Describe in detail the specimen of a potato with a drop of iodine in.pdf

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Describe in detail the specimen of a potato with a drop of iodine in comparison with a potatoe with just a drop of water under the microscope. Solution Answer: Starch (a carbohydrate) can be identified by a positive iodine test. Few drops of iodine solution are added to a raw or boiled sample of the substance suspected of containing starch. If starch is present, the substance will turn blue-black in the area where the iodine solution touches it. Substances with very small amounts of starch will turn faint blue or greenish instead of blue- black. Many materials of biological origin have high starch content. These materials can be identified with the iodine test. The sample specimen with potato and a drop of iodine will turn blue black concluding for the presence of large amount of starch. The sample specimen with potato and a drop of water will not undergo a change in colour..

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CASe Stic ato wad duun SolutionAggregates used in this method a.pdf

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Write MatLAb code that would produce the following print: Solution rgb = imread(\'coloredChips.png\'); figure imshow(rgb) d = imdistline; delete(d); gray_image = rgb2gray(rgb); imshow(gray_image); [centers, radii] = imfindcircles(rgb,[20 25],\'ObjectPolarity\',\'dark\') [centers, radii] = imfindcircles(rgb,[20 25],\'ObjectPolarity\',\'dark\', ... \'Sensitivity\',0.9) imshow(rgb); h = viscircles(centers,radii); [centers, radii] = imfindcircles(rgb,[20 25],\'ObjectPolarity\',\'dark\', ... \'Sensitivity\',0.92); length(centers) delete(h); % Delete previously drawn circles h = viscircles(centers,radii);.

Write MatLAb code that would produce the following printSolution.pdf

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Why do rays run radially in a woody stem? How would wood produced in a dry year differ from wood produced in a wet year? What is dendrochronology? Solution Dear student, Wood produced in dry year: Is just brought on by serpula lacrymans and is the most genuine type of parasitic rot in a building. It can spread onto and crush a great part of the timber. Signs for dry decay: Particular mushroom smell White contagious development with yellow and lilac tinges Profound splits show up inside the wood Both delicate and hardwoods can be harmed Wood produced in wet year: Happens all the more every now and again, yet is less genuine; rot is normally bound to the range where timber has gotten to be and stays wet. Indications of wet decay : Mutilation, discolouration, non-abrasiveness and breaking Loss of quality to the timber Noticeable contagious development – this may now and again happen Smell – there might be a soggy smelly smell Flare-ups of dry and wet decay begin in comparative ways. The develop fruiting assortments of wood-annihilating organisms that create amid an assault deliver a large number of tiny spores and these are generally scattered via air streams. In the event that they fall on untreated moist wood they will develop by pushing out an empty tube called a hypha which develops and branches to frame a mass of hyphal strings called mycelium. The principle contrasts between dry year and wet year are the level of advancement of mycelium on the wood surface and the capacity of the organism to spread into different timbers by means of nearby brick work. It is imperative that the two sorts of rot be recognized since they require distinctive treatment. Part3 Dendrochronology is the investigation of environmental change as recorded by tree development rings. Every year, trees include a layer of development between the more established wood and the bark. This layer, or ring as found in cross segment, can be wide, recording a wet season, or thin, recording a dry developing season. Since the rings are essentially recording a decent developing season or a terrible developing season, they are in a roundabout way recording more than just dampness. They likewise record temperature and overcast cover as they effect tree development too. This record of yearly summer data is imperative when you consider that specific sorts of trees develop gradually over several years, and subsequently contain a record of the same number of years of atmosphere and environmental change..

Why do rays run radially in a woody stemHow would wood produced i.pdf

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Write a java program that reads a number N as input and displays the following output using stacks with parameters. Example o Input: Enter N: o Output: 5 Solution import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; public class Stacks { public static void main(String[] args) throws IOException { // used variables BufferedReader reader; String input,outerSpaces,innerSpaces; Integer number; // taking input System.out.print(\"Enter N : \"); reader = new BufferedReader(new InputStreamReader(System.in)); input = reader.readLine(); number = Integer.parseInt(input); // printing upper stack for(int i=1;i0;i--){ outerSpaces = getOuterSpaces(i); innerSpaces = getInnerSpaces(number, i); System.out.print(outerSpaces); System.out.print(i); System.out.print(innerSpaces); if(i != number){ System.out.print(i); } System.out.print(outerSpaces); System.out.println(); } } public static String getOuterSpaces(int offset){ StringBuffer buffer = new StringBuffer(\"\"); for(int i=0;i.

