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Today:
 Warm Up
 Class Notes; Solving Quadratic Equations
 Questions from Class Work??
 Factoring Test
Factoring (ax2
+ bx + c) Trinomials
Factor 5x4y –
80x2y3
Warm Up/Test Review
Factor 5x – 5y + ax -
ay
Factor 16x2 – 8xy + y2
2𝑥2
+ 19𝑥 + 24
Quadratic Equations: (Write this down)
Class Notes:
1. Have a highest degree of 2.
2. Have a standard form of: ax2 + bx + c = 0
3. Have a graph which always results in a parabola.
4. Have solutions which
show the x intercept(s)
Solve: x2 + 3x - 4 = 0
(x ) (x ) = 0+ -4 1
x = (-4, 1)
x2 = 25, 4y2 + 2y - 1 = 0, y2 + 6y = 0, x2 + 2x - 4 = 0
The following are all examples of
quadratic equations:
A). The graphs of quadratics are not straight lines, they are always in
the shape of a Parabola.
B) Parabolas ALWAYS have two solutions.
C) The slope of a quadratic is not constant. The slope-intercept
formula will not work with parabolas.
What about (x – 4)2
?
These are referred to as repeated solutions.
Find the solutions to this quadratic equation.
D) The solutions of a equation are also called the roots of the equation.
Quadratic Equations
Parabolas: ...In Sports
Parabolas: ...In Archeticture
Parabolas: ...In Nature
Parabolas: ...Everywhere
And, of course, the most important Parabola of all
Solving Quadratic Equations by Factoring
Let's look at some of the different types of equations
you'll face and how to deal with each of them
1: Set the equation = to 0 and solve:
Example A. x2 + 6x + 9
x2 + 6x + 9 = 0; (x + 3) (x + 3) = 0, x = -3.This is a perfect square
trinomial, and the parabola only touches the x axis at -3 and
would be in this shape:
-3
Solving Quadratic Equations by Factoring
2. Solve x2 = 64. Remember the standard form?
ax2 + bx + c = 0, where only a cannot = 0
In this case, b is 0, and c is 64.
We can solve by taking the square root of both sides.
3. Solve: 2x2 - x = 3
Place all terms to the left of the = sign (Standard Form).
The result is x = + 8; x = 8, and x = -8
4. Solve: x2 = 5x ***Do not cancel an 'x' from each side.
Factor GCF first, then solve
Take 5, then we'll begin the test:
Please Clear Your Desks/Tables of everything
Except scratch paper, pencil, calculator.
 You will need:
 Your correct code, pencil only, no phones.,
scratch paper
 You can use a regular calculator, but one is
not necessary for this test.
V.4, Question # 8

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March 27, 2015

  • 1. Today:  Warm Up  Class Notes; Solving Quadratic Equations  Questions from Class Work??  Factoring Test
  • 2. Factoring (ax2 + bx + c) Trinomials Factor 5x4y – 80x2y3 Warm Up/Test Review Factor 5x – 5y + ax - ay Factor 16x2 – 8xy + y2 2𝑥2 + 19𝑥 + 24
  • 3. Quadratic Equations: (Write this down) Class Notes: 1. Have a highest degree of 2. 2. Have a standard form of: ax2 + bx + c = 0 3. Have a graph which always results in a parabola. 4. Have solutions which show the x intercept(s) Solve: x2 + 3x - 4 = 0 (x ) (x ) = 0+ -4 1 x = (-4, 1) x2 = 25, 4y2 + 2y - 1 = 0, y2 + 6y = 0, x2 + 2x - 4 = 0 The following are all examples of quadratic equations:
  • 4. A). The graphs of quadratics are not straight lines, they are always in the shape of a Parabola. B) Parabolas ALWAYS have two solutions. C) The slope of a quadratic is not constant. The slope-intercept formula will not work with parabolas. What about (x – 4)2 ? These are referred to as repeated solutions. Find the solutions to this quadratic equation. D) The solutions of a equation are also called the roots of the equation. Quadratic Equations
  • 8. Parabolas: ...Everywhere And, of course, the most important Parabola of all
  • 9. Solving Quadratic Equations by Factoring Let's look at some of the different types of equations you'll face and how to deal with each of them 1: Set the equation = to 0 and solve: Example A. x2 + 6x + 9 x2 + 6x + 9 = 0; (x + 3) (x + 3) = 0, x = -3.This is a perfect square trinomial, and the parabola only touches the x axis at -3 and would be in this shape: -3
  • 10.
  • 11. Solving Quadratic Equations by Factoring 2. Solve x2 = 64. Remember the standard form? ax2 + bx + c = 0, where only a cannot = 0 In this case, b is 0, and c is 64. We can solve by taking the square root of both sides. 3. Solve: 2x2 - x = 3 Place all terms to the left of the = sign (Standard Form). The result is x = + 8; x = 8, and x = -8 4. Solve: x2 = 5x ***Do not cancel an 'x' from each side. Factor GCF first, then solve
  • 12. Take 5, then we'll begin the test: Please Clear Your Desks/Tables of everything Except scratch paper, pencil, calculator.  You will need:  Your correct code, pencil only, no phones., scratch paper  You can use a regular calculator, but one is not necessary for this test.