NEED STEPS ON HOW TO SOLVE PROBLEMS IN NUMBER TWO! For each of the
numbers t in the above problem, find a number s in [0, 2pi] such that W(s) = W(t). Part a is done
for you. For each of the following values of t, find two other values, one positive and one
negative, that have value.
Solution
2)
W(9pi/2)=W(4pi+pi/2)=W(pi/2)
3)W(-15pi)=W(-16pi+pi)=W(pi)
4)W(-13pi/3)=W(-4pi-pi/3)=W(pi/3)
5)W(-8pi/6)=W(-4pi/3)=W(-2pi+2pi/3)=W(2pi/3)
6)W(-21pi/4)=W(-6pi+3pi/4)=W(3pi/4)
7)W(3pi)=W(2pi+pi)=W(pi)
8)W(-17pi/3)=W(-6pi+pi/3)=W(pi/3)
Steps to solve these questions are
Write given value of angle as multiple of 2Pi and add some angle between 0 and 2pi.That angle
between zero and 2pi will be the value at which function has same value because 2pi is time
period of function after which value of function repeats.
NEED STEPS ON HOW TO SOLVE PROBLEMS IN NUMBER TWO! For each .pdf
1. NEED STEPS ON HOW TO SOLVE PROBLEMS IN NUMBER TWO! For each of the
numbers t in the above problem, find a number s in [0, 2pi] such that W(s) = W(t). Part a is done
for you. For each of the following values of t, find two other values, one positive and one
negative, that have value.
Solution
2)
W(9pi/2)=W(4pi+pi/2)=W(pi/2)
3)W(-15pi)=W(-16pi+pi)=W(pi)
4)W(-13pi/3)=W(-4pi-pi/3)=W(pi/3)
5)W(-8pi/6)=W(-4pi/3)=W(-2pi+2pi/3)=W(2pi/3)
6)W(-21pi/4)=W(-6pi+3pi/4)=W(3pi/4)
7)W(3pi)=W(2pi+pi)=W(pi)
8)W(-17pi/3)=W(-6pi+pi/3)=W(pi/3)
Steps to solve these questions are
Write given value of angle as multiple of 2Pi and add some angle between 0 and 2pi.That angle
between zero and 2pi will be the value at which function has same value because 2pi is time
period of function after which value of function repeats
![NEED STEPS ON HOW TO SOLVE PROBLEMS IN NUMBER TWO! For each of the
numbers t in the above problem, find a number s in [0, 2pi] such that W(s) = W(t). Part a is done
for you. For each of the following values of t, find two other values, one positive and one
negative, that have value.
Solution
2)
W(9pi/2)=W(4pi+pi/2)=W(pi/2)
3)W(-15pi)=W(-16pi+pi)=W(pi)
4)W(-13pi/3)=W(-4pi-pi/3)=W(pi/3)
5)W(-8pi/6)=W(-4pi/3)=W(-2pi+2pi/3)=W(2pi/3)
6)W(-21pi/4)=W(-6pi+3pi/4)=W(3pi/4)
7)W(3pi)=W(2pi+pi)=W(pi)
8)W(-17pi/3)=W(-6pi+pi/3)=W(pi/3)
Steps to solve these questions are
Write given value of angle as multiple of 2Pi and add some angle between 0 and 2pi.That angle
between zero and 2pi will be the value at which function has same value because 2pi is time
period of function after which value of function repeats](https://image.slidesharecdn.com/needstepsonhowtosolveproblemsinnumbertwoforeach-230325062027-4deeb879/85/NEED-STEPS-ON-HOW-TO-SOLVE-PROBLEMS-IN-NUMBER-TWO-For-each-pdf-1-320.jpg)
