A storm warning siren emits sound uniformly in all directions. Along.pdf

•

0 likes•9 views

F

A storm warning siren emits sound uniformly in all directions. Along a line that is drawn radially outward from the sound source (the siren) determine the positions of two points, 0.77 m apart, such that the intensity level at one point is 4.12 dB greater than the intensity level at the other. point closer to siren: m point farther from siren: m Solution Power of source = P INtensity at r1 = I1 = P/4*pi*(r1)^2 Intensity at r2 = I2 = P/4*pi*(r2)^2 Now, 10log(I1/I2) = 4.12 20log(r2/r1) = 4.12 r2/r1 = 1.606 but r2 - r1 = 0.77 so r2 = 1.606(r2 - 0.77) = 1.606 r2 - 1.2366 r2 = 2.04 m r1 = 1.27 m.

A storm warning siren emits sound uniformly in all directions. Along a line that is drawn radially
outward from the sound source (the siren) determine the positions of two points, 0.77 m apart,
such that the intensity level at one point is 4.12 dB greater than the intensity level at the other.
point closer to siren: m
point farther from siren: m
Solution
Power of source = P
INtensity at r1 = I1 = P/4*pi*(r1)^2
Intensity at r2 = I2 = P/4*pi*(r2)^2
Now, 10log(I1/I2) = 4.12
20log(r2/r1) = 4.12
r2/r1 = 1.606
but r2 - r1 = 0.77
so r2 = 1.606(r2 - 0.77) = 1.606 r2 - 1.2366
r2 = 2.04 m
r1 = 1.27 m

More Related Content

More from footstatus

Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of toxaphene exposure on animals, groups of rats were given toxaphene in their diet. The article “Reproduction Study of Toxaphene in the Rat” (J. of Environ. Sci. Health, 1988: 101-126) reports weight gains (in grams) for rats given a low dose (4 ppm) and for control rats whose diet did not include the insecticide. The sample standard deviation for 23 female control rats was 32 g and for 20 female low-dose rats was 54 g. Does this data suggest that there is more variability in low-dose weight gains than in control weight gains? Assuming normality, carry out a test of hypotheses at significance level .05 For this problem, make a two-sided t interval & perform an F test for the ratio of variance, & create a confidence interval for the ratio of the variance. Solution.

tree to answer question 2. n Arabidopsis arenosa Arabidopsis halleri .pdf

tree to answer question 2. n Arabidopsis arenosa Arabidopsis halleri .pdf

tree to answer question 2. n Arabidopsis arenosa Arabidopsis halleri .pdf

The number of passengers (including the driver) in cars that cross a certain bridge is a random variable Y having mean E(Y) = 2.7 and variance V(Y) = 1.2. The toll on the bridge is $3.00 per car plus $0.50 per person in the car. The mean and variance of the total amount of money that is collected from a car that crosses the bridge are: (a) mean = $8.60, variance = $.30 (b) mean = $4.35, variance = $3.30 (c) mean = $8.60, variance = $.60 (d) mean = $4.35, variance = $.30 (e) mean = $1.35, variance = $.30 Solution The amount they pay in terms of Y is A = 3.00 + 0.50Y Thus, E(A) = E(3.00 + 0.50Y) = 3.00 + 0.50E(Y) = 3.00 + 0.50*2.7 E(A) = 4.35 Also, Var(A) = Var(3.00 + 0.50Y) = 0.50^2 Var(Y) = 0.50^2 * 1.2 Var(A) = 0.30 Thus, it is OPTION D. [ANSWER, D].