Write a java program that reads a number N as input and displays the.pdf

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Why is the DNA fragment amplified with Phusion DNA into pGEM-T plasmids? The colorless E. coli colonies in our experiment contain the recombinant pGEM-T/GFPuv plasmid. Some of the colonies emit green fluorescence whereas others don\'t when they are irradiated with long wave UV. light. Explain Why. Solution 1) Phusion DNA Polymerase enzyme is a proof-reading polymerase, with extreme specificity. The enzyme provides robust amplification. Since it is a proof-reading enzyme, Phusion DNA Polymerase creates blunt ends in the DNA fragment, because of which it cannot be directly cloned into the plasmid. 2) GFPuv ,the green fluorescent protein, exhibits structural polymorphism. Onlyproper conformationproduces fluorescence. Some colonies emitted fluorescence, because the GFPuv in them is in proper conformation while in colonies which did not emit fluorescence, the protein was not in a proper conformation..

Why is the DNA fragment amplified with Phusion DNA into pGEM-T plasmi.pdf

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Which of these is a function of the skeletal system? communication system creation of the structural framework within soft organs of the body storage site for calcium removal of old or damaged blood cells Solution Answer: storage site of calcium Explanation: The followings are the function of the skeletal system: 1. Support: Provides structural support for the entire body 2. Protection: Surrounds soft tissue- ex. ribs and sternum protect the heart and lungs, - skull protects the brain 3. Movement: Skeletal muscle is attached to bone so it pulls on the bone when it contracts 4. Mineral homeostasis: Stores calcium and phosphorus--minerals are released into the blood when needed. 5. Blood cell production: Red bone marrow produces red blood cells, white blood cells and other blood elements 6. Storage: Storage of minerals and lipids(fats)---yellow marrow stores fat --(found in long bones).

Which of these is a function of the skeletal system communication s.pdf

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what is transport layer? what are the typical attacks in transport layer? what are the controls that are employed in the layer to minimize the attack or vulnerability that leads to the attack? cite references Solution Transport Layer:- In computer networking, the transport layer is a conceptual division of methods in the layered architecture of protocols in the network stack in the Internet Protocol Suite and the Open Systems Interconnection (OSI). The protocols of the layerprovide host-to-host communication services for applications. Typical attacks in transport layer:- 1. SESSION HIJACKING: Session Hijacking is commonly known as TCP session Hijacking is a way of taking over a secure/ unsecure web user session by secretly obtaining user’s session ID and pretending to be the authorized user for accessing the data. How it works and types: Session hijacking works by taking advantage of the fact that most communications are protected (by providing credentials) at session setup, but not thereafter. These attacks generally fall into three categories: Man-in-the-middle (MITM), Blind Hijack, and Session Theft. In MITM attacks, an attacker intercepts all communications between two hosts. With communications between a client and server now flowing through the attacker, he or she is free to modify their content. Protocols that rely on the exchange of public keys to protect communications are often the target of these types of attacks. In blind hijacking, an attacker injects data such as malicious commands into intercepted communications between two hosts commands like “net.exe local group administrators /add Evil Attacker”. This is called blind hijacking because the attacker can only inject data into the communications stream; he or she cannot see the response to that data (such as “The command completed successfully.”) Essentially, the blind hijack attacker is shooting data in the dark, but as you will see shortly, this method of hijacking is still very effective. In a session theft attack, the attacker neither intercepts nor injects data into existing communications between two hosts. Instead, the attacker creates new sessions or uses old ones. This type of session hijacking is most common at the application level, especially Web applications. Main features are: -URL (Uniform resource locator) -Cookies -Session ID The cookies stores the previous records of the users and the URL logs can give the current visited site, a hacker take benefits from it and hacks user’s session ID through it, after doing that it pretends to be the authorized user and accesses the data. A cookie usually is a piece of text sent by a server to the web client and sent back unchanged by the client, each time it access the data. 1.1 Methods used to perform session hijacking: 1.1.1IP Spoofing: It basically means taking identity of someone else to perform some task, in this the attacker pretends to be the authorized user and access some confidential information, not only this, the.

