The Martian calendar has sixteen months instead of twelve. What is t.pdf

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Suppose that lines l1, l2, l3 are lines in an affine plane. Suppose that lines l1, l2 are parallel. Prove that if l1, l3 intersect then l2, l3 intersect. Solution Here we have the rule that when two parallel lines are intersected by a transversal, then the exteriior corresponding angles, thus formed are equal to each other. Now it is given that l1 and l2 are parallel lines and l3 intersects l1, that means l3 is transversal here, so that the exterior angles thus forming on line l1 and l3 will be equal to each other. Now as both exterior angles are forming at two different intersecting points of parallel lines l1 and l2, when intersected by line l3, that proved that being parallel lines, line l3 intersects both lines l1 and l2. Proved.

The Martian calendar has sixteen months instead of twelve. What is the fewest number of
Martians so that five of them will have the same birth-month?
Solution
The martian calendar has sixteen moths.
Lets say 16 different people are there -> 16
To make all the people have same month -> 16*5 = 80
The fewest number of Martians, so that five of them will have the same birth-month -> 80 - 15 -
> 65

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