The plant pathogen Xylella fastidiosa is a gram negative that attach.pdf

The plant pathogen Xylella fastidiosa is a gram negative that attach.pdf

The plant pathogen Xylella fastidiosa is a gram negative that attach.pdf

the projected number of households( in millions) with digital video records thats allow viewers to record shows onto a server and skip commercials are in the following 5. The projected number of households (in millions) with digital video recorders that allow viewers to record shows onto a server and skip commercials are given in the following table: Year Households 31.2 a) Let t = 0 correspond to the beginning of 2006, and use QuadReg to find a second- 2010 130.2 2006 2008 71.6 2009 97.0 2007 49.0 degree polynomial regression model based on the given data. (2 pts) b) Using your regression equation, find the number of households in 2008. (2 pts) c) Using your regression equation, find the number of households in 2013. (2 pts) Solution a) Using technology to get the best quadratic fit, y^ = 2.4t^2 + 15t + 31.4 [answer] where y^ = predicted number of housholds. b) Plugging in t = 2 to y^ above, y^ = 2.4(2)^2 + 15(2) + 31.4 = 71 [answer] c) Plugging in y = 7 above, y^ = 2.4(7)^2 + 15(7) + 31.4 = 254 [answer].

The region labeled with the letter B is transcribed into mRNA True.pdf

The region labeled with the letter B is transcribed into mRNA True.pdf

The region labeled with the letter B is transcribed into mRNA True.pdf

The plant pathogen Xylella fastidiosa is a gram negative that attaches to surfaces and forms a biofilm in host plants. Which of the following typically triggers an immune response? a) Pili b) Teichoic acid c) LPS d) EPS Solution Ans--(C) : LPS Lipopolysaccharide (LPS) is the predominant macromolecule displayed on the cell surface of Gram-negative bacteria and thus mediates bacterial interactions with the environment and potential hosts Utilizing a mutant that produces truncated O antigen we present results that link this LPS structural alteration to a significant decrease in the attachment of X,Xylella fastidiosa is a plant pathogenic bacterium that lives inside the host xylem vessels where it forms biofilm believed to be responsible for disrupting the passage of water and nutrients..

The positron decay of 15 o goes directly to the ground state of,15 N;.pdf

The positron decay of 15 o goes directly to the ground state of,15 N;.pdf

The positron decay of 15 o goes directly to the ground state of,15 N;.pdf

a) What is the Chromosome Theory of Inheritance and how was it determined? (SHOW WORK & EXPLAIN) b) Describe the contributions of Sutton, Boveri, McClung, Stevens, Wilson and Morgan to determining that genetic information is carried on chromosomes. (SHOW WORK & EXPLAIN) c) Describe the XX-XO, XX-XY and ZZ-ZW mechanisms of sex determination and give examples of organisms that use each mechanism. (SHOW WORK & EXPLAIN) d) How does the environment affect sexual phenotype in turtles and alligators? (SHOW WORK & EXPLAIN) Solution a) Chromosomal Theory of Inheritance is a fundamental theory of genetics.Thomas Hunt Morgan establishes the Chromosomal theory of heredity.In 1907 Morgan was based on experiments by using Drosphila melanogaster or fruit flies. Drosphila have red eyes.Red eye colour is dominant.Morgan discovered a recessive mutation that caused white eyes. B) Boveri-Sutton chromosome theory identifies chromosomes as the carriers of genetic material which states that chromosomes carry the unit of heredity. McClung : A zoologist studied the behaviour of chromosomes in the sex cells and discovered the sex determining chromosome. Stevens: Stevens was interested in the process of sex determination. Morgan proposed the Chromosomal Theory of Heredity by using a common fruit fly. C) Sex determination is a biological system that determines the development of sexual characteristics. XX-XO types : In this type females have two homomorphic sex chromosomes XX ,male have one sex chromosome XO. This type of sex determination seen in cockroaches. XX-XY : This sex determination occurs in human beings.Females have two identical homologous sex chromosome XX and males have XY. ZZ-ZW : Females carry two types of sex chromosome ZW heterogametic and males carry ZZ homogametic. This type of sex determination occurs in fishes reptiles. D) Sex determination in reptiles are classified into two categories that is genotypic sex determination and temperature dependent. Environmental sex determination in which temperature is a crucial factor in embryonic development. In many turtle species eggs from cooler nests hatch males and from warmer nests hatch the females..

