Use the properties of inverse functions to find the exact value of cos^-1(cos7pi/4). Solution Note that: arccos[cos(x)] = x for 0 < x <= pi. However, since pi < 7pi/4, the property is not yet applicable. Since the period of cosine is 2pi, we see that: cos(7pi/4) = cos(7pi/4 - 2?) = cos(-pi/4) = cos(pi/4). Since 0 < pi/4 <= pi, we see that: arccos[cos(7pi/4)] = arccos[cos(pi/4)] = pi/4. ANSWER.