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# Algebra 2 benchmark 3 review

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### Algebra 2 benchmark 3 review

1. 1. Algebra 2Benchmark Review Ms. Cheung
2. 2. Standard 1.01) The absolute value of any number will always be positive, thus the equation |5 – 6m| > - 7 will always be true!!
3. 3. Standard 1.0 2)10 5x 7 62 10 5x 55 10 5x 55 10 5x 55 5x 45 5x 65 x 9 x 13
4. 4. Standard 2.03. Which order pair is the solution to the system of equations below? x 7 y 20 Solve for x x 7 y 20 4 7 y 20 4 y 16 Substitute for x x 7(2) 20 28 y 80 4 y 16 Distribute x 14 20 32y 80 16 Combine Like Term x 6 32y 64 Combine Like term y 2 Solve for y
5. 5. Standard 2.04. Which order pair is the solution to the system of equations below? 8 x 2 y 20 4x y 2 2 4 x y 2 Multiply 2 to equation 2 4x 6 2 8 x 2 y 20 4x 4 Add the two equations 8x 2 y 4 x 1 4y 24 y 6
6. 6. Standard 2.05) Ms. Cheung’s current phone plan is about to be expired. She has been offered two promotions from two different phone providers. AT&T provides a 500 minute plan at \$30 with 40 cents per text message. T-Mobile provides a 500 minute plan at \$40 with 30 cents per text message. If x represents the number of text sent and y is the total amount charge for both plans, how do you write a system of equations that model this situation? y 30 0.4 x y 40 0 .3 x
7. 7. Standard 2.06) Gerardo wrote a matrix equation. 4 3 x 20 1 2 y 6What is the solution to Gerardo’s equation? 4 3 x 20 4x 3 y 20 1 2 y 6 x 2y 6 4x 3y 20 2, 4 x 2y 6
8. 8. Standard 2.07) Jackie wrote a matrix equation. 2 1 x 3 3 2 y 6What is the solution to Gerardo’s equation? 2 1 x 3 2x y 3 3 2 y 6 3x 2 y 6 2x y 3 0, 3 3x 2 y 6
9. 9. Standard 3.08) 5n 4 3n3 8n 2 3n 4 2n3 7n 2 2n 4 n3 15n 2
10. 10. Standard 3.0 6a 2 6a 14a 14 6a 2 20a 14
11. 11. Standard 3.0 6k 2 12 k 5k 10 6k 2 17k 10
12. 12. Standard 3.011) 6x 4 8x 3 4 2x 4 4x 3 3 4 3 8x 12x 1
13. 13. Standard 3.012)Given a polynomial expression x 4 10x 3 35x 2 50x 24such that it has two factors of ( x 1) and ( x 4).A) (x 1) and ( x 2). 1 4 4B) (x 1) and ( x 3).C) (x 2) and ( x 3). 2 3 6 24 4 6D) (x 3) and ( x 4).
14. 14. Standard 5.013) Which of the following represent the graph of 3 2i ? A C B D
15. 15. Standard 5.014. Kevin knows that 1 i . What will he get if he simplifies 16 ?A) 4 and 4B) 4C) 4iD) 4i and 4i
16. 16. Standard 5.015. Jocelyn knows that 1 i . What will he get if he simplifies 64 ?A) 8 and 8B) 8C) 8i and 8iD) 8i
17. 17. Standard 6.016. Jocelyn knows that 1 i . What will she get if he simplifies 2 25 ?A) 5iB) 10iC) 10iD) 5i
18. 18. Standard 6.017) (3 i )(3 i ) 9 3i 3i i 2 9 ( 1) 10
19. 19. Standard 6.018) 3 2i 5 i 2 3i
20. 20. Standard 6.019) 12 5i ( 3 4i) 12 5i 3 4i 9 i
21. 21. 20) 2p 4 0 a 1, b 0, c 4 0 0 2 4 (1)( 4 ) 16 4 x 2 (1) 2 2 x 2 or x 2
22. 22. 21)6x 2 5x 25 0 a 6, b 5, c 25 5 52 4 ( 6 )( 25) 5 25 600 5 625 5 25 x 2(6) 12 12 12 5 25 5 25 x 12 or x 12 x 5 3 or x 3 5
23. 23. Standard 9.022. Given the graph f(x)=ax2+bx+c. If a is negative, what would my graph look like? f(x)=ax2+bx+c is a Quadratic Equation since it has aA) A linear graph going up power of 2.B) A linear graph going up Since a isC) A quadratic graph going up negative, the graph will be goingD) A quadratic graph going down downward.
