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1. Provide a technical description of 4B/5B Digital Encoding Scheme. Contrast it with the Manchester scheme. Explain how and why it provides better data rates. 2. Create a ranked table based on transmission speed, comparing 3 types of twisted pair, coaxial cable, fiber-optic cable, microwave, and satellite. Include distances and typical installation use cases. 3. Draw a fully labeled diagram comparing a low earth satellite deployment with a geosynchronous satellite deployment in a situation where you would need 24/7 coverage of the whole earth as your basic criteria. Include ground stations and appropriate locations in your diagram. How expensive might the two different solutions be? 4. Provide 2 pages discussing the data communication features of USB standards and implementation. Include past, present and future analysis. The paper is intended to provide an overview for someone who needs to know as much as possible about USB communications in a concise manner. Part 2 1. Create a table of the four architectural layers of the TCP/IP suite. Include common protocols at each layer. Layer, Protocols, Responsibility 2. In a brief essay explain the concept of encapsulation. What is it and why is it important for you to understand? Are there encapsulation vulnerabilities that can be exploited? 3. Designing a Secure Network. Take two of the technologies from the list in the textbook and briefly describe what they are and why they are used in the topology of a secure network. 4. In a brief essay explain the difference between the three types of firewalls. Provide a brief scenario of the use of each of the three. 5. Do some research on the vulnerabilities of routers and switches. Describe at least two vulnerabilities for each. What can be done to reduce the threat to these two devices? 6. Create a table of the four types of intrusion detection systems. Type Description How it is used Solution Manchester encoding is able to tie up about twice the bandwidth of the unique signal. In this encoding plan, there is a broadcast following every bit. This means there have to be clocks with twice the speed to send the similar amount of data as the other plans. With the formation of 100 Mbps broadcasts this limited bandwidth needed a new type of encoding. The novel encoding arrangement is 4B or 5B MLT code. 4B or 5B encoding is a kind of Block coding. In this technique, blocks of data are procedure in its place of creating a signal for every individual bit. In 4B/5B encoding, present are 32 5-Bit codes, but 16 are utilized. Of the residual 16 codes, 7 are unacceptable and others are employed to send control in sequence 4 bits of data are twisted into a single 5-bit sequence and in that case encoded to be transmitted. In the 5-bit code, here must be one foremost zero and no more than two sprawling zeros. These guarantees there are in no way more than three successive zeros. This lets the baud rate to be equivalent to the bps, and is more competent. This is a importa.
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Comp6461 – Fall 2014 Theory Assignment 3 - Page 1 COM.docx
Comp6461 – Fall 2014 Theory Assignment 3 - Page 1
COMP 6461 - Fall 2014
Theory Assignment 3
1) What is the main difference between Pure Aloha and Slotted Aloha? Are there any
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days?
A
C
D
G
B
E
F
H
I
Comp6461 – Fall 2014 Theory Assignment 3 - Page 2
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Find the time it takes the boat to travel the given distance. A ball is thrown vertically upward
with a speed of 40.0 m/s. How high does it rise? How long does it take to reach its highest
point? How long does the ball take to hit the ground after it reaches its highest point? What is
its velocity when it returns to the level from which it started? The center of mass moves with
constant acceleration when constant forces act on the object. A gym ground. How high above
this point is her center of mass at the following times? Ignore the effects
Solution
initial velocity, u = + 40 m/s
a = - 9.8 m/s^2
(a) it will rise until its velocity becomes zero.
hence final velocity, v = 0
Applying, v^2 - u^2 = 2 a h
0^2 - 40^2 = 2(-9.8)(h)
h = 81.63 m
(B) v = u + at
0 = 40 - 9.8 t
t = 4.08 sec
(C) now for motion from highest point to ground,
initial velocity, v (velocity at highets point) = 0
displacement, y = - 81.63 m
a = - 9.8 m/s^2
applying, y = u t + a t^2 /2
- 81.63 = 0 - 9.8 t^2 / 2
t = 4.08 s
(D) applying v = u + at
v = 0 + (-9.8)(4.08)
v = - 40 m/s
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Discuss the character and impact of the economic and legal revoulutions on the American
economy between 1815 and 1840. Did this market revolution have to be so antagonistic toward
laborers? Explain your answer.
Solution
Market revolution refers to the changes in market structure from local to national markets.
Revolution impacted highly in agricultural sector. It has changed agricultural sector positively.
Textile and manufacturing industries drastically boom and strengthened the economy. Roadways
and canal system expanded, coin was made from precious metal, and there was huge financial
growth. During market revolution Americans began to experience the forces of supply and
demand. Transportation network highly changed during revolution and play a vital role in
commerce and new market.
Due to revolution there was drastic changes occurred in manual labor process. It has changed the
schedules, wages and working environment for laborers. Artisanal trades started to give way to
best efficient system of production, instead of using skilled labor and thus skilled labor were not
required for the production. There was no job security and laborer was paid low wages..
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This document appears to be a student paper submission for a networking course. It discusses using a microwave backhaul link to connect two company branch offices located on different Greek islands. The paper will analyze how the bit error rate of the microwave link at different signal-to-noise ratios can impact the TCP throughput between the two branches. It will include simulations of the microwave link and the network implementation to examine this relationship and draw conclusions. The paper is divided into sections covering the theoretical background of the communication channel, analysis of error correction coding and modulation, and the planned simulations.
