically. The vice versa is
also correct, increasing the confidence interval minimizes the
probability of the value falling outside the set interval.
Running Head: Analysis of the job salaries
Examine Job salaries for the state of Minnesota.
Jessica Seifert
Rasmussen College
January 6, 2018
Background of the data
The provided data in excel sheet is all about different job types
in a specific area Minnesota.
The data shows and explains us about the Salary of given job
type. The salary gets presented in per annum terms. The
objective of this analysis is to understand the salary distribution
for different types of jobs.
The provided excel sheet data contains 364 various job types.
The given excel gets supplied by Bureau of Labor Statistics.
In the given data there are two types of attributes (variables).
1) Job title
2) Salary
The job title is qualitative, and the level of measurement of the
job title is nominal.
The salary gets presented in digits that are quantitative and
discrete data, and the level of measurement of the wage is the
ratio.
Importance of the measure of variation and central tendency
The size of the center tendency plays a substantial and essential
in our daily life. It helps us to figure out the single center point
and help us to figure out reference point of the whole data. The
most well-known and commonly used measure of central
tendency is mean. The mode shows the most data value in the
data and median tells help us to find middle amounts of the
arranged data. So, the measure of center is significant as they
help us to use reference point of the whole data from that we
can analyze different real-life problems. (Pharmacother, 2011)
The Measures of variation shows and make the data accessible
to know the consistency in the entire data or a specific data
values, the measure of change shows us that how the data varied
in the data set and we can easily compare the two data sets. The
different types of sizes of variation, like standard deviation,
mean deviation, quartile deviation, the coefficient of variation
these all get used in the different scenarios in various aspects
which help us understand the data efficiently. (Pharmacother,
2011)
Using excel command the output of the descriptive statistics
gets presented below.
Salary
Mean
62306.13
Standard Error
1003.692
Median
56520
Mode
46100
Standard Deviation
19149.21
Sample Variance
3.67E+08
Kurtosis
0.258251
Skewness
1.028919
Range
79680
Minimum
40170
Maximum
119850
Sum
22679430
Count
364
Confidence Level (95.0%)
1973.78
Mid-range = (min+ max) / 2
Mid-Range
80010
References
Pharmacother, J. P. (2011). Measures of central tendency.

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  • 1. U.S. Department of Homeland Security Citizenship and Immigration Services [LOCATION] Service Center [see p. 10 of the I-589 instructions] [ADDRESS LINE 1] [ADDRESS LINE 2] [DATE] Re: Letter of Asylum Respected Sir/ Madam, My name is __________, I am _____________ years old and I belong to Tunisia. I migrated to the United States in 2014 after completing my school. From 2014 to till now I am still living here as an immigrant. Due to some uncertainties, I left my homeland. At my homeland, there was a holy site of Muslims where they teach Quran to children. Later on, I noticed that there were no more teachings of Quran was given to children, but instead, it turned out in a reunion house where many Islamic extremists meet. As there were a lot of people who regularly visited than and it seems to be abnormal to me. With every passing day, the number of students reduced and some Islamic extremist increase. I decided to took a precautionary action by calling the police and informed them about the current situation. The police give me special instruction to keep an eye on them and if I noticed any suspicious activity then urgently call them. I started noticing their activities, and one day I see that they were not using this holy site for good purpose. They were using it for a bad purpose, and they were planning on creating a mess in the country. From 2012 to 2015, there were many terrorist attacks in Tunisia. One day I noticed some suspicious activities in my neighborhood as they were planning for something big. I immediately called the police and informed them what’s going on there. At the meanwhile the police arrive, inspect that place and arrest some of their partners who were accused of doing such crimes. Some of their fellows admit that they embraced
  • 2. Radical and they believed in Jihad. It was my bad luck that some of them found out that it was me behind the whole strong who informed the police about their suspicious activities. I started receiving threatening letters from their side. These letters state that I was never safe because I am the one who ruined their plan. Sometimes, these lines were also written on my house wall. Therefore, in 2014 when I completed my school I left my homeland and moved to the United States. After living here for one year. I went back to my home in late 2015 to get married. But unfortunately, these groups still existed there. I received a letter again from their side that they will not let me go until they buried six feet under the ground. I didn’t take it seriously. But after few days when I have my bachelors party, I got into my house and ruined my whole party. I called the police. It was my good luck that police arrived on time and save me. They arrested some of them while other remain successful in fleeing away from the scene. I decided to go back to the United States and live my whole life there. Therefore, I am applying for asylum the land of freedom and safety. In my homeland, I informed the police about the whole situation. I did not apply for asylum before I thought that situation might be changed in my homeland and I will be able to live there. But it was my bad luck that all things remain the same after so many years. I was so much stress from this situation that I have fee meetings with a psychologist that help me in overcoming my fear. With this letter, I am also attaching police reports, my medical reports along with psychologist certificate. Please do not hesitate to connect me at my number. If you have any question regarding my matter, please call me. Thank you for your consideration. Sincerely, Name: ___________________ Cell Number: ___________________
