Evaluate the following expression. Your answer must be in exact form: for example, type pi/6 for pi/6 or DNE if the expression is undefined. arcsin(sin(-pi/2)) = Solution ANS: As sin has a period of 2pi so bringing -pi/2 to the principal period of (0,2pi) we add 2pi to it. So, -pi/2 + 2pi = 3pi/2 sin(3pi/2) = -1 So the question is arc sine(-1) which is 3pi/2. Also for any angle x, arc sine (sin (x)) = x..