Application Aware Topology Generation for Surface Wave Networks-on-Chip
This document summarizes a research paper that proposes a new algorithm called the maximal declining sorting algorithm (MDSA) to optimize network-on-chip (NoC) performance and power consumption. The MDSA aims to reduce communication time in NoCs by minimizing the number of hops between cores that communicate frequently. It does this by adding wireless transceivers between cores based on the product of their traffic volume and number of hops. The MDSA is shown to reduce communication time by up to 35.6% compared to the conventional genetic algorithm approach, and also lowers power consumption.
networking1.ppt
The document discusses networking concepts such as network topologies, devices, and the OSI model. It begins by explaining how businesses realized networking could increase productivity and save costs. It then describes common networking devices like NICs, hubs, switches, and routers. The document also covers standard network topologies and the layers of the OSI model, providing examples of how data is encapsulated as it travels through each layer.
BOMA Teaser
This document discusses how to increase 4G LTE network downlink capacity through a simple software patch called BOMA. BOMA can provide a 50-60% boost in downlink capacity through software updates to LTE base stations and devices, requiring no hardware changes. This increases capacity much faster and cheaper than alternatives like acquiring new spectrum that require billions in spending and 3-5 years for implementation. The document provides technical details on how BOMA pairs users with different modulations to improve spectral efficiency over traditional OFDMA.
The Minimum Cost Forwarding Using MAC Protocol for Wireless Sensor Networks
The document discusses the Minimum Cost Forwarding (MCF) routing protocol for wireless sensor networks. MCF establishes optimal routing paths with few message exchanges and is scalable and simple to implement. The authors formally model MCF as timed automata and use model checking to verify its properties. Their analysis identified weaknesses in MCF concerning equal-cost paths and node failures. The authors present improvements to address deficiencies in the original MCF protocol.
Ba2641224127
The document discusses the Minimum Cost Forwarding (MCF) routing protocol for wireless sensor networks. MCF establishes optimal routing paths with few message exchanges and is scalable and simple to implement. The authors formally model MCF as timed automata and use model checking to verify its properties. Their analysis identified weaknesses in MCF concerning equal-cost paths and node failures. The authors present improvements to address deficiencies in the original MCF protocol.
Frame Relay And Leased Lines Essay
Here are the key differences between interrupts and asynchronous communication:
Interrupts:
- Are event-driven signals triggered by internal or external events in the hardware/firmware.
- Cause the processor to pause its current task and handle the interrupt request before returning.
- Allow asynchronous prioritized responses to events outside of the main program flow.
Asynchronous communication:
- Refers to communication between software programs or components without strict synchronization.
- Uses message passing or queues to exchange data without blocking the sender or receiver.
- Allows independent and concurrent execution of communicating programs or threads.
The main benefits of interrupts are precise, prioritized responses to external hardware events. The benefits of asynchronous communication are concurrent execution
Comp6461 – Fall 2014 Theory Assignment 3 - Page 1 COM.docx
Comp6461 – Fall 2014 Theory Assignment 3 - Page 1
COMP 6461 - Fall 2014
Theory Assignment 3
1) What is the main difference between Pure Aloha and Slotted Aloha? Are there any
circumstances where Pure Aloha would perform better than Slotted Aloha? If so, give
such circumstances/conditions. If no, explain why Pure Aloha could never perform better
that Slotted Aloha.
2) Given a network with 9 routers as shown in the figure below. Assume the utilization of
center-based spanning tree construction, where router D is assigned as the center (or
root) router. Assume routers join the tree in the following order: C, A, H, B, F, G, E, and
I. Show the final constructed spanning tree for that given network.
3) Consider two substitution ciphers. One adds a value of i to the ASCII code of the
plaintext character. The other adds a value of j to the plaintext character. All additions are
modulo 256. Now consider a double-encryption method that adds i to each plaintext
character and then adds j to the resulting ciphertext character to get another ciphertext
character. Again, all calculations are modulo 256 How much more secure is this double
encryption when compared with either single-encryption method? Explain your answer.
4) Consider the bit string 001011010101000011111101001101 and the key 10110. Use the
key to encrypt and then decrypt the string using bit level ciphering.
5) Suppose you were trying to crack an encryption method that used a 64-bit key. Assuming
a brute force attack, how many keys per second must you try to crack the code in 30
days?
A
C
D
G
B
E
F
H
I
Comp6461 – Fall 2014 Theory Assignment 3 - Page 2
6) Three broad classes to multiple access techniques exist, which are: channel partitioning,
random access and taking turns. In general, it is assumed that any network would use one
of these techniques or the other. However, cable Internet access networks utilize all three
techniques. Describe how this is done by such networks, and explain how the utilization
of any of these techniques does not conflict with the utilization of the other two.
7) In general, fully-connected topology is exhaustive and very unlikely to be used for the
construction of a network.
a. Are there any clear and significant advantages of such topology? Explain clearly.
b. Explain why it is unlikely that such topology be used for network construction.
You should clearly indicate the major disadvantages of such topology.
c. While this topology seems to make little sense for the construction of networks, in
the general terms, it is actually used as part of Data Centers to connect Tier-1 and
Tier-2 switches. Explain clearly the major advantages of such utilization in data
centers. You should provide some example that shows, through some numerical
values, the obvious advantages of such utilization.
8) Assume the utilization of Hamming Codes for single-bit.
50120140503006
This document summarizes research on combining fountain coding and network coding over wireless channels. Fountain coding is an error correction technique that allows recovery from erased packets. Network coding improves throughput in wireless networks by allowing nodes to combine packets. The study models a simple network using both techniques and simulates its performance over different wireless fading channels. The results show that combining fountain and network coding improves throughput by over 70% compared to using only network coding. It also achieves zero error rate under different channel conditions, outperforming the use of only network coding.