  • 3. HYPOTHESIS TESTING 1 Course Project - Phase 3 6 Course Project - Phase 3 Jessica Seifert Rasmussen College January 21, 2018 1. Discuss the process of hypothesis testing. In statistics and other subjects of learning, the hypothesis is an opinion or a claim on an issue or item which is then tested to find out if it is accurate. The statistical inference to be specific is a conjuncture on a population parameter which then gets checked to find out whether it is correct or not. 2. The eight steps of hypothesis testing I. Null hypothesis stating This process involves the creation of a statement that can get defined on the opposite side of the calculated guess towards the research. A good example is where a biologist thinks that using fertilizer will lead to different height for the plants. The null
  • 4. hypothesis, in this instance, will be that there will be no different is plant heights. II. Alternative Hypothesis This statement is the opposite of null hypothesis. In our example, the alternative hypothesis will be that there will be a difference in plant heights. III. Setting the level of significance This process is setting the probability of the commitment of a Type 1 error which is arguably the most grievous error one can commit when conducting the exercise. The error gets denoted by α. IV. Data collection This part is where the data set gets collected. That implies that the data collection can either be observational or experimental exercises. V. Test statistic In this stage, one states what they want to test this could be the sample proportion, sample mean or a difference of the two. VI. Decision on type of test The test can either be one or two-tailed. One tail testing is where the error will be found on one side of the data while two- tailed testing is where the error will be on the two side extremes. VII. Acceptance or rejection regions This method is where the critical values of the test will be used to determine the rejection or acceptance region of the hypothesis. An appropriate level of significance is used to manage the regions. VIII. Standardization of the test statistic This part is where the z-test will assist in the decision making on the rejection and acceptance of the set hypothesis. The standardization helps in concluding H0 so that where p-value will be less than less than α, then Accept Ha and Reject H0. 3. Preferred method - P-Value method or Critical Value
  • 5. method? Why? The critical value is the preferred method as it involves the determination of the unlikeliness or likeliness thereby determining whether the observed test statistic is extreme than the expectation of the null hypothesis was correct. It entails the comparison between the test statistic and a cutoff value known as the critical value. Where the test statistic is found to be extreme than the critical value, the null hypothesis will get rejected, and the alternative hypothesis accepted and vice versa. This method gives a clear explanation on when to accept or reject the null hypothesis. 4. Test the hypothesis for the Minnesota case. Since σ is unknown, we thus use the t-test which is given by: t = (Mean –u)/s/√n Mean = 65,000 From the case scenario, the mean is u = 62,306 And the standard deviation is unknown. Hence we use the sample in scenario 1=19149 Sample size n= 364. Definition of the hypothesis will be H0= The average wage for all jobs in Minnesota is equal to $65,000.(μ=65000) H1= the average salary for all jobs in Minnesota less than $65,000( μ<65000) Hence t = (65000-62306)/(19149/√364 t = 2694/100.68 t = 2.68 At α = 0.05 with n-1 degree of freedom (364-1)=363 under one tail t- Value v= 1.658 Since the t-computed (2.68) is greater than t-tabulated (from table=1.658), the null hypothesis will be rejection, and a conclusion made that the average salary for all job categories is lower than $65,000. 5. Null and alternative hypothesis symbolically H0= μ=65,000
  • 6. H1= μ<65,000 6. Is the test two-tailed, left-tailed or even right-tailed? Explain… The test is left tailed since the chances for the average salary being lower than the mean are greater. This part is on the left- hand side of the normal distribution shape. 7. Which test statistic will you use for your hypothesis test; z-test or t-test? Explain. A t-test will get used because the data gets normally distributed and that the σ is unknown therefore the need for finding the standard error to be able to standardize the average salary. 8. What is the value of the test statistic? What is the P-value? t=2.68, p-value<0.05. 9. What is the critical Value? From the table t (.05,263) =1.658 10. What is your decision? The decision is to reject null hypothesis since the t-computed (2.68) is greater than the t-tabulate found from the table (1.658) at p<.05 11. The conclusion in non-technical terms The null hypothesis got rejected because there was enough evidence to show that the average salary for all job categories is lower than $65,000.