what is transport layer what are the typical attacks in transport l.pdf

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Which monetary aggregate would you expect the Federal Reserve to have the greatest control. Explain. Solution Fed controls the money supply in the economy, by expanding money supply during recession and contracting money supply during uncontrolled expansion (that leads to inflation). In this context, Fed has highest control over M0 which is notes and coins in circulation. That\'s because M0 is the most liquid form of monetary aggregate which Fed can directly control. Starting from M1, other modes of savings are added to the aggregate, reducing their liquidity, and Fed has no direct control over how individuals or firms save their money..

Which monetary aggregate would you expect the Federal Reserve to hav.pdf

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wavelet decomposition process code in matlab??? Solution WAVELET DECOMPOSITION PROCESS :- function [coef,scf]=mywavedec2(x,N, wname) coef={cA_N;cV_N;cH_N;cD_N;cV_N-1;cH_N-1;cD_N-1;… …;cV_1;cH_1;cD_1} [Lo_D,Hi_D] = wfilters(wname,\'d\'); lf=length(Lo_D); imshow(x);title(\'Original Image\'); [r,c]=size(x); xlabel([\'Size : \',num2str(r),\'*\',num2str(c)]); xd=double(x); [rx,cx]=size(x); [o2sa,f1sa,rsx]=sizcoef([rx,cx],lf,N); a=[o2sa,f1sa,rsx] coef=[]; scf=[rx,cx]; for i=1:N [cA,cV,cH,cD]=mydwt2(xd,Lo_D,Hi_D); xd=cA; outmp={cV;cH;cD}; scf=[size(cV);scf]; coef=[outmp;coef]; end coef=[cA;coef]; scf=[size(cA);scf]; plotcoef(N,wname,coef); subplot(N+1,3,2); yt=uint8(coef{1}); [yrow,ycol]=size(yt); imshow(yt);title( [\'Approximation A\',num2str(N)]); xlabel([\'Size : \',num2str(yrow),\'*\',num2str(ycol)]); titllist={[\'Vertical Detail V\'];[\'Horizontal Detail H\']; [\'Diagonal Detail D\']}; pn=2; for pr=1:N for pc=1:3 subplot(N+1,3,pn+2); yt=[ ]; yt=uint8(coef{pn}); [yrow,ycol]=size(yt); imshow(yt);title([ titllist{pc},num2str(N-pr+1)]); xlabel([\'Size : \',num2str(yrow),\'*\',num2str(ycol)]); if mod(pn+2,3)==1 ylabel([\'Level \',num2str(N-pr+1)]); end pn=pn+1; end end function [o2sa,f1sa,rsx]=sizcoef(sx,lf,N)^4 o2sa=sx; f1sa=[0 0]; osx=sx; for i=1:N ot=osx+lf-1; sa=floor(ot/2); o2sa=[o2sa;ot]; f1sa=[f1sa;sa]; osx=sa; end rsx=zeros(N+1,2); rsx(1,:)=sx; addln=0; for j=2:N+1 aln=floor((addln+lf-1)/2); tsx=f1sa(j,:)-aln; rsx(j,:)=tsx; addln=aln; end function y=downspl(x) N=length(x); M=floor(N/2); i=1:M; y(i)=x(2*i).