Iterative network channel decoding with cooperative space-time transmission
This document summarizes an iterative network-channel decoding scheme for cooperative space-time transmission with network coding. The scheme uses convolutional codes as network codes at the relay node and Reed-Solomon codes as channel codes at the user nodes. An iterative joint network-channel decoder exchanges soft information between convolutional code-based network decoder and Reed-Solomon code-based channel decoders. Extrinsic information transfer analysis is performed to investigate the convergence properties of the proposed iterative decoder.
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IJSTEV2I12120
This document describes the design and implementation of an IP core for the CAN protocol. It begins with an introduction to CAN and its use in automotive and industrial applications. It then discusses the protocol layers, frame formats, arbitration, and error handling mechanisms of CAN. The document proceeds to describe the design of Verilog modules for a CAN transceiver including transmitter and receiver modules. It presents simulation waveforms showing the transmission and reception of CAN frames between two FPGA boards. It concludes that the IP core was successfully implemented on Spartan 3 and Spartan 6 FPGAs to demonstrate node-to-node communication over a CAN bus.
MMedia-Lau
This document discusses two schemes for implementing multirate transmission in fiber-optic code-division multiple access (CDMA) networks: the parallel scheme and the serial mapping scheme. The parallel scheme assigns each user multiple addresses based on their data rate and encodes bits in parallel. The serial mapping scheme encodes bits serially using optical orthogonal codes (OOCs) constructed from frequency hop codes. Analysis shows the parallel scheme can support error correction coding to increase network capacity, while the serial mapping performs well even without coding. Both schemes allow accommodating high numbers of multirate users without increasing optical processing complexity.
Optimal configuration of network
Chennai Office: JP INFOTECH, Old No.31, New No.86, 1st Floor, 1st Avenue, Ashok Nagar, Chennai-83. Landmark: Next to Kotak Mahendra Bank/Bharath Scans
Landline: (044) - 43012642 / Mobile: (0)9952649690
Pondicherry Office: JP INFOTECH, #45, Kamaraj Salai, Thattanchavady, Puducherry - 9
Landmark: Opp. to Thattanchavady Industrial Estate & Next to VVP Nagar Arch.
Landline: (0413) - 4300535 / Mobile: (0)8608600246 / (0)9952649690
Ff34970973
International Journal of Engineering Research and Applications (IJERA) is an open access online peer reviewed international journal that publishes research and review articles in the fields of Computer Science, Neural Networks, Electrical Engineering, Software Engineering, Information Technology, Mechanical Engineering, Chemical Engineering, Plastic Engineering, Food Technology, Textile Engineering, Nano Technology & science, Power Electronics, Electronics & Communication Engineering, Computational mathematics, Image processing, Civil Engineering, Structural Engineering, Environmental Engineering, VLSI Testing & Low Power VLSI Design etc.
Can Protocol For Automobiles
This pdf is about the CAN communication protocol, which is vital for automobiles.A Brief Overview. The CAN bus protocol is defined by the ISO 11898-1 standard and can be summarized like this: The physical layer uses differential transmission on a twisted pair wire. A non-destructive bit-wise arbitration is used to control access to the bus. This is made with the help of Engineersgarage.
Similar to 1. Provide a technical description of 4B5B Digital Encoding Scheme..pdf (20)
Implementation of a bit error rate tester of a wireless communication system ...
Implementation of a bit error rate tester of a wireless communication system ...
Energy Efficient Wireless Sensor Network Using Network Coding Based Multipath...
Energy Efficient Wireless Sensor Network Using Network Coding Based Multipath...
Application Aware Topology Generation for Surface Wave Networks-on-Chip
Application Aware Topology Generation for Surface Wave Networks-on-Chip
The Minimum Cost Forwarding Using MAC Protocol for Wireless Sensor Networks
The Minimum Cost Forwarding Using MAC Protocol for Wireless Sensor Networks
Comp6461 – Fall 2014 Theory Assignment 3 - Page 1 COM.docx
Comp6461 – Fall 2014 Theory Assignment 3 - Page 1 COM.docx
Iterative network channel decoding with cooperative space-time transmission
Iterative network channel decoding with cooperative space-time transmission
More from fashiongallery1
For this lab you will complete the class MyArrayList by implementing.pdf
Find the time it takes the boat to travel the given distance. A ball is thrown vertically upward
with a speed of 40.0 m/s. How high does it rise? How long does it take to reach its highest
point? How long does the ball take to hit the ground after it reaches its highest point? What is
its velocity when it returns to the level from which it started? The center of mass moves with
constant acceleration when constant forces act on the object. A gym ground. How high above
this point is her center of mass at the following times? Ignore the effects
Solution
initial velocity, u = + 40 m/s
a = - 9.8 m/s^2
(a) it will rise until its velocity becomes zero.
hence final velocity, v = 0
Applying, v^2 - u^2 = 2 a h
0^2 - 40^2 = 2(-9.8)(h)
h = 81.63 m
(B) v = u + at
0 = 40 - 9.8 t
t = 4.08 sec
(C) now for motion from highest point to ground,
initial velocity, v (velocity at highets point) = 0
displacement, y = - 81.63 m
a = - 9.8 m/s^2
applying, y = u t + a t^2 /2
- 81.63 = 0 - 9.8 t^2 / 2
t = 4.08 s
(D) applying v = u + at
v = 0 + (-9.8)(4.08)
v = - 40 m/s
(minus sign indicates that direction is downwards).
Discuss the character and impact of the economic and legal revouluti.pdf
Discuss the character and impact of the economic and legal revoulutions on the American
economy between 1815 and 1840. Did this market revolution have to be so antagonistic toward
laborers? Explain your answer.