  • 7. Running Head: STATISTICS – CONFIDENCE INTERVALS 1 CONFIDENCE INTERVALS 5 Course Project - Phase 2 Jessica Seifert Rasmussen College January 12, 2018 Question 1 Confidence intervals get used for giving a range of two figures whereby we can expect the population parameter which would include the mean to fall in within. Confidence intervals include confidence levels which get given by a percentage of how sure we are on where the population parameter will fall into the specified range. The confidence interval is calculated using the below formula: (x ̅-E<μ<x ̅+E). A point estimate is represented as a single value and can also be said to be one statistic. An example is the best point estimate for a population mean (μ) would be defined as a sample mean (x ̅). This is arguably the best point estimate because we are aware of the value of the
  • 8. entire population`s mean and therefore would take a sample of the population and calculate the sample mean and then use it on our confidence interval formula which would help in figuring the entire range of the whole population. Confidence intervals get used as we are not aware of what is the real value of the population parameter. We, therefore, opt to use a small sample data to help us get a better idea of the data. Question 2 After reviewing the data in the excel sheet, I found that the sample mean 62,306 although both sample mean and population mean are not the same it’s a reasonable point estimate for the population mean. I found the standard deviation of my spreadsheet is 19,149.21. Question 3 We already know that the sample mean is (x ̅=62,306) and sample standard deviation (s=19,149.21), we would have to find our margin of error to construct our confidence interval. The formula to see our margin of error when σ is unknown is =t_(α/2) ∙s/√n. To solve this equating we need to find our t critical value corresponding to a 95% confidence level. Step 1 Degrees of freedom (df) = n-1 364-1 = 363 Alpha (α) = 1-(confidence level/100) = 1-(95/100) =0.05 Critical probability (p) = 1-( α/2). = 05/2 is .025 1-0.25 = p=.975. Step 2 Use excel formula to find t critical value =T.INV(.975,363) gives us t_(α/2)=1.967
  • 9. To calculate margin of error =1.967*19,149.21/sqrt(364) E=1,974.261 (x ̅-E<μ<x ̅+E). 62,306 – 1,974.261=60,331.739, and 62,306 + 1,974.261=64,280.261 The confidence interval in this scenario being (60,331.739 < μ < 64,280.261). Question 4 This confidence interval means that the population mean of the salaries in Minnesota that range in between $40,000 and $120,000 have a 95% chance of being around $60,331.739 and $64,280.261 a year. The values give a range in which to expect the value of the mean of the population. The sample mean is the midpoint between the two numbers that provide the confidence interval. For this reason, the sample mean is referred to as the best point estimate of the population mean. Question 5 The confidence intervals are 95% and 99%. This affects the standard deviation since the other factors are constant. As standard deviation changes so do risk, it reduces as one increases the confidence interval. Increase in confidence interval means a subsequent increase in standard deviation. A confidence interval is meant to give a range of values where the estimated value will fall. The best value to use as the point of the estimate is the mean of the sample data. This occurs when the midpoint of two figures that are part of the range where the actual number could fall. By reducing the confidence interval, one increases the risk of the figure falling outside the set intervals. This means that the likelihood of obtaining the actual value would be reduced dramatically. The vice versa is also correct, increasing the confidence interval minimizes the probability of the value falling outside the set interval.
  • 10. Running Head: Analysis of the job salaries Examine Job salaries for the state of Minnesota. Jessica Seifert Rasmussen College January 6, 2018 Background of the data The provided data in excel sheet is all about different job types in a specific area Minnesota. The data shows and explains us about the Salary of given job type. The salary gets presented in per annum terms. The objective of this analysis is to understand the salary distribution for different types of jobs. The provided excel sheet data contains 364 various job types. The given excel gets supplied by Bureau of Labor Statistics. In the given data there are two types of attributes (variables). 1) Job title 2) Salary The job title is qualitative, and the level of measurement of the job title is nominal. The salary gets presented in digits that are quantitative and discrete data, and the level of measurement of the wage is the
  • 11. ratio. Importance of the measure of variation and central tendency The size of the center tendency plays a substantial and essential in our daily life. It helps us to figure out the single center point and help us to figure out reference point of the whole data. The most well-known and commonly used measure of central tendency is mean. The mode shows the most data value in the data and median tells help us to find middle amounts of the arranged data. So, the measure of center is significant as they help us to use reference point of the whole data from that we can analyze different real-life problems. (Pharmacother, 2011) The Measures of variation shows and make the data accessible to know the consistency in the entire data or a specific data values, the measure of change shows us that how the data varied in the data set and we can easily compare the two data sets. The different types of sizes of variation, like standard deviation, mean deviation, quartile deviation, the coefficient of variation these all get used in the different scenarios in various aspects which help us understand the data efficiently. (Pharmacother, 2011) Using excel command the output of the descriptive statistics gets presented below. Salary Mean 62306.13 Standard Error 1003.692 Median 56520 Mode 46100 Standard Deviation
  • 13. References Pharmacother, J. P. (2011). Measures of central tendency.