Let x be the number of students that visit Dr. Smith\'s office on a given day. The following table lists the probability distribution of x. 3. 0 .24 2 .12 .08 04 P(x) .28 .24 Solution Probability that Dr.Smith has atleast one student visit,given that fewer than 4 students visit =P(X>=1|X<4) =P(X>=1,X<4) /P(X<4) =(P(X=1)+P(X=2)+P(X=3) )/(P(X=0)+P(X=1)+P(X=2)+P(X=3)) =0.727273.