Solution
Market revolution refers to the changes in market structure from local to national markets.
Revolution impacted highly in agricultural sector. It has changed agricultural sector positively.
Textile and manufacturing industries drastically boom and strengthened the economy. Roadways
and canal system expanded, coin was made from precious metal, and there was huge financial
growth. During market revolution Americans began to experience the forces of supply and
demand. Transportation network highly changed during revolution and play a vital role in
commerce and new market.
Due to revolution there was drastic changes occurred in manual labor process. It has changed the
schedules, wages and working environment for laborers. Artisanal trades started to give way to
best efficient system of production, instead of using skilled labor and thus skilled labor were not
required for the production. There was no job security and laborer was paid low wages..
Discrete Math -Use induction to prove. The city of Inductionapolis.pdf
Discrete Math -
Use induction to prove. The city of Inductionapolis has multiple police districts. Any two
districts are connected by a one-way street. Show that there is a route that passes through every
district of the city.
Solution
Base case: 2 districts
Since there are one-way streets between any two districts. So there is a route passing through the
two districts
Hence base case is true
Inductive hypothesis: Assume it is true for some n number of districts, n>=2
Inductive step: We show it is true for n+1
COnsider any arbitrary district , say, D
Remaining n district have a route,R, passing through them because of inductive hypothesis
So, the C be a district which is the end point . Since there is a one way street from C to D call it ,
S
So the route, R+S is the route passing through all n+1 districst
Hence true for n+1
And hence for all n>=2.
Describe polarization and why it is important to WLANs.Solution.pdf
Describe polarization and why it is important to WLANs.
Solution
Polarization, likewise called wave polarization, is a declaration of the introduction of the lines of
electric flux in an electromagnetic field ( EM field ). Polarization can be consistent - that is,
existing in a specific introduction at all circumstances, or it can turn with each wave cycle.
Polarization is essential in remote correspondences frameworks. The physical introduction of a
remote reception apparatus relates to the polarization of the radio waves got or transmitted by
that recieving wire. In this way, a vertical reception apparatus gets and transmits vertically
captivated waves, and an even radio wire gets or emanates on a level plane spellbound waves.
The best short-run correspondences is acquired when the transmitting and accepting (source and
goal) reception apparatuses have a similar polarization. The slightest proficient short-run
interchanges for the most part happens when the two reception apparatuses are at right edges (for
instance, one even and one vertical). Over long separations, the environment can bring about the
polarization of a radio wave to change, so the refinement amongst flat and vertical turns out to be
less noteworthy.
Some remote radio wires transmit and get EM waves whose polarization turns 360 degrees with
each total wave cycle. This kind of polarization, called curved or roundabout polarization, can be
either clockwise or counterclockwise. The best interchanges results are gotten when the
transmitting and getting reception apparatuses have a similar feeling of polarization (both
clockwise or both counterclockwise). The most noticeably bad correspondences for the most part
happens when the two radio wires emanate and get in the inverse sense (one clockwise and the
other counterclockwise).
Polarization influences the proliferation of EM fields at infrared ( IR ), noticeable, bright ( UV ),
and even X-beam wavelength s. In conventional noticeable light, there are various wave parts
aimlessly polarization points. At the point when such light is gone through an uncommon
channel, the channel hinders all light aside from that having a specific polarization. At the point
when two polarizing channels are put so a beam of light goes through them both, the measure of
light transmitted relies on upon the edge of the polarizing channels regarding each other. The
most light is transmitted when the two channels are arranged so they spellbind light in a similar
bearing. The slightest light is transmitted when the channels are arranged at right points to each
other.One of the minimum comprehended properties of a remote flag is its polarization,
particularly in the event that you are introducing a considerable measure of WiFi Antennas in
one area, as on a tower. Polarization is dictated by the way a radio wire is mounted, and can
normally just be either level or vertical. This is imperative, particularly in indicate point remote
correspondence, in light of .
Describe the four basic elements of most communication systems.So.pdf
Describe the four basic elements of most communication systems.
Solution
A communication (message) system transmits, receives, and processes information in order
between two or more locations by means of electronic circuits.
Source or else Information
1.Analog [analog voice, video signal]
2. Digital [data]
Transmitter
A group of electronic workings and circuits intended to convert the in order into a signal suitable
for transmission over a known communication intermediate.
Receiver
Another set of electronic mechanism and circuits that accept the transmit communication from
the channel and change it back into a form comprehensible by humans.
Noise
Any random, unwanted energy that enters the connections system via the association’s medium
and interfere with the transmitted signal.
Channel
Provides means of transporting signals from a transmitter to a receiver.
Can someone please help me figure out how to do this Required Resou.pdf
Can someone please help me figure out how to do this? Required Resources Device with
Internet access Optional: IPv4 address calculator Identify IPv4 Addresses In Part 1, you will be
given several examples of IPv4 addresses and will complete tables with appropriate information.