wavelet decomposition process code in matlabSolution WAVE.pdf

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What happens if a red hot inoculation loop plunges into the nutrient media? Name the type(s) of culture used to make your cultures of two unknown specimens. For inoculating into a liquid media, what is the most appropriate transfer (inoculation) tool? For inoculating into a solid media, what is the most appropriate transfer (inoculation) tool? Describe & sketch the appearance of growth on nutrient agar slant. Solution 1. what happens when red hot inoculation loop plunges into nutrient media ? ANSWER - An aerosol may be created, releasing bacteria in to the air .an aerosol release within the laboratory can pose an infection risk, which may not be immediately recognized and may affect all users of the laboratory . 2. name the culture used to make your cultures of two unknown specimens ? ANSWER - USE OF SELECTIVE AND DIFFERENTIAL MEDIA Differential medium types are those that distinguish microorganisms from one another based on growth characteristics evident when grown on specific medium types. Organisms with differing growth characteristics typically show visible differences in growth when placed on differential media. Examples include blood agar, Eosin Methylene Blue (EMB) agar, Mannitol Salt agar, and MacConkey agar. Selective medium types are formulated to support the growth of one group of organisms, but inhibit the growth of another. These media contain antimicrobials, dyes, or alcohol to inhibit the growth of the organisms not targeted for study. Selective medium types include EMB agar, Mannitol Salt agar, MacConkey agar, and Phenylethyl Alcohol (PEA) agar. 3. For inoculating in to liquid media what is the most appropriate transfer tool ? ANSWER - Inoculating Loop , as the loop can hold a drop of liquid . 4. For inoculating in to solid media what is the most appropriate transfer tool ? ANSWER - same , inoculating loop . 5. Describe the appearance of growth on nutrient agar slant ? ANSWER - Cultures are often transferred to agar slants, in addition to broth tubes and agar plates. An agar slant is a test tube containing agar, in which the solid agar forms a slant in the test tube. When inoculating an agar slant, draw the loop containing the inoculum very lightly over the surface in a zigzag formation while being careful not to break the surface. A needle can be used instead of a loop to inoculate an agar slant by stabbing the needle containing the inoculum into the agar ..

What happens if a red hot inoculation loop plunges into the nutrient .pdf

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What are speaking notes? Have you used speaking notes before? What works? What doesn\'t? Solution Speaker Notes – Meaning: Speaker Notes is a tool / feature offered by power point presentation to allow presenter to add reminder on what the presenter presents when a presentation is done using power point software. Speaker Notes will be available on presenter\'s screen only and will not be visible on the presentation shown to the viewers and can be added to all slides of the power point presentation by the presenter. (Person who prepares and presents power point presentation). Speaker Notes - How to insert? Speaker Notes will appear at the bottom of each slide of the power point presentation if added by the presenter. To insert Speaker Notes in a slide, presenter must click on \"Notes\" tab that appears at the bottom of respective slide and add required notes on the pop-window that appears at the bottom of respective slide on the screen. After completing the notes, presenter can click anywhere on the slide other than on pop-up window to complete the notes and continue using other slides. Notes added will appear constantly without being hidden always for presenter\'s easy reference. What works? What doesn\'t? I\'ve made a power point presentation at my college during a seminar. Speaker Notes on power point presentation done by me was very much helpful whenever I needed sudden references to improve the presentation\'s quality. However, as the notes were appearing as low font and each slide contained different notes applicable to respective slide, my presentation was affected due to oversight in one or two instances. That is, referring to another slide\'s notes visually but tried delivering current slide\'s presentation as a virtual image and the presentation was collapsed for a while..

What are speaking notes Have you used speaking notes before What wo.pdf

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There are five components of internal control: 1) Control environment 2) Risk assessment 3) Control activities 4) Information and communication system 5) Monitoring processes. In your own words explain the purpose of internal controls. Then select one of the components shown above and explain the role it plays in protecting the assets of the business. Many of these activities can be observed in the workplace both inside and outside of the accounting department. Please share any work experiences you may have had with these activities or any that you have observed in other businesses, even if they are not in the accounting department. Be sure to provide a reference for any material used from a source. Solution Internal Control Purpose - It support business by provide an idea to employees and other personnel’s regarding the aspect, objective of business. Due to the internal control the stake holders will be get facilitated that the business transactions are recorded properly and there is no any under reporting or none reporting of transactions. The consumers also preferred those organizations which have proper internal control, as it helps consumers in understanding organisation. Control Activities The control activities led down policies and procedures to be followed by personnel’s so that there will not be any misuse of assets of the organization. There should be proper backup as per control over any event of loss of data due to any unfortunate event. The control activities ensure that the applications and network are safeguarded from any threat as part of internal control. Internal control ensure that control activities must have business continuity plan..

