Create a function mean comp that compares the mean value of the odd numbered elements with the mean value of the even numbered elements and returns: if they are equal, if the mean of the odd numbered elements is greater, if the mean of the even numbered elements is greater. Solution A sample Java Program methods public static void main(String []args){ float[] list = {1.0f, 7.0f, 8.0f, 1.0f}; System.out.println(meancomp(list)); } static int meancomp(float[] list) { float evenSum = 0.0f; float oddSum = 0.0f; for (int i = 0; i < list.length; i++) { if (i % 2 == 1) evenSum = evenSum + list[i]; else oddSum = oddSum + list[i]; } int noOfEvenElements = list.length / 2; int noOfOddElements = list.length / 2 + list.length % 2; float evenMean = evenSum / (float) noOfEvenElements; float oddMean = oddSum / (float) noOfOddElements; int result = Float.compare(evenMean, oddMean); if (result == 0) return 0; else if (result < 0) return 1; else return 2; }.