24. 24. Standard 9.0 23) Vertex (-3, -2)Vertex From (-3, -2) to (2, 2) (2, 2) We get ( 2, 2) ( 3, 2) (2 3, 2 2) (5, 4) Positive 5, so it’s 5 unit to Positive 4, the right. 4 units UP!!
25. 25. Standard 9.0 24) Vertex (5, 1) Vertex (-5, 1) Both functions are positive, so their vertices are minimums.Both functionshave the samecoefficient: 3, bothhave the sameshape. Both functions are positive, so both vertices are minimum.
26. 26. Standard 10.025) What is the minimum value of the function f(x)=x2 – 9? Minimum  The lowest Point!A) –9 Find the vertex!B) –3 X= - b/2a X = 0/2 = 0C) 0 y = 0 – 9= -9D) 9 The lowest Point!
27. 27. Standard 10.026) X= - b/2a X = -6/2 = - 3 y=(-3)2+6(-3)+5 = 9 – 18 + 5 = - 4 Vertex: ( - 3, - 4)
28. 28. Standard 24.027)
29. 29. Standard 24.028)
30. 30. Standard 24.029) Which of the following functions is the inverse of f(x) = 3x – 2? A) 1 3 f ( x) x 2 B) f 1 ( x) 3 x 2 1 x 2 C) f ( x) 3 D) f 1 ( x) x 2 3
31. 31. Standard 7.030) Rewrite the following exponents to positive exponents. x 2 A) f ( x) 3 y 2 5 x y B) f ( x) 4 2 x y
32. 32. Standard 7.031)
33. 33. Standard 7.032)
34. 34. Standard 7.033)
35. 35. Standard 7.034) -1
36. 36. Standard 22.035) Strategy: Convert to decimal =0.5 + 0.25+ 0.125 + 0.625 + … =0.5 + 0.25+ 0.125 + 0.0625 + … =0.9375 Closest to 1
37. 37. Standard 22.036) Strategy: 1st term 2nd term term 4th term5th term Substitute n=1, 2, 3, 4, 5 3rd into the answer choice to n=1 n=2 n=3 n=4 n=5 see if the term generated is = 4(1) = 4 (first term) same as the question the = 3+4(1) = 7 (first term) = 2(1)+1 = 3 (first term) = 2(2)+1 = 5 (second term) = 4(1)-1 = 3 (first term) = 4(2)-1 = 7 (second term) = 4(3)-1 = 11 (third term) = 4(4)-1 = 15 (fourth term) = 4(5)-1 = 19 (fifth term)
38. 38. Standard PS 1.0 Strategy: Identify Keywords37) P(cm label & no labels) Multiply No. of rulers No. of rulers with cm labels without labels One less ruler Total No. of Rulers
39. 39. Standard PS 1.038) Strategy: Identify Keywords Not raining in San Francisco Multiply and not raining in Sydney P(not raining in SF & not raining in Sydney)
40. 40. Standard PS 1.0 Strategy:39) Identify Keywords Green and green Multiply P(green & green) No. of green marble in 1st No. of green marbles bag in 2nd bag Total No. of Total No. of marbles in 2nd Marbles in bag 1st bag
41. 41. Standard PS 2.040)
42. 42. 41) Standard PS 2.0