chemistry hydrogen decom p&d lab

1. Title:Analysisof HydrogenPeroxide
Purpose: To analyze the concentrationof hydrogenperoxidebyusingpotassiumpermanganate in
titrationtobe able tocheck the oxidation.
Materials:I, Hydrogenperoxide solution,3%,4 mL ii.Potassiumpermanganatesolution,KMnO4,0.02
M, 80 mL iii.Sulfuricacidsolution,H2SO4,3 M, 50 mL iv.Ferrousammoniumsulfate,Fe
(NH4)2(SO4)26H2O,3 g v. Water,distilledordeionizedvi.Burette,50mL vii. Beakers,100 mL (2) viii.
Burette clampix.Balance,0.001 g precisionx.Pipet,serological,1mL xi.Pipetbulborpipetfillerxii.
Erlenmeyerflask,250 mL (3) xiii.Graduatedcylinders,10mL (2) xiv.Ringstandxv.Washbottle xvi.Wax
pencil xvii.Weighingboats(2)
Procedure:
1. Setup a clean50 mL burette on burette standwithaburette clamp.
2. Rinse the burette with5-10 mL of water andthenrinse the burette withtwo5- 10 mL portionsof
potassiumpermanganate solution.Then,fill the burettewiththe potassiumpermanganatesolution.
3. Using a 10 mL graduatedcylinder,measure out10 mL of water.Inanother10 mL graduatedcylinder,
measure out10 mL of 3 MH2SO4. Putthe H2O and the H2SO4 intoa 250 mL Erlenmeyerflask.
4. Using a serological pipet,measure 1mL of 3% H2O2 into the Erlenmeyerflask.
5. Swirl the flasktomix the solutions.
6. Place the Erlenmeyerflaskdirectlyunderthe stopcockof the burette withthe potassium
permanganate solution.
7. Slowlytitrate the potassium permanganate solutionintothe Erlenmeyerflaskuntil alightpinkcolor
persistsfor30 seconds,reachingthe equivalence point.
Expected data and results.
Determinationof PercentHydrogenPeroxide:
Qualitative:
VOLUME OF3% H2O2
INITIALVOLUME OF
MnO4
FINALVOLUME OF
MnO4
VOLUME OFMnO4
ADDED

2. Quantitative:
- CalculatedNumberof Molesof H2O2 Reacted:
MolesKMnO4 = MolarityKMnO4 x Volume KMnO4Added
MolesKMnO4 = M x L = moles
MolesH2O2 = MolesKMnO4 x mole H2O2
mole KMnO4
= mole KMnO4x mole H2O2
mole KMnO4
= [ x molesH2O2]
- CalculatedMassof H2O2 Reacted:
Mass of H2O2 = MolesH2O2 x Molar Mass H2O2
Mass of H2O2 = molesx grams
mole
= [ grams H2O2]
- PercentByMass of H2O2 In Solution:
% H2O2 = grams
1.00 g solution
= [ ]

3. Conclusion:Inresulttothe data,one may reach the conclusionthatthe percentof hydrogenperoxidein
the bottle is . There is a difference inthe concentrationgivenonthe label of the bottle. The
label reads3% hydrogenperoxide.Thisdifference indatacouldbe explainedbyhumanerrorandthe
lack of precise equipment.