Analyze the table shown below and identify the network portion and host portion of the given
IPv4 addresses. The first two rows show examples of how the table should be completed. Key
for table: N = all 8 bits for an octet are in the network portion of the address n = a bit in the
network portion of the address H = all 8 bits for an octet are in the host portion of the address h
= a bit in the host portion of the address
Solution
Ip address/prefix
Network/host N,n=network H,h=host
Subnet mask
Network address
192.168.10.10/24
N.N.N.H
255.255.255.0
192.168.10.0
10.101.99.17/23
N.N.nnnnnnnh.H
255.255.254.0
10.101.98.0
209.165.200.227/27
N.N.N.nnnhhhhh
255.255.255.224
209.165.200.224
172.31.45.252/24
N.N.N.H
255.255.255.0
172.31.45.255
10.1.8.200/26
N.N.N.nnhhhhhh
255.255.255.192
10.1.8.192
172.16.117.77/20
N.N.nnnnhhhh.H
255.255.240.0
172.16.112.0
10.1.1.101/25
N.N.N.nhhhhhhh
255.255.255.128
10.1.1.0
209.165.202.140/27
N.N.N.nnnhhhhh
255.255.255.224
209.165.202.128
192.168.28.45/28
N.N.N.nnnnhhhh
255.255.255.240
192.168.28.32
Ip address/prefix
Network/host N,n=network H,h=host
Subnet mask
Network address
192.168.10.10/24
N.N.N.H
255.255.255.0
192.168.10.0
10.101.99.17/23
N.N.nnnnnnnh.H
255.255.254.0
10.101.98.0
209.165.200.227/27
N.N.N.nnnhhhhh
255.255.255.224
209.165.200.224
172.31.45.252/24
N.N.N.H
255.255.255.0
172.31.45.255
10.1.8.200/26
N.N.N.nnhhhhhh
255.255.255.192
10.1.8.192
172.16.117.77/20
N.N.nnnnhhhh.H
255.255.240.0
172.16.112.0
10.1.1.101/25
N.N.N.nhhhhhhh
255.255.255.128
10.1.1.0
209.165.202.140/27
N.N.N.nnnhhhhh
255.255.255.224
209.165.202.128
192.168.28.45/28
N.N.N.nnnnhhhh
255.255.255.240
192.168.28.32.
Assume that the Current Assets for Shine Co. as of Decebmer 31, 2011.pdf
Assume that the Current Assets for Shine Co. as of Decebmer 31, 2011, are listed below.
Assume further that the total Current Liabilites on the same date are $150,000. What is the
current ratio for Shine Co. on December 31, 2011?
ASSETS
Current assets:
Cash $90,000
Temporary Investments 30,000
Accounts Receivable 78,000
Inventories 99,000
Prepaid Expenses 20,700
Total current assets $317,700
.3
1.0
1.3
2.1
Solution.
All computer are configured for TCPIP connectivity. This exercise i.pdf
All computer are configured for TCP/IP connectivity. This exercise is to find out the IP
addresses and related information on a computer:
Perform this on a local computer:
From Start - Type CMD to go to the Command Line - Blue screen is displayed
On the Command Line Type IPCONFIG /all
Several items and details of the network and IP will be displayed.
Make a screen capture
Describe the items listed on that screen.
Assignment Submission:
1. The screen capture
2. Details of the items listed on the screen.
Solution
C:\\Users\\Desire>ipconfig /all
Windows IP Configuration
Host Name . . . . . . . . . . . . : DESIRE
Primary Dns Suffix . . . . . . . : microsoft.com
Node Type . . . . . . . . . . . . : Hybrid
IP Routing Enabled. . . . . . . . : No
WINS Proxy Enabled. . . . . . . . : No
DNS Suffix Search List. . . . . . : microsoft.com
Ethernet adapter Bluetooth Network Connection:
Media State . . . . . . . . . . . : Media disconnected
Connection-specific DNS Suffix . :
Description . . . . . . . . . . . : Bluetooth Device (Personal Area Network)
Physical Address. . . . . . . . . : CC-3D-82-8F-29-DC
DHCP Enabled. . . . . . . . . . . : Yes
Autoconfiguration Enabled . . . . : Yes
Wireless LAN adapter Wireless Network Connection:
Connection-specific DNS Suffix . :
Description . . . . . . . . . . . : Intel(R) Dual Band Wireless-N 7260
Physical Address. . . . . . . . . : CC-3D-82-8F-29-D8
DHCP Enabled. . . . . . . . . . . : Yes
Autoconfiguration Enabled . . . . : Yes
Link-local IPv6 Address . . . . . : fe80::d34:f753:2eab:997e%12(Preferred)
IPv4 Address. . . . . . . . . . . : 192.168.0.16(Preferred)
Subnet Mask . . . . . . . . . . . : 255.255.255.0
Lease Obtained. . . . . . . . . . : Wednesday, November 30, 2016 7:39:12 AM
Lease Expires . . . . . . . . . . : Wednesday, December 07, 2016 7:53:06 AM
Default Gateway . . . . . . . . . : 192.168.0.1
DHCP Server . . . . . . . . . . . : 192.168.0.1
DHCPv6 IAID . . . . . . . . . . . : 248266114
DHCPv6 Client DUID. . . . . . . . : 00-01-00-01-1D-BD-33-64-48-0F-CF-23-E3-09
DNS Servers . . . . . . . . . . . : 202.88.174.6
202.88.174.8
NetBIOS over Tcpip. . . . . . . . : Enabled
Ethernet adapter Local Area Connection:
Media State . . . . . . . . . . . : Media disconnected
Connection-specific DNS Suffix . : es.ad.adp.com
Description . . . . . . . . . . . : Intel(R) Ethernet Connection I218-LM
Physical Address. . . . . . . . . : 48-0F-CF-23-E3-09
DHCP Enabled. . . . . . . . . . . : Yes
Autoconfiguration Enabled . . . . : Yes
Tunnel adapter isatap.{DD8F0340-D0FE-4237-A79F-B19A3EB7CD56}:
Media State . . . . . . . . . . . : Media disconnected
Connection-specific DNS Suffix . :
Description . . . . . . . . . . . : Microsoft ISATAP Adapter
Physical Address. . . . . . . . . : 00-00-00-00-00-00-00-E0
DHCP Enabled. . . . . . . . . . . : No
Autoconfiguration Enabled . . . . : Yes
Tunnel adapter Teredo Tunneling Pseudo-Interface:
Media State . . . . . . . . . . . : Media disconnected
Connection-specific DNS Suffix . :
Description . ..