a) What is the Chromosome Theory of Inheritance and how was it deter.pdf

a) What is the Chromosome Theory of Inheritance and how was it deter.pdf

a) What is the Chromosome Theory of Inheritance and how was it deter.pdf

QuestionProblem 1 In a source file carddeck.cpp, provide an impl.pdf

QuestionProblem 1 In a source file carddeck.cpp, provide an impl.pdf

QuestionProblem 1 In a source file carddeck.cpp, provide an impl.pdf

Prove that the chromatic number of a cycle graph_n of odd length equals 3. Solution Chromatic Number: The chromatic number of a graph G is the least k for which a k-coloring of G exists. First note that the chromatic number must be at least 2 for any graph which has an edge in it, including all cycles. We now prove the theorem by induction on n. We will consider two base cases, C3 and C4. C3 is isomorphic to K3 which has chromatic number 3. C4 can be colored with two colors by giving opposing corners of the square the same color. For n > 4, we can take a coloring of Cn-2 and insert 2 adjacent vertices and edges and then color the new vertices appropriately to get a coloring of Cn. Thus the chromatic number of Cn is not greater than that of Cn-2. In the case where n is odd, note that if Cn had chromatic number 2, we could remove two adjacent vertices and edges to get a 2-coloring of Cn-2 which contradicts the inductive hypothesis since n-2 must be odd if n is odd. Therefore for odd numbers the chromatic number will be 2+1 = 3..

provide a brief definition of self assemblySolutionMolecular s.pdf

provide a brief definition of self assemblySolutionMolecular s.pdf

provide a brief definition of self assemblySolutionMolecular s.pdf

Many non-scientists have focused their criticism of evolution on the fact that even scientists have criticized Darwin’s theory. Is this true? In what respect did Darwin get it wrong, or maybe in what way has Darwin’s theory been modified? Solution The \"Origin of Species\" of Darwin described about the heritable change in an organism over a period of time due to natural selection. Scientists also criticized of Danwin\'s opinion on use and disuse theory. At the time of Origin of species, Darwin do not know about the existed of microorganisms and his theory of tree of life became wrong. Pangenesis theory of Darwin also became wrong as he do not know anything about genetics..

Match the Statements below with bacteriological tests. Eosin-methyle.pdf

Match the Statements below with bacteriological tests. Eosin-methyle.pdf

Match the Statements below with bacteriological tests. Eosin-methyle.pdf

M2-13 Identifying Transactions and Preparing Journal Entries [LO 2-3] J.K. Builders was incorporated on July 1 a. Received $83,000 cash invested by owners and issued common stock. b. Bought an unused field from a local farmer by paying $73,000 cash. As a construction site for smaller projects, it is estimated to be worth $78,000 to J.K. Builders c. Alumber supplier delivered lumber supplies to J.K. Builders for future use. The lumber supplies would have normally sold for $23,000, but the supplier gave J.K. Builders a 10 percent discount. J.K. Builders has not yet received the $20,700 bill from the supplier d. Borrowed $38,000 from the bank with a plan to use the funds to build a small workshop in August. The loan must be repaid in two years. e. One of the owners sold $23,000 worth of his common stock to another shareholder for $24,000 Prepare journal entries for the above transactions from the first month of business. (If no entry is required fora transactionlevent, selec \"No Journal Entry Required\" in the first account field.) Solution Ref Account Debit Credit a Cash 83000 Common stock 83000 b Land 73000 Cash 73000 c Lumber supplies 20700 Accounts payable 20700 d cash 38000 Notes payable 38000 e No entry.

Many non-scientists have focused their criticism of evolution on the.pdf

Many non-scientists have focused their criticism of evolution on the.pdf

Many non-scientists have focused their criticism of evolution on the.pdf

iQ2 In a study about children?s pocket money, two samples of schoolchildren were asked how much money they received each week. In one sample, of size 80, the mean is ?6.65. In the other sample, of size 41, the mean is pound 8.21. Calculate the mean based on the combined sample. Give your answer correct to two decimal places. (Do NOT include the pound sign in your answer.) Solution n1=80 x1=6.65 n2=41 x2=8.21 combined mean = (n1*x1+n2*x2)/( n1+n2) =( 80*6.65+41*8.21) /( 80+41) =868.61/121 =7.1785 Combined mean =7.18 ( two decimals).

