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- 1. Algebra 2Benchmark Review Ms. Cheung
- 2. Standard 1.01) The absolute value of any number will always be positive, thus the equation |5 – 6m| > - 7 will always be true!!
- 3. Standard 1.0 2)10 5x 7 62 10 5x 55 10 5x 55 10 5x 55 5x 45 5x 65 x 9 x 13
- 4. Standard 2.03. Which order pair is the solution to the system of equations below? x 7 y 20 Solve for x x 7 y 20 4 7 y 20 4 y 16 Substitute for x x 7(2) 20 28 y 80 4 y 16 Distribute x 14 20 32y 80 16 Combine Like Term x 6 32y 64 Combine Like term y 2 Solve for y
- 5. Standard 2.04. Which order pair is the solution to the system of equations below? 8 x 2 y 20 4x y 2 2 4 x y 2 Multiply 2 to equation 2 4x 6 2 8 x 2 y 20 4x 4 Add the two equations 8x 2 y 4 x 1 4y 24 y 6
- 6. Standard 2.05) Ms. Cheung’s current phone plan is about to be expired. She has been offered two promotions from two different phone providers. AT&T provides a 500 minute plan at $30 with 40 cents per text message. T-Mobile provides a 500 minute plan at $40 with 30 cents per text message. If x represents the number of text sent and y is the total amount charge for both plans, how do you write a system of equations that model this situation? y 30 0.4 x y 40 0 .3 x
- 7. Standard 2.06) Gerardo wrote a matrix equation. 4 3 x 20 1 2 y 6What is the solution to Gerardo’s equation? 4 3 x 20 4x 3 y 20 1 2 y 6 x 2y 6 4x 3y 20 2, 4 x 2y 6
- 8. Standard 2.07) Jackie wrote a matrix equation. 2 1 x 3 3 2 y 6What is the solution to Gerardo’s equation? 2 1 x 3 2x y 3 3 2 y 6 3x 2 y 6 2x y 3 0, 3 3x 2 y 6
- 9. Standard 3.08) 5n 4 3n3 8n 2 3n 4 2n3 7n 2 2n 4 n3 15n 2
- 10. Standard 3.0 6a 2 6a 14a 14 6a 2 20a 14
- 11. Standard 3.0 6k 2 12 k 5k 10 6k 2 17k 10
- 12. Standard 3.011) 6x 4 8x 3 4 2x 4 4x 3 3 4 3 8x 12x 1
- 13. Standard 3.012)Given a polynomial expression x 4 10x 3 35x 2 50x 24such that it has two factors of ( x 1) and ( x 4).A) (x 1) and ( x 2). 1 4 4B) (x 1) and ( x 3).C) (x 2) and ( x 3). 2 3 6 24 4 6D) (x 3) and ( x 4).
- 14. Standard 5.013) Which of the following represent the graph of 3 2i ? A C B D
- 15. Standard 5.014. Kevin knows that 1 i . What will he get if he simplifies 16 ?A) 4 and 4B) 4C) 4iD) 4i and 4i
- 16. Standard 5.015. Jocelyn knows that 1 i . What will he get if he simplifies 64 ?A) 8 and 8B) 8C) 8i and 8iD) 8i
- 17. Standard 6.016. Jocelyn knows that 1 i . What will she get if he simplifies 2 25 ?A) 5iB) 10iC) 10iD) 5i
- 18. Standard 6.017) (3 i )(3 i ) 9 3i 3i i 2 9 ( 1) 10
- 19. Standard 6.018) 3 2i 5 i 2 3i
- 20. Standard 6.019) 12 5i ( 3 4i) 12 5i 3 4i 9 i
- 21. 20) 2p 4 0 a 1, b 0, c 4 0 0 2 4 (1)( 4 ) 16 4 x 2 (1) 2 2 x 2 or x 2
- 22. 21)6x 2 5x 25 0 a 6, b 5, c 25 5 52 4 ( 6 )( 25) 5 25 600 5 625 5 25 x 2(6) 12 12 12 5 25 5 25 x 12 or x 12 x 5 3 or x 3 5
- 23. Standard 9.022. Given the graph f(x)=ax2+bx+c. If a is negative, what would my graph look like? f(x)=ax2+bx+c is a Quadratic Equation since it has aA) A linear graph going up power of 2.B) A linear graph going up Since a isC) A quadratic graph going up negative, the graph will be goingD) A quadratic graph going down downward.
- 24. Standard 9.0 23) Vertex (-3, -2)Vertex From (-3, -2) to (2, 2) (2, 2) We get ( 2, 2) ( 3, 2) (2 3, 2 2) (5, 4) Positive 5, so it’s 5 unit to Positive 4, the right. 4 units UP!!
- 25. Standard 9.0 24) Vertex (5, 1) Vertex (-5, 1) Both functions are positive, so their vertices are minimums.Both functionshave the samecoefficient: 3, bothhave the sameshape. Both functions are positive, so both vertices are minimum.
- 26. Standard 10.025) What is the minimum value of the function f(x)=x2 – 9? Minimum The lowest Point!A) –9 Find the vertex!B) –3 X= - b/2a X = 0/2 = 0C) 0 y = 0 – 9= -9D) 9 The lowest Point!
- 27. Standard 10.026) X= - b/2a X = -6/2 = - 3 y=(-3)2+6(-3)+5 = 9 – 18 + 5 = - 4 Vertex: ( - 3, - 4)
- 28. Standard 24.027)
- 29. Standard 24.028)
- 30. Standard 24.029) Which of the following functions is the inverse of f(x) = 3x – 2? A) 1 3 f ( x) x 2 B) f 1 ( x) 3 x 2 1 x 2 C) f ( x) 3 D) f 1 ( x) x 2 3
- 31. Standard 7.030) Rewrite the following exponents to positive exponents. x 2 A) f ( x) 3 y 2 5 x y B) f ( x) 4 2 x y
- 32. Standard 7.031)
- 33. Standard 7.032)
- 34. Standard 7.033)
- 35. Standard 7.034) -1
- 36. Standard 22.035) Strategy: Convert to decimal =0.5 + 0.25+ 0.125 + 0.625 + … =0.5 + 0.25+ 0.125 + 0.0625 + … =0.9375 Closest to 1
- 37. Standard 22.036) Strategy: 1st term 2nd term term 4th term5th term Substitute n=1, 2, 3, 4, 5 3rd into the answer choice to n=1 n=2 n=3 n=4 n=5 see if the term generated is = 4(1) = 4 (first term) same as the question the = 3+4(1) = 7 (first term) = 2(1)+1 = 3 (first term) = 2(2)+1 = 5 (second term) = 4(1)-1 = 3 (first term) = 4(2)-1 = 7 (second term) = 4(3)-1 = 11 (third term) = 4(4)-1 = 15 (fourth term) = 4(5)-1 = 19 (fifth term)
- 38. Standard PS 1.0 Strategy: Identify Keywords37) P(cm label & no labels) Multiply No. of rulers No. of rulers with cm labels without labels One less ruler Total No. of Rulers
- 39. Standard PS 1.038) Strategy: Identify Keywords Not raining in San Francisco Multiply and not raining in Sydney P(not raining in SF & not raining in Sydney)
- 40. Standard PS 1.0 Strategy:39) Identify Keywords Green and green Multiply P(green & green) No. of green marble in 1st No. of green marbles bag in 2nd bag Total No. of Total No. of marbles in 2nd Marbles in bag 1st bag
- 41. Standard PS 2.040)
- 42. 41) Standard PS 2.0

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