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Bell, Buddhism, QM
Richard Gill
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☯
Question: can you colour the four balls green and red, so that
the two on the bottom have the same colour ❤️
the two on top have different colours ☯
the two on the
left have the
same colour ❤️
the two on the
right have the
same colour ❤️
❤️
❤️
❤️
☯
✓
✓
✓
✗
❤️
❤️
❤️
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✓
✓
✓
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☯
✓
✓
✗
✓
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✓
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❤️
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✓
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❤️
☯
✓
✗
✗
✗
❤️
❤️
❤️
☯
Question: can you colour the four balls green and red, so that
Answer:
No you can’t.
Either one
or three
failures
the two on top have different colours ☯
the two on the
left have the
same colour ❤️
the two on the
right have the
same colour ❤️
the two on the bottom have the same colour ❤️
Bell game
• Alice and Bob collaborate against Eve
• Alice and Bob get to colour the balls
(two each, opposite corners)
• Eve gets to choose a side of the square
= one of Alice’s and one of Bob’s balls
• Alice and Bob want their colours to comply with the
requirement on Eve’s chosen side (other sides
don’t matter)
J. S. Bell (1964) “On the Einstein Podolski Rosen paradox”
❤️
❤️
❤️
☯
Alice
1
Alice
2
Bob
1
Bob
2
Eve chooses a side
= one of Alice’s &
one of Bob’s balls
Bell game
• Alice chooses colours top left and right bottom ball
• Bob chooses colours top right and left bottom ball
• Eve chooses one of the four sides = chooses one of Alice’s two balls and
one of Bob’s two balls
• Alice and Bob win if their chosen colours comply with the demand for Eve’s
chosen side
• Optimal strategy for Alice and Bob: choose colouring with mismatch on one
side; side of mismatch completely random
• Optimal strategy for Eve: choose one of the four sides completely at random
• Alice and Bob will win three times out of four (i.e., with probability 75%)
Bell game
• What if Eve has to choose first, Alice and Bob
colour afterwards? (or vice versa)
• Boring game!
• We’ll make it more interesting by separating Alice
and Bob and only telling them which ball of theirs
will be checked, afterwards
Bell game:
distributed variant
• Alice and Bob confer (in secret)
• Alice and Bob are separated (no more
communication; but they can take notebooks,
computers, etc etc with them)
• Eve tells Alice which of her two balls will be inspected
• Eve tells Bob which of his two balls will be inspected
• Alice and Bob choose colours of designated balls
Bell game:
distributed variant
• Optimal (classical) solution: Alice and Bob choose
in advance, at random, one of the “solutions” of the
original game
• Why? Because they may as well perform in
advance (in secret) any randomisations (tosses of
coins, dice throws…) which might be needed; and
they might just as well decide in advance how each
of their own two balls will be coloured if it happens
to get chosen
Bell game:
distributed variant
• Optimal (quantum) solution: Alice and Bob each take
one part of a pair of maximally entangled qubits with
them (qubit = quantum two-level system, e.g.,
polarisation of a photon, spin of an electron, …)
• When told which ball they should colour, they measure
their qubit according to one of two pre-chosen settings,
and colour according to measurement outcome
• Alice and Bob can win with probability 85%
= 100 * (1 / 2 + √2 / 4) %
Alice 1
Alice 2
Bob 1
Bob 2
❤️
❤️
❤️
☯
Measuring in
(nearly) opposite directions
gives (mostly) same result ❤️
Measuring in
(nearly) same directions
gives (mostly) opposite result ☯
Singlet state, two spin half particles

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Bell, Buddhism, QM

  • 2. ❤️ ❤️ ❤️ ☯ Question: can you colour the four balls green and red, so that the two on the bottom have the same colour ❤️ the two on top have different colours ☯ the two on the left have the same colour ❤️ the two on the right have the same colour ❤️
  • 9. ❤️ ❤️ ❤️ ☯ Question: can you colour the four balls green and red, so that Answer: No you can’t. Either one or three failures the two on top have different colours ☯ the two on the left have the same colour ❤️ the two on the right have the same colour ❤️ the two on the bottom have the same colour ❤️
  • 10. Bell game • Alice and Bob collaborate against Eve • Alice and Bob get to colour the balls (two each, opposite corners) • Eve gets to choose a side of the square = one of Alice’s and one of Bob’s balls • Alice and Bob want their colours to comply with the requirement on Eve’s chosen side (other sides don’t matter) J. S. Bell (1964) “On the Einstein Podolski Rosen paradox”
  • 11. ❤️ ❤️ ❤️ ☯ Alice 1 Alice 2 Bob 1 Bob 2 Eve chooses a side = one of Alice’s & one of Bob’s balls
  • 12. Bell game • Alice chooses colours top left and right bottom ball • Bob chooses colours top right and left bottom ball • Eve chooses one of the four sides = chooses one of Alice’s two balls and one of Bob’s two balls • Alice and Bob win if their chosen colours comply with the demand for Eve’s chosen side • Optimal strategy for Alice and Bob: choose colouring with mismatch on one side; side of mismatch completely random • Optimal strategy for Eve: choose one of the four sides completely at random • Alice and Bob will win three times out of four (i.e., with probability 75%)
  • 13. Bell game • What if Eve has to choose first, Alice and Bob colour afterwards? (or vice versa) • Boring game! • We’ll make it more interesting by separating Alice and Bob and only telling them which ball of theirs will be checked, afterwards
  • 14. Bell game: distributed variant • Alice and Bob confer (in secret) • Alice and Bob are separated (no more communication; but they can take notebooks, computers, etc etc with them) • Eve tells Alice which of her two balls will be inspected • Eve tells Bob which of his two balls will be inspected • Alice and Bob choose colours of designated balls
  • 15. Bell game: distributed variant • Optimal (classical) solution: Alice and Bob choose in advance, at random, one of the “solutions” of the original game • Why? Because they may as well perform in advance (in secret) any randomisations (tosses of coins, dice throws…) which might be needed; and they might just as well decide in advance how each of their own two balls will be coloured if it happens to get chosen
  • 16. Bell game: distributed variant • Optimal (quantum) solution: Alice and Bob each take one part of a pair of maximally entangled qubits with them (qubit = quantum two-level system, e.g., polarisation of a photon, spin of an electron, …) • When told which ball they should colour, they measure their qubit according to one of two pre-chosen settings, and colour according to measurement outcome • Alice and Bob can win with probability 85% = 100 * (1 / 2 + √2 / 4) %
  • 17. Alice 1 Alice 2 Bob 1 Bob 2 ❤️ ❤️ ❤️ ☯ Measuring in (nearly) opposite directions gives (mostly) same result ❤️ Measuring in (nearly) same directions gives (mostly) opposite result ☯ Singlet state, two spin half particles