The document calculates the freezing point of a solution containing 8.27 g of CaCl2 dissolved in 45.0 g of water, assuming complete dissociation of CaCl2. The molality is computed to be 1.655, and the freezing point depression yields a final solution temperature of 8.24 °C. This is derived using the freezing point depression constant for water and the Van 't Hoff factor.

1. 4. At what temperature will a solution of 8.27 g CaCl2 in 45.0 g H2O begin to freeze? Assume
complete dissociation
of CaCl2. (The freezing point depression constant for water is
Solution
molality = (8.27/111)*(1000/45) = 1.655
vant hoff factor = 3
so deltaT= K*M*i = 1.86 * 1.655 *3 = 9.24
so Tsolvent - Tsolution = deltaT........ => Tsolution = Tsolvent - deltaT.... =>Tsolution = 1-9.24
= 8.24'C