It has been observed that F_st increases with the distance between po.pdf

It has been observed that F_st increases with the distance between po.pdf

It has been observed that F_st increases with the distance between po.pdf

Let f(x), g(x), h(x), epsilon F[x] such that f(x) does not equal 0. Prove that: If f(x) | g(x) and f(x) | [g(x)^2 +h(x)], then f(x). Hint: g(x)^2 = g(x) * g(x) Solution given f(x) | g(x) =>g(x)=k.f(x) =>g(x)2=k2.f(x)2 =>g(x)2=l.f(x) eq1 where l=k2.f(x) and f(x) | [g(x)^2 +h(x)] =>[g(x)^2 +h(x)]=m.f(x) eq2 eq2-eq1 =>h(x)=(l-m)f(x)=p.f(x) where p=l-m there fore f(x)|h(x) then f(x). Hint: g(x)^2 = g(x) * g(x).

Let R be an integral domain and F a field such that R is a subring of.pdf

Let R be an integral domain and F a field such that R is a subring of.pdf

Let R be an integral domain and F a field such that R is a subring of.pdf

Judith, Martha, and Sophia are organizing their backpacks. While org.pdf

Judith, Martha, and Sophia are organizing their backpacks. While org.pdf

Judith, Martha, and Sophia are organizing their backpacks. While org.pdf

A population of 10,000 students spends an average of $8.50 a day on dinner. The standard deviation of the expenditure is $4. A simple random sample of 100 students is taken. What is the standard deviation of the sampling distribution of the sample mean? Round your answer to 3 decimal places and no dollar sign. Solution As s(X) = s/sqrt(n) Then, as s = 4, n = 100, s(X) = 4/sqrt(100) = 0.4 [ANSWER].

A population of 10,000 students spends an average of $8.50 a day on .pdf

A population of 10,000 students spends an average of $8.50 a day on .pdf

A population of 10,000 students spends an average of $8.50 a day on .pdf

a local fan club surveyed 67 of its members regarding their viewing habits last weekend, and the 44 following information was obtained: 30 members watched an episode of Naruto, 44 watched an episode of Death Note, 23 watched an episode of Inuyasha, 20 watched both Naruto and Inuyasha, 5 watched Naruto and Inuyasha but not Death Note, 15 watched both Death Note and Inuyasha, and 23 watched onlyDeath Note. Draw a Venn Diagram. Solution.

a local fan club surveyed 67 of its members regarding their viewing .pdf

a local fan club surveyed 67 of its members regarding their viewing .pdf

a local fan club surveyed 67 of its members regarding their viewing .pdf

A gas is a fluid. It has less molecular space and freedom of motion than liquids as well negligible cohesive intermolecular forces. Shear thinning and thickening are types of non- Newtonian fluids. Gage pressure = Absolute Pressure + 14.7 4. The specific weight of an unknown object is 75 lbf/ft^3. The object is placed in water. The object will float within the water but not float to the water surface. The center of mass is the point through which the resultant force acts on a submerged inclined plane. Solution 1.TRUE...ie correct explaination 2.TRUE SHEAR THICKENING IS DILATENT...SHEAR THINING IS PSEUDOPLASTIC 3.FALSE....ABSOLUTE PRESSURE=GAUGE+ ABSOLUTE PRESSURE 4.FALSE..IT IS ALWAYS FLOAT ON THE WATER 5. TRUE...