4. At what temperature will a solution of 8.27 g CaCl2 in 45.0 g H2.pdf
4. At what temperature will a solution of 8.27 g CaCl2 in 45.0 g H2O begin to freeze? Assume
complete dissociation
of CaCl2. (The freezing point depression constant for water is
Solution
molality = (8.27/111)*(1000/45) = 1.655
vant hoff factor = 3
so deltaT= K*M*i = 1.86 * 1.655 *3 = 9.24
so Tsolvent - Tsolution = deltaT........ => Tsolution = Tsolvent - deltaT.... =>Tsolution = 1-9.24
= 8.24\'C.
Briefly Explain all these points belowA. Marketing channels VS cha.pdf
Briefly Explain all these points below
A. Marketing channels VS changes in technology (online marketing)
B. Vertical marketing system (VMS) VS Conventional marketing system
C. Role of marketing intermediaries
D. Distribution strategies
E. Levels of service that retailers can offer
F. Types of retailers
Solution
c) Role of marketing intermediaries:
Marketing Intermediaries can be defined as the individuals or organizations the link the producer
to ultimate customer.The marketing intermediaries play a very important role in the development
of business by selling and promoting the products and services.The marketing intermediaries can
also be termed as agents of organizations.The different marketing intermediariers are agents,
wholesalers and retailers.They get the product at a certain price from organization and then they
sell it at somewhat higher price to the customer.The link the retail chain and are a part of supply
chain.Their exists different levels of channels in supply chain.
1) One level channel:
Producer---retiler----customer
2) two level channel:
producer---wholesaler---retailer---customer
3)Three level channel
Producer---distibutor---wholesaler---retailer---customer
4) Four level channel
Producer---agent-----distibutor---wholesaler---retailer---customer.
The detailed role of the marketing intermediaries is :
1) They facilitate or improve the salesby physically available to or close to customers.
2) They act as a sub distribution channel
3)They divide the bulk according to the minimum requirements of customers.
4) they provide according to suitability of customers.
5) They give presale and post sale service to customers.
6) They also bare risk of organization
7) They act as chain and chane agents of both technology and products.
D) Distribution strategies:The distribution startegies are ainly decided by the top
management.They are generally decided by keeping in view the 4Psof marketing i.e.,
product,price,place and promotion.There are different types of distribution strategies:
1) Exclusive distribution:It includes few intermediaries and usage of less retail outlets.
2)Selective distribution : It is one in which the manufacturer uses few selected intermediariers to
pass the product.
3)Intensive distribution: It is the one in which a firm sells through more number of outlets or
intermediaries.
F) Types of retilers:Retailers are individuals who direcly sell to the ultimate customer the
products.They mainly reach the customers who require less amont of goods.
The different types of retaiilers are:
1) spetiality stores: such retailers carry very narrow product line and offer high level of service.
2)Department stores:these type of retailers provide high range of producta and services.They
offer different levels of service at diffrent pricing.
3)Supermarkets: such type of retailers sell food and bevarage products and services.
4)Convienece retailers: These retailers sell few products at higher prices and are usually located
at the housin.
Write a class that implements the BagInterface. BagInterface should .pdf
Which one is NOT a duty of MySQL Administration? (Points : 2) Server startup and
shutdown
User account maintenance
Log maintenance
Running SQL statementsQuestion 2.2. (TCO A) How do you display the current system
variable values? (Points : 2) SHOW SYSTEM;
SHOW VARIABLES;
SHOW VALUES;
SHOW SYSTEM VARIABLES;Question 3.3. (TCO A) How do you display the global
variable values? (Points : 2) SHOW SYSTEM;
SHOW VARIABLES;
SHOW VALUES;
SHOW GLOBAL VARIABLES;Question 4.4. (TCO A) Which statement enables you to
rename tables or modify their structure? (Points : 2) MODIFY TABLE
ALTER TABLE
CHANGE TABLE
CREATE TABLEQuestion 5.5. (TCO A) Which is the statement that will rename the
instructor table to a new name? (Points : 2) ALTER TABLE instructor RENAME TO instr;
RENAME instructor instr;
This task is not available in MySQL.
ALTER TABLE instructor TO instr;Question 6.6. (TCO A) Review the following SQL
statement:
CHECKSUM TABLE instructor;
What is going to be the result if there is no table named instructor? (Points : 2)
CHECKSUM value is zero.
CHECKSUM value is negative.
CHECKSUM value is NULL.
An error occurs.Which one is NOT a duty of MySQL Administration? (Points : 2)
Server startup and shutdown
User account maintenance
Log maintenance
Running SQL statements
Solution
1.1 Which one is NOT a duty of MySQL Administration?
a) log maintainance
2.2 How do you display the current system variable values?
show variables
3.3 How do you display the global variable values?
SHOW GLOBAL VARIABLES;
4.4 Which statement enables you to rename tables or modify their structure?
ALTER TABLE
5.5 Which is the statement that will rename the instructor table to a new name?
This task is not available in MySQL.
6.6. CHECKSUM TABLE instructor;
CHECKSUM value is NULL..
write an equation for the transformation of the graph of y =f(x) tra.pdf
Write a C program in Linux to implement the following functionalities
Declare a global variable usr_interrupt=1
Write a signal handler function
voidreset_signalvaluezero ()
When a SIGALRM signal arrives this function will be called in which variable will be set
sig_atomic_t usr_interrupt = 0;
Write a signal handler function
voidIncrement_signalvalue ()
When a SIGINT signal arrives this function will be called in which variable will be incremented
the usr_interrupt by 1.