There are five components of internal control1) Control environme.pdf

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The height of a right triangle is 2 feet more than twice the length .pdf

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ST=TS show that the generalized eigenspace of T are invariant under .pdf

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Singer and Nicolson proposed the fluid mosaic model of the cell membrane The main type of membrane lipids: phospholipids, glycolipids, and sterols could be represented with the respectively membrane lipids phosphoglycerides, cerebrosides and cholesterol. In E. coli the enzyme responsible for creating unsaturated bonds from saturated ones in the fatty adds of the cell membrane is denaturize Substances that can readily pass through the cell membrane are chemically hydrophobic or nonpolar in nature. Transmembrane proteins involved in detecting external stimuli and relaying that Information to the cell are most likely receptor proteins. The current understanding of the membranes of the cell is based on the fluid mosaic model. The ability of some organisms to alter their membrane lipid composition in response to temperature is known as homeoviscous adaptation The technique of transferring proteins from SDS-PAGE gels onto a membrane and using labeled antibodies to identify particular proteins is known as western blot Triglycerides are composed of three fatty acids attached to a molecule of glycerol Solution Ans. 1. True. They proposed the model in 1972, and were awarded Nobel prize for it. Ans. 2. True Phospholipids = phsophoglycerides Sterol = cholesterol Glycolipids are lipids containing covalently linked carbohydrate moieties. Cerebrosides, also known as, glycosphingolipids, also contain glucose or galactose residues linked to the ceramide (lipid) skeleton. Thus, cerebrosides are also glycolipid in nature because have carbohydrate moieties linked to lipid. Ans. 3. True Fatty acid desaturase creates double bond (unsaturation) in fatty acids by removing two H-atoms from adjacent carbo atoms in the chain. Ans. 4. True Since the lipid bilayer has a hydrophobic core, small, non-polar or hydrophobic molecules (for example, CO2) can readily pass through it. In contrast to it, polar or charged ion/ molecules or large molecules (non-polar as well as polar) can’t pass through the membrane so efficiently. Ans. 5. True Receptor proteins need to bind an effector molecule at the extracellular face and transmit the signal to cytoplasmic side of the cell. Thus, it shall be a transmembrane protein, i.e. a protein that spans the lipid bilayer. Ans. 6. True Ans. 7. True Many organism can change the lipid composition of the membrane depending of the environmental temperature. The phenomenon being called “homeoviscous adaptation”. For example, in winters, the membrane of a plant cell also retains the fluid-nature under freezing conditions. Relatively larger abundance of cis-fatty acids, unsaturated fatty acid in the phospholipids and steroids makes the membrane more fluid because both cis-form and unsaturation makes the chain irregular-shaped and hinders the close packing of hydrophobic core. So, such membrane retain fluidity even at very low temperatures. Ans 8. True Western blot detects specific protein through combined use of SDS-PAGE and immunoblotting technique.