A gas is a fluid. It has less molecular space and freedom of motion t.pdf

A gas is a fluid. It has less molecular space and freedom of motion t.pdf

A gas is a fluid. It has less molecular space and freedom of motion t.pdf

A man accidentally let his parakeet out the door. The bird flew up to a power line and sat there. Unable to coax the bird down, the man stands on an aluminium ladder and reaches for the bird with an aluminium pole. Is there any potential danger in this situation? If so, what, and if not, why not? (Figure adapted from: Irwin, J. D. & Kerns, D. v. (1995). Introduction to Electrical Engineering. Upper Saddle River, NJ: Prentice-Hall.) Solution Yes there a potentially fatal scenario because here the man may provide a path to ground from the power line through his body. Since aluminium pole is a conductor so as soon as the man touches power line there there will be a electrical path produced through him and power passes from pole to man and then to ground..

A man accidentally let his parakeet out the door. The bird flew up to.pdf

A man accidentally let his parakeet out the door. The bird flew up to.pdf

A man accidentally let his parakeet out the door. The bird flew up to.pdf

A culture of yeast was grown in a media containing sucrose labeled by 14C at 2nd position of fructose. Determine the localization of the label in palmitic acid synthesized by the yeast. Solution GLYCOLYSIS result in synthesis of acetyl CoA acetyl CoA formed from fructose will be labeled by 14C as 2nd position of fructose is labeled by 14C this will result in sub cellular localisation of pamitic acid synthesis......by acetyl CoA which is labeled by 14C.

A culture of yeast was grown in a media containing sucrose labeled b.pdf

A culture of yeast was grown in a media containing sucrose labeled b.pdf

A culture of yeast was grown in a media containing sucrose labeled b.pdf

a. Dipole b. Set of a finite number of point charges c. A uniformly charged rod d. A uniformly charged ring e. A uniformly charged disk f. A solid sphere uniformly charged throughout its volume g. A spherical shell with a uniformly charged surface Solution its better to choose A solid Sphere uniformly charged throughout its volume. because, it just acts as a point charge. and there will be no change in either Electric field, Potential or Force etc except at the distance from centre to R..

a. Dipole b. Set of a finite number of point charges c. A uniformly c.pdf

a. Dipole b. Set of a finite number of point charges c. A uniformly c.pdf

a. Dipole b. Set of a finite number of point charges c. A uniformly c.pdf

5. When a phosphate group is found in water: a) The partially-negative oxygen atoms of the water molecules surround the oxygen atoms of the phosphate group. b) The partially-positive hydrogen atoms of the water molecules surround the oxygen atoms of the phosphate group. c) The partially-positive oxygen atoms of the water molecules surround the oxygen atoms of the phosphate group. d) Hydrophobic forces push the phosphate groups together to minimize their disruption on hydrogen bonding between water molecules. e) There is more than one correct answer above. Solution ANS: b) The partially-positive hydrogen atoms of the water molecules surround the oxygen atoms of the phosphate group. Explanation: In the water molecule two polar covalent bonds are present. Among this oxygen molecule had a partial negative charge and both hydrogen atoms partial positive charge. The positive and negative ends of the bond cause charge separation or a dipole. So water molecule had 2 polar covalent bonds and 2 bond dipoles. In phosphate group two oxygen molecules had partial negative charges, so the partially-positive hydrogen atoms of the water molecules surround the oxygen atoms of the phosphate group..

5. When a phosphate group is found in water a) The partially-negati.pdf

5. When a phosphate group is found in water a) The partially-negati.pdf

5. When a phosphate group is found in water a) The partially-negati.pdf

Implement a minimum spanning tree using Boruvka\'s algorithm. Implement a minimum spanning tree using Boruvka\'s algorithm. Solution The psuedo code is as follows: 1 Graph input = /* read input */; 2 UnionFind uf (input.getNodes ()); 3 Workset ws = input.getNodes(); 4 foreach (Node n : ws) { 5 Edge e = minWeight (input.getOutEdges (n)); 6 Node rep1 = uf.find (e.src); 7 Node rep2 = uf.find (e.dst); 8 if (rep1 != rep2) { 9 e.markInMST(); 10 Node rep = uf.union (rep1, rep2); 11 ws.add (rep) 12 } 13 }.