Write a main function
intmain (void)
Handle two Signals SIGALRM and SIGINT.
Set the alarm for 10 sec
Parent process will sit in tight loop by keeping check on usr_interrupt variable once this variable
will be 5 parent process will print some ENDING message and will exit.
Solution
#include
#include
#include
#include
#include
sig_atomic_t usr_interrupt = 1;
void reset_signalvaluezero(int signo)
{
if (signo == SIGALRM)
usr_interrupt = 0;
}
void Increment_signalvalue(int signo)
{
if (signo == SIGINT)
usr_interrupt++;
}
int main(void)
{
if (signal(SIGINT, Increment_signalvalue) == SIG_ERR)
printf(\"\ can\'t catch SIGINT\ \");
if (signal(SIGALRM, reset_signalvaluezero) == SIG_ERR)
printf(\"\ can\'t catch SIGALRM\ \");
alarm(10);
while(1)
{
if (usr_interrupt >= 5)
{
printf (\"Exiting...\");
return 0;
}
}
return 0;
}.
Using c++Im also using a the ide editor called CodeLiteThe hea.pdf
Typed out please In a short and simple response comment on this persons answer for masonry
work Additives combined with concrete to achieve certain properties are called what? Name a
few that would benefit the Engineer and Customer.
Response - Additives to concrete are utilized to provide certain benefits when placing concrete.
These additives called \"Admixtures\" can be used to speed up the curing process, slow down the
curing process, or help in working with concrete during cold temperatures. Retarders can be
added to concrete to slow down curing. Accelerators can be used to speed up the curing. The
most advanced additive is the Air-entrainment agent which gives mason the ability to work with
concrete in colder months.
Typed out please In a short and simple response comment on this persons answer for masonry
work Additives combined with concrete to achieve certain properties are called what? Name a
few that would benefit the Engineer and Customer.
Response - Additives to concrete are utilized to provide certain benefits when placing concrete.
These additives called \"Admixtures\" can be used to speed up the curing process, slow down the
curing process, or help in working with concrete during cold temperatures. Retarders can be
added to concrete to slow down curing. Accelerators can be used to speed up the curing. The
most advanced additive is the Air-entrainment agent which gives mason the ability to work with
concrete in colder months.
Response - Additives to concrete are utilized to provide certain benefits when placing concrete.
These additives called \"Admixtures\" can be used to speed up the curing process, slow down the
curing process, or help in working with concrete during cold temperatures. Retarders can be
added to concrete to slow down curing. Accelerators can be used to speed up the curing. The
most advanced additive is the Air-entrainment agent which gives mason the ability to work with
concrete in colder months.
Solution
The response of the person is good. He/she explained the admixtures and their applications pretty
well and also explained accelators, retarders and air entertainment in a simple straight forward
fashion.Overall i would say that the answer is satisfactory.
I will like to add \"PLASTICIZERS\" in the list of admixtures that would benefit the engineer
and customer. Plasticizers are water reducing admixtures and are added to the concrete mix for
making it more plastic without any further addition of water. In other words, they reduce the
quantity of water required to make concrete mixture of better plasticity.
PLEASE HIT LIKE BUTTON IF YOU FIND MY ANSWER SATISFACTORY.
THANK YOU..
Why are helper T-cells called helper cellsThey help pathogens i.pdf
Which observation about the system of equations squareroot a + 2 squareroot b - c = 12 and 3
squareroot ab = 24 squareroot c is correct? The system has exactly three solution because there
are three unknowns. The system has exactly two solutions because there are two equations. The
system has infinitely many solutions because there is more than one unknown. The system has
no solution because there are more equations than unknowns. The system has no solution
because there are more unknowns than equations.
Solution
The answer is last one because inorder to solve any equations the number of equations should be
given which is equal to number of arbitrary constants we have to find
Please rate my answer thank you.
Which of the following is NOT true of the Sons of Liberty a. New Yor.pdf
What type of performance measurement could managerial accountants use to determine the value
and productivity of human resources?
Solution
WAYS TO MEASURE HUMAN CAPITAL OR VALUE OF HUMAN RESOURCES
Human capital is considered a resource; an asset similar to land, equipment, bonds, and stocks.
However, it is INTANGIBLE IN NATURE, just like intellectual property or patents are.
Intangible assets are no less valuable than tangible ones, it’s just that their value cannot be
discerned easily.
One method to value is human capital’s return on investment (ROI).
Steps Involved
Formula = TOTAL ORGANIZATION PROFITS / INVESTMENTS ON HUMAN CAPITAL
Where Total Organizational Profits is profit after covering all of its expen
And Investment on Human Capital refers to money that your organization has put in to develop
its human capital; i.e. recruitment and selection, training and development, compensation, etc
If your ROI is sufficient, and if it is comparable to that of other companies in the same industry.
ROIs differ from one company to the next depending on their size, strategy, and industry, but
bench-marking is always considered good practice!
Some More human capital measurement techniques:
(a). Skills Inventory- It deals with the skills, capabilities, qualifications, trainings, and
certifications of your employees. The skills inventory may also include your employees’
preferences, career goals, and other developmental information.
(b) Personality-Focus on their “other attributes” along with skills, etc.The most important and
considered is personality.
An individual’s attitudes, and innate traits defines the employee. Many recent studies have
shown that over half the organizations today believe that HR is more influential than it was five
years ago. Executives are now recognizing HR’s ability to making strategic contributions to the
organization’s overall objective..