Singer and Nicolson proposed the fluid mosaic model of the cell membr.pdf

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Opportunity or temptation? Journal of Case Studies Introduction Their facility was just too small. Steady growth had them bursting at the seams. Finally, after years of searching, they thought that a suitable location finally had been found, a location that might garner enough support to win membership approval when it came time to vote. Capacity, turmoil, turnover, a bad economy, limited budget, and aged physical plant were all constraints that had held back Hope Community Church (HCC). But there were good reasons that its name was Hope. One was that its leadership core was made up of people who were of strong faith and strong will. Leadership believed that constraints were nothing more than speed bumps that could be overcome. Turmoil and turnover had already been overcome. The bad economy was subsiding and, at least regarding monthly operations, the church budget was no longer an issue. The final constraints, capacity and structural integrity of the church building continued to be problematic and underscored the need to relocate the church. Sometimes, things are beyond repair or are no longer suitable for their intended purpose, but facing the need for change can be a difficult challenge. HCC\'s church sanctuary had some serious structural problems. So, for many years, a church building committee had been in search of a better facility or building site. More than once it was thought that a suitable \"new\" location or facility had been found, but each time a fatal flaw had been discovered. Finally, the church building committee had found what seemed to be an affordable acreage on which they could build. Now church members had to make the decision as to whether or not to buy the new site. Still, it was not without potential problems. But hopefully, church members would not consider any of them to be major when it came time for them to vote. Should the church membership vote yes on its opportunity to purchase the land for construction of a new church, or, vote no and continue to meet in the current facility, and once again ask its building committee to start over in its quest for a new building site? The thought of moving to a new location touched emotions on both sides of the issue. One group of church members had strong personal attachments and memories that were inextricably tied to the old sanctuary. For many of these long term members who favored remodeling and making do with the current facility, moving was out of the question. The oldest active member of the church, and perhaps the church\'s most loved member, was a stoic advocate for remaining with the status quo as she had been married in the old sanctuary decades ago and had no desire to move. She had a strong following, and it was no secret that she was not excited about the possibility of the church relocating. In fact, her opinions were so well known that there was concern among the church leaders that moving to a new location could so offend her and other long term members that .

Opportunity or temptationJournal of Case StudiesIntroductionT.pdf

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Multiple choice. Is there evidence that the age at which women get married has changed over the past 100 years? The accompanying scatterplot shows the trend in age at first marriage for women. Complete parts a through d below. Solution We do all these by inspection, so we cannot really explain it better other than by looking at the graph. a) OPTION D. It explains itself. ***************** b) OPTION A. The association appears relatively strong. [There is obviously a ternd everywhere, although it is irregular.] ************** c) OPTION B. No, as a whole, the graph is clearly nonlinear. [We take it as a whole from 1900 to 2020] ****************** d) OPTION B. No, a linear model would not be appropriate, although one could fit a linear model to the period from 1975 to 2003. [It is linear on that part, and has many data points.].

Multiple choice.Is there evidence that the age at which women get .pdf

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List three Key characteristics of DNA used in studying DNA in electrophoresis Solution Three key characteristics of DNA used in studying DNA in electrophoresis= 1) Neghative charge of DNA- The negative charge of its phosphate backbone moves the DNA towards the positively charged anode.during electrophoresis. 2)Fragment size of DNA- Small DNA molecules molve more quickly through the gel than larger DNA molecules.In gel Electrophoresis ,the bands furthest from the start of the gel contain the smallest fragment of DNA whereas the bands closest from the start of gel contain the largest fragment of DNA molecules. 3)Conformation of DNA - Super coiled DNA moves faster than relaxed DNA. 4)Molecular weight of DNA- In the Electrophoresis,the migration of DNA molecules in solution,in the absense of a gel matrix ,is independent opf molecular weight..

List three Key characteristics of DNA used in studying DNA in electr.pdf

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Let T be the transform from P2 (the vector space of second degree polynomials) into 3 defined by, T(p(t)) = [p(1) p(2) p(3)](where the prime denotes the derivative.) Show that T is a linear transformation. Is T an isomorphism Solution T(p(t))= [p(1), p(2), p(3)] we have to show that T is linear tranformation so T(p(t)+kQ(t)) = [p(1), p(2), p(3)] + k [Q(1), Q(2), Q(3)] hence T is linear tranformation.

Let T be the transform from P2 (the vector space of second degree po.pdf

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Liens: Kanahara is employed part-time by the Cross-Bar Packing Corp. and earns take-home pay of $400 per week. He is $2,000 in debt to the Holiday Department Store for goods purchased on credit over the past 8 months. Most of this property is non-exempt and is now in Kanahara\'s apartment. Kantara is in default on his payments to Holiday. Holiday learns that Kanahara has a girlfriend in another state and that he plans to give her most of this property for Christmas. Discuss what actions are available to and should be taken by Holiday to collect the debt owed by Kanahara. Solution There are some actions taken by Holiday to collect the debt owed by Kanahara are 1.Company can hold his salary , 2.Company can stop providing any facility like conveyance,transport allowance,phone allownace. 3.He has to work for over time.

Liens Kanahara is employed part-time by the Cross-Bar Packing Corp..pdf

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