Implement the additional 5 methods as indicated in the LinkedList fi.pdf

Implement the additional 5 methods as indicated in the LinkedList fi.pdf

Implement the additional 5 methods as indicated in the LinkedList fi.pdf

More from footstatus (20)

tree to answer question 2. n Arabidopsis arenosa Arabidopsis halleri .pdf

tree to answer question 2. n Arabidopsis arenosa Arabidopsis halleri .pdf

tree to answer question 2. n Arabidopsis arenosa Arabidopsis halleri .pdf

The plant pathogen Xylella fastidiosa is a gram negative that attach.pdf

The plant pathogen Xylella fastidiosa is a gram negative that attach.pdf

The plant pathogen Xylella fastidiosa is a gram negative that attach.pdf

The region labeled with the letter B is transcribed into mRNA True.pdf

The region labeled with the letter B is transcribed into mRNA True.pdf

The region labeled with the letter B is transcribed into mRNA True.pdf

The positron decay of 15 o goes directly to the ground state of,15 N;.pdf

The positron decay of 15 o goes directly to the ground state of,15 N;.pdf

The positron decay of 15 o goes directly to the ground state of,15 N;.pdf

a) What is the Chromosome Theory of Inheritance and how was it deter.pdf

a) What is the Chromosome Theory of Inheritance and how was it deter.pdf

a) What is the Chromosome Theory of Inheritance and how was it deter.pdf

QuestionProblem 1 In a source file carddeck.cpp, provide an impl.pdf

QuestionProblem 1 In a source file carddeck.cpp, provide an impl.pdf

QuestionProblem 1 In a source file carddeck.cpp, provide an impl.pdf

provide a brief definition of self assemblySolutionMolecular s.pdf

provide a brief definition of self assemblySolutionMolecular s.pdf

provide a brief definition of self assemblySolutionMolecular s.pdf

Match the Statements below with bacteriological tests. Eosin-methyle.pdf

Match the Statements below with bacteriological tests. Eosin-methyle.pdf

Match the Statements below with bacteriological tests. Eosin-methyle.pdf

Many non-scientists have focused their criticism of evolution on the.pdf

Many non-scientists have focused their criticism of evolution on the.pdf

Many non-scientists have focused their criticism of evolution on the.pdf

It has been observed that F_st increases with the distance between po.pdf

It has been observed that F_st increases with the distance between po.pdf

It has been observed that F_st increases with the distance between po.pdf

Let R be an integral domain and F a field such that R is a subring of.pdf

Let R be an integral domain and F a field such that R is a subring of.pdf

Let R be an integral domain and F a field such that R is a subring of.pdf

Judith, Martha, and Sophia are organizing their backpacks. While org.pdf

Judith, Martha, and Sophia are organizing their backpacks. While org.pdf

Judith, Martha, and Sophia are organizing their backpacks. While org.pdf

A population of 10,000 students spends an average of $8.50 a day on .pdf

A population of 10,000 students spends an average of $8.50 a day on .pdf

A population of 10,000 students spends an average of $8.50 a day on .pdf

a local fan club surveyed 67 of its members regarding their viewing .pdf

a local fan club surveyed 67 of its members regarding their viewing .pdf

a local fan club surveyed 67 of its members regarding their viewing .pdf

A gas is a fluid. It has less molecular space and freedom of motion t.pdf

A gas is a fluid. It has less molecular space and freedom of motion t.pdf

A gas is a fluid. It has less molecular space and freedom of motion t.pdf

A man accidentally let his parakeet out the door. The bird flew up to.pdf

A man accidentally let his parakeet out the door. The bird flew up to.pdf

A man accidentally let his parakeet out the door. The bird flew up to.pdf

A culture of yeast was grown in a media containing sucrose labeled b.pdf

A culture of yeast was grown in a media containing sucrose labeled b.pdf

A culture of yeast was grown in a media containing sucrose labeled b.pdf

a. Dipole b. Set of a finite number of point charges c. A uniformly c.pdf

a. Dipole b. Set of a finite number of point charges c. A uniformly c.pdf

a. Dipole b. Set of a finite number of point charges c. A uniformly c.pdf

