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excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol
the moles of NaOH reacting with carboxylic acid = 0.1135 -0.0533 = 0.0602 mol
Solution
excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol
the moles of NaOH reacting with carboxylic acid = 0.1135 -0.0533 = 0.0602 mol

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excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol.pdf

  • 1. excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol the moles of NaOH reacting with carboxylic acid = 0.1135 -0.0533 = 0.0602 mol Solution excess moles (reacting with HCl) of NaOH = 0.0287 x 1.86 =0.0533 mol the moles of NaOH reacting with carboxylic acid = 0.1135 -0.0533 = 0.0602 mol