What made the Later Roman Economy so unstable (Bennette, Medieval E.pdf
What forms the corpus luteum and what hormones does it secrete?
The corpus albicans becomes the corpus luteum after ovulation and secretes estrogen and
progesterone.
The cumulus oophorus becomes the corpus luteum before ovulation and secretes luteinizing
hormone and estrogen to promote oocyte development.
The follicular cells become the corpus luteum after ovulation and secrete follicle stimulating
hormone and estrogen to promote oocyte development.
The Graafian follicle becomes the corpus luteum after ovulation and secretes estrogen and
progesterone.
The corpus albicans becomes the corpus luteum after ovulation and secretes estrogen and
progesterone.
The cumulus oophorus becomes the corpus luteum before ovulation and secretes luteinizing
hormone and estrogen to promote oocyte development.
The follicular cells become the corpus luteum after ovulation and secrete follicle stimulating
hormone and estrogen to promote oocyte development.
The Graafian follicle becomes the corpus luteum after ovulation and secretes estrogen and
progesterone.
Solution
Answer: D: the graffian follicle becomes the corpus luteum after ovulation and secretes estrogen
and progesterone.
The degenerating corpus luteum is called corpus albicans.
The corpus luteum secretes large quantity of progesterone and moderrior piyate quantity of
estrogen.
Leutinizing hormone and follicle stimulating hormone are from anterior pituitary..
What data would illustrate whether these underlying problems are occ.pdf
//variable to store probing location
//calculating the hash code
//if the position is empty, immediately return failure...
//...but if it\'s a match, return the data straight away...
//...otherwise, probe to the next item, looping to zero if necessary
//keep probing until data is found or entire table has been visited
//if the probed element is completely empty, return failure
//if the probed element is a match, return the data...
//...otherwise, keep probing for the next item, looping back to zero if necessary
//if nothing has been returned by now, data is not present
Solution
int probe;
//assignment is a constant time operation so O(1)
//here we are checking if table[code] == null which is also a constant time operation so O(1)
//if the position is empty, immediately return failure...
//same here O(1)
//...but if it\'s a match, return the data straight away...
//...otherwise, probe to the next item, looping to zero if necessary
//The time complexity isO(n) for while loop since we are looping the elements and O(1) for if
loop, but as weconsider only the biggest term , time complexity is O(n)
//O(n) is also time complexity for whole program for the same reason that we consider only
highest term
//keep probing until data is found or entire table has been visited
//same here O(1)
//if the probed element is completely empty, return failure
//same here O(1)
//if the probed element is a match, return the data...
//same here O(1),reason mentioned above
//...otherwise, keep probing for the next item, looping back to zero if necessary
return null;
//if nothing has been returned by now, data is not present.
1. What are distinct characteristics of baby boomers, generation X, .pdf
1. What are distinct characteristics of baby boomers, generation X, and generation Y employees?
2. How should managers use this understanding in their leadership, motivation of, and
communication with employees?
3. How does a manager reach out to employees when there are critical differences in values and
beliefs between manager and employee?
Solution
1) Different characteristics of baby boomers, generation X and generation Y employess:
Baby Boomers: Baby boomers are typically people who are born just after world war 2 and are
mostly in their 50-55 age. This generation of employees posses below mentiones chracteristics:
Generation X: These are the people who are next generation to baby boomers are in there 30s.
Few characteristics possed by this generation are:
Generation Y: They are born in the next generation to genration X. They are typically in the age
group of 18-25
Characteristics possed by them are:
2) Managers may use the above mentioned characteristics to deal differently with different
generations. Like, they can reward gen Y for good work to boost their confidence. They can
assign good designation to gen X to use there energy to make great decisions. Baby boomers can
be assigned strategic decision as they have work ethics of high standard and also have great
experience.
3) According to different generations, managers need to take different set of decisions to reach
out to employees. Like baby boomers need more high authority assurance to deal as they are
very much experienced. Gen Y needs ethical codes to convey the message as they are resonablly
new to work place..
VERSION The cells denoted by the letter Ain the figure to.pdf
Use the diagram below to answer the question that follows. Aguilar Manufacturing Company
packages a product for shipping by wrapping tape around the package as shown in the diagram.
An additional 10% length of tape per package is needed for overlap. What is the total length of
tape needed per package? 40 inch inches 66 inches 77 inches 110 inches.
Solution
Original length= 2(2(5+10))+2(15+5)=100
So. Length of package =100+100×10/100=110 inch
Correct answer is E..
Using standard libraries like stdio and sdtlib.h and using stats.h a.pdf
Unlike the Federal income tax, most states do not require some form of state income tax.
True
False
Solution
Correct answer is True
Unlike Federal income tax, most states do not require some form of state income tax - This
statement is true as fililng of Fedral income tax return is mandatory for almost everybody but
some US states like Alaska, Florida, Navada, South Dakota, Texas, Washington and Wayoming
do not require filing of state income tax..
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Chapter 2
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- 2. technique, blocks of data are procedure in its place of creating a signal for every individual bit. In 4B/5B encoding, present are 32 5-Bit codes, but 16 are utilized. Of the residual 16 codes, 7 are unacceptable and others are employed to send control in sequence 4 bits of data are twisted into a single 5-bit sequence and in that case encoded to be transmitted. In the 5-bit code, here must be one foremost zero and no more than two sprawling zeros. These guarantees there are in no way more than three successive zeros. This lets the baud rate to be equivalent to the bps, and is more competent. This is a important improvement over the other plans.