5. When a phosphate group is found in water a) The partially-negati.pdf

5. When a phosphate group is found in water a) The partially-negati.pdf

5. When a phosphate group is found in water a) The partially-negati.pdf

Implement the additional 5 methods as indicated in the LinkedList fi.pdf

Implement the additional 5 methods as indicated in the LinkedList fi.pdf

Implement the additional 5 methods as indicated in the LinkedList fi.pdf

Recently uploaded

Model Attribute _rec_name in the Odoo 17

Model Attribute _rec_name in the Odoo 17

Model Attribute _rec_name in the Odoo 17

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

Nguyen Thanh Tu Collection

𝐋𝐞𝐬𝐬𝐨𝐧 𝐎𝐮𝐭𝐜𝐨𝐦𝐞𝐬: -Discern accommodations and modifications within inclusive classroom environments, distinguishing between their respective roles and applications. -Through critical analysis of hypothetical scenarios, learners will adeptly select appropriate accommodations and modifications, honing their ability to foster an inclusive learning environment for students with disabilities or unique challenges.

Understanding Accommodations and Modifications

Understanding Accommodations and Modifications

Understanding Accommodations and Modifications

Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf

Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf

Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf

Dr Vijay Vishwakarma

What is 3 Way Matching Process in Odoo 17.pptx

What is 3 Way Matching Process in Odoo 17.pptx

What is 3 Way Matching Process in Odoo 17.pptx

VAMOS CUIDAR DO NOSSO PLANETA! .

VAMOS CUIDAR DO NOSSO PLANETA! .

VAMOS CUIDAR DO NOSSO PLANETA! .

Colégio Santa Teresinha

80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...

80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...

80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...

Nguyen Thanh Tu Collection

HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx

HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx

HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx

REMIFENTANIL: An Ultra short acting opioid.pptx

REMIFENTANIL: An Ultra short acting opioid.pptx

REMIFENTANIL: An Ultra short acting opioid.pptx

Dr. Ravikiran H M Gowda

diagnosting testing bsc 2nd sem.pptx....

diagnosting testing bsc 2nd sem.pptx....

diagnosting testing bsc 2nd sem.pptx....

Wellbeing inclusion and digital dystopias.pptx

Wellbeing inclusion and digital dystopias.pptx

Wellbeing inclusion and digital dystopias.pptx

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

Pondicherry University

FSB Advising Checklist - Orientation 2024

FSB Advising Checklist - Orientation 2024

FSB Advising Checklist - Orientation 2024

Elizabeth Walsh

A procedure when multiple vendors are asked to submit proposals for a supply contract or project. It helps businesses to assess offers and select the best vendor based on factors like cost, quality, and other relevant factors. In Odoo 17, the Call for Tenders feature has undergone significant improvements, making procurement process management more efficient and seamless. Accessing and managing this feature can still be done through the same interface as Blanket Orders, with the addition of creating an exclusive agreement type for Call for Tenders.

How to Manage Call for Tendor in Odoo 17

How to Manage Call for Tendor in Odoo 17

How to Manage Call for Tendor in Odoo 17

Accessible Digital Futures project (20/03/2024)

Accessible Digital Futures project (20/03/2024)

Accessible Digital Futures project (20/03/2024)

How to setup Pycharm environment for Odoo 17.pptx

How to setup Pycharm environment for Odoo 17.pptx

How to setup Pycharm environment for Odoo 17.pptx

dusjagr & nano talk on open tools for agriculture research and learning

dusjagr & nano talk on open tools for agriculture research and learning

dusjagr & nano talk on open tools for agriculture research and learning

Marc Dusseiller Dusjagr

How to Add New Custom Addons Path in Odoo 17

How to Add New Custom Addons Path in Odoo 17

How to Add New Custom Addons Path in Odoo 17

Andreas Schleicher presents at the launch of What does child empowerment mean...

