Using a little algebra, and assuming that \"a\" is the nth Fibonacci Number and that \"b\" is the next Fibonacci number after \"a\" explain why 2 odd Fibonacci number precede every even one Solution beacuse fibonacii terms are sum of previous two consecutive fibonnaci terms so if anyone is even : : and other is odd : then there sum is ODD : so next terms comes out again ODD but nwxt terms comes out = EVEN.

1. Using a little algebra, and assuming that "a" is the nth Fibonacci Number and that "b" is the
next Fibonacci number after "a" explain why 2 odd Fibonacci number precede every even one
Solution
beacuse fibonacii terms are sum of previous two consecutive fibonnaci terms so if
anyone is even : : and other is odd : then there sum is ODD : so next terms comes out again
ODD but nwxt terms comes out = EVEN