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• Charles Coulomb
                  (1736-1806: French)
                   – Studied relationship between
                     force and charge
Coulomb’s Law




                • SI unit of charge = 1 coulomb (C)
                   – NOT charge of 1 e- (1.6 x 10-19)
                   – Charge of 6.24 x 1018 e-
                      • We’ll get real definition later
                 1 Coulomb is about how many electrons flow
                 through a 100 W light bulb every second.
• The LAW!
                 – Force directly related to magnitude of
                   the charges
                 – Force inversely related to the square of
                   the distance between the two charges
Coulomb’s Law




                  Fα q Q

                  Fα
                        1             kq Q
                                    F= 2
                       r2              r
                  F α qQ
                       r2
• Coulomb’s Law:
  Should look familiar
                             Large Magnitude
                               9 x 109 N·m2/C2
  Attractive or
   Repulsive                                     Product of
                           kQ q                   charges
                         F= 2
                            r
    Small Magnitude                     Both are
     6.67 x 10-11 N·m2/kg2           inverse-square
                                          laws

                             GMm                 Product of
                     F=         r2                masses
Only Attractive
• Sample problem 0! YEAH!
                 – A negative charge of -5.3μC and a
                   positive charge of 12 μC are
                   separated by 0.69 m. What is the
                   force of attraction between the two of
Coulomb’s Law




                   them?
                  (Remember that μ means 10-6 and n means 10-9)



                 F= kq Q        (9 x   (5.3 x 10- (12 x 10-6)
                     r2  =      109)       6
                                            )
                                        (0.69)  2



                 F = 1.2 N
• Sample problem 1! YEAH!
                 – What is the magnitude of the
                   electrostatic force between 2 protons
                   in the nucleus? (assume the distance
                   to be 3.0x10-13 cm)
Coulomb’s Law




                 F= kq Q      (9 x    (1.6 x 10- (1.6 x 10-
                     r2  =    109)        19
                                             )       19
                                                        )
                                     (3.0 x 10  -15
                                                   )
                                           2

                 F =25.6 N
• Sample problem 1! YEAH!
                 – What is the magnitude of the
                   electrostatic force between 2 protons
                   in the nucleus? (assume the distance
                   to be 3.0x10-13 cm)
Coulomb’s Law




                 F= kq Q      (9 x    (1.6 x 10- (1.6 x 10-
                     r2  =    109)        19
                                             )       19
                                                        )
                                     (3.0 x 10  -15
                                                   )
                                           2

                 F =25.6 N

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11 Coulomb's Law Notes

  • 1. • Charles Coulomb (1736-1806: French) – Studied relationship between force and charge Coulomb’s Law • SI unit of charge = 1 coulomb (C) – NOT charge of 1 e- (1.6 x 10-19) – Charge of 6.24 x 1018 e- • We’ll get real definition later 1 Coulomb is about how many electrons flow through a 100 W light bulb every second.
  • 2. • The LAW! – Force directly related to magnitude of the charges – Force inversely related to the square of the distance between the two charges Coulomb’s Law Fα q Q Fα 1 kq Q F= 2 r2 r F α qQ r2
  • 3. • Coulomb’s Law: Should look familiar Large Magnitude 9 x 109 N·m2/C2 Attractive or Repulsive Product of kQ q charges F= 2 r Small Magnitude Both are 6.67 x 10-11 N·m2/kg2 inverse-square laws GMm Product of F= r2 masses Only Attractive
  • 4. • Sample problem 0! YEAH! – A negative charge of -5.3μC and a positive charge of 12 μC are separated by 0.69 m. What is the force of attraction between the two of Coulomb’s Law them? (Remember that μ means 10-6 and n means 10-9) F= kq Q (9 x (5.3 x 10- (12 x 10-6) r2 = 109) 6 ) (0.69) 2 F = 1.2 N
  • 5. • Sample problem 1! YEAH! – What is the magnitude of the electrostatic force between 2 protons in the nucleus? (assume the distance to be 3.0x10-13 cm) Coulomb’s Law F= kq Q (9 x (1.6 x 10- (1.6 x 10- r2 = 109) 19 ) 19 ) (3.0 x 10 -15 ) 2 F =25.6 N
  • 6. • Sample problem 1! YEAH! – What is the magnitude of the electrostatic force between 2 protons in the nucleus? (assume the distance to be 3.0x10-13 cm) Coulomb’s Law F= kq Q (9 x (1.6 x 10- (1.6 x 10- r2 = 109) 19 ) 19 ) (3.0 x 10 -15 ) 2 F =25.6 N

Editor's Notes

  1. 1 coulomb = The amount of electricity transported by a current of one ampere flowing for one second. About as many electrons that pass through 100-W bulb every second
  2. What do we need to replace the ‘ α ’ with?
  3. Electrostatic interactions may be attractive or repulsive, but gravity is ONLY attractive
  4. Because both protons have the same charge we replace q 1 q 2 with q 2 .
  5. Because both protons have the same charge we replace q 1 q 2 with q 2 .