Andreas Schleicher presents at the launch of What does child empowerment mean...

Andreas Schleicher presents at the launch of What does child empowerment mean...

PANDITA RAMABAI- Indian political thought GENDER.pptx

PANDITA RAMABAI- Indian political thought GENDER.pptx

PANDITA RAMABAI- Indian political thought GENDER.pptx

akanksha16arora

Recently uploaded (20)

Model Attribute _rec_name in the Odoo 17

Model Attribute _rec_name in the Odoo 17

Model Attribute _rec_name in the Odoo 17

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

Understanding Accommodations and Modifications

Understanding Accommodations and Modifications

Understanding Accommodations and Modifications

Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf

Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf

Unit 3 Emotional Intelligence and Spiritual Intelligence.pdf

What is 3 Way Matching Process in Odoo 17.pptx

What is 3 Way Matching Process in Odoo 17.pptx

What is 3 Way Matching Process in Odoo 17.pptx

VAMOS CUIDAR DO NOSSO PLANETA! .

VAMOS CUIDAR DO NOSSO PLANETA! .

VAMOS CUIDAR DO NOSSO PLANETA! .

80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...

80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...

80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...

HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx

HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx

HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx

REMIFENTANIL: An Ultra short acting opioid.pptx

REMIFENTANIL: An Ultra short acting opioid.pptx

REMIFENTANIL: An Ultra short acting opioid.pptx

diagnosting testing bsc 2nd sem.pptx....

diagnosting testing bsc 2nd sem.pptx....

diagnosting testing bsc 2nd sem.pptx....

Wellbeing inclusion and digital dystopias.pptx

Wellbeing inclusion and digital dystopias.pptx

Wellbeing inclusion and digital dystopias.pptx

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

FSB Advising Checklist - Orientation 2024

FSB Advising Checklist - Orientation 2024

FSB Advising Checklist - Orientation 2024

How to Manage Call for Tendor in Odoo 17

How to Manage Call for Tendor in Odoo 17

How to Manage Call for Tendor in Odoo 17

Accessible Digital Futures project (20/03/2024)

Accessible Digital Futures project (20/03/2024)

Accessible Digital Futures project (20/03/2024)

How to setup Pycharm environment for Odoo 17.pptx

How to setup Pycharm environment for Odoo 17.pptx

How to setup Pycharm environment for Odoo 17.pptx

dusjagr & nano talk on open tools for agriculture research and learning

dusjagr & nano talk on open tools for agriculture research and learning

dusjagr & nano talk on open tools for agriculture research and learning

How to Add New Custom Addons Path in Odoo 17

How to Add New Custom Addons Path in Odoo 17

How to Add New Custom Addons Path in Odoo 17

Andreas Schleicher presents at the launch of What does child empowerment mean...

Andreas Schleicher presents at the launch of What does child empowerment mean...

Andreas Schleicher presents at the launch of What does child empowerment mean...

PANDITA RAMABAI- Indian political thought GENDER.pptx

PANDITA RAMABAI- Indian political thought GENDER.pptx

PANDITA RAMABAI- Indian political thought GENDER.pptx

A storm warning siren emits sound uniformly in all directions. Along.pdf

1. A storm warning siren emits sound uniformly in all directions. Along a line that is drawn radially outward from the sound source (the siren) determine the positions of two points, 0.77 m apart, such that the intensity level at one point is 4.12 dB greater than the intensity level at the other. point closer to siren: m point farther from siren: m Solution Power of source = P INtensity at r1 = I1 = P/4*pi*(r1)^2 Intensity at r2 = I2 = P/4*pi*(r2)^2 Now, 10log(I1/I2) = 4.12 20log(r2/r1) = 4.12 r2/r1 = 1.606 but r2 - r1 = 0.77 so r2 = 1.606(r2 - 0.77) = 1.606 r2 - 1.2366 r2 = 2.04 m r1 = 1.27 m