Based on the number of Barr bodies seen in the somatic cells of the following individuals
assume their most probable phenotypes and karyotypes: a. For example, John has no Barr body:
i. Phenotype: Normal man ii. Karyotype: 46,XY b. Sue has no Barr body: i. Phenotype: i.
Karyotype:. c. Julie has three Barr bodies: Phenotype: ii. Karyotype:. i. d. Margie is clinically
diagnosed as a case of Turner syndrome. She has 46 chromosomes and an unusually very small
Barr body. In spite of having genotype Aa, she does not show phenotypic mosaicism. Why: Janet
is a carrier for Huntington disease and has decided not to have any child. For this and other
reasons she married Jeff who was diagnosed as a case of klinefleter, But, surprisingly, Janet is
pregnant, and fetal paternity test shows that Jeff is the father of the fetus. Based on Jeff\'s
chromosomal study, the couple have been informed that Jeff still might father another child.
Jeff\'s chromosomal constitution could be e. f. Jim is nfertile, has 46 chromosomes and one Barr
body i. Phenotype could be Karyotype could be
Solution
B. Sue.
Phenotype: Turner syndrome Female.
Karyotype: 45, XO
C.Julie:
Phenotype: Poly X female.
Karyotype: 48, XXXX.
D. In the case of Margie, she has 46 chromosomes and a single Barr body. It is the karyotype of
normal female and not Turner syndrome female. In case of Turner syndrome, one X
chromosome is missing in females and resulting karyotype is 45, XO.
E.
F. Jim being infertile with one Barr body
Phenotype: klinefelter syndrome male.
Karyotype: 47, XXY..
Based on the number of Barr bodies seen in the somatic cells of the f.pdf
1. Based on the number of Barr bodies seen in the somatic cells of the following individuals
assume their most probable phenotypes and karyotypes: a. For example, John has no Barr body:
i. Phenotype: Normal man ii. Karyotype: 46,XY b. Sue has no Barr body: i. Phenotype: i.
Karyotype:. c. Julie has three Barr bodies: Phenotype: ii. Karyotype:. i. d. Margie is clinically
diagnosed as a case of Turner syndrome. She has 46 chromosomes and an unusually very small
Barr body. In spite of having genotype Aa, she does not show phenotypic mosaicism. Why: Janet
is a carrier for Huntington disease and has decided not to have any child. For this and other
reasons she married Jeff who was diagnosed as a case of klinefleter, But, surprisingly, Janet is
pregnant, and fetal paternity test shows that Jeff is the father of the fetus. Based on Jeff's
chromosomal study, the couple have been informed that Jeff still might father another child.
Jeff's chromosomal constitution could be e. f. Jim is nfertile, has 46 chromosomes and one Barr
body i. Phenotype could be Karyotype could be
Solution
B. Sue.
Phenotype: Turner syndrome Female.
Karyotype: 45, XO
C.Julie:
Phenotype: Poly X female.
Karyotype: 48, XXXX.
D. In the case of Margie, she has 46 chromosomes and a single Barr body. It is the karyotype of
normal female and not Turner syndrome female. In case of Turner syndrome, one X
chromosome is missing in females and resulting karyotype is 45, XO.
E.
F. Jim being infertile with one Barr body
Phenotype: klinefelter syndrome male.
Karyotype: 47, XXY.
