excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol the moles of NaOH reacting with carboxylic acid = 0.1135 -0.0533 = 0.0602 mol Solution excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol the moles of NaOH reacting with carboxylic acid = 0.1135 -0.0533 = 0.0602 mol.